How to display only few columns of a table based on the data - sql

Question

Consider the table below
Name partno. sch_date WO# owed panels
aa 1234 08/22/2017 121 22 26
aa 1234 08/22/2017 222 22 27
aa 1234 08/22/2017 242 22 27
aa 1234 08/29/2017 152 20 24
aa 1234 08/29/2017 167 20 24
aa 1234 08/29/2017 202 20 26`
Is it possible to display the data in such way that when the number of panels is greater than owed, then i don't won't to dispaly the other partno. schedule on the same date(sch_date).
Expected Result
Name partno. sch_date WO# owed panels
aa 1234 08/22/2017 121 22 26
aa 1234 08/29/2017 152 20 24

Answer 1

Cross apply may help here. (note you can see why I asked about order in my earlier comment as the ORDER of records in a table is not guaranteed! we need to know in what you want the records evaluated! Date isn't enough (unless it has a time compoent not displayed that is different!)
WORKING example on Rextester: http://rextester.com/CAUK18185
Many assumptions made:
When owned is > panels you don't need to see the record.
You want to see the the lowest WO# when owed is < panels and suppress all other records including ones where owed > panels.
If there are no records for a date, name and partno that have owed < panels, you want to see no records.
If these assumptions are incorrect, please provide a better sample set and expected results to test these types of situations and explain what you want to have happen.
SELECT Distinct B.*
FROM tblName Z
CROSS APPLY (SELECT TOP 1 A.*
FROM tblName A
WHERE A.owed < A.panels
and Z.Name = A.Name
and Z.[partno.] = a.[partno.]
and Z.sch_date = a.sch_date
ORDER by A.name, A.[partno.], A.sch_date, A.[wo#]) B
For each record in A run a query which returns the lowest wo# for a name, partno and sch_date when the owed < panels.
UPDATED:
I see in a comment you want to keep records if owed > panels... if it's encountered first.... but what if it's not encountered first?
http://rextester.com/NXS51018
--First we get all the records w/ a owed < panels per group and assign the earliest row (that having the lowest WO) a RN of 1. then we return that set.
cte as (
Select A.*, row_number() over (Partition by Name, [partno.], sch_date ORDER BY [WO#]) RN
from tblName A
where owed < panels)
Select * from cte where RN =1
UNION ALL
--We then union in the records where owed >=panels and their WO# < the wo# from the CTE.
SELECT Z.*, 0 as rn FROM tblName Z where owed >=panels
and exists (Select * from cte
where Z.name = CTE.name
and Z.[partno.] = cte.[partno.]
and Z.sch_date = cte.sch_date
and CTE.[WO#] > Z.[WO#]) --Now this line may not be needed, depending on if you want all or just some of the WO#'s when owed >=panels.
ORDER BY name, [partno.], Sch_date, [Wo#]
After last comment update:
cte as (
Select A.*, row_number() over (Partition by Name, [partno.], sch_date ORDER BY [WO#]) RN
from tblName A
where owed < panels),
cte2 as (Select * from cte where RN =1
UNION ALL
SELECT Z.*, 0 as rn FROM tblName Z where owed >=panels
and exists (Select * from cte
where Z.name = CTE.name
and Z.[partno.] = cte.[partno.]
and Z.sch_date = cte.sch_date
and CTE.[WO#] > Z.[WO#]))
Select * into SOQ#45619304 from CTE2; --This line creates the table based on the 2nd cte results.
Select * from SOQ#45619304;

Answer 2

You can try this -
SELECT Name, partno., sch_date, WO#, owed, panels
FROM YOUR_TABLE
WHERE panels < owed
UNION ALL
SELECT Name, partno., sch_date, MIN(WO#), owed, MIN(panels)
FROM YOUR_TABLE
WHERE panels > owed
GROUP BY Name, partno., sch_date, owed
ORDER BY Name