I have the following table:
ID | Keyword | Date
87NB | skill,love,hate,funny,very funny | 02/19/2004
27YV | funny,tiger,movie,king | 08/10/2014
92JK | sun,light,funny,baby | 06/27/2015
65TH | moon,cow,bird,car | 04/22/2017
From the above table, i want to obtain ID's of everyone who have "funny" as a keyword. The result would be
ID
87NB
27YV
92JK
you can use split and then the function array_contains
select ID from yourtable where array_contains(split(Keyword, ","), "funny");
select ID
from t
where find_in_set('funny',Keyword) > 0
;
+------+
| id |
+------+
| 87NB |
+------+
| 27YV |
+------+
| 92JK |
+------+
Related
I need help getting the User which has an 'IN' and 'Out' in Column isIN. If the user has an IN and OUT do not select them in the list. I need to select the user who has only had an IN. Please I need help. Thanks in advance.
This is the table:
| Users | IsIN |
|:------------------:|:-----:|
| MHYHDC61TMJ907867 | IN |
| MHYHDC61TMJ907867 | OUT |
| MHYHDC61TMJ907922 | IN |
| MHYHDC61TMJ907922 | OUT |
| MHYHDC61TMJ907923 | IN |
| MHYHDC61TMJ907923 | OUT |
| MHYHDC61TMJ907924 | IN | - I need to get only this row
| MHYHDC61TMJ907925 | IN |
| MHYHDC61TMJ907925 | OUT |
| MHYHDC61TMJ908054 | IN | - I need to get only this row
| MHYHDC61TMJ908096 | IN | - I need to get only this row
| MHYHDC61TMJ908109 | IN | - I need to get only this row
Need to get the result like
| Users | IsIN |
|:------------------:|:-----:|
| MHYHDC61TMJ907924 | IN |
| MHYHDC61TMJ908054 | IN |
| MHYHDC61TMJ908096 | IN |
| MHYHDC61TMJ908109 | IN |
I tried using this query and sample query below but it doesn't work.
select s.[Users], s.[isIn] [dbo].[tblIO] s
where not exists (
select 1
from [dbWBS].[dbo].[tblIO] s2
where s2.[Users] = s.[Users] and s2.isIn = 'IN'
);
You can use not exists:
select s.*
from sample s
where not exists (select 1
from sample s2
where s2.user = s.user and s2.inout = 'OUT'
);
If you want only users that meet the condition (and not the full rows):
select user
from sample s
group by user
having min(inout) = max(inout) and min(inout) = 'IN';
Bearing in mind that an 'OUT' IsIn must be always preceded by an 'IN' record, you could use a query like this:
select s.Users, 'IN' as IsIn
from sample s
group by s.Users
having count(distinct s.IsIn) = 1
I have a one tables in Postgresql and cannot find how to build a query.
The table contains columns nr_serii and deleteing_time. I trying to count nr_serii and substract from this positions with deleting_time.
My query:
select nr_serii , count(nr_serii ) as ilosc,count(deleting_time) as ilosc_delete
from MyTable
group by nr_serii, deleting_time
output is:
+--------------------+
| "666666";1;1 |
| "456456";1;0 |
| "333333";3;0 |
| "333333";1;1 |
| "111111";1;1 |
| "111111";3;0 |
+--------------------+
The part of table with raw data:
+--------------------------------+
| "666666";"2020-11-20 14:08:13" |
| "456456";"" |
| "333333";"" |
| "333333";"" |
| "333333";"" |
| "333333";"2020-11-20 14:02:23" |
| "111111";"" |
| "111111";"" |
| "111111";"2020-11-20 14:08:04" |
| "111111";"" |
+--------------------------------+
And i need substract column ilosc and column ilosc_delete
example:
nr_serii:333333 ilosc:3-1=2
Expected output:
+-------------+
| "666666";-1 |
| "456456";1 |
| "333333";2 |
| "111111";2 |
| ... |
+-------------+
I think this is very simple solution for this but i have empty in my head.
I see what you want now. You want to subtract the number where deleting_time is not null from the ones where it is null:
select nr_serii,
count(*) filter (where deleting_time is null) - count(deleting_time) as ilosc_delete
from MyTable
group by nr_serii;
Here is a db<>fiddle.
Assume there is a table employee:
+-----------+------------------+
| col_name | data_type |
+-----------+------------------+
| id | string |
| perf | map<string,int> |
+-----------+------------------+
and the data inside this table:
+-----+------------------------------------+--+
| id | perf |
+-----+------------------------------------+--+
| 1 | {"job":80,"person":70,"team":60} |
| 2 | {"job":60,"team":80} |
| 3 | {"job":90,"person":100,"team":70} |
+-----+------------------------------------+--+
I tried the following two queries but they all return the same result:
1. select explode(perf) from employee;
2. select key,value from employee lateral view explode(perf) as key,value;
The result:
+---------+--------+--+
| key | value |
+---------+--------+--+
| job | 80 |
| team | 60 |
| person | 70 |
| job | 60 |
| team | 80 |
| job | 90 |
| team | 70 |
| person | 100 |
+---------+--------+--+
So, what is the difference between them? I did not find suitable examples. Any help is appreciated.
For your particular case both queries are OK. But you can't use multiple explode() functions without lateral view. So, the query below will fail:
select explode(array(1,2)), explode(array(3, 4))
You'll need to write something like:
select
a_exp.a,
b_exp.b
from (select array(1, 2) as a, array(3, 4) as b) t
lateral view explode(t.a) a_exp as a
lateral view explode(t.b) b_exp as b
I have the following table running on Postgres SQL 9.5:
+---+------------+-------------+
|ID | trans_id | message |
+---+------------+-------------+
| 1 | 1234567 | abc123-ef |
| 2 | 1234567 | def234-gh |
| 3 | 1234567 | ghi567-ij |
| 4 | 8902345 | ced123-ef |
| 5 | 8902345 | def234-bz |
| 6 | 8902345 | ghi567-ij |
| 7 | 6789012 | abc123-ab |
| 8 | 6789012 | def234-cd |
| 9 | 6789012 | ghi567-ef |
|10 | 4567890 | abc123-ab |
|11 | 4567890 | gex890-aj |
|12 | 4567890 | ghi567-ef |
+---+------------+-------------+
I am looking for the rows for each trans_id based on a LIKE query, like this:
SELECT * FROM table
WHERE message LIKE '%def-234%'
This, of course, returns just three rows, the three that match my pattern in the message column. What I am looking for, instead, is all the rows matching that trans_id in groups of messages that match. That is, if a single row matches the pattern, get all the rows with the trans_id of that matching row.
That is, the results would be:
+---+------------+-------------+
|ID | trans_id | message |
+---+------------+-------------+
| 1 | 1234567 | abc123-ef |
| 2 | 1234567 | def234-gh |
| 3 | 1234567 | ghi567-ij |
| 4 | 8902345 | ced123-ef |
| 5 | 8902345 | def234-bz |
| 6 | 8902345 | ghi567-ij |
| 7 | 6789012 | abc123-ab |
| 8 | 6789012 | def234-cd |
| 9 | 6789012 | ghi567-ef |
+---+------------+-------------+
Notice rows 10, 11, and 12 were not SELECTed because there was not one of them that matched the %def-234% pattern.
I have tried (and failed) to write a sub-query to get the all the related rows when a single message matches a pattern:
SELECT sub.*
FROM (
SELECT DISTINCT trans_id FROM table WHERE message LIKE '%def-234%'
) sub
WHERE table.trans_id = sub.trans_id
I could easily do this with two queries, but the first query to get a list of matching trans_ids to include in a WHERE trans_id IN (<huge list of trans_ids>) clause would be very large, and would not be a very inefficient way of doing this, and I believe there exists a way to do it with a single query.
Thank you!
This will do the job I think :
WITH sub AS (
SELECT trans_id
FROM table
WHERE message LIKE '%def-234%'
)
SELECT *
FROM table JOIN sub USING (trans_id);
Hope this help.
Try this:
SELECT ID, trans_id, message
FROM (
SELECT ID, trans_id, message,
COUNT(*) FILTER (WHERE message LIKE '%def234%')
OVER (PARTITION BY trans_id) AS pattern_cnt
FROM mytable) AS t
WHERE pattern_cnt >= 1
Using a FILTER clause in the windowed version of COUNT function we can get the number of records matching the predefined pattern within each trans_id slice. The outer query uses this count to filter out irrelevant slices.
Demo here
You can do this.
WITH trans
AS
(SELECT DISTINCT trans_id
FROM t1
WHERE message LIKE '%def234%')
SELECT t1.*
FROM t1,
trans
WHERE t1.trans_id = trans.trans_id;
I think this will perform better. If you have enough data, you can do an explain on both Sub query and CTE and compare the output.
I am casting a real to an int and a float to an int and comparing the two like this:
where
cast(a.[SUM(PAID_AMT)] as int)!=cast(b.PAID_AMT as int)
but i am still getting results where the two are equal. for example:
+-----------+-----------+------------+------------+----------+
| accn | load_dt | pmtdt | sumpaidamt | Bpaidamt |
+-----------+-----------+------------+------------+----------+
| A133312 | 6/7/2011 | 11/28/2011 | 98.39 | 98.39 |
| A445070 | 6/2/2011 | 9/22/2011 | 204.93 | 204.93 |
| A465606 | 5/19/2011 | 10/19/2011 | 560.79 | 560.79 |
| A508742 | 7/12/2011 | 10/19/2011 | 279.65 | 279.65 |
| A567730 | 5/27/2011 | 10/24/2011 | 212.76 | 212.76 |
| A617277 | 7/12/2011 | 10/12/2011 | 322.02 | 322.02 |
| A626384 | 6/16/2011 | 10/21/2011 | 415.84 | 415.84 |
| AA0000044 | 5/12/2011 | 5/23/2011 | 197.38 | 197.38 |
+-----------+-----------+------------+------------+----------+
here is the full query:
select
a.accn,
a.load_dt,
a.pmtdt,
a.[SUM(PAID_AMT)] sumpaidamt,
sum(b.paid_amt) Bpaidamt
from
[MILLENNIUM_DW_DEV].[dbo].[Millennium_Payment_Data_May2011_July2012] a
join
F_PAYOR_PAYMENTS_DAILY b
on
a.accn=b.ACCESSION_ID
and
a.final_rpt_dt=b.FINAL_REPORT_DATE
and
a.load_dt=b.LOAD_DATE
and
a.pmtdt=b.PAYMENT_DATE
where
cast(a.[SUM(PAID_AMT)] as int)!=cast(b.PAID_AMT as int)
group by
a.accn,
a.load_dt,
a.pmtdt,
a.[SUM(PAID_AMT)]
what am i doing wrong? how do i return only records that are NOT equal?
I don't see why there is an issue.
The query is returning the sum of the payments in b (sum(b.paid_amt) Bpaidamt). The where clause is comparing individual payments. This just means that there is more than one payment.
Perhaps your intention is to have a HAVING clause instead:
having cast(a.[SUM(PAID_AMT)] as int)!=cast(sum(b.PAID_AMT) as int)
You can do a round and a cast statement.
cast(round(sumpaidamt,2) as money) <> cast(round(Bpaidamt,2) as money)
Sql Fiddle showing how it would work http://sqlfiddle.com/#!3/4eb79/1