could you explain sender and receiver in oop and give examples? - oop

I have read this similar topic but i still don't understand at all,therefore i hope u guys can help me to understand general meaning and give more examples of it. Thanks

Sending a message in this context is basically "calling a ,method/accessing a property", as the post you mentioned said.
Let's see an example in Java:
class MyClass {
public void myMethod() {
Foo foo = new Foo();
foo.doStuff(); // *
}
}
class Foo {
public void doStuff() {}
}
In the line marked by the asterisk, a method call is done. I.e. You are sending a message. The "sender" of the message is where you are calling the method i.e. MyClass. The "receiver" is the object on which you call the method i.e. an instance of Foo. And the message itself is the method called i.e. doStuff.
In languages where properties exist, like in Swift and C sharp, accessing properties also counts as sending a message.

Related

Testing private methods in Raku

Is there a way to test private methods in Raku?
I understand that one should ideally define their tests targeting the public methods, but is there a way to do it "the wrong way"? :)
I initially thought about defining a subclass for the Testing that inherited from the class I wanted to test and do the tests there, but it seems that private methods are not inherited.
Then I saw the 'trusts' routine, but I wouldn't want to reference a Testing class on any of the classes of the code.
Is there something like changing the 'private' property of a method via introspection?
What would be the best way to call/test a private method?
This can be done using introspection.
Consider this is the class you want to test:
class SomeClass {
has Int $!attribute;
method set-value(Int $value) returns Nil {
$!attribute = $value;
return;
}
method get-value returns Int {
return $!attribute;
}
# Private method
method !increase-value-by(Int $extra) returns Nil {
$!attribute += $extra;
return;
}
}
You may create a test like this:
use Test;
use SomeClass;
plan 3;
my SomeClass $some-class = SomeClass.new;
my Method:D $increase-value = $some-class.^find_private_method: 'increase-value-by';
$some-class.set-value: 1;
$increase-value($some-class, 4);
is $some-class.get-value, 5, '1+4 = 5';
$increase-value($some-class, 5);
is $some-class.get-value, 10, '5+5 = 10';
my SomeClass $a-new-class = SomeClass.new;
$a-new-class.set-value: 0;
$increase-value($a-new-class, -1);
is $a-new-class.get-value, -1, '0+(-1) = -1; The method can be used on a new class';
done-testing;
You first create an instance of the class and the use ^find_private_method to get its private Method. Then you can call that Method by passing an instance of a class as the first parameter.
There's a more complete explanation on this answer:
How do you access private methods or attributes from outside the type they belong to?
A fresh cup of tea and #Julio's and #JJ's answers inspired the following:
class SomeClass { method !private ($foo) { say $foo } }
use MONKEY-TYPING; augment class SomeClass { trusts GLOBAL }
my SomeClass $some-class = SomeClass.new;
$some-class!SomeClass::private(42); # 42
My solution tweaks the class using monkey typing. Monkey typing is a generally dodgy thing to do (hence the LOUD pragma). But it seems tailor made for a case just like this. Augment the class with a trusts GLOBAL and Bob's your Uncle.
Raku requires the SomeClass:: qualification for this to work. (Perhaps when RakuAST macros arrive there'll be a tidy way to get around that.) My inclination is to think that having to write a class qualification is OK, and the above solution is much better than the following, but YMMV...
Perhaps, instead:
use MONKEY-TYPING;
augment class SomeClass {
multi method FALLBACK ($name where .starts-with('!!!'), |args) {
.(self, |args) with $?CLASS.^find_private_method: $name.substr: 3
}
}
and then:
$some-class.'!!!private'(42); # 42
I've used:
A multi for the FALLBACK, and have required that the method name string starts with !!!;
A regular method call (. not !);
Calling the method by a string version of its name.
The multi and !!! is in case the class being tested already has one or more FALLBACK methods declared.
A convention of prepending !!! seems more or less guaranteed to ensure that the testing code will never interfere with how the class is supposed to work. (In particular, if there were some call to a private method that didn't exist, and there was existing FALLBACK handling, it would handle that case without this monkey FALLBACK getting involved.)
It should also alert anyone reading the test code that something odd is going on, in the incredibly unlikely case that something weird did start happening, either because I'm missing something that I just can't see, or because some FALLBACK code within a class just so happened to use the same convention.
Besides using introspection, you can try and use a external helper role to access all private methods and call them directly. For instance:
role Privateer {
method test-private-method ( $method-name, |c ) {
self!"$method-name"(|c);
}
}
class Privateed does Privateer {
method !private() { return "⌣" }
}
my $obj = Privateed.new;
say $obj.test-private-method( "private" );
The key here is to call a method by name, which you can do with public and private methods, although for private methods you need to use their special syntax self!.

Using public and private methods inside their class in Perl 6

If I have a public method, I can call it inside its class using both $.name and self.name:
class TEST {
has Int $.a;
method b($x) {
return $!a * $x;
}
method c($y) {
return self.b($y) * 3; # or $.b($y)
}
}
my $m = TEST.new(a => 10);
say $m.c(2); # 60
But if I make b a private method, I only can call it with self!b, not $!b, otherwise I get the following error message:
Attribute $!b not declared in class TEST
What's behind this rule? What are the rules of calling a method inside its own class?
An attribute can always be referred to as $!foo in a class. If you do that, than the code will be generated to directly access the attribute itself, and any classes subclassing your class will not be able to change this behaviour.
If you use has $.foo in the declaration of a class, it means that a public accessor (and if you add is rw it can also function as a mutator).
When you use $.foo in your code otherwise, it is exactly the same as $( self.foo ). This means that it will call the method foo on self, and itemize the return value (make it a single "thing" if it wasn't yet). This will go wrong if you defined your attribute with $!foo and you did not supply a method foo yourself.
This goes even further: $.bar really means self.bar: you only need to have a method existing by the name bar, which may not be related to any attribute at all.
If you define a private method !baz, the ! just indicates the privacy of the method, which means you need to call it indeed as self!baz. There is no short syntax for it.
Personally I dislike the fact that you can say $.zippo even if zippo is not an attribute. But I'm afraid that ship has sailed. But this behaviour is now causing you confusion :-(
So what's behind the rule for not having a short syntax for calling a private method? Not sure, I guess really that $!foo was already taken to mean direct access to the attribute, and provide you with a compile time error if the attribute doesn't exist.
Hope this answers your question!

Mockito mocking method with class parameter vs actual object parameter

What is the difference between these two as per Mockito -
Mockito.when(serviceObject.myMethod(Customer.class)).thenThrow(new
RuntimeException());
and
Customer customer = new Customer();
Mockito.when(serviceObject.myMethod(customer)).thenThrow(new
RuntimeException());
And if both serve the same purpose then using which one is considered to be best practice?
There is a misunderstanding on your side - that method specification myMethod(SomeClass.class) is only possible when the signature of that method allows for a class parameter. Like:
Whatever myMethod(Object o) {
or directly
Whatever myMethod(Class<X> clazz) {
In other words: it is not Mockito that does something special about a parameter that happens to be of class Class!
Thus your first option is not something that works "in general". Example: I put down this code in a unit test:
static class Inner {
public int foo(String s) { return 5; }
}
#Test
public void testInner() {
Inner mocked = mock(Inner.class);
when(mocked.foo(Object.class)).thenReturn(4);
System.out.println(mocked.foo(""));
}
And guess what - the above does not compile. Because foo() doesn't allow for a Class parameter. We can rewrite to
static class Inner {
public int foo(Object o) { return 5; }
}
#Test
public void testInner() {
Inner mocked = mock(Inner.class);
when(mocked.foo(Object.class)).thenReturn(4);
System.out.println(mocked.foo(""));
}
And now the above compiles - but prints 0 (zero) when invoked. Because the above would be the same as mocked.foo(eq(Object.class)). In other words: when your method signature allows for passing a Class instance and you then pass a class instance, that is a simple mocking specification for mockito. In my example: when the incoming object would be Object.class - then 4 would be returned. But the incoming object is "" - therefore the Mockito default kicks in and 0 is returned.
I am with the other answer here - I think you are mixing up that older versions of Mockito asked you to write down when(mocked.foo(any(ExpectedClass.class))) - which can nowadays be written as when(mocked.foo(any())). But when(mocked.foo(ExpectedClass.class)) is not a Mockito construct - it is a simple method specification that gives a specific object to "match on" - and that specific object happens to be an instance of class Class.
First one which uses generic Customer class to match type can also be written as:
Mockito.when(serviceObject.myMethod(Mockito.any(Customer.class))).thenThrow(new
RuntimeException());
In case of the second one, you are passing the actual object that will be used in stubbing.
Usage:
If your method myMethod throws the exception based on the state of the Customer object then you can use the latter approach, where you can set the state of the Customer object appropriately.
However If your method myMethod does not depend on the Customer object to throw the exception rather you need it only to pass it as an argument just to invoke the method, then you can take the former approach.

To create an object (of some class) in a listener

I'm creating a script and have troubles.
Is it possible to create an object (of some class) from within a listener?
I tried it but I get an error: ``class not found''.
I want to do something like:
class ONE {
class_ONE_code
}
class TWO {
object o = alloc(ONE)
}
I need this to create a new listener when I execute another listener.
What you wish to do is certainly possible. Most likely you have a syntax error in your code. For example, your implementation of class TWO is invalid since a member variable like "o" cannot be initialized in the member declaration section of the class code. This can only be done within a class method, as illustrated in the example code below.
class One
{
void DoClassOneAction(Object self)
{
OKDialog("Class One action executed.");
}
}
class Two
{
Object oneInstance;
void DoClassTwoAction(Object self)
{
if (!oneInstance.ScriptObjectIsValid())
oneInstance = Alloc(One);
oneInstance.DoClassOneAction();
}
}
void main()
{
Object twoInstance = Alloc(Two);
twoInstance.DoClassTwoAction();
}
main();
Note that the coding requirements for DM script classes differ somewhat from those of other languages that support objects. You may want to review details in the Scripting > Objects section of the DM on-line help (accessed via Help > Search… menu item).

Method returns an object of a different class

I have noticed a situation where there is a class (say: ClassA) with variable declarations and various methods. And in another class (say: Class B), there is a method(MethodofClassB()) with the return type of the method as ClassA.
so it is like:
Class A
{
variable i,j;
public int MethodA()
{
//some operation
}
}
Class B
{
variable x,y;
public static A MethodB()
{
//some operation
return obj;
}
}
1) I understand that MethodB() return an object of ClassA. Waty would be the use(the intention) of returning the object of ClassA
2) What is the reason for defining MethodB() as Public static. what would happen if static was not used for MethodB()
3)What would the returned objct look like. I mean if my method returned an integer, it would return some numerical value say '123' . If a method returns an object of a class, what would be in the returrned value.
please help me understand this with a small example
1) I understand that MethodB() return an object of ClassA. Waty would be the use(the intention) of returning the object of ClassA
Depends on what the method does, which isn't illustrated in this example. If the result of the operation is an instance of A then it stands to reason that it would return an instance of A, whatever A is.
For example, if A is a Car and B is a CarFactory then the method is likely producing a new Car. So it would return a Car that's been produced.
2) What is the reason for defining MethodB() as Public static. what would happen if static was not used for MethodB()
public allows it to be accessed by other objects. static means it's not associated with a particular instance of B. Both are subjective based, again, on the purpose of the method (which isn't defined in the example). Being static, it can be called as such:
var newInstance = B.MethodB();
If it wasn't static then an instance of B would be required:
var objectB = new B();
var newInstance = objectB.MethodB();
There are more and more implications here, including things like memory/resource usage and thread safety. All stemming from the purpose and business logic meaning of what B is and what MethodB does.
3)What would the returned objct look like. I mean if my method returned an integer, it would return some numerical value say '123' . If a method returns an object of a class, what would be in the returrned value.
It would be an instance of A. Similar to creating an instance here:
var objectA = new A();
This method also creates (or in some way gets) an instance:
var objectA = B.MethodB();
Without knowing more about what A is, what its constructor does, and what MethodB does, these two operations are otherwise the same.
First, your code is incorrect. There is no "ClassA" class. The class name is A, so the return type should be A not ClassA.
Second, the standard Java coding standards say to start methods and variables with lower case letters. So, your example should have been:
Class A
{
A anA;
B aB;
public int methodA()
{
//some operation
}
}
Class B
{
SomeType x, y;
public static A methodB()
{
//some operation
return obj;
}
}
David's answer shortly before mine is technically correct on points 1 and 2, although he also uses your mistake of calling the A type ClassA. His code for his answer to point 3, though, is incorrect and misleading. I would change his wording to this:
`3)What would the returned objct look like. I mean if my method returned an
integer, it would return some numerical value say '123' . If a method returns
an object of a class, what would be in the returrned value`.
It would be an instance of class A. Similar to creating an instance here:
A objectA = new A();
This method also creates (or in some way gets) an instance:
A objectA = B.methodB();
Without knowing more about what class A is, what its constructor does, and what methodB does, these two operations are otherwise the same.