I have a varchar column which has values like "Aug 07 2017, 04:14 AM,EDT".
I need to convert this to a date column so that its possible to take the maximum value of the date.
I tried this:
select CONVERT(datetime, #dateField, 108)
from table
But I am getting the following error:
Conversion failed when converting date and/or time from character string.
You can just use left() and convert():
select convert(date, left('Aug 07 2017, 04:14 AM,EDT', 11))
If you want a datetime then convert the date and time separately, then:
select ( convert(datetime,
left('Aug 07 2017, 04:14 AM,EDT', 11)
) +
convert(datetime,
convert(time,
substring('Aug 07 2017, 04:14 AM,EDT', 14, 8)
)
)
)
Note: This is not taking the time zone into account.
Better Datetime solution
DECLARE #dateField AS NVARCHAR(50) = 'Aug 07 2017, 04:14,EDT'
-- Get index of last comma
DECLARE #validDateField AS NVARCHAR(20) = REPLACE(LEFT(#dateField, LEN(#dateField)- CHARINDEX(',', reverse(#dateField))), ',','')
SELECT CONVERT(DATETIME, #validDateField, 108)
Here is a solution:
select CONVERT(datetime, REPLACE(LEFT(#dateField, LEN(#dateField) - 3),',','') ,108 )
Related
IF I Select #rpmMonth = SEP 2019 it should pull the data from JAN 2019 to SEP 2019
**I Have only One Parameter Value i.e #rpmMonth of VARCHAR Type.
Declare #firstDay Date=(
select convert(varchar(10),DATEADD(Year,-1*DateDiff(Year,getdate(),0),0),120))
Declare #CurDate Date=(
SELECT convert(varchar(10),DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE())+1,0)),120))
select * from YOURTABLE
where colname between #firstDay and #CurDate
Ideally, you should be using a date datatype, not a varchar. If we do, however, have to use a varchar then you could do something like this:
SELECT {Columns}
FROM {Your Schema And Table}
WHERE {DateColumn} >= CONVERT(date,CONCAT(RIGHT(#rpmMonth),'0101'))
AND {DateColumn} < DATEADD(MONTH, 1, CONVERT(date, '01 ' + #rpmMonth));
(Obviously replace the parts in braces ({}) and assumes the language of the LOGIN is an English based language.)
This would give you all rows on or after Jan 01 of the year for #rpmMonth and before the month after #rpmMonth.
If you use a proper date, and pass the first date of the month i.e. (2019-09-01 for the sample you gave), then you could do the below:
SELECT {Columns}
FROM {Your Schema And Table}
WHERE {DateColumn} >= DATEADD(YEAR, DATEDIFF(YEAR, 0, #rpmMonth),0)
AND {DateColumn} < DATEADD(MONTH, 1, #rpmMonth);
SQL Server is pretty good about converting date values. You should be able to do:
select . . .
from t cross join
(values (convert(date, #rpmMonth)) as v(dte)
where datecol >= datefromparts(year(v.dte), 1, 1) and
datecol < datefromparts(year(dateadd(month, 1, v.dte)), month(dateadd(month, 1, v.dte)), 1)
I'm passing a start date and end date parameter to my stored procedure. I'm doing a simple test here:
DECLARE #StartDate DATE = '10/06/2013' --dd/mm/yyyy
SELECT #StartDate -- this statement running successfully
DECLARE #EndDate DATE = '30/06/2013' --dd/mm/yyyy
SELECT #EndDate -- this statement giving error
This statement returns the following error
Msg 241, Level 16, State 1, Line 2
Conversion failed when converting date and/or time from character string.
Does anybody have idea what's going wrong with EndDate?
I'm pretty sure the error is on this line:
DECLARE #EndDate DATE = '30/06/2013' --dd/mm/yyyy
Not on the SELECT. It wouldn't make sense that it would be on the SELECT, because processing a variable should be fine.
I would recommend that you use YYYYMMDD formats. The following is my preference:
DECLARE #EndDate DATE = '2013-30-06' ;
However, it can fail for certain internationalization settings. The following is documented to always work:
DECLARE #EndDate DATE = '20133006' ;
'10/06/2013' means 06-Oct-2013 not 10-Jun-2013. There is nothing exists with month 30 as in your #EndDate '30/06/2013'.
DECLARE #StartDate DATE='10/06/2013'
DECLARE #DummyDate DATE = '2013-Oct-06'
IF #StartDate = #DummyDate
BEGIN
SELECT 1
END
By default sql server takes date value in 'yyyy-mm-dd' format,
So you need to follow that format or you need to convert date format accordingly.
T-SQL convert string to datetime - SQL Server convert string to date
SELECT convert(datetime, '10/23/2016', 101) -- mm/dd/yyyy
SELECT convert(datetime, '2016.10.23', 102) -- yyyy.mm.dd
SELECT convert(datetime, '23/10/2016', 103) -- dd/mm/yyyy
SELECT convert(datetime, '23.10.2016', 104) -- dd.mm.yyyy
SELECT convert(datetime, '23-10-2016', 105) -- dd-mm-yyyy
-- mon types are nondeterministic conversions, dependent on language setting
SELECT convert(datetime, '23 OCT 2016', 106) -- dd mon yyyy
SELECT convert(datetime, 'Oct 23, 2016', 107) -- mon dd, yyyy
-- SQL string to datetime conversion without century - some exceptions
SELECT convert(datetime, '10/23/16', 1) -- mm/dd/yy
SELECT convert(datetime, '16.10.23', 2) -- yy.mm.dd
SELECT convert(datetime, '23/10/16', 3) -- dd/mm/yy
SELECT convert(datetime, '23.10.16', 4) -- dd.mm.yy
SELECT convert(datetime, '23-10-16', 5) -- dd-mm-yy
SELECT convert(datetime, '23 OCT 16', 6) -- dd mon yy
SELECT convert(datetime, 'Oct 23, 16', 7) -- mon dd, yy
I have a problem in converting sql server 2008 datetime to varchar,
Select convert(varchar(20),convert(datetime, '2013-12-11 00:59:00.000'))
the result is Dec 11 2013 12:59AM but I need it to be actually Dec 11 2013 00:59AM as in the database dates are of 24-Hour format.
How can I correct the query?
There are two functions, cast and convert that you can use.
http://msdn.microsoft.com/en-us/library/ms187928.aspx
You forgot to put in the format style.
-- Using cast
Select cast('2013-12-11 00:59:00.000' as varchar(20)) as my_casted_date
-- Using convert
Select convert(varchar(24), '2013-12-11 00:59:00.000', 113) as my_converted_date
Use format with custom date time strings for utlitmate flexibility.
http://msdn.microsoft.com/en-us/library/8kb3ddd4(v=vs.110).aspx
-- Using format
DECLARE #my_date datetime2 = '2013-12-11 00:59:00.000';
SELECT format(#my_date, 'MMM dd yyyy HH:MM tt', 'en-us') as str_english_date
Solution that will work with SQL Server 2008.
-- Create a date time variable
DECLARE #my_date DATETIME2 = '2013-12-11 00:59:00.000';
-- Using convert
SELECT
CONVERT(varchar(24), #my_date, 113) +
CASE
WHEN DATEPART(HH, #my_date) < 12 THEN ' AM'
ELSE ' PM'
END
AS my_converted_date;
This will be perfect for you..
declare #dt datetime
set #dt='12-Jan-2014 23:59'
SELECT Right(CONVERT(VARCHAR, #dt, 100),7) AS DateTime_In_12h_Format
It's not nice but it does its job:
DECLARE #Var DATETIME;
SET #Var = '2013-12-11T00:59:00.000';
SELECT
#Var AS SourceValue,
CONVERT(VARCHAR(50), #Var, 100) AS FormatedValue1,
CASE
WHEN CONVERT(VARCHAR(50), #Var, 100) LIKE '%[ ]12:__AM' THEN REPLACE(CONVERT(VARCHAR(50), #Var, 100), ' 12:', ' 00:')
ELSE CONVERT(VARCHAR(50), #Var, 100)
END AS FormatedValue2
SourceValue FormatedValue1 FormatedValue2
----------------------- ------------------- -------------------
2013-12-11 00:59:00.000 Dec 11 2013 12:59AM Dec 11 2013 00:59AM
Please try this
Select convert(varchar(20),convert(datetime, '2013-12-11 00:59:00.000'),113) + ' ' +RIGHT(CONVERT(VARCHAR(26), Convert(datetime,'2013-12-11 00:59:00.000'), 109), 2)
Output
11 Dec 2013 00:59:00 AM
Fiddle Demo
I have a table which has a datetime column. I want to show date in date-month-year forma.I am using SQL Server 2008.
You need to convert datetime column
select convert(varchar,datecolumn,103) from yourtable
Some datetime convertions:
SELECT convert(datetime, '10/23/2016', 101) -- mm/dd/yyyy
SELECT convert(datetime, '2016.10.23', 102) -- yyyy.mm.dd
SELECT convert(datetime, '23/10/2016', 103) -- dd/mm/yyyy
SELECT convert(datetime, '23.10.2016', 104) -- dd.mm.yyyy
SELECT convert(datetime, '23-10-2016', 105) -- dd-mm-yyyy
SELECT CONVERT(VARCHAR(10), GETDATE(), 111) AS [YYYY/MM/DD]
/* YYYY/MM/DD
2015/07/11 */
SELECT CONVERT(VARCHAR(10), GETDATE(), 112) AS [YYYYMMDD]
/* YYYYMMDD
20150711 */
-- SQL convert date string to datetime - time set to 00:00:00.000 or 12:00AM
PRINT CONVERT(datetime,'07-10-2012',110) -- Jul 10 2012 12:00AM
PRINT CONVERT(datetime,'2012/07/10',111) -- Jul 10 2012 12:00AM
PRINT CONVERT(datetime,'20120710', 112) -- Jul 10 2012
You can learn all DateTime convertion from here
FORMAT can be used for this;
SELECT FORMAT(GETDATE(), 'dd-MM-yyyy') --20-09-2021
in your case;
SELECT FORMAT(datetime, 'dd-MM-yyyy') AS datetime --20-09-2021
Edit;
Sorry to inform that I've just seen you mentioned SQL Server 2008 this code works for SQL Server 2012 for those who use 2012 and ends up in here!
MySQL has a function called STR_TO_DATE, that converts a string to date.
Question:
Is there a similar function in SQL Server?
If you need to parse a particular format, use CONVERT(datetime, #mystring, #format). Use this as a reference: https://web.archive.org/web/20200729210252/http://www.sqlusa.com/bestpractices/datetimeconversion/
Some examples:
SELECT convert(datetime, '10/23/2016', 101) -- mm/dd/yyyy
SELECT convert(datetime, '2016.10.23', 102) -- yyyy.mm.dd ANSI date with century
SELECT convert(datetime, '23/10/2016', 103) -- dd/mm/yyyy
SELECT convert(datetime, '23.10.2016', 104) -- dd.mm.yyyy
SELECT convert(datetime, '23-10-2016', 105) -- dd-mm-yyyy
-- mon types are nondeterministic conversions, dependent on language setting
SELECT convert(datetime, '23 OCT 2016', 106) -- dd mon yyyy
SELECT convert(datetime, 'Oct 23, 2016', 107) -- mon dd, yyyy
-- 2016-10-23 00:00:00.000
SELECT convert(datetime, '20:10:44', 108) -- hh:mm:ss
-- 1900-01-01 20:10:44.000
What if the string is 7/7/2010?
Then use CONVERT with either 101 (mm/dd/yy) or 103 (dd/mm/yy) depending on what you want:
SELECT CONVERT(DATE, '7/7/2010', 103)
Result:
2010-07-07
CAST(<string> AS DATETIME)
Use CAST.
declare #MyString varchar(10)
declare #MyDate datetime
set #MyString = '2010-08-19'
set #MyDate = cast(#MyString as datetime)
select #MyDate
Here is a good example:
declare #myDate datetime
set #myDate = '06/09/2017'
select concat(convert(varchar(20), #myDate,101), ' -- ',
convert(varchar(20), #myDate,103), ' -- ',
convert(varchar(20), #myDate,6))
This is what you get, depending on 101 or 103 or 6:
09/06/2017 -- 06/09/2017 -- 06 Sep 17
A good summary of types of dates is here - https://www.w3schools.com/sql/func_convert.asp
On MSSQL:
select cast('2012/06/12 10:32AM' as datetime);
You will get it:
2012-06-12 10:32:00.000