SQL date time Query - sql

Need help to get the data of particular format
We have a table which have a data which of production now we need to select the data of each day with particular time period which is differentiate between three shift A,B,C.
In our table we have a datetime column which capture's each seconds data now that data we need in shiftwise like 6am to 2pm is of A shift production count and 2pm to 10pm of shift B and 10pm to 6 am of shift C.
here i am getting the data for single day where i have written the below query which is working good.
select distinct(count(PRD_SERIAL_NUMBER)),(select convert(date,getdate())) as date,'B' as shift_name
from table_name
where status=02
and LAST_UPDATED_DATE
between (SELECT FORMAT(GETDATE(),'yyyy-MM-dd 14:01:00.000')) and
(SELECT FORMAT(GETDATE()-26,'yyyy-MM-dd 22:01:00.000'))
refer below output image 1
Here i am getting the count for single day and for upcoming days i have solution but now the question arise is i have a past 4 Month data which i need to get in datewise and shiftwise count and for the column prd_serial_number have duplicate entries so it should be in distinct.
please refer below image 2 for required output format

Related

How to insert a record on next selected date if count of a date is full

I have a table where I maintain working days in a week like 2nd and 4th day and number of records it can accept is 10 records per working day
usercode DaysofWeek NumberOfRecords
0623PO54 2 10
0623PO54 4 10
On insertion I have application date example 01-09-2017(dd/mm/yyyy) which is Friday.
Now I have to insert this record in closest working day from 01-09-2017 which is 05-09-2017 as it is 2nd working day. After inserting 10 records next records should be insert on 4th working day which is 07-09-2017.
I don't know how to get closest date from application date and insert record on it.
If you also want to exclude holidays than use a master table for Ex. CalenderMastr of dates which have holidays flag and day of week like Monday=2. and as you mansion that you are maintaining working days in a table for ex. workdaymaster. Now make a select query to get next date from CalenderMastr from current date and day of week stored in workdaymaster. now on output date check if in your transaction table count is smaller or not if count is small insert new record or if not than move to next date using while loop in your query. hope you can understand what i am trying to say.

Cumulative count in SQL

I am working on SQL and came across one scenario that needs to build in SQL.
Below is scenario:
PatientID AdmitDate DischargeDate
12 7/24/2017 09:45 7/24/2017 11:01
13 7/21/2016 08:37 7/22/2017 00:15
I want result set as below:
For patientID 13, count is calculated in first 2 rows and
For patientid 12, count is calculated in last row.
Well, that looks like whatever you do will be slow. I think I'd use a tally table. The table, instead of just containing the usual n years worth of dates / days / day of week etc. would also contain one record for each hour in the day. The Primary Key would represent one of those segments.
Then you could pass the admission date and discharge date for a patient to a function that would return a list, or range, of the hours that the patient is in for. So, Patient 13 might get a return value of (for example) 1500,1517 (i.e the patient was in for 17 hours and you will know the date and time because 1500 will be the Primary Key of a record that gives you the date and hour of the day he was admitted). Patient 12 would (to continue the example) return a value of 1544,1546
You could then build the dataset from Date A to Date B by returning all the data between those dates from the tally table and then check whether each hour is a yes or no for a particular patient.
The display of the data - your desired result set - I would do in somewhere else. I'd probably return two datasets. One would be used to build your table structure. The other would be used to decide whether to put a '1' in the box or not. You could do your summing on the fly.
I imagine this would get interesting with patients on the same dates ... you'd have to show each patient separately?

Time looping an average

I have a table with 17,000 records that is ordered by time spaced in 15 minute intervals. The time values loop back onto themselves every 24 hours, so for example, I could have 100 records that are all at 1 AM, just on different days. I want to create a 'average day' by taking those 100 records at 1 am and finding the average of them for the averaged 1 am.
I don't know how to format the table to make it show up nicely here.
I'm assuming you want to calculate the average value per time interval regardless of the day in a query. You could use this SQL to group your table by Time interval only (assuming that it's separate from the date field), and average whichever fields you want to average. Do not select or group by the date field, just select and group by the time field.
SELECT TimeField
, AVG([Field1ToAverage])
, AVG([Field2ToAverage])
FROM MyTable
GROUP BY TimeField;
If the date and time fields are stored together in the same column, you will have to extract the time only:
SELECT TimeValue([DateTimeField])
, AVG([Field1ToAverage])
, AVG([Field2ToAverage])
FROM MyTable
GROUP BY TimeValue([DateTimeField]);

SQL- Last 4 weeks with date column

USERS
ID TIMEMODIFIED
1 1400481271
2 1400481489
3 1400486453
4 1400486525
5 1401777484
I have timemodified field, From timemodified, I need to get the rows of last 4 weeks by taking from today's date.
SELECT id FROM USERS
WHERE FROM_UNIXTIME(timemodified,'%d-%m-%Y') >= curdate()
AND FROM_UNIXTIME(timemodified,'%d-%m-%Y') < curdate()-1
Your times are already in Unix timestamp format. Bear in mind that it'll be far more efficient to compare [TIMEMODIFIED] against the current date converted to a Unix timestamp. In addition, you don't need to check any upper bound unless [TIMEMODIFIED] can be in the future.
Try:
-- 60x60x24x7x4 = 2419200 seconds in four weeks
SET #unix_four_weeks_ago = UNIX_TIMESTAMP(curdate()) - 2419200;
SELECT id FROM USERS
WHERE timemodified >= #unix_four_weeks_ago;
NB. Four weeks ago (i.e. today – 28 days) was 1,437,696,000 (24th July) at the time of this answer. The latest record in the sample you provided has a timestamp going back to the 3rd June 2014, and so none of these records will be returned by the query.

extracting common data of current months and last two monnth sql

I have a table with more than 20000 rows, In one of column i have month from jan 2014 to Dec 2014, and in another column i have a loan number. Most of the loan Numbers are reapeting every months,now i need to get only the loan Number which are apperead in all three monthy consecutively. For eg if i am getting data for current months i also wanted get data which are common in two months before the current months. The database that i m using is Access DB. Any adivice will be more than a help, Thanks in Advance.
SELECT Loans.LoanID, Sum(IIf([period]=[month],1,0)) AS CM, Sum(IIf([period]=[month]-1,1,0)) AS [m-1], Sum(IIf([period]=[month]-2,1,0)) AS [m-2]
FROM Loans
GROUP BY Loans.LoanID
HAVING (((Sum(IIf([period]=[month],1,0)))>1) AND ((Sum(IIf([period]=[month]-1,1,0)))>1) AND ((Sum(IIf([period]=[month]-2,1,0)))>1));
I used month as an integer, and didn't make any adjustment for months 1 and 2 to loop back and look at prior year - you should be able to modify this based on the actual format you are using for the month.