I'm trying to write a query in oracle SQL, first I am trying to edit a profile, so I want to change the institution that the user previously select it, but for that I must get all the institutions from a table named institution (id_institution, name_institution),
select user.user_name, institution.name_institution from user
inner join institution_has_user on user.id_user = institution_has_user.user_id_user
inner join institution on institution_has_user.institution_id_institution = institution.id_institution
where user = 'george';
But all I get It is the data that he register, and I want all the institutions, so I can fill a select html, just for editing purposes
If you want to return all the institutions from your above query, then you'll need to use an OUTER JOIN and move your WHERE criteria to your JOIN. This will however return NULL records for the user name field where there aren't any matches which might not be what you're looking for:
select distinct user.user_name, institution.name_institution
from institution
left join institution_has_user on institution_has_user.institution_id_institution = institution.id_institution
left join user on user.id_user = institution_has_user.user_id_user
and user.user_name = 'george';
Perhaps an easier alternative solution, just run two queries -- it should be perfectly fine to create a drop down list from a single select statement:
select name_institution
from institution
Related
I have a database with 2 tables in it one is 'enlistments' and the other one is 'users'. In the enlistments table I have a user_id and in the users table I have a name. I want to get the name of the user which belongs to the id.
I know I need to do this with an inner join like this:
SELECT enlistments.round_id, users.name
FROM enlistments
INNER JOIN users
ON enlistments.user_id=users.name
WHERE enlistments.activity_id = 1;
However I get this error: Warning: #1292 Truncated incorrect DOUBLE value
I did some research and found out it has to do with comparing an int with a string but I don't know how to solve the problem.
This is how my database looks like
join on is the condition you use to join the tables. Here it's enlistments.user_id=users.id.
select e.round_id
,u.name
from enlistments e join users u on u.id = e.user_id
where activity_id = 1
round_id
name
1
test2
Fiddle
To validate and be sure you are pulling back the exact data desired, I usually provide aliases for each column brought back and make sure to bring back the join columns also. It's good practice to label where the columns returned originated.
SELECT
Enlistments.UserID as Enlistments_UserID,
Users.ID as Users_ID,
enlistments.round_id as Enlistments_RoundID,
users.name as Users_Name
FROM enlistments
INNER JOIN users
ON enlistments.user_id=users.id
WHERE enlistments.activity_id = 1;
SELECT EN.round_id, US.name
FROM enlistments EN
INNER JOIN users US
ON US.name= CAST(EN.user_id AS VARCHAR)
WHERE EN.activity_id = 1
What you are needing is the function cast that can convert any kind of data into another, so you'll pass your integer value as the first argument followed by "AS '%DATATYPE'" where %DATATYPE is the kind of data you want to achieve.
In your case:
SELECT CAST(123456 AS VARCHAR)
-- RETURNS : '123456'
Anyway, I’m not sure that you can be able to join these two tables with the join you are using.
For more help please share some data.
I have a table with Customers which includes their contact person in the helpdesk. I have another table that lists all vacancies of the helpdesk employees - if they are currently sick or on vacation etc.
I need to get the helpdesk contact and the start/end time of their vacation IF there is an entry.
I currently have this (simplified):
SELECT *
FROM dbo.Customers, dbo.Projects, dbo.Vacations
WHERE ($Phone = dbo.Customers.Phone)
AND dbo.Customers.CustomerID = dbo.Projects.CustomerID
AND dbo.Projects.HDContactID = dbo.Vacations.HDContactID
So if there is a vacation listed in the Vacations table, it works fine, but if there is no vacation at all, this will not return anything - what i want is that if there is no vacation, it simply returns the other data, and ignores the missing data (returns NULL, doesn't return anything, not important)
In any case, I need to get the Customers and Project data, even if the query can't find an entry in the Vacations table. How would I do this? I pretty new to SQL and couldn't find a similar question on this site
EDIT: I'm using SQL Server, currently using HeidiSQL
Try below query:
SELECT * FROM dbo.Customers, dbo.Projects
left join dbo.Vacations on dbo.Projects.HDContactID = dbo.Vacations.HDContactID
WHERE ($Phone = dbo.Customers.Phone)
AND dbo.Customers.CustomerID = dbo.Projects.CustomerID
Use left join as mentioned by #Flying Thunder,
Example of the left join:
SELECT country.country_name_eng, city.city_name, customer.customer_name
FROM customer
LEFT JOIN city ON customer.city_id = city.id
LEFT JOIN country ON city.country_id = country.id;
You can find a nice guide for the joins and SQL here:
https://www.sqlshack.com/learn-sql-join-multiple-tables/
You should be using LEFT JOIN. In fact, you should never be using commas in the FROM clause. That is just archaic syntax and closes the powerful world of JOINs from your queries.
I also recommend using table aliases that are abbreviations of table names. The best are abbreviations for the table names:
SELECT *
FROM dbo.Customers c LEFT JOIN
dbo.Projects p
ON c.CustomerID = p.CustomerID LEFT JOIN
dbo.Vacations v
ON p.HDContactID = v.HDContactID
WHERE c.Phone = $Phone;
Have you try this to skip vacation record if not present like this:
SELECT * FROM dbo.Customers, dbo.Projects, dbo.Vacations
WHERE ($Phone = dbo.Customers.Phone)
AND dbo.Customers.CustomerID = dbo.Projects.CustomerID
AND (dbo.Vacations.HDContactID IS NULL OR dbo.Projects.HDContactID = dbo.Vacations.HDContactID)
This is task table:
This is user table:
I want to select user tasks.
I would give from backend ("given_to_user) id.
But The thing is I want that SELECTED data would have usernames instead of Id which is (created_by_user and given_to_user).
SELECTED table would look like this.
Example:
How to achieve what I want?
Or maybe I designed poorly my tables that It is difficult to select data I need? :)
task table has to id values that are foreign keys to user table.
I tried many thinks but couldn't get desired result.
You did not design poorly the tables.
In fact this is common practice to store the ids that reference columns in other tables. You just need to learn to implement joins:
SELECT
task.id, task.title, task.information, user.usename AS created_by, user2.usename AS given_to
FROM
(task INNER JOIN user ON task.created_by_user = user.id)
INNER JOIN user AS user2 ON task.created_by_user = user2.id;
Do you just want two joins?
select t.*, uc.username as created_by_username,
ug.username as given_to_username
from task t left join
users uc
on t.created_by_user = uc.id left join
users ug
on t.given_to_user = ug.id;
This uses left join in case one of the user ids is missing.
I am trying to do a query on three different tables.
The variable table
The variable table carries information about what "area", "rounds" and
"days" the variable belongs to. The variable table also holds a pk column.
The pk is used to determine which variable a record belongs to.
The area table
The area table carries information about the "name" of the area as well as
the "role" the area belongs to. A user is assigned a role and then has
access to specific areas.
The record table
The record table carries information about the record that was entered. It
contains the "value", "alarmed", and "alarmType" columns. You can search
for a record based on the variable, round and day.
I am trying to query all of the variables in a certain round and day for a user.
I want to display all the variables whether or not there is a record found. Currently I have a query that only returns the variables that have records, but not the ones that don't.
If there is no record then thevalue, alarmed, and alarmType column should be null.
This is the query that I have so far constructed:
SELECT DISTINCT variable.name, area.name AS "areaName", variable.pk, CAST(record.value AS TEXT) AS "value", record.alarmed, record.alarmType
FROM variable, area, record
WHERE variable.round LIKE '%,1,%'
AND variable.day LIKE '%,3,%'
AND variable.readOnly = 0
AND variable.area IN (SELECT pk
FROM area
WHERE role = (SELECT role
FROM user
WHERE userName LIKE 'Leo'))
AND variable.area = area.pk
AND record.value = (SELECT CASE WHEN COUNT() < 1 THEN NULL
ELSE CAST(value AS TEXT) END
FROM record
WHERE round = 1
AND day = "11-14-2018"
AND variable = variable.pk)
ORDER BY variable.area, variable.position ASC;
Currently it returns something like this:
There are a lot more variables and I want to know how to display them even if there are no records.
I think I see what you're trying to do. The key is using joins (specifically OUTER joins) instead of trying to mash all the tables together and then find similarities. There are also LEFT, RIGHT and INNER flavors (read more about these here and here), depending on what you consider the "complete" or "master" data set - the starting point of your query.
Here's how I understand your relationships (let me know if I have this wrong):
record.variable --> variable.pk
variable.area --> area.pk
area.role --> user.role
In your case, you stated that you need all records from the variable table, so I would start with this:
SELECT v.*
FROM variable v;
Then, you might find all the AREA records related to a particular USER. Use an INNER join to find only records that exist on BOTH sides of the join:
SELECT a.*, u.*
FROM area a
INNER JOIN user u -- Define the table to join
ON a.role = u.role -- Which columns contain keys to match on
WHERE u.userName = 'Leo';
The WHERE filter applies to the user table, but because we are ONLY asking for records from the area table that have a match with user, then that limits the results from the area table.
The next step is to join these two extracts together using another INNER join, again, to find the intersection - matches that exist on BOTH sides of the join(s):
SELECT v.*, a.*, u.*
FROM variable v -- New starting point
INNER JOIN area a
ON a.pk = v.area
INNER JOIN user u
ON a.role = u.role
WHERE u.userName = 'Leo';
Now, we find all the records for a certain day by adding WHERE clauses:
SELECT v.*, a.*, u.*
FROM variable v
INNER JOIN area a
ON a.pk = v.area
INNER JOIN user u
ON a.role = u.role
WHERE u.userName = 'Leo'
AND v.round = 1 -- Add filters for "round"
AND v.day = '11-14-2018'; -- and "day" columns
Next, we use a LEFT join to give us all the records from the table on the "left" plus any matches we find on the "right" side (the "record" table) or NULL if no match is made:
SELECT v.name
,a.name as "areaName"
,CAST(r.value as TEXT) as "value"
,r.alarmed
,r.alarmType
FROM variable v
INNER JOIN area a
ON v.area = a.pk
INNER JOIN user u
ON a.role = u.role
LEFT JOIN record r -- LEFT is important here
ON v.pk = r.variable
WHERE u.userName = 'Leo'
AND v.round = 1
AND v.day = '11-14-2018'
ORDER BY v.area, v.position;
The result from INNER joins (variable + area + user) becomes the "left" side of this join, and the record becomes the "right" side. Using the LEFT join declares that we want ALL records from the left, whether they have a match on the right or not.
I don't have a dataset to test this with, so please excuse any errors I've made.
Hopefully, this illustrates how joins would be used to both eliminate rows and add data (columns) the result, without having to make individual queries or resort to sub-queries (using IN or EXISTS).
I have 3 tables; CASES, USERS and USER_META. For this issue you need to know that the USER_META table has 3 columns; user_id, meta_key and meta_value
Each user is associated with many CASES and each USER is associated with many USER_META
My current query is like this
SELECT CASES.*, USERS.*, USER_META.*
FROM CASES
JOIN USERS ON USERS."user_id" = CASES."user_id"
JOIN USER_META ON USER_META_"user_id" = USERS."user_id"
The problem with this approach is that each USER has A LOT of USER_META so my result set has too many rows. How can I rewrite this query so that I can select only the USER_META where the USER_META."meta_key" is equal to a certain value yet still get the result if they do not have this USER_META."meta_key" set yet
For example:
SELECT CASES.*, USERS.*, USER_META.*
FROM CASES
JOIN USERS ON USERS."user_id" = CASES."user_id"
JOIN USER_META ON USER_META_"user_id" = USERS."user_id"
WHERE USER_META."meta_key" = 'my_key'
This would work great but not all users have a value of "my_key" in the "meta_key" column and we still need to view their CASE. For users that do not have the "meta_key" the result should just return the CASE and USER columns.
How can I rewrite this query so it gets the result for both users with this meta_key and without?
Thanks, I hope this makes sense.
I would use a LEFT JOIN
SELECT CASES.*, USERS.*, USER_META.*
FROM CASES
JOIN USERS ON USERS."user_id" = CASES."user_id"
LEFT JOIN USER_META ON USER_META."user_id" = USERS."user_id" AND USER_META."meta_key" = ?
you need to use OUTER JOIN with the table that may have no results. In Oracle, use (+) near to the field name of the join sentence with this table. This link may help you: http://download.oracle.com/docs/cd/B28359_01/server.111/b28286/queries006.htm