Users
Screenshot users table
field_data_field_user_first_name
screenshot fields table
What query should I use to get a table like this:
Uid Email First name
1 123#123.com example
I have tried without luck:
SELECT * FROM users
LEFT JOIN field_data_field_user_first_name
ON users.uid = ield_data_field_user_first_name.entity_id
You will get same result as mentioned above by using this query
SELECT users.uid as Uid,users.mail as Email,field_data_field_user_first_name.field_user_first_name_value as FirstName FROM users
LEFT JOIN field_data_field_user_first_name
ON users.uid = ield_data_field_user_first_name.entity_id;
Related
Suppose I have a table called UserFollows, where I keep Follow relationships ;
UserId
FollowedId
Then I have a general Users table and it is like ;
Id
Username
I use a query like the following when I want to get all followers of a user with ID 100 ;
SELECT*FROM UserFollows WHERE FollowedId = 100;
And suppose that I also want to query the following case ;
I want to search among the followers of a particular user, with a specific Username.
So, It should be like GET ME ALL OF THE USERS THAT HAS THE WORD 'hey' IN THEIR USERNAMES AMONG THOSE FOLLOWING ME
If I had Username in my UserFollows table , I'd easily write it like ;
SELECT*FROM UserFollows WHERE FollowedId = 100 AND Username LIKE '%a';
But I don't keep their Usernames in UserFollows
You need to include the Users table in the query.
SELECT uf.*
FROM UserFollows uf
inner join Users u on u.Id = uf.UserId
WHERE uf.FollowedId = 100
AND u.Username LIKE '%a';
or, more clearly
SELECT uf.*
FROM UserFollows uf
inner join Users follower on follower.Id = uf.UserId
inner join Users followed on followed.Id = uf.FollowedId
WHERE followed.UserName = 'ME'
AND follower.Username LIKE '%a';
Although "followed" may be a keyword, so you would need different aliases or you would need to handle the names appropriately.
I'm having trouble doing the following query. The idea is that I have two tables Stores and Users. In Stores I have the columns store_owners and store_last_modified, both values are integer that are related to the id of dbo.Users. How I can display the name that is stored in users related to the two columns. Like that:
select stores.name , users.name as name_store_owner , users.name as name_store_last_modified
from stores
LEFT JOIN users ON stores.store_owners=users.id (related to name_store_owner)
LEFT JOIN users ON stores.store_last_modified=users.id (related to name_store_last_modified)
How do I do that?
Thank you in advance.
You need to give the tables aliases, so you can refer to the same table twice in the from clause. In addition, you need to refer to the right table (users not stores):
select s.name, uo.name as name_store_owner, um.name as name_store_last_modified
from stores s left join
users uo
on s.store_owners = uo.id left join
users um
on s.store_last_modified = um.id
It appears that the condition can be checked without referring the table twice.
select * from
stores s
left join
users u on u.id = s.store_owners
and u.id = s.store_last_modified
From your question it appears that user id (id) should match with both the columns in the stores table for a single row.
Sorry if that title is a bit convoluted... I'm spoiled by an ORM usually and my raw SQL skills are really poor, apparently.
I'm writing an application that links to a vBulletin forum. Users authenticate with their forum username, and the query for that is simple (selecting by username from the users table). The next half of it is more complex. There's also a subscriptions table that has a timestamp in it, but the primary key for these is a user id, not a username.
This is what I've worked out so far:
SELECT
forum.user.userid,
forum.user.usergroupid,
forum.user.password,
forum.user.salt,
forum.user.pmunread,
forum.subscriptionlog.expirydate
FROM
forum.user
JOIN forum.subscriptionlog
WHERE
forum.user.username LIKE 'SomeUSER'
Unfortunately this returns the entirety of the subscriptionlog table, which makes sense because there's no username field in it. Is it possible to grab the subscriptionlog row using the userid I get from forum.user.userid, or does this need to be split into two queries?
Thanks!
The issue is that you are blindly joining the two tables. You need to specify what column they are related by.
I think you want something like:
SELECT * FROM user u
INNER JOIN subscriptionlog sl ON u.id = sl.userid
WHERE u.username LIKE 'SomeUSER'
select * from user u JOIN subscriptions s ON u.id = s.id where u.username = 'someuser'
The bit in bold is what you want to add, it combines the 2 tables into one that you return results from.
try this
SELECT
forum.user.userid,
forum.user.usergroupid,
forum.user.password,
forum.user.salt,
forum.user.pmunread,
forum.subscriptionlog.expirydate
FROM
forum.user
INNER JOIN forum.subscriptionlog
ON forum.subscriptionlog.userid = forum.user.userid
WHERE
forum.user.username LIKE 'SomeUSER'
I'm trying to write a query in oracle SQL, first I am trying to edit a profile, so I want to change the institution that the user previously select it, but for that I must get all the institutions from a table named institution (id_institution, name_institution),
select user.user_name, institution.name_institution from user
inner join institution_has_user on user.id_user = institution_has_user.user_id_user
inner join institution on institution_has_user.institution_id_institution = institution.id_institution
where user = 'george';
But all I get It is the data that he register, and I want all the institutions, so I can fill a select html, just for editing purposes
If you want to return all the institutions from your above query, then you'll need to use an OUTER JOIN and move your WHERE criteria to your JOIN. This will however return NULL records for the user name field where there aren't any matches which might not be what you're looking for:
select distinct user.user_name, institution.name_institution
from institution
left join institution_has_user on institution_has_user.institution_id_institution = institution.id_institution
left join user on user.id_user = institution_has_user.user_id_user
and user.user_name = 'george';
Perhaps an easier alternative solution, just run two queries -- it should be perfectly fine to create a drop down list from a single select statement:
select name_institution
from institution
I have 3 tables; CASES, USERS and USER_META. For this issue you need to know that the USER_META table has 3 columns; user_id, meta_key and meta_value
Each user is associated with many CASES and each USER is associated with many USER_META
My current query is like this
SELECT CASES.*, USERS.*, USER_META.*
FROM CASES
JOIN USERS ON USERS."user_id" = CASES."user_id"
JOIN USER_META ON USER_META_"user_id" = USERS."user_id"
The problem with this approach is that each USER has A LOT of USER_META so my result set has too many rows. How can I rewrite this query so that I can select only the USER_META where the USER_META."meta_key" is equal to a certain value yet still get the result if they do not have this USER_META."meta_key" set yet
For example:
SELECT CASES.*, USERS.*, USER_META.*
FROM CASES
JOIN USERS ON USERS."user_id" = CASES."user_id"
JOIN USER_META ON USER_META_"user_id" = USERS."user_id"
WHERE USER_META."meta_key" = 'my_key'
This would work great but not all users have a value of "my_key" in the "meta_key" column and we still need to view their CASE. For users that do not have the "meta_key" the result should just return the CASE and USER columns.
How can I rewrite this query so it gets the result for both users with this meta_key and without?
Thanks, I hope this makes sense.
I would use a LEFT JOIN
SELECT CASES.*, USERS.*, USER_META.*
FROM CASES
JOIN USERS ON USERS."user_id" = CASES."user_id"
LEFT JOIN USER_META ON USER_META."user_id" = USERS."user_id" AND USER_META."meta_key" = ?
you need to use OUTER JOIN with the table that may have no results. In Oracle, use (+) near to the field name of the join sentence with this table. This link may help you: http://download.oracle.com/docs/cd/B28359_01/server.111/b28286/queries006.htm