New to SQL and want to complete a LEFT JOIN.
I have two seperate tables with the below code:
SELECT
StockCode, SalesOrder, SUM(OrderQty)
FROM
dbo.IopSalesPerf
WHERE
dbo.IopSalesPerf.CustRequestDate BETWEEN '2017-07-01' AND '2017-07-31'
AND EntrySystemTime = 1
AND Warehouse = '01'
AND StockCode = '001013'
GROUP BY
StockCode,SalesOrder
ORDER BY
StockCode ASC
SELECT
SalesOrder, SUM(NetSalesValue), SUM(QtyInvoiced)
FROM
ArTrnDetail
GROUP BY
SalesOrder
I would like to LEFT JOIN the last table onto the first using SalesOrder as the joining column. Can anyone assist with the syntax?
Simpliest way would be:
SELECT * FROM
(
SELECT StockCode,SalesOrder,sum(OrderQty)
FROM dbo.IopSalesPerf
WHERE dbo.IopSalesPerf.CustRequestDate between '2017-07-01' and '2017-07-31'
and EntrySystemTime = 1 and Warehouse = '01' and StockCode = '001013'
GROUP BY StockCode,SalesOrder
Order BY StockCode ASc
) AS A
LEFT JOIN
(
SELECT SalesOrder,sum(NetSalesValue),sum(QtyInvoiced)
FROM ArTrnDetail
Group by SalesOrder
) AS B
ON A.SalesOrder = B.SalesOrder
Related
I'm using SQL Server 2014 and I have a problem with a query.
I want to have in my report, ALL the items of the order with ID_Order = 9 that have been delivered. And for the items that have been delivered at two times (Item Code = Art3 for example), I just want to have the last row, that means the last delivery of this Item, with NO repetition.
I already tried these two queries without success:
Attempt #1: DISTINCT
SELECT DISTINCT
Order.ItemCode, Delivery. Qty, Delivery.ID_Delivery,
Order.ID_Order
FROM
Delivery
INNER JOIN
Order ON Order.ID_Order = Delivery.ID_Order
WHERE
Order.ID_Order = '9'
Attempt #2: subquery
SELECT *
FROM
(SELECT
Order.ItemCode, Delivery.Qty,
FROM
Delivery
INNER JOIN
Order ON Order.ID_Order = Delivery.ID_Order
WHERE
Order.ID_Order = '9')
GROUP BY
a.ItemCode, a.Qty
Try this query --
;WITH CTE
AS (
SELECT C.ID_Order
,D.ID_Delivery
,C.ItemCode
,C.Quantity
,ROW_NUMBER() OVER (
PARTITION BY C.ItemCode ORDER BY D.ID_Delivery DESC
) AS RowNum
FROM Customer_Order C
INNER JOIN Delivery D ON C.ID_Order = D.ID_Order
AND C.ItemCode = D.ItemCode
WHERE C.ID_Order = 9
)
SELECT ID_Order
,ID_Delivery
,ItemCode
,Quantity
FROM CTE
WHERE RowNum = 1
SELECT
Order.ItemCode, Delivery. Qty, Delivery.ID_Delivery,
Order.ID_Order
FROM
Delivery
INNER JOIN
Order ON Order.ID_Order = Delivery.ID_Order
WHERE
Order.ID_Order = '9'
AND Delivery.ID_Delivery IN
(
SELECT MAX(ID_Delivery) FROM Delivery D WHERE D.ID_Order = Delivery.ID_Order GROUP BY D.ID_Order
)
I hope it will work for you.
I'm quite new to SQL and I hope you can help me.
I'm trying to retrieve unique values from my table based on the latest date where specific users are selected.
This is the data:
Raw Data
And this is what I'm looking to achieve:
Desired Data
I tried to write 2 queries but unfortunately:
My 1st query would display duplicated rows for each company:
SELECT DISTINCT FilteredAppointment.regardingobjectidname ,FilteredAppointment.owneridname ,FilteredAppointment.subject ,MAX(FilteredAppointment.scheduledstart) as Date ,FilteredAppointment.location ,FilteredCcx_member.ccx_mnemonic FROM FilteredAppointment INNER JOIN FilteredAccount ON FilteredAppointment.regardingobjectid = FilteredAccount.accountid INNER JOIN FilteredCcx_member ON FilteredAccount.accountid = FilteredCcx_member.ccx_accountid WHERE FilteredAppointment.statecodename != N'Canceled' AND FilteredAppointment.owneridname IN (N'User1', N'User2', N'User3') GROUP BY FilteredAppointment.regardingobjectidname ,FilteredAppointment.owneridname ,FilteredAppointment.subject ,FilteredAppointment.scheduledstart ,FilteredAppointment.location ,FilteredCcx_member.ccx_mnemonic ORDER BY FilteredAppointment.regardingobjectidname
And my 2nd query would display one row only:
SELECT DISTINCT FilteredAppointment.regardingobjectidname ,FilteredAppointment.owneridname ,FilteredAppointment.subject ,FilteredAppointment.scheduledstart ,FilteredAppointment.location ,FilteredCcx_member.ccx_mnemonic FROM FilteredAppointment INNER JOIN FilteredAccount ON FilteredAppointment.regardingobjectid = FilteredAccount.accountid INNER JOIN FilteredCcx_member ON FilteredAccount.accountid = FilteredCcx_member.ccx_accountid WHERE FilteredAppointment.scheduledstart = (SELECT MAX(FilteredAppointment.scheduledstart) FROM FilteredAppointment WHERE FilteredAppointment.regardingobjectidname = FilteredAppointment.regardingobjectidname) AND FilteredAppointment.statecodename != N'Canceled' AND FilteredAppointment.owneridname IN (N'User1', N'User2', N'User3') GROUP BY FilteredAppointment.regardingobjectidname ,FilteredAppointment.owneridname ,FilteredAppointment.subject ,FilteredAppointment.scheduledstart ,FilteredAppointment.location ,FilteredCcx_member.ccx_mnemonic ORDER BY FilteredAppointment.regardingobjectidname
Try this:-
SELECT distinct a.date, a.company, a.companyID, a.User, a.Location, a.topic
FROM tablename a
inner join
(
Select company, companyID, User, max(date) as recent_date
from
tablename
group by company, companyID, User
) b
on a.date=b.recent_date and a.company=b.company and a.companyID=b.companyID
and a.User=b.User;
I managed to solve the issue - Thank you for the help again!
WITH apptmts AS (SELECT TOP 1 WITH TIES fa.scheduledstart,fa.location,fa.regardingobjectidname,mem.ccx_mnemonic,fa.owneridname,fa.subject FROM FilteredAppointment fa JOIN FilteredAccount acc on fa.regardingobjectid = acc.accountid JOIN FilteredCcx_member mem ON acc.accountid = mem.ccx_accountid WHERE fa.statecodename != N'Canceled' AND fa.owneridname IN (N'User1', N'User2', N'User3') ORDER BY ROW_NUMBER() OVER(PARTITION BY fa.regardingobjectidname ORDER BY fa.scheduledstart DESC) ) SELECT * FROM apptmts ORDER BY scheduledstart DESC
I'm trying to get a grand total of the qty_on_hand between our 2 warehouses combined but after I do a group by the totals don't combine. I'm not sure what I am doing wrong.
SELECT
sku_master.warehouse,
sku_master.sku
, sku_master.min_on_hand
, sku_master.max_on_hand
, x.total_qty_on_hand
FROM [wms].dbo.[sku_master]
left join
(
SELECT
sku_master.sku, sum(location_inventory.qty_on_hand) as total_qty_on_hand
FROM [wms].[dbo].[location_inventory]
JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku
GROUP BY sku_master.sku) x on sku_master.sku = x.sku
Results
Expected Results
Looks like you want sum all qty_on_hand for each sku. Try something like this using OUTER APPLY
SELECT m.sku,
m.min_on_hand,
m.max_on_hand,
oa.total_qty_on_hand
FROM (SELECT sku,
Min(min_on_hand) min_on_hand,
Max(max_on_hand) max_on_hand
FROM [wms].dbo.[sku_master] m
GROUP BY sku) m
OUTER Apply (SELECT Sum(l.qty_on_hand) AS total_qty_on_hand
FROM [wms].[dbo].[location_inventory] l
WHERE l.sku = m.sku) oa
If you need only the grand total then don't join or just for sample add with a union this
SELECT
sku_master.warehouse,
sku_master.sku
, sku_master.min_on_hand
, sku_master.max_on_hand
, x.total_qty_on_hand
FROM [wms].dbo.[sku_master]
left join
(
SELECT
sku_master.sku, sum(location_inventory.qty_on_hand) as total_qty_on_hand
FROM [wms].[dbo].[location_inventory]
JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku
GROUP BY sku_master.sku) x on sku_master.sku = x.sku
union
SELECT null, null, nullm null, sum(location_inventory.qty_on_hand)
FROM [wms].[dbo].[location_inventory]
JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku
or do the fact you have sku_master.warehouse not grouped and repeated .. remove it form select
SELECT
sku_master.sku
, sku_master.min_on_hand
, sku_master.max_on_hand
, x.total_qty_on_hand
FROM [wms].dbo.[sku_master]
left join
(
SELECT
sku_master.sku, sum(location_inventory.qty_on_hand) as total_qty_on_hand
FROM [wms].[dbo].[location_inventory]
JOIN [wms].dbo.[sku_master] ON location_inventory.sku = sku_master.sku
GROUP BY sku_master.sku) x on sku_master.sku = x.sku
you can use this simple query
SELECT
t.sku,
min(t.min_on_hand) as min_qty_on_Hand,
max(t.max_on_hand) as max_on_hand,
sum(t.total_qty_on_hand) + sum(t2.total_qty_on_hand) as total_qty_on_hand
FROM table1 t
inner join table2 t2
on t.sku = t2.sku
group by t.sku
the attached image shows the process including the result
Note: the result here is same as you mentioned in your question and what you need here just change the table names into your table name
In your request's comments you explain that you prefer one warehouse over the other. In this case you should have a table containing the warehouses with a column for the priority. Thus the query wouldn't have to know about warehouse priorities. (Just imagine you add a warehouse some day - you'd have to change all your queries.)
My query aggregates sku_master records per SKU and warehouse and then picks the best warehouse per SKU. It then joins the aggregated inventory rows by SKU.
Here is the query without a warehouse table.
select
m.warehouse,
m.sku,
m.total_min_on_hand,
m.total_max_on_hand,
li.total_qty_on_hand
from
(
select
sku,
warehouse,
sum(min_on_hand) as total_min_on_hand,
sum(max_on_hand) as total_max_on_hand,
row_number() over (partition by sku
order by case when warehouse = 'XDGM' then 1 else 2 end) as rn
from sku_master
group by sku
) m
join
(
select sku, sum(qty_on_hand) as total_qty_on_hand
from location_inventory
group by sku
) li on li.sku = m.sku
where m.rn = 1; -- only the better warehouse when there is more than one for the SKU
With a warehouse table the from clause would slightly change to:
from
(
select
sku,
warehouse,
sum(min_on_hand) as total_min_on_hand,
sum(max_on_hand) as total_max_on_hand,
row_number() over (partition by sku order by w.priority) as rn
from sku_master sm
join warehouse w on w.warehouse = sm.warehouse
group by sku
) m
Using SQL Server 2012
I have seen a few threads about this topic but I can't find one that involves multiple joins in the query. I can't create a VIEW on this database so the joins are needed.
The Query
SELECT
p.Price
,s.Type
,s.Symbol
, MAX(d.Date) Maxed
FROM AdventDW.dbo.FactPrices p
INNER JOIN dbo.DimSecurityMaster s
ON s.SecurityID = p.SecurityID
INNER JOIN dbo.DimDateTime d
ON
p.DateTimeKey = d.DateTimeKey
GROUP BY p.Price ,
s.Type ,
s.Symbol
ORDER BY s.Symbol
The query works but does not produce distinct results. I am using Order by to validate the results, but it is not required once I get it working. I The result set looks like this.
Price Type Symbol Maxed
10.57 bfus *bbkd 3/31/1989
10.77 bfus *bbkd 2/28/1990
100.74049 cbus 001397AA6 8/2/2005
100.8161 cbus 001397AA6 7/21/2005
The result set I want is
Price Type Symbol Maxed
10.77 bfus *bbkd 2/28/1990
100.74049 cbus 001397AA6 8/2/2005
Here were a few other StackOverflow threads I tried but couldn't get t work with my specific query
How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?
SQL Selecting distinct rows from multiple columns based on max value in one column
If you want data for the maximum date, use row_number() rather than group by:
SELECT ts.*
FROM (SELECT p.Price, s.Type, s.Symbol, d.Date,
ROW_NUMBER() OVER (PARTITION BY s.Type, s.Symbol
ORDER BY d.Date DESC
) as seqnum
FROM AdventDW.dbo.FactPrices p INNER JOIN
dbo.DimSecurityMaster s
ON s.SecurityID = p.SecurityID INNER JOIN
dbo.DimDateTime d
ON p.DateTimeKey = d.DateTimeKey
) ts
WHERE seqnum = 1
ORDER BY s.Symbol;
You should use a derived table since you really only want to group the DateTimeKey table to get the MAX date.
SELECT p.Price ,
s.Type ,
s.Symbol ,
tmp.MaxDate
FROM AdventDW.dbo.FactPrices p
INNER JOIN dbo.DimSecurityMaster s ON s.SecurityID = p.SecurityID
INNER JOIN
( SELECT MAX(d.Date) AS MaxDate ,
d.DateTimeKey
FROM dbo.DimDateTime d
GROUP BY d.DateTimeKey ) tmp ON p.DateTimeKey = tmp.DateTimeKey
ORDER BY s.Symbol;
/*
this is your initial select which is fine because this is base from your original criteria,
I cannot ignore this so i'll keep this in-tact. Instead from here i'll create a temp
*/
SELECT
p.Price
, s.Type
, s.Symbol
, MAX(d.Date) Maxed
INTO #tmpT
FROM AdventDW.dbo.FactPrices p
INNER JOIN dbo.DimSecurityMaster s
ON s.SecurityID = p.SecurityID
INNER JOIN dbo.DimDateTime d
ON p.DateTimeKey = d.DateTimeKey
GROUP BY p.Price ,
s.Type ,
s.Symbol
ORDER BY s.Symbol
SELECT innerTable.Price, innerTable.Symbol, innerTable.Type, innerTable.Maxed
FROM (
SELECT
ROW_NUMBER () OVER (PARTITION BY t1.Symbol, t1.Type, t1.Maxed ORDER BY t1.Maxed DESC) as row
, *
FROM #tmpT AS t1
) AS innerTable
WHERE row = 1
DROP TABLE #tmpT
Sigh ... can anyone help? In the SQL query below, the results I get are incorrect. There are three (3) labor records in [LaborDetail]
Hours / Cost
2.75 / 50.88
2.00 / 74.00
1.25 / 34.69
There are two (2) material records in [WorkOrderInventory]
Material Cost
42.75
35.94
The issue is that the query incorrectly returns the following:
sFunction cntWO sumLaborHours sumLaborCost sumMaterialCost
ROBOT HARNESS 1 12 319.14 236.07
What am I doing wrong in the query that is causing the sums to be multiplied? The correct values are sumLaborHours = 6, sumLaborCost = 159.57, and sumMaterialCost = 78.69. Thank you for your help.
SELECT CASE WHEN COALESCE(work_orders.location, Work_Orders_Archived.location) IS NULL
THEN '' ELSE COALESCE(work_orders.location, Work_Orders_Archived.location) END AS sFunction,
(SELECT COUNT(*)
FROM work_orders
FULL OUTER JOIN Work_Orders_Archived
ON work_orders.order_number = Work_Orders_Archived.order_number
WHERE COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = '919630') AS cntWO,
SUM(Laborhours) AS sumLaborHours,
SUM(LaborCost) AS sumLaborCost,
SUM(MaterialCost*MaterialQuanity) AS sumMaterialCost
FROM work_orders
FULL OUTER JOIN Work_Orders_Archived
ON work_orders.order_number = Work_Orders_Archived.order_number
LEFT OUTER JOIN
(SELECT HoursWorked AS Laborhours, TotalDollars AS LaborCost, WorkOrderNo
FROM LaborDetail) AS LD
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = LD.WorkOrderNo
LEFT OUTER JOIN
(SELECT UnitCost AS MaterialCost, Qty AS MaterialQuanity, OrderNumber
FROM WorkOrderInventory) AS WOI
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = WOI.OrderNumber
WHERE COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = '919630'
GROUP BY CASE WHEN COALESCE(work_orders.location, Work_Orders_Archived.location) IS NULL
THEN '' ELSE COALESCE(work_orders.location, Work_Orders_Archived.location) END
ORDER BY sFunction
Try using the SUM function inside a derived table subquery when doing the full join to "WorkOrderInventory" like so...
select
...
sum(hrs) as sumlaborhrs,
sum(cost) as sumlaborcost,
-- calculate material cost in subquery
summaterialcost
from labordetail a
full outer join
(select ordernumber, sum(materialcost) as summaterialcost
from WorkOrderInventory
group by ordernumber
) b on a.workorderno = b.ordernumber
i created a simple sql fiddle to demonstrate this (i simplified your query for examples sake)
Looks to me that work_orders and work_orders_archived contains the same thing and you need both tables as if they were one table. So you could instead of joining create a UNION and use it as if it was one table:
select location as sfunction
from
(select location
from work_orders
union location
from work_orders_archived)
Then you use it to join the rest. What DBMS are you on? You could use WITH. But this does not exist on MYSQL.
with wo as
(select location as sfunction, order_number
from work_orders
union location, order_number
from work_orders_archived)
select sfunction,
count(*)
SUM(Laborhours) AS sumLaborHours,
SUM(LaborCost) AS sumLaborCost,
SUM(MaterialCost*MaterialQuanity) AS sumMaterialCost
from wo
LEFT OUTER JOIN
(SELECT HoursWorked AS Laborhours, TotalDollars AS LaborCost, WorkOrderNo
FROM LaborDetail) AS LD
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = LD.WorkOrderNo
LEFT OUTER JOIN
(SELECT UnitCost AS MaterialCost, Qty AS MaterialQuanity, OrderNumber
FROM WorkOrderInventory) AS WOI
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = WOI.OrderNumber
where wo.order_number = '919630'
group by sfunction
order by sfunction
The best guess is that the work orders appear more than once in one of the tables. Try these queries to check for duplicates in the two most obvious candidate tables:
select cnt, COUNT(*), MIN(order_number), MAX(order_number)
from (select order_number, COUNT(*) as cnt
from work_orders
group by order_number
) t
group by cnt
order by 1;
select cnt, COUNT(*), MIN(order_number), MAX(order_number)
from (select order_number, COUNT(*) as cnt
from work_orders_archived
group by order_number
) t
group by cnt
order by 1;
If either returns a row where cnt is not 1, then you have duplicates in the tables.