SQL variable concatenation with xml - sql

have the following table coming from this query:
SELECT
[Document],
[Description],
[Value],
FROM [DocDetails]
Document Description Value Line No_
120 First Row 100 1
120 Second Row 0 2
120 Third row 0 3
120 Fourth row 0 4
120 fifth row 0 5
120 sixth row 203 6
120 seventh row 256 7
120 eighth row 259 8
120 ninth row 0 9
120 tenth row 0 10
120 eleventh row 0 11
I need to concatenate the description according to the value. I would need such result:
Document Description Value
120 First Row;second row;Third row;Fourth row;fifth row 100
120 sixth row 203
120 seventh row 256
120 eighth row;ninth row;tenth row;eleventh row 259
I tried the following:
SELECT
[Document],
All_Descriptions = STUFF(
(SELECT ';' + Description AS [text()]
FROM [DocDetails] D1
WHERE D1.[Document] = D2.[Document]
FOR XML PATH('')),1,1,'')
FROM [DocDetails] D2
GROUP BY D2.[Document]
As I don't have a variable that specifies the order I am not able to concatenate properly ( the code above concatenates everything but that's not what I want). Also if I group by value I am not getting the desired result.
How can I tell SQL to basically "concatenate the row with an amount with all the following having value 0"
Thanks for your help!

This is another solution that works with SQL 2008 too.
DECLARE #DocDetails TABLE( [Document] int, [Description] varchar(20), [Value] int, [Line_No] int )
INSERT INTO #DocDetails VALUES
(120,'First Row',100,1),
(120,'Second Row',0,2),
(120,'Third row',0,3),
(120,'Fourth row',0,4),
(120,'fifth row',0,5),
(120,'sixth row',203,6),
(120,'seventh row',256,7),
(120,'eighth row',259,8),
(120,'ninth row',0,9),
(120,'tenth row',0,10),
(120,'eleventh row',0,11),
(121,'eleventh row',0,11)
;WITH
LinesWithValue AS (
SELECT *, ROW_NUMBER() OVER(PARTITION BY [Document] ORDER BY Line_No ) RN
FROM #DocDetails
WHERE Value > 0
)
,LinesWithNext AS (
SELECT L.*, L1.Line_No Next_Line_No
FROM LinesWithValue L
LEFT JOIN LinesWithValue L1 ON L.RN + 1 = L1.RN AND L.[Document] = L1.[Document]
)
,NewTable AS (SELECT
B.Document,
B.Description,
CASE B.Value WHEN 0 THEN A.Value ELSE B.Value END Value,
B.Line_No
FROM LinesWithNext A
FULL JOIN #DocDetails B ON A.[Document] = B.[Document] AND ( ( B.Line_No >= A.Line_No ) AND ( A.Next_Line_No IS NULL OR B.Line_No < A.Next_Line_No ) )
)
SELECT
[Document],
[Value],
All_Descriptions = STUFF(
(SELECT ';' + Description AS [text()]
FROM NewTable D1
WHERE D1.[Document] = D2.[Document] AND D1.[Value] = D2.[Value]
FOR XML PATH('')) , 1, 1, '')
FROM NewTable D2
GROUP BY D2.[Document], [Value]

Here's a way....
declare #table table(Document int,[Description] varchar(64), [Value] int, Line_No int)
insert into #table
values
(120,'First Row',100,1),
(120,'Second Row',0,2),
(120,'Third row',0,3),
(120,'Fourth row',0,4),
(120,'fifth row',0,5),
(120,'sixth row',203,6),
(120,'seventh row',256,7),
(120,'eighth row',259,8),
(120,'ninth row',0,9),
(120,'tenth row',0,10),
(120,'eleventh row',0,11)
--Find the end / anchor line which to stop the concatenation later
;with cte as(
select
t.Document
,t.[Value]
,t.Description
,t.Line_No
,Parent_Line = isnull(min(t2.Line_No) - 1, (select max(Line_No) from #table))
from
#table t
full join
#table t2 on t2.Document = t.Document
and t2.Line_No > t.Line_No
and t2.Value <> 0
where
t.Document is not null
group by
t.Document
,t.[Value]
,t.Line_No
,t.Description),
--Do the concatenation of the Description
cte2 as (
select
Document
,value
,All_Descriptions = STUFF((
SELECT ',' + t2.Description
FROM cte t2
WHERE t.Parent_Line = t2.Parent_Line
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
,Parent_Line
from
cte t)
--Get max [Value] for uniqueness
select
Document
,All_Descriptions
,[Value] = max([Value])
from
cte2
group by
Document
,All_Descriptions
order by
max([Value])

Related

SQL Server Loop thru rows to form Groups

I using SQL Server 2008 R2 / 2014. I wish to find a SQL query that can do the following:
Rules:
Each [Group] must have [Number] 1 to 6 to be complete group.
[Name] in each [Group] must be unique.
Each row only can use 1 time.
Table before sorting is...
Name Number Group
---- ------ -----
A 1
B 6
A 123
C 3
B 4
C 23
D 45
D 4
C 56
A 12
D 56
After sorting, result I want is below or similar....
Name Number Group
---- ------ -----
A 1 1
C 23 1
D 45 1
B 6 1
A 123 2
D 4 2
C 56 2
A 12 3
C 3 3
B 4 3
D 56 3
What I tried before is to find a subgroup that have [Number] consist of 1-6 with below concatenate method...
SELECT *
FROM [Table1] ST2
WHERE
SUBSTRING((SELECT ST1.[Number] AS [text()]
FROM [Table1] ST1
-- WHERE ST1.[Group] = ST2.[Group]
ORDER BY LEFT(ST1.[Number],1)
FOR XML PATH ('')), 1, 1000) = '123456'
Maybe you should check ROW_NUMBER function.
select Name
, Number
, ROW_NUMBER () OVER(PARTITION BY Name ORDER BY Number) as Group
from [Table1]
If you have more than 6 rows with same NAME value then it will return more groups. You can filter additional groups out since you are interested in only 6 groups with unique values of NAME column.
I'm not sure if this can be done more simply or not, but here's my go at it...
Advanced warning, this requires some means of splitting strings. Since you're not on 2016, I've included a function at the beginning of the script.
The bulk of the work is a recursive CTE that builds the Name and Number columns into comma delimited groups. We then reduce our working set to only the groups where the numbers would create 123456, split the groups and use ROW_NUMBER() OVER... to identify them, and then select based on the new data.
Demo: http://rextester.com/NEXG53500
CREATE FUNCTION [dbo].[SplitStrings]
(
#List NVARCHAR(MAX),
#Delimiter NVARCHAR(255)
)
RETURNS TABLE
WITH SCHEMABINDING
AS
RETURN
(
SELECT Item = y.i.value('(./text())[1]', 'nvarchar(4000)')
FROM
(
SELECT x = CONVERT(XML, '<i>'
+ REPLACE(#List, #Delimiter, '</i><i>')
+ '</i>').query('.')
) AS a CROSS APPLY x.nodes('i') AS y(i)
);
GO
CREATE TABLE #temp
(
name VARCHAR(MAX),
number INT
)
INSERT INTO #temp
VALUES
('a',1),
('b',6),
('a',123),
('c',3),
('b',4),
('c',23),
('d',45),
('d',4),
('c',56),
('a',12),
('d',56);
/*** Recursively build groups based on information from #temp ***/
WITH groupFinder AS
(
SELECT CAST(name AS VARCHAR(MAX)) AS [groupNames], CAST(number AS VARCHAR(max)) AS [groupNumbers] FROM #temp
UNION ALL
SELECT
cast(CONCAT(t.[Name],',',g.[groupNames]) as VARCHAR(MAX)),
CAST(CONCAT(CAST(t.[Number] AS VARCHAR(max)),',',CAST(g.[groupNumbers] AS VARCHAR(max))) AS VARCHAR(max))
FROM #temp t
JOIN groupFinder g
ON
g.groupNames NOT LIKE '%' + t.name+'%'
AND g.[groupNumbers] NOT LIKE '%' + CAST(t.number/100 AS VARCHAR(10)) +'%'
AND g.[groupNumbers] NOT LIKE '%' + CAST(t.number/10 AS VARCHAR(10)) +'%'
AND g.[groupNumbers] NOT LIKE '%' + CAST(t.number%10 AS VARCHAR(10)) +'%'
)
/*** only get groups where the numbers form 123456 ***/
, groupPruner AS
(
SELECT *, ROW_NUMBER() OVER (ORDER BY [groupNames]) AS [rn] FROM groupFinder WHERE REPLACE([groupNumbers],',','') = '123456'
)
/*** split the name group and give it identifiers ***/
, nameIdentifier AS
(
SELECT g.*, c1.[item] AS [Name], ROW_NUMBER() OVER (PARTITION BY [rn] ORDER BY (SELECT NULL)) AS [rn1]
FROM groupPruner g
CROSS APPLY splitstrings(g.groupnames,',') c1
)
/*** split the number group and give it identifiers ***/
, numberIdentifier AS
(
SELECT g.*, c1.[item] AS [Number], ROW_NUMBER() OVER (PARTITION BY [rn], [rn1] ORDER BY (SELECT NULL)) AS [rn2]
FROM nameIdentifier g
CROSS APPLY splitstrings(g.groupNumbers,',') c1
)
SELECT [Name], [Number], [rn] AS [Group]
--,groupnames, groupNumbers /*uncomment this line to see the groups that were built*/
FROM numberIdentifier
WHERE rn1 = rn2
ORDER BY rn, rn1
DROP TABLE #temp

SQL Server - Return All possible combinations of a 4 digit number passed to a stored procedure

I have a task to write a stored procedure or a function to return all possible combinations of a 4 digit number.
For example, if I pass 1234 to the stored procedure or function, it should return 4 digit numbers (all possible combinations), like
1123, 1112, 1324, 1342, 2134, 2234
and so on.
It can be of 4 digits only.
I have been doing this with using LIKE operator:
select *
from Table
where mynumber like '%1%'
and mynumber like '%2%'
and mynumber like '%3%'
and mynumber like '%4%'
but the problem is, I have hardcoded the numbers 1,2,3 and 4.
The number can be anything.
And these many LIKE operators can also impact the performance on a large table.
Can anybody give me some generic query to get the combinations?
Thanks in advance.
You can use a cross join:
with digits as (
select substring(num, 1, 1) as d union all
select substring(num, 2, 1) as d union all
select substring(num, 3, 1) as d union all
select substring(num, 4, 1) as d
)
select (d1.d + d2.d + d3.d + d4.d)
from digits d1 cross join
digits d2 cross join
digits d3 cross join
digits d4;
Note: This assumes that the number is a string (based on the fact that you use like in your question).
First you need to be able to break a four-digit number into separate digits. I suggest using a table variable and the modulus operator. Assuming we have an integer input named #input, we can break it into its digits using this:
DECLARE #Digits Table(Number int)
INSERT INTO #Digits(Number)
VALUES (#input % 10),
(#input / 10 % 10),
(#input / 100 % 10),
(#input / 1000 % 10)
Now we have a table with four rows, one row per digit.
To create a combination of four digits, we need to include the table four times, meaning we need three joins. The joins have to be set up so no digit is duplicated. Thus our FROM and JOIN clauses will look like this:
FROM #Digits D1
JOIN #Digits D2 ON D2.Number <> D1.Number
JOIN #Digits D3 ON D3.Number <> D1.Number
AND D3.Number <> D2.Number
JOIN #Digits D4 ON D4.Number <> D1.Number
AND D4.Number <> D2.Number
AND D4.Number <> D3.Number
Now to take the values and make a new, four-digit integer:
SELECT Number = D1.Number * 1000
+ D2.Number * 100
+ D3.Number * 10
+ D4.Number
The complete solution:
CREATE PROC Combine(#input AS int)
AS
BEGIN
DECLARE #Digits Table(Number int)
;
INSERT INTO #Digits(Number)
VALUES (#input % 10),
(#input / 10 % 10),
(#input / 100 % 10),
(#input / 1000 % 10)
;
SELECT Number = D1.Number * 1000
+ D2.Number * 100
+ D3.Number * 10
+ D4.Number
FROM #Digits D1
JOIN #Digits D2 ON D2.Number <> D1.Number
JOIN #Digits D3 ON D3.Number <> D1.Number
AND D3.Number <> D2.Number
JOIN #Digits D4 ON D4.Number <> D1.Number
AND D4.Number <> D2.Number
AND D4.Number <> D3.Number
ORDER BY Number
;
END
Usage:
EXEC Combine 1234
Resultset:
Number
------
1234
1243
1324
1342
1423
1432
2134
2143
2314
2341
2413
2431
3124
3142
3214
3241
3421
4123
4132
4213
4231
4312
4321
24 row(s)
Click here to run the above code on RexTester
Improving #GordonLinoff's answer, you can add an additional column in you CTE so that you can only make sure that each number is only used once:
declare #num varchar(max);
set #num = '1234';
with numCTE as (
select SUBSTRING(#num, 1,1) as col, 1 as cnt union
select SUBSTRING(#num, 2,1) as col, 3 as cnt union
select SUBSTRING(#num, 3,1) as col, 9 as cnt union
select SUBSTRING(#num, 4,1) as col, 27 as cnt
)
select DISTINCT (a1.col+a2.col+a3.col+a4.col)
from numCTE a1
cross join numCTE a2
cross join numCTE a3
cross join numCTE a4
where a1.cnt + a2.cnt + a3.cnt + a4.cnt = 40
Additionally, you can remove the WHERE to allow each number to be used more than once.
Don't forget the DISTINCT keyword. :)
You can try this.
select * from Table where mynumber like '%[1234][1234][1234][1234]%'
if it should only be 4 digit
select * from Table where mynumber like '[1234][1234][1234][1234]'
Also, you can use [1-4] instead of [1234]
Here's query to return all combinations of four digits (characters in general):
select A.col + B.col + C.col + D.col [Combinations] from
(values ('1'),('2'),('3'),('4')) as A(col) cross join
(values ('1'),('2'),('3'),('4')) as B(col) cross join
(values ('1'),('2'),('3'),('4')) as C(col) cross join
(values ('1'),('2'),('3'),('4')) as D(col)
Taking inspiration from this answer:
WITH n AS (
SELECT n FROM (VALUES (1), (2), (3), (4)) n (n)
) SELECT ones.n + 10*tens.n + 100*hundreds.n + 1000*thousands.n
FROM n ones, n tens, n hundreds, n thousands
You can define a table in your stored procedure will all possible combinations but using letters for codding:
DECLARE #Combinations TABLE
(
[value] CHAR(4)
);
INSERT INTO #Combinations ([value])
VALUES ('AAAA')
,('AAAB')
,('AAAC')
,('AAAD')
...
Then update every latter with the input number:
DECLARE #Numner1 TINYINT = 2
,#Numner2 TINYINT = 5
,#Numner3 TINYINT = 1
,#Numner4 TINYINT = 3;
UPDATE #Combinations
SET [value] = REPLACE([value], 'A', #Numner1);
UPDATE #Combinations
SET [value] = REPLACE([value], 'B', #Numner2);
UPDATE #Combinations
SET [value] = REPLACE([value], 'C', #Numner3);
UPDATE #Combinations
SET [value] = REPLACE([value], 'D', #Numner4);
Then just join the table with your table:
select *
from Table A
INNER JOIN #Combinations B
ON A.[mynumber] = B.[value];
Try This approach
DECLARE #Num INT = 5432
;WITH CTE
AS
(
SELECT
SeqNo = 1,
Original = CAST(#Num AS VARCHAR(20)),
Num = SUBSTRING(CAST(#Num AS VARCHAR(20)),1,1)
UNION ALL
SELECT
SeqNo = SeqNo+1,
Original,
Num = SUBSTRING(Original,SeqNo+1,1)
FROM CTE
WHERE SeqNo < LEN(Original)
)
SELECT
MyStr = C1.Num+C2.Num+C3.Num+C4.Num
FROM CTE C1
CROSS JOIN CTE C2
CROSS JOIN CTE C3
CROSS JOIN CTE C4
WHERE
(
C1.SeqNo <> C2.SeqNo
AND
C3.SeqNo <> C4.SeqNo
AND
C4.SeqNo <> C1.SeqNo
AND
C2.SeqNo <> C3.SeqNo
AND
C1.SeqNo <> C3.SeqNo
AND
C4.SeqNo <> C2.SeqNo
)
ORDER BY 1
My Result
MyStr
2345
2354
2435
2453
2534
2543
3245
3254
3425
3452
3524
3542
4235
4253
4325
4352
4523
4532
5234
5243
5324
5342
5423
5432
Please try this. SET BASED Approach to generate all Possible combinations of a number-
IF OBJECT_ID('Tempdb..#T') IS NOT NULL
DROP TABLE tempdb..#T
DECLARE # AS INT = 1234
IF LEN(#) <= 7
BEGIN
DECLARE #str AS VARCHAR(100)
SET #str = CAST(# AS VARCHAR(100))
DECLARE #cols AS VARCHAR(100) = ''
SELECT DISTINCT SUBSTRING(#str,NUMBER,1) n INTO #T FROM MASTER..spt_values WHERE number > 0 AND number <= LEN(#)
SELECT #cols = #cols + r
FROM ( SELECT DISTINCT CONCAT(', o',number,'.n') r FROM MASTER..spt_values WHERE number > 0 AND number <= (LEN(#)-1) )q
DECLARE #ExecStr AS VARCHAR(1000) = ''
SET #ExecStr = 'SELECT CAST(CONCAT( a.n' + #cols + ' ) AS INT) Combinations FROM #T a'
SELECT #ExecStr = #ExecStr + r FROM
(
SELECT DISTINCT CONCAT(' CROSS APPLY ( SELECT * FROM #T b' , number , ' WHERE ( b' , number, '.n' , ' <> a.n ) ',
CASE WHEN number = 1 then ''
WHEN number = 2 then ' AND ( b2.n <> o1.n )'
WHEN number = 3 then ' AND ( b3.n <> o1.n ) AND ( b3.n <> o2.n ) '
WHEN number = 4 then ' AND ( b4.n <> o1.n ) AND ( b4.n <> o2.n ) AND ( b4.n <> o3.n ) '
WHEN number = 5 then ' AND ( b5.n <> o1.n ) AND ( b5.n <> o2.n ) AND ( b5.n <> o3.n ) AND ( b5.n <> o4.n ) '
WHEN number = 6 then ' AND ( b6.n <> o1.n ) AND ( b6.n <> o2.n ) AND ( b6.n <> o3.n ) AND ( b6.n <> o4.n ) AND ( b6.n <> o5.n ) '
END
,') o' , number ) r FROM
MASTER..spt_values
WHERE number > 0 AND number <= (LEN(#)-1)
)p
EXEC (#ExecStr)
END
IF OBJECT_ID('tempdb..#T') IS NOT NULL
DROP TABLE tempdb..#T
OUTPUT
1432
1342
1423
1243
1324
1234
2431
2341
2413
2143
2314
2134
3421
3241
3412
3142
3214
3124
4321
4231
4312
4132
4213
4123
from - https://msbiskills.com/2016/05/20/sql-puzzle-generate-possible-combinations-of-a-number-puzzle/
You can try following alternative SQL Script as well
declare #param varchar(4) = '1234'
;with combination as (
select
distinct rn = DENSE_RANK() over (Order By num), num
from (
select substring(#param,1,1) as num
union all
select substring(#param,2,1)
union all
select substring(#param,3,1)
union all
select substring(#param,4,1)
) t
)
select
c1.num, c2.num, c3.num, c4.num,
cast(c1.num as char(1)) + cast(c2.num as char(1)) + cast(c3.num as char(1)) + cast(c4.num as char(1)) as number
from combination c1, combination c2, combination c3, combination c4
It produces 256 numbers for 4 digits
Actually this code is from SQL code which returns non-repeatable combinations in SQL of given set of items, but modified it to enable repeats of items in the output

Get result from select without repeated records next to each other

i have table with records :
City Name Seq
London 1
London 2
London 3
Madrid 4
London 5
Porto 6
Problem is how to get a result in string ( merge all without repeated records ).
Result : London-Madrid-London-Porto
Another option if 2012+ ... LAG()
Example
Declare #YourTable Table ([City Name] varchar(50),[Seq] int)
Insert Into #YourTable Values
('London',1)
,('London',2)
,('London',3)
,('Madrid',4)
,('London',5)
,('Porto',6)
Select Stuff((Select '-' +Value From
(
Select top 1000 Value = case when [City Name]=lag([City Name],1) over (Order By Seq) then null else [City Name] end
From #YourTable
Order By Seq
) A
For XML Path ('')),1,1,'')
Returns
London-Madrid-London-Porto
How about this?
declare #table table (CityName varchar(64), seq int)
insert into #table
values
('London',1),
('London',2),
('London',3),
('Madrid',4),
('London',5),
('Porto',6)
--find the next row that isn't the same city name (t2seq)
;with cte as(
select distinct
t.CityName
,t.seq
,min(t2.seq) as t2seq
from #table t
left join #table t2 on
t2.seq > t.seq
and t2.CityName <> t.CityName
group by
t.CityName
,t.seq),
--limit the result set to distinct list
cte2 as(
select distinct
CityName
,seq = isnull(t2seq,9999999)
from cte)
--use stuff to concat it together
select distinct
stuff(( select '-', + t2.CityName
from cte2 t2
order by seq
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
from cte2

SQL Select Concat between 2 numbers

I work with SQL Server 2012 and need a concatenate between 2 different columns.
eg:
3 and 7 = 34567
or 1 and 4 = 1234
or 2 and 2 = 2
When I use the Concat Function, I am just able to Concate the first and the last number. But I need the numbers between, too.
Try this query. Here firstcolumn =3 and secondcolumn=7
SELECT t.Id,
,STUFF((SELECT '' + CAST( n AS VARCHAR(50)) [text()]
FROM (SELECT DISTINCT n = number
FROM master..[spt_values]
WHERE number >= firstcolumn AND number <= secondcolumn
)a
FOR XML PATH(''), TYPE)
.value('.','NVARCHAR(MAX)'),1,0,'') List_Output
FROM tablename t
There are multiple ways to generate sequences in sql-server. Here is a simple that doesn't need a number-table:
WITH Numbers AS
(
SELECT TOP (2000) n = ROW_NUMBER() OVER (ORDER BY object_id)
FROM sys.all_objects ORDER BY n
)
SELECT n FROM Numbers
WHERE n BETWEEN 3 AND 7
Here's a recursive query that will go from start to end recursively and generate the string you want or an INTEGER value:
DECLARE #start INT = 3
DECLARE #end INT = 7
DECLARE #int_value INT = 0
DECLARE #str_value VARCHAR(100) = '';
WITH rec AS (
SELECT #start AS val
UNION ALL
SELECT val + 1
FROM rec
WHERE val < #end
)
SELECT #str_value = CONCAT(#str_value, val),
#int_value = #int_value * 10 + val
FROM rec
SELECT #str_value, #int_value
This is Itzik's style
declare #values varchar(100)='', #from int, #to int
select #from=3, #to=7
;WITH
n0 AS (SELECT 0 AS number UNION ALL SELECT 0),
n1 AS (SELECT 0 AS number FROM n0 AS a CROSS JOIN n0 AS b),
n2 AS (SELECT 0 AS number FROM n1 AS a CROSS JOIN n1 AS b),
n3 AS (SELECT 0 AS number FROM n2 AS a CROSS JOIN n2 AS b)
select #values=#values+ltrim(sno) from
(select row_number() over (order by number) as sno from n3) as t
where sno between #from and #to
select #values as [values]
Thank you for the Answer.
I am going to use the answer from #Mukesh Kalgude.
So, my full query is the follow:
select
DayFrom,DayTo,
STUFF((SELECT TOP 7'' + CAST( n AS VARCHAR(50)) [text()]
FROM (SELECT DISTINCT n = number
FROM master..[spt_values]
WHERE number >= DayFrom AND DayTo <= 7
)a
FOR XML PATH(''), TYPE)
.value('.','NVARCHAR(MAX)'),1,0,'') List_Output
from SwitchProfilePairs
The result is
dayFrom = 1 day To = 1 But the List_Output is 1234567
Try this using SUBSTRING() function(Fiddle example):
--Declare sample table
DECLARE #T TABLE (id int identity, numCol1 int, numCol2 int)
--Add some values
INSERT #T (numCol1, numCol2)
VALUES (3, 7), (1, 4), (2, 2)
--Actual Query
SELECT *, SUBSTRING('123456789', numCol1, numCol2 - numCol1 + 1) Number
FROM #T
Above query works only with single digit numbers. Modified version (below) to work with numbers like 34, 78
SELECT *,
SUBSTRING('123456789', CONVERT(int, LEFT(numCol1,1)),
CONVERT(int, RIGHT(numCol2, 1)) - convert(int, LEFT(numCol1,1)) + 1) YourNumber
FROM #T
Note: Number column is returning a string, can be converted to an int using convert() function

Split string and divide value

I got a table Test with columns A and B.
The A column contains different values in one entry, e.g. abc;def;ghi, all separated by ;. And the B column contains numeric values, but only one.
What I want is to seperate the values from column A into multiple rows.
So:
abc;def;ghi;jkl
-->
abc
def
ghi
jkl
In column B is one value, e.g. 20 and I want that value split to the amount of rows,
So the final result shut be:
abc 5
def 5
ghi 5
jkl 5
The issue is that the amount of values in column A must be variable.
First you need to create this function
REATE FUNCTION Split
(
#delimited nvarchar(max),
#delimiter nvarchar(100)
) RETURNS #t TABLE
(
-- Id column can be commented out, not required for sql splitting string
id int identity(1,1), -- I use this column for numbering splitted parts
val nvarchar(max),
origVal nvarchar(max)
)
AS
BEGIN
declare #xml xml
set #xml = N'<root><r>' + replace(#delimited,#delimiter,'</r><r>') + '</r></root>'
insert into #t(val,origval)
select
r.value('.','varchar(max)') as item, #delimited
from #xml.nodes('//root/r') as records(r)
RETURN
END
GO
then this query might help
Select x.Val, test.B / (len(test.A) - len(replace(Test.A, ';', '')) + 1) from Test
inner join dbo.Split(Test.A,';') x on x.origVal = Test.A
this part len(test.A) - len(replace(Test.A, ';', '')) will count the number of ; in string
Be aware this query might have some malfunctioning if there will be duplicate strings in A column, in this situation you need to pass the unique value (for example ID) to split function and return it in the result table, then join it by this value (ie. x.origVal = Test.A => x.origID = Test.ID)
You can use some tricks with CTE, STUFF and windows functions
DECLARE #t TABLE
(
ID INT ,
A NVARCHAR(MAX) ,
B INT
)
INSERT INTO #t
VALUES ( 1, 'a;b;c;d;', 20 ),
( 2, 'x;y;z;', 40 );
WITH cte ( ID, B, D, A )
AS ( SELECT ID ,
B ,
LEFT(A, CHARINDEX(';', A + ';') - 1) ,
STUFF(A, 1, CHARINDEX(';', A + ';'), '')
FROM #t
UNION ALL
SELECT ID ,
B ,
LEFT(A, CHARINDEX(';', A + ';') - 1) ,
STUFF(A, 1, CHARINDEX(';', A + ';'), '')
FROM cte
WHERE A > ''
)
SELECT ID ,
B ,
D,
CAST(B AS DECIMAL) / COUNT(*) OVER (PARTITION BY ID) AS Portion
FROM cte
Output:
ID B D Portion
1 20 a 5.00000000000
1 20 b 5.00000000000
1 20 c 5.00000000000
1 20 d 5.00000000000
2 40 x 13.33333333333
2 40 y 13.33333333333
2 40 z 13.33333333333
this an example how you can achieve required result
DECLARE #table AS TABLE
(
ColumnA VARCHAR(100) ,
ColumnB FLOAT
)
INSERT INTO #table
( ColumnA, ColumnB )
VALUES ( 'abc;def;ghi;jkl', 20 ),
( 'asf;ret;gsd;jas', 30 ),
( 'dfa;aef;gffhi;fjfkl', 40 );
WITH C AS ( SELECT n = 1
UNION ALL
SELECT n + 1
FROM C
WHERE n <= 100
),
SetForSplit
AS ( SELECT T.ColumnA ,
T.ColumnB ,
C.n ,
( CASE WHEN LEFT(SUBSTRING(T.ColumnA, n, 100), 1) = ';'
THEN SUBSTRING(T.ColumnA, n + 1, 100) + ';'
ELSE SUBSTRING(T.ColumnA, n, 100) + ';'
END ) AS SomeText
FROM #table AS T
JOIN C ON C.n <= LEN(T.ColumnA)
WHERE SUBSTRING(T.ColumnA, n, 1) = ';'
OR n = 1
)
SELECT ROW_NUMBER() OVER ( PARTITION BY columnA ORDER BY LEFT(SomeText,
CHARINDEX(';',
SomeText) - 1) ) AS RowN,
LEFT(SomeText, CHARINDEX(';', SomeText) - 1) AS ColA ,
ColumnB / COUNT(*) OVER ( PARTITION BY ColumnA ) AS ColB
FROM SetForSplit
ORDER BY ColumnA
This is full working exmaple:
DECLARE #DataSource TABLE
(
[A] VARCHAR(MAX)
,[B] INT
);
INSERT INTO #DataSource ([A], [B])
VALUES ('a;b;c;d', 20 ),
('x;y;z', 40 );
SELECT T.c.value('.', 'VARCHAR(100)')
,[B] / COUNT([B]) OVER (PARTITION BY [B])
FROM #DataSource
CROSS APPLY
(
SELECT CONVERT(XML, '<t>' + REPLACE([A], ';', '</t><t>') + '</t>')
) DS([Bxml])
CROSS APPLY [Bxml].nodes('/t') AS T(c)
and of couse you can ROUND the devision as you like.