pandas df remove items from df1 that are also in df2 - pandas

I have two very large csv files. They are both only one col with integers. I need to check for every integer in dfA if they are in dfB. If so, I need to remove item a from dfA.
I would probably loop through dfA and check for every value if in dfB, but looping is wayyyy too slow.
dfA :
0
0 9312969810
1 3045897298
2 8162414592
3 2030000000
4 7876904982
dfB:
0
0 2030000000
1 2030156119
2 2030389149
3 2030641047
4 2030693850
output:
0
0 2030156119
1 2030389149
2 2030641047
3 2030693850
Since 2030000000 is in dfB, we need to remove from dfA.
Does anyone have a better way.
Thanks
edit: csv for dfB is 2gb and dfA is 5mb

There's no 'magic bullet' here, you'll have to loop through each list at least once
You can iterate through just one of the lists as follows (though, i think under the hood, we iterate through both lists)
dfA = pd.read_csv(file1)
dfB = pd.read_csv(file2)
for n in dfB.values:
dfA = dfA[dfA[0] != n]
Alternative, what Zero said, but I think that's still (under the hood) doing (more efficient) looping
dfA[~dfA[0].isin(dfB[0])]

Related

How to remove line with lowercase characters in dataframe?

I have a dataframe with two columns with a different amino acid mutations and a predicted stability score such as GLYA35A 0.16139. However there are some rows that contains lines with a lower case character such as GLYA35e. I need to remove all the rows where the line contains a lower case character.
I tried to use this
sub = "e"
new_list = df_list["Mutation"].str.find(sub)
However the output only provides this.
0 -1
1 -1
2 -1
3 -1
4 -1
...
Is it possible to directly remove the unwanted lines from the dataframe? Seems like a straight forward question but I'm not able to see a good solution.

Count in string terms and stored mapped to other value

I have a pandas dataframe which includes columns (amongst others) like this, with RATING being integers 0 to 5 and COMMENT is string:
RATING COMMENT
1 some text
2 more text
3 other text
... ...
I would now like to mine (for lack of better word ) the key words for a list of strings:
list = ['like', trust', 'etc etc etc']
and would like to iterate through the COMMENT and count the number of key words by rating to get a df out like so
KEYWORD RATING COUNT
like 1 202
like 2 325
like 3 0
like 4 967
like 5 534
...
trust 1 126
....
how can I achieve this?
I am beginner so would really appreciate your help (and the simpler and more understandable the better)
thank you
hi at the moment I have been iterating through manually,
ie
#DATA_df is the original data
word_list = ['word', 'words', 'words', 'more']
values = [0] * len(word_list)
tot_val=[values]*5
rating_table = pd.DataFrame(tot_val, columns=word_list)
for i in len(word_list):
for g in len (DATA_df[COMMENT]):
if i in DATA_df[COMMENT][g]:
rating_table[i][DATA_df[RATING]-1] +=1
this give a DF like so
word words words more
0 0 0 0 0
1 0 0 0 0
2 0 0 0 0
3 0 0 0 0
4 0 0 0 0
that I am then trying to add to.... it appears really clunky
I managed to solve it, key points learnt are use group by to pre-select data based on the rating, this slices the data and it is possible to alternate through the groups. also use of str.lower() in combination with str.count() worked well.
I am thankful if more experienced programmers could show me a better solution, but at least this works.
rating = [1,2,3,4,5]
rategroup = tp_clean.groupby('Rating')
#print (rategroup.groups)
results_list =[]
for w in word_list:
current = [w]
for r in rating:
stargroup = rategroup.get_group(str(r))
found = stargroup['Content'].str.lower().str.count(w)
c = found.sum()
current.append(c)
results_list.append(current)
results_df = pd.DataFrame (results_list, columns=['Keyword','1 Star','2 Star','3 Star','4 Star','5 Star'])
The one thing I am still struggling with is how to use regex to make it look for full words. I believe \b is the right one but how do I put it into str.count function?

For each element in the array find the number of ways to present it as a sum of two other numbers from this array

You are given the size of an array and the array itself. I know this problem can be solved effectively with the use of the binary search idea, but i don't know how to use it here. Would appreciate any help and code in c++ or python.
Here is the input-output example:
input:
5
3 3 2 2 1
output:
2 2 0 0 0
P.S. Sorry for my English, I'm from Russia and I'm 16
Try below code, it is not the exact output you want, but is very close:
import itertools
count =[]
stuff = [3,3,2,2,1]
for L in range(0, len(stuff)+1):
for subset in itertools.combinations(stuff, L):
if len(subset) ==2:
add = sum(subset)
count.append(len([i for i in stuff if i == add]))
print count

Extractive Text Summarization: Weighting sentence location in document

I am looking at an extractive text summarization problem. Eventually, I want to generate a list of words (not sentences) that seem to be the most important. One of the ideas that I had was to the words that appear early in the document more heavily.
I have two dataframes. the first is a set of words with their occurrence counts:
words.head()
words occurrences
0 '' 2
1 11-1 1
2 2nd 1
3 april 1
4 b.
And the second is a set of sentences. 0 is the first sentence in the document, 1 is the secont.. etc.
sentences.head()
sentences
0 Site Menu expandHave a correction?...
1 This will be a chance for ...
2 The event will include...
3 Further, this...
4 Contact:Share:
I managed to accomplish my goal like this:
weights = []
for value in words.index.values:
weights.append(((len(sentences) - sentences.index.values) *
sentences['sentences'].str.contains(words['words'][value])).sum())
weights
[0,
5,
5,
0,
12,...]
words['occurrences'] *= weights
words.head()
words occurrences
0 '' 0
1 11-1 5
2 2nd 5
3 april 0
4 b. 12
However, this seems sort of sloppy. I know that I can use list comprehension (I thought it would be easier to read on here without it) - but, other than that, does anyone have thoughts on a more elegant solution to this problem?

Organizing data (pandas dataframe)

I have a data in the following form:
product/productId B000EVS4TY
1 product/title Arrowhead Mills Cookie Mix, Chocolate Chip, 1...
2 product/price unknown
3 review/userId A2SRVDDDOQ8QJL
4 review/profileName MJ23447
5 review/helpfulness 2/4
6 review/score 4.0
7 review/time 1206576000
8 review/summary Delicious cookie mix
9 review/text I thought it was funny that I bought this pro...
10 product/productId B0000DF3IX
11 product/title Paprika Hungarian Sweet
12 product/price unknown
13 review/userId A244MHL2UN2EYL
14 review/profileName P. J. Whiting "book cook"
15 review/helpfulness 0/0
16 review/score 5.0
17 review/time 1127088000
I want to convert it to a dataframe such that the entries in the 1st column
product/productId
product/title
product/price
review/userId
review/profileName
review/helpfulness
review/score
review/time
review/summary
review/text
are the column headers with the values arranged corresponding to each header in the table.
I still had a tiny doubt about your file, but since both my suggestions are quite similar, I will try to address both the scenarios you might have.
In case your file doesn't actually have the line numbers inside of it, this should do it:
filepath = "./untitled.txt" # you need to change this to your file path
column_separator="\s{3,}" # we'll use a regex, I explain some caveats of this below...
# engine='python' surpresses a warning by pandas
# header=None is that so all lines are considered 'data'
df = pd.read_csv(filepath, sep=column_separator, engine="python", header=None)
df = df.set_index(0) # this takes column '0' and uses it as the dataframe index
df = df.T # this makes the data look like you were asking (goes from multiple rows+1column to multiple columns+1 row)
df = df.reset_index(drop=True) # this is just so the first row starts at index '0' instead of '1'
# you could just do the last 3 lines with:
# df = df.set_index(0).T.reset_index(drop=True)
If you do have line numbers, then we just need to do some little adjustments
filepath = "./untitled1.txt"
column_separator="\s{3,}"
df = pd.read_csv(filepath, sep=column_separator, engine="python", header=None, index_col=0)
df.set_index(1).T.reset_index(drop=True) #I did all the 3 steps in 1 line, for brevity
In this last case, I would advise you change it in order to have line numbers in all of them (in the example you provided, the numbering starts at the second line, this might be an option about how you handle headers when exporting the data in whatever tool you might be using
Regarding the regex, the caveat is that "\s{3,}" looks for any block of 3 consecutive whitespaces or more to determine the column separator. The problem here is that we'll depend a bit on the data to find the columns. For instance, if in any of the values just so happens to appear 3 consecutive spaces, pandas will raise an exception, since the line will have one more column than the others. One solution to this could be increasing it to any other 'appropriate' number, but then we still depend on the data (for instance, with more than 3, in your example, "review/text" would have enough spaces for the two columns to be identified)
edit after realising what you meant by "stacked"
Whatever "line-number scenario" you have, you'll need to make sure you always have the same number of columns for all registers and reshape the continuous dataframe with something similar to this:
number_of_columns = 10 # you'll need to make sure all "registers" do have the same number of columns otherwise this will break
new_shape = (-1,number_of_columns) # this tuple will mean "whatever number of lines", by 10 columns
final_df = pd.DataFrame(data = df.values.reshape(new_shape)
,columns=df.columns.tolist()[:-10])
Again, take notice of making sure that all lines have the same number of columns (for instance, a file with just the data you provided, assuming 10 columns, wouldn't work). Also, this solution assumes all columns will have the same name.