So i have a table that has a set of information like this
name Type PRICE
11111 XX 0.001
22222 YY 0.002
33333 ZZ 0.0001
11111 YY 0.021
11111 ZZ 0.0111
77777 YY 0.1
77777 ZZ 1.2
Now these numbers go on for about a million rows and there could be upwards of 20 of the same 'name' mapping to 20 different TYPE. But there will only be 1 unique type per name. What I mean by this is that 11111 could have XX,YY,ZZ on it but it cannot have YY,ZZ,YY on it.
What I need is to get the lowest 3 prices and what TYPE they are per name.
Right now I can get the lowest price per name by doing:
select name, type, min(price) from table group by name;
However that is just for the lowest price but I need the lowest 3 prices. I've been trying for a couple days and I cant seem to get it. All help is appreciated.
Also, please let me know if I forgot any information, i'm still trying to figure out stack overflow :P
Oh and the database is a noSQL that uses SQL syntax.
edit: I can't seem to get the format down for my example data from my table to show correctly
If your database supports window functions, and allowing for the possibility that there may be more than three rows in your data with any of the three lowest prices, this should do it:
select the_table.*
from
the_table
inner join (
select name, price
from (
select name, price, row_number() over(partition by name order by price) as rn
from the_table) as x
where rn < 4
) as y on y.name=the_table.name and y.price=the_table.price;
Related
(this is homework, not going to lie)
I have an ANSI SQL query I wrote
this produces
the required
3rd highest prices correctly,
table sample is
select unique uni, price
from
(
(
select unique uni, price
from
(
select unique uni, price
from table1
group by uni
having price < max(price)
)
group by uni
having price < max(price)
)
group by uni
having price < max(price)
)
now i need to list the 1st, 2nd and 3rd into one table but make is such that it could be used nth times.
example:
Col1 Col2
uni1 10
uni1 20
uni2 20
uni2 10
uni3 30
uni3 20
uni1 30
/sorry for the formatting i havent been here for a very long time, i appreciate any assistance, i will supply a link to the uni of which i have asked the tutor if i can do so he said yes but not the whole code, something like 10%, but anyways./
In SAS you can use the proprietary option OUTOBS to restrict how many rows of a result set are output.
Example:
Use OUTOBS=3 to create top 3 table. Then use that table in a subsequent query.
data have;
input x ##; datalines;
10 9 8 7 6 5 4 3 2 1 0
;
proc sql;
reset outobs=3;
create table top3x as
select * from have
order by x descending;
reset outobs=max;
* another query;
quit;
I have two tables Medication and Inventory. I'm trying to SELECT all the below details from both tables but there are multiple listings of medication ids with different BRANCH_NO also in the INVENTORY table (the primary key in INVENTORY is actually BRANCH_NO, MEDICATION_ID composite key)
I need to total up the various medication_IDs and also join the tables in one SELECT command and display all the infomation for each med (there are 5) with a total sum of each med at the end of each row. But im getting all muddled trying Group by and Sum and at one point partition. Help please I'm new to this.
Below is the latest non working version - but it doesn't display
Medication Name
Medication Desc
Manufacturer
Pack Size
like i chanced it might.
SELECT I.MEDICATION_ID,
SUM(I.STOCK_LEVEL)
FROM INVENTORY I
INNER JOIN (SELECT MEDICATION_NAME, SUBSTR(MEDICATION_DESC,1,20) "Medication Description",
MANUFACTURER, PACK_SIZE FROM MEDICATION) M ON MEDICATION_ID=I.MEDICATION_ID
GROUP BY I.MEDICATION_ID;
For the data imagine I want this sort of output:
MEDICATION_ID MEDICATION_NAME STOCK_LEVEL OtherColumns.....
1 Alpha 10
2 Bravo 20
3 Charlie 20
1 Alpha 30
4 Delta 10
5 Echo 20
5 Echo 40
2 Bravo 10
grouping and totalling into this:
MEDICATION_ID MEDICATION_NAME STOCK_LEVEL OtherColumns.....
1 Alpha 40
2 Bravo 30
3 Charlie 20
4 Delta 10
5 Echo 60
I can get this when its just one table but when Im trying to join tables and also SELECT things its just not working.
Thanks in advance guys. I appreciate it may be a simple solution, but it will be a big help.
You need to write explicitly all non-aggregated columns into both SELECT and GROUP BY lists ( Btw, no need to use a nested query, and if it's the case MEDICATION_ID column is missing in it ) :
SELECT I.MEDICATION_ID, M.MEDICATION_NAME, SUM(I.STOCK_LEVEL) AS STOCK_LEVEL,
SUBSTR(M.MEDICATION_DESC,1,20) "Medication Description", M.MANUFACTURER, M.PACK_SIZE
FROM INVENTORY I
JOIN MEDICATION M ON M.MEDICATION_ID = I.MEDICATION_ID
GROUP BY I.MEDICATION_ID, M.MEDICATION_NAME, SUBSTR(M.MEDICATION_DESC,1,20),
M.MANUFACTURER, M.PACK_SIZE;
This way, you'll be able to return all the listed columns.
I am looking for a way to add up averages in SQL. Here is an example of the data I have:
product avg_price
phone 104.28
car 1000.00
And I'm looking to build something like this:
product avg_price
[all] 544.27
phone 104.28
car 1000.00
The way I'm currently doing it is to store the count and sum in two different columns, such as:
product cnt total
phone 203 20,304.32
car 404 304,323.30
And from that get the average. However, I was wondering if it is possible in SQL to just 'keep the fraction' and be able to add them as needed. For example:
product avg_price
[all] [add the fractions]
phone 20,304.32 / 203
car 304,323.30 / 404
Or do I need to use two columns in order to get an average of multiple aggregated rows?
You don't need 2 columns to get the average, but if you want to display as a fraction then you will need both numbers. They don't need to be in 2 columns though.
select product, sum(total) ||'/'||sum(count)
from table a
join table b on a.product=b.product
union
select product, total ||'/'||count
from table a
join table b on a.product=b.product;
I have a query that collects many different columns, and I want to include a column that sums the price of every component in an order. Right now, I already have a column that simply shows the price of every component of an order, but I am not sure how to create this new column.
I would think that the code would go something like this, but I am not really clear on what an aggregate function is or why I get an error regarding the aggregate function when I try to run this code.
SELECT ID, Location, Price, (SUM(PriceDescription) FROM table GROUP BY ID WHERE PriceDescription LIKE 'Cost.%' AS Summary)
FROM table
When I say each component, I mean that every ID I have has many different items that make up the general price. I only want to find out how much money I spend on my supplies that I need for my pressure washers which is why I said `Where PriceDescription LIKE 'Cost.%'
To further explain, I have receipts of every customer I've worked with and in these receipts I write down my cost for the soap that I use and the tools for the pressure washer that I rent. I label all of these with 'Cost.' so it looks like (Cost.Water), (Cost.Soap), (Cost.Gas), (Cost.Tools) and I would like it so for Order 1 it there's a column that sums all the Cost._ prices for the order and for Order 2 it sums all the Cost._ prices for that order. I should also mention that each Order does not have the same number of Costs (sometimes when I use my power washer I might not have to buy gas and occasionally soap).
I hope this makes sense, if not please let me know how I can explain further.
`ID Location Price PriceDescription
1 Park 10 Cost.Water
1 Park 8 Cost.Gas
1 Park 11 Cost.Soap
2 Tom 20 Cost.Water
2 Tom 6 Cost.Soap
3 Matt 15 Cost.Tools
3 Matt 15 Cost.Gas
3 Matt 21 Cost.Tools
4 College 32 Cost.Gas
4 College 22 Cost.Water
4 College 11 Cost.Tools`
I would like for my query to create a column like such
`ID Location Price Summary
1 Park 10 29
1 Park 8
1 Park 11
2 Tom 20 26
2 Tom 6
3 Matt 15 51
3 Matt 15
3 Matt 21
4 College 32 65
4 College 22
4 College 11 `
But if the 'Summary' was printed on every line instead of just at the top one, that would be okay too.
You just require sum(Price) over(Partition by Location) will give total sum as below:
SELECT ID, Location, Price, SUM(Price) over(Partition by Location) AS Summed_Price
FROM yourtable
WHERE PriceDescription LIKE 'Cost.%'
First, if your Price column really contains values that match 'Cost.%', then you can not apply SUM() over it. SUM() expects a number (e.g. INT, FLOAT, REAL or DECIMAL). If it is text then you need to explicitly convert it to a number by adding a CAST or CONVERT clause inside the SUM() call.
Second, your query syntax is wrong: you need GROUP BY, and the SELECT fields are not specified correctly. And you want to SUM() the Price field, not the PriceDescription field (which you can't even sum as I explained)
Assuming that Price is numeric (see my first remark), then this is how it can be done:
SELECT ID
, Location
, Price
, (SELECT SUM(Price)
FROM table
WHERE ID = T1.ID AND Location = T1.Location
) AS Summed_Price
FROM table AS T1
to get exact result like posted in question
Select
T.ID,
T.Location,
T.Price,
CASE WHEN (R) = 1 then RN ELSE NULL END Summary
from (
select
ID,
Location,
Price ,
SUM(Price)OVER(PARTITION BY Location)RN,
ROW_number()OVER(PARTITION BY Location ORDER BY ID )R
from Table
)T
order by T.ID
i have table that store questions each question have different answers and each answer have different weight and now i want to Calculation the rank but i don't now how do this.please help me
i use sql server
i have this table stored answers and weight of each answer
AdminQuesAns
=======================
Id QuesId Ans Value
10 1000 Yes 10
11 1000 somewhat 5
12 1000 No 0
10 1001 Yes 0
12 1001 No 10
and this table store Customer answers
AdminRank
==================================
Id SDId QuesId AnsValue
1 100 1000 10
2 100 1001 0
You can use the below query.
1.
Select SDId ,b.QuesId,
((sum(a.AnsValue) *100)/(Select sum(c.value)
from AdminQuesAns c where c.QuesId =b.QuesId))as'Rank'
from AdminRank a join AdminQuesAns b on a.QuesId=b.QuesId and value=AnsValue
group by SDId ,b.QuesId
This is how I'd go about it.
This has an inner query which gets the max value for each question, then the outer query pairs those with the values from the individual answers, sums across the questions and calculates one as a percentage of the other.
I'm also grouping by SDId, on the assumption that that is the ID of the person filling out the survey.
SELECT
ar.SDId,
100 * cast(sum(ar.AnsValue) as numeric(5,2)) / sum(mv.maxValue) as Rank
FROM
AdminRank ar
JOIN
(
SELECT
qa.QuesId,
max(qa.Value) as maxValue
FROM
AdminQuesAns qa
GROUP BY
qa.QuesId
) mv on ar.QuesId = mv.QuesId
GROUP BY
ar.SDId
Depending on your data types you may be able to remove the cast part.