How can I get the corresponding value of MAX(date).
Access it returns me an error when I select directly the column with the specified value.
For example, I want to be shown only the line from the image.
Thank you.
Use TOP and ORDER BY:
select top 1 *
from t
order by date desc;
EDIT:
If you want the last date per code, then use a correlated subquery:
select t.*
from t
where t.date = (select max(t2.date) from t t2 where t2.code = t.code);
select * from tblName where DocumentDate in (select max(DocumentDate ) from tblName)
Please use this
If you need last date per code then try this one
SELECT Code, MAX(DocumentDate)
FROM table
GROUP BY Code
You mast creat the join query. For example find MAX(DocumentDate):
SELECT DocumentNumber, Code, SoldPuncte, DocumentDate
from yourTable a inner join
(SELECT DocumentNumber, Code, SoldPuncte, MAX(DocumentDate) as
DocumentDate
from yourTable group by DocumentNumber) b
on a.DocumentNumber=b.DocumentNumber and a.DocumentDate = b.DocumentDate
Related
I have a table Activity having data like below.It contains multiple rows of CreatedBY like IVR,Raghu and IT.
But I need to get the data only when the first row of CreatedBY='IVR'.
This following query will return firstcreated row for each user (CreatedBy)-
SELECT * FROM
(
SELECT *,
ROW_NUMBER() OVER(PARTITION BY CreatedBy ORDER BY CreatedBy,[Date And Time]) RN
FROM your_table
)A
WHERE RN = 1
I suspect you want the first row per ticket_no. At least, that makes more sense as a query.
If so, in SQL Server, you can use a correlated subquery:
select a.*
from activity a
where a.createdby = 'Raghu' and
a.datetime = (select min(a2.datetime)
from activity a2
where a2.ticket_no = a.ticket_no
);
use exists
select a.*
from table a where createdby='IVR'
and datetime in
(select min(datetime) from table b where a.ticketno=b.ticketno
and createdby='IVR')
I want to count id_r and then return the maxim value of count using
MAX(COUNT(id_r))
but shows me this error
the error
Thanks :)
You can only use one aggregation function at a time.
The ANSI standard way to do what you want is:
select count(*)
from t
group by ?
order by count(*) desc
fetch first 1 row only;
Or alternatively a subquery:
select max(cnt)
from (select count(*) as cnt
from t
group by ?
) x;
Note that you want a group by of something, perhaps id_r.
Try this:
SELECT MAX(e1) as Expr1 FROM (
SELECT COUNT(id_r) as e1
FROM Angajat) as t1
COUNT(id_r) wil return only 1 result since there is no group by clause. Hence, there is no use of max.
You need to add a group by clause in subquery:
SELECT MAX(e1) as Expr1 FROM (
SELECT column1, COUNT(id_r) as e1
FROM Angajat
GROUP BY column1
) as t1
You can't see on the image but I have many till_id numbers. (1,2,3,4,5).
What I want to do is just showing the last "trans_num" without repeating the till_id.
For example:
till_id trans_num
1 14211
2 14333
3 14555
A typical way to do this is:
select t.*
from t
where t.trans_date = (select max(t2.trans_date)
from t t2
where t2.till_id = t.till_id
);
select till_id ,trans_num, max(transdate) from tableA
group by till_id ,trans_num
Filter the columns you need in outer query or write inner query in where condition
You can use group by till_id in subselect
Select a.till_id a.trans_num
from your_table as a
where (a.trans_date. a.till_id) = (select max(b.trans_date), b-till_id
from your_table as b
group_by b.till_id
);
How can I select by (ID) but still show distinct (Name) by the newest (Mod.Date) to eliminate the duplicates in the (Name) column. I'm assuming this is easy but i've never done this. Thank you
You need a Subquery which selects the latest date for each ID:
SELECT t.ID, max(t.`mod.date`) last_date
FROM YourTable t
GROUP BY t.ID
This subquery has to be linked to the original table using the ID and the date.
SELECT t.ID,t.Name,t.`mod.date`
FROM YourTable t
JOIN (SELECT t.ID, max(t.`mod.date`) last_date
FROM YourTable t
GROUP BY t.ID) tmp ON tmp.ID=t.ID AND tmp.`mod.date`=t.`mod.date`
This gives you ID and (latest) Name for all IDs.
Update: Another possibility which should work in Access also is to use the ALL comparison:
SELECT t.ID,t.Name,t.`mod.date`
FROM YourTable t
WHERE t.`mod.date` >= ALL (SELECT max(t1.`mod.date`)
FROM YourTable t1
WHERE t1.ID=t.ID GROUP BY t1.ID)
I'm trying to select the latest date and group by name and keep other columns.
For example:
name status date
-----------------------
a l 13/19/04
a n 13/09/05
a dd 13/18/03
b l 13/01/01
b dd 13/01/02
b n 13/01/03
and I want the result like:
name status date
-----------------
a n 13/09/05
b n 13/01/03
Here's my code
SELECT
Name,
MAX(DATE) as Date,
Status
FROM
[ST].[dbo].[PS_RC_STATUS_TBL]
GROUP BY
Name
I know that I should put max(status) because There are a lot of possibilities in each case, and nothing in the query makes it clear which value to choose for status in each group. Is there anyway to use inner join ?
It's not clear to me you want the max or min status. Rather it seems to me you want the name and status as of a date certain. That is, you want the rows with the lastest date for each name. So ask for that:
select * from PS_RC_STATUS_TBL as T
where exists (
select 1 from PS_RC_STATUS_TBL
where name = T.name
group by name
having max(date) = T.date
)
Another way to think about it is
select T.*
from PS_RC_STATUS_TBL as T
join (
select name, max(date) as date
from PS_RC_STATUS_TBL
group by name
) as D
on T.name = D.name
and T.date = D.date
SQL Server needs to know what to do with the rows that you are not grouping on (it has multiple rows to show on 1 line - so how?). If you have aggregated on them (MIN, MAX, AVG, etc) then you are telling it what to do with these rows. If not it will not know what to do - and will give you an error like the one you are getting.
From what you are saying though - it sounds like you do not want to group by the status. It sounds like you are not interested in that column at all. Let me know If that assumption is wrong.
SELECT
Name,
MAX(Date) AS 'Date',
FROM
PS_RC_STATUS_TBL
GROUP BY
Name
If you really do want the status, but don't want to group on it - try this:
SELECT
MyTable1.Name,
MyTable2.Status,
MyTable1.Date
FROM
(SELECT Name, MAX(Date) AS 'Date' FROM PS_RC_STATUS_TBL GROUP BY Name) MyTable1
INNER JOIN
(SELECT Name, Date, Status FROM PS_RC_STATUS_TBL) MyTable2
ON MyTable1.Name = MyTable2.Name
AND MyTable1.Date = MyTable2.Date
That gives the exact results you've asked for - so does the method below using a CTE.
OR
WITH cte AS (
SELECT Name, MAX(Date) AS Date
FROM PS_RC_STATUS_TBL
GROUP BY Name)
SELECT cte.Name,
tbl.Status,
cte.Date
FROM cte INNER JOIN
PS_RC_STATUS_TBL tbl ON cte.Name = tbl.Name
AND cte.Date = tbl.Date
SQLFiddle example.
It just means that you need to put all non-aggregated columns in the GROUP BY clause, so in the case you need to put the other one
Select Name ,
MAX(DATE) as Date ,
Status
FROM [ST].[dbo].[PS_RC_STATUS_TBL] PS
Group by Name, Status
This is a common problem with text fields in SQL aggregation scenarios. Using either MAX(Status) or MIN(Status) in your field list is a solution, usually MAX(Status) because of the lexical ordering:
"" < " " < "a"
In cases where you really need a more detailed ordering:
Join to a StatusOrder relation (*Status, OrderSequence) in your main query;
select Max(OrderSequence) in your aggregated query; and
Join back to your StatusOrder relation on OrderSequence to select the correct Status value for display.
Whatever fields you're selecting other than aggregation function, need to mention in group by clause.
SELECT
gf.app_id,
ma.name as name,
count(ma.name) as count
FROM [dbo].[geo_fen_notification_table] as gf
inner join dbo.mobile_applications as ma on gf.app_id = ma.id
GROUP BY app_id,name
Here im accessing app_id and name in select, so i need to mention that after group by clause. otherwise it will throw error.