I have a query that collects many different columns, and I want to include a column that sums the price of every component in an order. Right now, I already have a column that simply shows the price of every component of an order, but I am not sure how to create this new column.
I would think that the code would go something like this, but I am not really clear on what an aggregate function is or why I get an error regarding the aggregate function when I try to run this code.
SELECT ID, Location, Price, (SUM(PriceDescription) FROM table GROUP BY ID WHERE PriceDescription LIKE 'Cost.%' AS Summary)
FROM table
When I say each component, I mean that every ID I have has many different items that make up the general price. I only want to find out how much money I spend on my supplies that I need for my pressure washers which is why I said `Where PriceDescription LIKE 'Cost.%'
To further explain, I have receipts of every customer I've worked with and in these receipts I write down my cost for the soap that I use and the tools for the pressure washer that I rent. I label all of these with 'Cost.' so it looks like (Cost.Water), (Cost.Soap), (Cost.Gas), (Cost.Tools) and I would like it so for Order 1 it there's a column that sums all the Cost._ prices for the order and for Order 2 it sums all the Cost._ prices for that order. I should also mention that each Order does not have the same number of Costs (sometimes when I use my power washer I might not have to buy gas and occasionally soap).
I hope this makes sense, if not please let me know how I can explain further.
`ID Location Price PriceDescription
1 Park 10 Cost.Water
1 Park 8 Cost.Gas
1 Park 11 Cost.Soap
2 Tom 20 Cost.Water
2 Tom 6 Cost.Soap
3 Matt 15 Cost.Tools
3 Matt 15 Cost.Gas
3 Matt 21 Cost.Tools
4 College 32 Cost.Gas
4 College 22 Cost.Water
4 College 11 Cost.Tools`
I would like for my query to create a column like such
`ID Location Price Summary
1 Park 10 29
1 Park 8
1 Park 11
2 Tom 20 26
2 Tom 6
3 Matt 15 51
3 Matt 15
3 Matt 21
4 College 32 65
4 College 22
4 College 11 `
But if the 'Summary' was printed on every line instead of just at the top one, that would be okay too.
You just require sum(Price) over(Partition by Location) will give total sum as below:
SELECT ID, Location, Price, SUM(Price) over(Partition by Location) AS Summed_Price
FROM yourtable
WHERE PriceDescription LIKE 'Cost.%'
First, if your Price column really contains values that match 'Cost.%', then you can not apply SUM() over it. SUM() expects a number (e.g. INT, FLOAT, REAL or DECIMAL). If it is text then you need to explicitly convert it to a number by adding a CAST or CONVERT clause inside the SUM() call.
Second, your query syntax is wrong: you need GROUP BY, and the SELECT fields are not specified correctly. And you want to SUM() the Price field, not the PriceDescription field (which you can't even sum as I explained)
Assuming that Price is numeric (see my first remark), then this is how it can be done:
SELECT ID
, Location
, Price
, (SELECT SUM(Price)
FROM table
WHERE ID = T1.ID AND Location = T1.Location
) AS Summed_Price
FROM table AS T1
to get exact result like posted in question
Select
T.ID,
T.Location,
T.Price,
CASE WHEN (R) = 1 then RN ELSE NULL END Summary
from (
select
ID,
Location,
Price ,
SUM(Price)OVER(PARTITION BY Location)RN,
ROW_number()OVER(PARTITION BY Location ORDER BY ID )R
from Table
)T
order by T.ID
Related
I have two tables Medication and Inventory. I'm trying to SELECT all the below details from both tables but there are multiple listings of medication ids with different BRANCH_NO also in the INVENTORY table (the primary key in INVENTORY is actually BRANCH_NO, MEDICATION_ID composite key)
I need to total up the various medication_IDs and also join the tables in one SELECT command and display all the infomation for each med (there are 5) with a total sum of each med at the end of each row. But im getting all muddled trying Group by and Sum and at one point partition. Help please I'm new to this.
Below is the latest non working version - but it doesn't display
Medication Name
Medication Desc
Manufacturer
Pack Size
like i chanced it might.
SELECT I.MEDICATION_ID,
SUM(I.STOCK_LEVEL)
FROM INVENTORY I
INNER JOIN (SELECT MEDICATION_NAME, SUBSTR(MEDICATION_DESC,1,20) "Medication Description",
MANUFACTURER, PACK_SIZE FROM MEDICATION) M ON MEDICATION_ID=I.MEDICATION_ID
GROUP BY I.MEDICATION_ID;
For the data imagine I want this sort of output:
MEDICATION_ID MEDICATION_NAME STOCK_LEVEL OtherColumns.....
1 Alpha 10
2 Bravo 20
3 Charlie 20
1 Alpha 30
4 Delta 10
5 Echo 20
5 Echo 40
2 Bravo 10
grouping and totalling into this:
MEDICATION_ID MEDICATION_NAME STOCK_LEVEL OtherColumns.....
1 Alpha 40
2 Bravo 30
3 Charlie 20
4 Delta 10
5 Echo 60
I can get this when its just one table but when Im trying to join tables and also SELECT things its just not working.
Thanks in advance guys. I appreciate it may be a simple solution, but it will be a big help.
You need to write explicitly all non-aggregated columns into both SELECT and GROUP BY lists ( Btw, no need to use a nested query, and if it's the case MEDICATION_ID column is missing in it ) :
SELECT I.MEDICATION_ID, M.MEDICATION_NAME, SUM(I.STOCK_LEVEL) AS STOCK_LEVEL,
SUBSTR(M.MEDICATION_DESC,1,20) "Medication Description", M.MANUFACTURER, M.PACK_SIZE
FROM INVENTORY I
JOIN MEDICATION M ON M.MEDICATION_ID = I.MEDICATION_ID
GROUP BY I.MEDICATION_ID, M.MEDICATION_NAME, SUBSTR(M.MEDICATION_DESC,1,20),
M.MANUFACTURER, M.PACK_SIZE;
This way, you'll be able to return all the listed columns.
I want to add 1 more columns where segment out whether the customer had sold at least one product or not.
Data example:
ProductID Customer Status
1 John Not sold
2 John Not Sold
3 John Sold
My expect result
ProductID Customer Status Sold_at_least_1
1 John Not sold Yes
2 John Not Sold Yes
3 John Sold Yes
4 Andrew Not Sold No
5 Andrew Not Sold No
6 Brandon Sold Yes
This is an example data. Sorry for any inconvenience as I unable to extract data out. Btw, appreciating for any helps.
You can do a window count of records of the same customer that have status = 'Sold' in a case expression:
select
t.*,
case when sum( (status = 'Sold')::int ) over(partition by customer) >= 1
then 'Yes'
else 'No'
end
from mytable
NB: note that this does not magically create new records (as shown in your sample data). This query gives you as many records in the resultset as there are in the table, with an additionnal column that indicates whether each cutsomer has at least one sold item in the table.
Here is a demo provided by VBokšić (thanks).
Another option is to use bool_or() as a window function. If you can live with a boolean column rather than a varchar with Yes/No, this makes the expression even simpler:
select productid, customer, status,
bool_or(status = 'Sold') over (partition by customer) as sold_at_least_one
from mytable;
Online example: https://rextester.com/NDN54253
So i have a table that has a set of information like this
name Type PRICE
11111 XX 0.001
22222 YY 0.002
33333 ZZ 0.0001
11111 YY 0.021
11111 ZZ 0.0111
77777 YY 0.1
77777 ZZ 1.2
Now these numbers go on for about a million rows and there could be upwards of 20 of the same 'name' mapping to 20 different TYPE. But there will only be 1 unique type per name. What I mean by this is that 11111 could have XX,YY,ZZ on it but it cannot have YY,ZZ,YY on it.
What I need is to get the lowest 3 prices and what TYPE they are per name.
Right now I can get the lowest price per name by doing:
select name, type, min(price) from table group by name;
However that is just for the lowest price but I need the lowest 3 prices. I've been trying for a couple days and I cant seem to get it. All help is appreciated.
Also, please let me know if I forgot any information, i'm still trying to figure out stack overflow :P
Oh and the database is a noSQL that uses SQL syntax.
edit: I can't seem to get the format down for my example data from my table to show correctly
If your database supports window functions, and allowing for the possibility that there may be more than three rows in your data with any of the three lowest prices, this should do it:
select the_table.*
from
the_table
inner join (
select name, price
from (
select name, price, row_number() over(partition by name order by price) as rn
from the_table) as x
where rn < 4
) as y on y.name=the_table.name and y.price=the_table.price;
Here's the situation. I created a view that has all the following information
CREATE VIEW view2 AS
SELECT activity_id,
subject_code,
academic_period_code,
DATEDIFF(HOUR,time_start,time_end) AS duration
FROM activity
Okay, now I'm trying to make a query that can produce two columns,
1. one with subject code and the academic_period code concatenated into one column
2. The second column contains the total number of duration for each subject that is in that academic period
So its like: CS123 in academic_period 121 has total of 5 hours activity. I'm fine with the first column but I've been wondering how do I get the 2nd column. If I use the SUM function it just totals up the column itself so I'm not sure how to deal with this.
Sample data
Subject Code Activity_code Academic_Period_Code Duration
CS123 1 121 2
CS123 2 121 3
CS123 3 122 2
CS123 4 122 2
What I have done?]
SELECT subject_code + academic_period_code AS subject,
(I think I have to do a subquery but I'm not sure how its suppose to work out) AS total_activity_time
FROM view2
Assuming SQL Server and that I understand what you are looking for:
select
subject_code + academic_period_code as [Type],
sum(duration) as duration
from view2
group by
subject_code + academic_period_code;
should get you where I think you're trying to get.
select
subject_code + academic_period_code as subjects,
sum(duration) as duration
from view2
group by
subject_code, academic_period_code;
I have a following query. It uses only one table (Customers) from Northwind database.
I completely have no idea how does it work, and what its intention is. I hope there is a lot of DBAs here so I ask for explanation. particularly don't know what the OVER and PARTITION does here.
WITH NumberedWomen AS
(
SELECT CustomerId ,ROW_NUMBER() OVER
(
PARTITION BY c.Country
ORDER BY LEN(c.CompanyName) ASC
)
women
FROM Customers c
)
SELECT * FROM NumberedWomen WHERE women > 3
If you needed the db schema, it is here
This function:
ROW_NUMBER() OVER (PARTITION BY c.Country ORDER BY LEN(c.CompanyName) ASC)
assigns continuous row numbers to records within each country, ordering the records by LEN(companyName).
If you have these data:
country companyName
US Apple
US Google
UK BAT
UK BP
US GM
, then the query will assign numbers from 1 and 3 to the US companies and 1 to 2 to UK companies, ordering them by the name length:
country companyName ROW_NUMBER()
US GM 1
US Apple 2
US Google 3
UK BP 1
UK BAT 2
ROW_NUMBER() is a ranking function.
OVER tells it how to create rank numbers.
PARTITION BY [expression] tells the ROW_NUMBER function to restart ranking whenever [expression] contains a new value
In your case, for every country, a series of numbers starting with 1 is created. Within a country, the Companies are ordered by the length of their name (shorter name = lower rank).
The final query:
SELECT * FROM NumberedWomen WHERE women > 3
selects all customers except if the company-country combination is part of one of the companies with the 3 shortest names in the same country.