Cumulative count in SQL - sql

I am working on SQL and came across one scenario that needs to build in SQL.
Below is scenario:
PatientID AdmitDate DischargeDate
12 7/24/2017 09:45 7/24/2017 11:01
13 7/21/2016 08:37 7/22/2017 00:15
I want result set as below:
For patientID 13, count is calculated in first 2 rows and
For patientid 12, count is calculated in last row.

Well, that looks like whatever you do will be slow. I think I'd use a tally table. The table, instead of just containing the usual n years worth of dates / days / day of week etc. would also contain one record for each hour in the day. The Primary Key would represent one of those segments.
Then you could pass the admission date and discharge date for a patient to a function that would return a list, or range, of the hours that the patient is in for. So, Patient 13 might get a return value of (for example) 1500,1517 (i.e the patient was in for 17 hours and you will know the date and time because 1500 will be the Primary Key of a record that gives you the date and hour of the day he was admitted). Patient 12 would (to continue the example) return a value of 1544,1546
You could then build the dataset from Date A to Date B by returning all the data between those dates from the tally table and then check whether each hour is a yes or no for a particular patient.
The display of the data - your desired result set - I would do in somewhere else. I'd probably return two datasets. One would be used to build your table structure. The other would be used to decide whether to put a '1' in the box or not. You could do your summing on the fly.
I imagine this would get interesting with patients on the same dates ... you'd have to show each patient separately?

Related

How to get a count of occurrences in a timeframe of 7 and 30 days in SQL?

I have a table Emp and I want to get the count of records starting from a particular date to next seven days for each unique ID.
For instance, there are two occurrences of ID1 each day from 2020-11-01 to 2020-11-07, then the count for this ID would be 14.
Next, the count would start from 2020-11-08 to 2020-11-14 and so on for each given ID. The same question holds for a range of 30 days.
I have tried DATEADD(), GETDATE() and DATEDIFF(), but none of them return the correct output.
It's easy to get the count for a given date but seems a bit tricky to get the same for a range. Any help would be appreciated.

SQL date time Query

Need help to get the data of particular format
We have a table which have a data which of production now we need to select the data of each day with particular time period which is differentiate between three shift A,B,C.
In our table we have a datetime column which capture's each seconds data now that data we need in shiftwise like 6am to 2pm is of A shift production count and 2pm to 10pm of shift B and 10pm to 6 am of shift C.
here i am getting the data for single day where i have written the below query which is working good.
select distinct(count(PRD_SERIAL_NUMBER)),(select convert(date,getdate())) as date,'B' as shift_name
from table_name
where status=02
and LAST_UPDATED_DATE
between (SELECT FORMAT(GETDATE(),'yyyy-MM-dd 14:01:00.000')) and
(SELECT FORMAT(GETDATE()-26,'yyyy-MM-dd 22:01:00.000'))
refer below output image 1
Here i am getting the count for single day and for upcoming days i have solution but now the question arise is i have a past 4 Month data which i need to get in datewise and shiftwise count and for the column prd_serial_number have duplicate entries so it should be in distinct.
please refer below image 2 for required output format

extracting common data of current months and last two monnth sql

I have a table with more than 20000 rows, In one of column i have month from jan 2014 to Dec 2014, and in another column i have a loan number. Most of the loan Numbers are reapeting every months,now i need to get only the loan Number which are apperead in all three monthy consecutively. For eg if i am getting data for current months i also wanted get data which are common in two months before the current months. The database that i m using is Access DB. Any adivice will be more than a help, Thanks in Advance.
SELECT Loans.LoanID, Sum(IIf([period]=[month],1,0)) AS CM, Sum(IIf([period]=[month]-1,1,0)) AS [m-1], Sum(IIf([period]=[month]-2,1,0)) AS [m-2]
FROM Loans
GROUP BY Loans.LoanID
HAVING (((Sum(IIf([period]=[month],1,0)))>1) AND ((Sum(IIf([period]=[month]-1,1,0)))>1) AND ((Sum(IIf([period]=[month]-2,1,0)))>1));
I used month as an integer, and didn't make any adjustment for months 1 and 2 to loop back and look at prior year - you should be able to modify this based on the actual format you are using for the month.

When a start date and end date span more than one week, I need to split a row up in 2 or more new rows

I would like to begin by saying I'm quite new to sql.
That said, here is my question/problem:
I have a view that has two date columns, a variable column and a text column (for comments).
I need to be able to split up all rows where the two dates are not in the same week. And I need to be able to split the variable value as well, so that it gets evenly distributed, based on how many days were in each week. The comment must be copied as well, so to be shown in each row.
My dataset looks like this:
DateIn DateOut Amount Comment
2014-11-01 2014-11-08 600 Good
And what I want is this:
DateIn DateOut Amount Comment
2014-11-01 2014-11-07 525 Good
2014-11-08 2014-11-08 75 Good
And if the time period spreads over more weeks, I would need it to split up to equivalent number of rows.
I would be very greatful if somebody could take the time to tell me how to achive my goal, using an sql-query.
As this is my first post on the forum, I apologize for any format errors in my post.
First, you need a weeks table. I mean physical table or view, where exists one row for every week possible. (We have dates table here, +/- 30 years from now - allows easily create weeks view and similar).
Then you need link your data to weeks table with left join; join condition should check date ranges overlap with week date range (probably you have to have both week start and week end fields in your weeks table - makes comparisons easier).
Then you need to divide amounts between weeks. Because you know date range length, week length and overlapping date range length, this should be trivial :)

SQL Aggregate Subtotal

DATE|Sales
1|2
1|3
2|2
2|4
2|2
3|3
4|4
4|5
5|3
5|3
6|3
7|2
7|2
I have a table which is in this format. The first column is the date and the second one is the sales in dollars.
The table is 2 million rows.
So from the above table we can get that
after the first day we gained 5$
after the second day we gained 13$
after the third day we gained 16$
after the fourth day we gained 25$
after the fifth day we gained 31$
after the sixth day we gained 34$
after the seventh day we gained 38 $
What i want is to create a function to calculate the sales from one specific day (this date would be the input parameter to the function) to the most recent date to the table.
For example i would like to calculate the sales after the 5th 6th and 7th of the month.
Imagine that my table is two million rows and the dates instead of 3 (like in the previous case e.g.5th 6th and 7th) they might me thousands. Which is the most efficient way of doing that ?
Well, it sounds like you're basically going to be doing a table scan no matter what, it's just you need to start part-way down. I'm guessing the timestamp is indexed? Try doing WHERE date > START_DATE, and then you just do a sum(sales) as usual. Not sure that there's a more efficient way.