Split string and divide value - sql

Question

I got a table Test with columns A and B.
The A column contains different values in one entry, e.g. abc;def;ghi, all separated by ;. And the B column contains numeric values, but only one.
What I want is to seperate the values from column A into multiple rows.
So:
abc;def;ghi;jkl
-->
abc
def
ghi
jkl
In column B is one value, e.g. 20 and I want that value split to the amount of rows,
So the final result shut be:
abc 5
def 5
ghi 5
jkl 5
The issue is that the amount of values in column A must be variable.

Answer 1

First you need to create this function
REATE FUNCTION Split
(
#delimited nvarchar(max),
#delimiter nvarchar(100)
) RETURNS #t TABLE
(
-- Id column can be commented out, not required for sql splitting string
id int identity(1,1), -- I use this column for numbering splitted parts
val nvarchar(max),
origVal nvarchar(max)
)
AS
BEGIN
declare #xml xml
set #xml = N'<root><r>' + replace(#delimited,#delimiter,'</r><r>') + '</r></root>'
insert into #t(val,origval)
select
r.value('.','varchar(max)') as item, #delimited
from #xml.nodes('//root/r') as records(r)
RETURN
END
GO
then this query might help
Select x.Val, test.B / (len(test.A) - len(replace(Test.A, ';', '')) + 1) from Test
inner join dbo.Split(Test.A,';') x on x.origVal = Test.A
this part len(test.A) - len(replace(Test.A, ';', '')) will count the number of ; in string
Be aware this query might have some malfunctioning if there will be duplicate strings in A column, in this situation you need to pass the unique value (for example ID) to split function and return it in the result table, then join it by this value (ie. x.origVal = Test.A => x.origID = Test.ID)

Answer 2

You can use some tricks with CTE, STUFF and windows functions
DECLARE #t TABLE
(
ID INT ,
A NVARCHAR(MAX) ,
B INT
)
INSERT INTO #t
VALUES ( 1, 'a;b;c;d;', 20 ),
( 2, 'x;y;z;', 40 );
WITH cte ( ID, B, D, A )
AS ( SELECT ID ,
B ,
LEFT(A, CHARINDEX(';', A + ';') - 1) ,
STUFF(A, 1, CHARINDEX(';', A + ';'), '')
FROM #t
UNION ALL
SELECT ID ,
B ,
LEFT(A, CHARINDEX(';', A + ';') - 1) ,
STUFF(A, 1, CHARINDEX(';', A + ';'), '')
FROM cte
WHERE A > ''
)
SELECT ID ,
B ,
D,
CAST(B AS DECIMAL) / COUNT(*) OVER (PARTITION BY ID) AS Portion
FROM cte
Output:
ID B D Portion
1 20 a 5.00000000000
1 20 b 5.00000000000
1 20 c 5.00000000000
1 20 d 5.00000000000
2 40 x 13.33333333333
2 40 y 13.33333333333
2 40 z 13.33333333333

Answer 3

this an example how you can achieve required result
DECLARE #table AS TABLE
(
ColumnA VARCHAR(100) ,
ColumnB FLOAT
)
INSERT INTO #table
( ColumnA, ColumnB )
VALUES ( 'abc;def;ghi;jkl', 20 ),
( 'asf;ret;gsd;jas', 30 ),
( 'dfa;aef;gffhi;fjfkl', 40 );
WITH C AS ( SELECT n = 1
UNION ALL
SELECT n + 1
FROM C
WHERE n <= 100
),
SetForSplit
AS ( SELECT T.ColumnA ,
T.ColumnB ,
C.n ,
( CASE WHEN LEFT(SUBSTRING(T.ColumnA, n, 100), 1) = ';'
THEN SUBSTRING(T.ColumnA, n + 1, 100) + ';'
ELSE SUBSTRING(T.ColumnA, n, 100) + ';'
END ) AS SomeText
FROM #table AS T
JOIN C ON C.n <= LEN(T.ColumnA)
WHERE SUBSTRING(T.ColumnA, n, 1) = ';'
OR n = 1
)
SELECT ROW_NUMBER() OVER ( PARTITION BY columnA ORDER BY LEFT(SomeText,
CHARINDEX(';',
SomeText) - 1) ) AS RowN,
LEFT(SomeText, CHARINDEX(';', SomeText) - 1) AS ColA ,
ColumnB / COUNT(*) OVER ( PARTITION BY ColumnA ) AS ColB
FROM SetForSplit
ORDER BY ColumnA

Answer 4

This is full working exmaple:
DECLARE #DataSource TABLE
(
[A] VARCHAR(MAX)
,[B] INT
);
INSERT INTO #DataSource ([A], [B])
VALUES ('a;b;c;d', 20 ),
('x;y;z', 40 );
SELECT T.c.value('.', 'VARCHAR(100)')
,[B] / COUNT([B]) OVER (PARTITION BY [B])
FROM #DataSource
CROSS APPLY
(
SELECT CONVERT(XML, '<t>' + REPLACE([A], ';', '</t><t>') + '</t>')
) DS([Bxml])
CROSS APPLY [Bxml].nodes('/t') AS T(c)
and of couse you can ROUND the devision as you like.