How to get the number of hours between the two dates in SQL Server
Example:
staffing_start_date (2017-08-01 06:00:00.00000)
staffing_end_dt (2017-08-01 18:00:00.00000)
You would use datediff():
select datediff(hour, staffing_start_date, staffing_end_date)
If you need the number of fractional hours, you can use below
DATEDIFF(second, staffing_start_date, staffing_end_date) / 3600.0
Please be aware of DateDiff's unexpected gotcha though. It does no rounding at all. It will truncate to the level you are looking for (Day, hour, min etc)
For example, both of these will return 1, so rounding Ferdinand's answer is a better fit most of the time.
declare #Start DateTime = '1/1/17 7:59 AM'
Declare #End Datetime = '1/1/17 8:00 AM'
select DATEDIFF(hour, #Start, #end)
declare #Start DateTime = '1/1/17 7:01 AM'
Declare #End Datetime = '1/1/17 8:59 AM'
select DATEDIFF(hour, #Start, #end)
Thanks #Jay Wheeler for your comments.
If you want hour to be very specific, you can use as given below:
Declare #Start DateTime = '1/1/17 7:59 AM'
Declare #End Datetime = '1/1/17 8:00 AM'
select DATEDIFF(MINUTE, #Start, #end) /60 AS Hour
Just in case you didn't understand the other answers, you can use DATEDIFF.
Dates are just numbers. The integral part of the number is the date and the fraction is the time. To get a difference in days, you can just cast to int and to get the difference in hours multiply by 24.
DECLARE #Date1 DateTime
DECLARE #Date2 DateTime
SELECT #Date1 = {ts '2017-08-29 00:00:00.000'},
#Date2 = {ts '2017-08-27 00:00:00.000'}
SELECT CONVERT(int, #Date1) - CONVERT(int, #Date2) AS DifferenceInDays
SELECT (CONVERT(int, #Date1) - CONVERT(int, #Date2)) * 24 AS DifferenceInHours
Or you could use DATEDIFF.
See DATEDIFF function - https://learn.microsoft.com/en-us/sql/t-sql/functions/datediff-transact-sql.
For your question, you can use:
DATEDIFF ( HOUR, staffing_start_date , staffing_end_dt )
DATEDIFF ( HH, staffing_start_date , staffing_end_dt )
Related
In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000
You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.
If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table
This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.
This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)
If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!
If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)
This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others
Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)
Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)
I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.
Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)
DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000
To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable
SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)
Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14
simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;
select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate
The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.
SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm
I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000
I wanna know how to differentiate a time period in a day between two columns like in time and out time?
DATEDIFF
DATEDIFF (datepart , startdate , enddate)
The datepart you have mentioend in your question is day. You can use any of day, d and dd
Sample
DECLARE #inTime DATETIME, #outTime DATETIME
SET #inTime = '2015-05-01 12:10:09'
SET #outTime = '2015-05-22 05:15:36'
SELECT DATEDIFF(DAY, #inTime, #outTime) AS timedifferentiate
In a query
SELECT ,inTime
,outTime
DATEDIFF(DAY, inTime, outTime) AS timedifferentiate
FROM yourTable
Just use a minus operator, and convert to time
SELECT
CONVERT(time, -- Note the time datatype range is 00:00:00.0000000 through 23:59:59.9999999
CONVERT(datetime, '2015-04-01 19:03') -- Out time
- CONVERT(datetime, '2015-04-01 09:02') -- In time
) TimeDiff
I'm writing a report that needs to collect data each day, between 0900hs and 1700hs.
I thought it would be fine as follows:
cast(convert(char(8),t.trxtime,112)as time)
between CONVERT(VARCHAR(5),getdate(),108) >= '09:00'
and CONVERT(VARCHAR(5),getdate(),108) < '17:00'
....BUT no cigar.
Thank you!!!
Hmmm, you could just use datepart():
where datepart(hour, t.trxtime) between 9 and 16 and
cast(t.trxtime as date) = cast(getdate() as date)
I'm not sure if the date comparison is actually necessary.
You could do something like this (assuming you mean actually for the current date, and not for every date in a range:
declare #startDate datetime
declare #endDate datetime
select #startDate = '2014-11-03 09:00:00',
#endDate = '2014-11-03 17:00:00'
select *
from table
where myDate between #startDate and #endDate
if you did mean between 0900 and 1700 for each day, you could do:
declare #startDate datetime
declare #endDate datetime
select #startDate = '2014-10-03',
#endDate = '2014-11-03' -- note i'm still limiting it to a range of ~1 month
select *
from table
where myDate between #startDate and #endDate
and datepart(hour, myDate) between 9 and 17
I would like to calculate the exact hours difference between two datetime variables. The hours difference should be exact like this:
1.5
2
6.25
Anybody please help out..Thanks in advance...
You could use DATEDIFF to find the difference in minutes and convert that into hours:
select datediff(mi, startdate, enddate)
Assuming 1.5 means 1 hour and 30 minutes you could simply divide the result by 60:
select datediff(mi, startdate, enddate) / 60.0
Keep it simple:
declare #date1 datetime
declare #date2 datetime
select #date1 = GETDATE();
select #date2 = '2013-02-02 14:05'
select DATEDIFF(hh, #date2, #date1)
Results
-----------
71
(1 row(s) affected)
it will help you....
Declare #Date1 dateTime
Declare #Date2 dateTime
Set #Date1 = '22:30:00'
Set #Date2 = '00:00:00'
Select Cast((#Date1 - #Date2) as Float) * 24.0
To get Exact Time Difference in HH:MM try the below code in MS-SQL
Declare #InTime datetime='2017-11-27 10:00:00',
#OutTime datetime='2017-11-27 11:15:00'
SELECT CONVERT(varchar(5),DATEADD(minute,DATEDIFF(minute,#InTime,#OutTime),0), 114)
-----------
Result
01:15
Please try:
declare #dt1 datetime, #dt2 datetime, #Seconds int
select #dt1='2013-02-05 14:05:55.113', #dt2 =getdate()
set #Seconds=datediff(second, #dt1, #dt2)
declare #Hour nvarchar(50)
declare #Min nvarchar(50)
declare #MinTemp int
if #Seconds >0
begin
set #Hour=cast((#Seconds / 3600) as nvarchar(20)) +' Hrs '
set #MinTemp= (#Seconds % 3600) / 60
set #Min=cast(#MinTemp as nvarchar(20))
if #MinTemp<10
select #Hour+'0'+#Min +' Min'
else
select #Hour+#Min +' Min'
end
else
select '00 Hrs 00 Min'
In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000
You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.
If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table
This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.
This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)
If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!
If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)
This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others
Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)
Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)
I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.
Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)
DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000
To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable
SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)
Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14
simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;
select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate
The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.
SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm
I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000