I have a database that contains columns that are text fields (strings, a few sentences long) and columns that are shorter strings (eg: college majors). Is there any way I can use the 'LIKE' function in SQL to search whether one of the values of the College Major column appears in another column?
I don't want to write out each of the college majors as a string since there are over 100.
Yes you can. Something like
where bigdatacolumn like '%' + computer_major + '%'
Since you said, other column contains few lines (Text column), you probably want to consider using Full Text Search instead of using LIKE operator
Use The ANY operator to compare in an array as shown in the below query.
select * from staff where department ILIKE ANY ( ARRAY['AUT%', '%COM%' ,'SP%' ] :: TEXT[] );
Related
I have table
raw TABLE
=========
id class_ids
------------------------
1 1234,12334,12341,1228
2 12281,12341,12283
3 1234,34221,31233,43434,1123
How to define regex to select raws if class_ids contains special id.
If we select raws with '1234' in class_ids result list should not contain raws with '12341' in class_ids.
IDs in column class_ids separated with ,
SELECT FROM raw re WHERE re.class_ids LIKE (regex)
You shouldn't be storing comma separated values in a single column.
However, this is better done using string_to_array() in Postgres instead of a regex:
SELECT *
FROM raw
WHERE '1234'= any(string_to_array(class_ids, ','));
If you really want to de-normalize your data, it's better to store those numbers in a proper integer array, instead of comma separated list of strings
A simple way uses like:
where ',' || re.class_ids || ',' like '%,1234,%'
However, this is not the real issue. You should not be storing lists of ids in a string. The SQLish way of storing them would have a table with one row per id and one row per class_id. This is called a junction table.
Even if you don't use a separate table, you should at least use Postgres's built-in mechanisms, such as an array. However, a separate table is much the preferred method, because you can explicitly declare foreign key relationships.
If you really want to do this with regular expressions, you can use the ~ operator:
SELECT FROM raw re WHERE re.class_ids ~ '^(^|,)1234(,|$)$';
But I prefer a_horse_with_no_name's answer that uses arrays.
I have a list of 100 words that I need to do a pattern match on 55 Million rows of data. Is there a way to create a list of words and pass the list through the REGEXP_LIKE function, instead of using the | (or) statement multiple times, can a list be input instead?
Search *
From table
Where REGEXP_LIKE(C1, 'wordlword2letc...', 'i');
You cannot pass a list of words as pattern in REGEXP_LIKE.
pattern is the regular expression and usually is text literal and cannot be more than 512 bytes.
What you can possibly do is, store the words you're trying to search in separate table/column and then use LIKE condition in your query as you're just trying to search for the occurrence of the words and not expecting regular expression search support.
So, if there is a table/column (new_table.col) which stores your input items to search for, your query might look like (using UPPER function to ensure case insensitive search as you were trying) -
SELECT a.* FROM table a, new_table b WHERE UPPER(a.col1) LIKE UPPER(b.col);
I would like to ask if it is possible to do this:
For example the search string is '009' -> (consider the digits as string)
is it possible to have a query that will return any occurrences of this on the database not considering the order.
for this example it will return
'009'
'090'
'900'
given these exists on the database. thanks!!!!
Use the Like operator.
For Example :-
SELECT Marks FROM Report WHERE Marks LIKE '%009%' OR '%090%' OR '%900%'
Split the string into individual characters, select all rows containing the first character and put them in a temporary table, then select all rows from the temporary table that contain the second character and put these in a temporary table, then select all rows from that temporary table that contain the third character.
Of course, there are probably many ways to optimize this, but I see no reason why it would not be possible to make a query like that work.
It can not be achieved in a straight forward way as there is no sort() function for a particular value like there is lower(), upper() functions.
But there is some workarounds like -
Suppose you are running query for COL A, maintain another column SORTED_A where from application level you keep the sorted value of COL A
Then when you execute query - sort the searchToken and run select query with matching sorted searchToken with the SORTED_A column
I need to find the '&' in a string.
SELECT * FROM TABLE WHERE FIELD LIKE ..&...
Things we have tried :
SELECT * FROM TABLE WHERE FIELD LIKE '&&&'
SELECT * FROM TABLE WHERE FIELD LIKE '&\&&'
SELECT * FROM TABLE WHERE FIELD LIKE '&|&&' escape '|'
SELECT * FROM TABLE WHERE FIELD LIKE '&[&]&'
None of these give any results in SQLServer.
Well some give all rows, some give none.
Similar questions that didn't work or were not specific enough.
Find the % character in a LIKE query
How to detect if a string contains special characters?
some old reference Server 2000
http://web.archive.org/web/20150519072547/http://sqlserver2000.databases.aspfaq.com:80/how-do-i-search-for-special-characters-e-g-in-sql-server.html
& isn't a wildcard in SQL, therefore no escaping is needed.
Use % around the value your looking for.
SELECT * FROM TABLE WHERE FIELD LIKE '%&%'
Your statement contains no wildcards, thus is equivalent to WHERE FIELD = '&'.
& isn't a special character in SQL so it doesn't need to be escaped. Just write
WHERE FIELD LIKE '%&%'
to search for entries that contain & somewhere in the field
Be aware though, that this will result in a full table scan as the server can't use any indexes. Had you typed WHERE FIELD LIKE '&%' the server could do a range seek to find all entries starting with &.
If you have a lot of data and can't add any more constraints, you should consider using SQL Server's full-text search to create and use and FTS index, with predicates like CONTAINS or FREETEXT
How to retrieve a column containing special characters including alphabets in SQL Query. i have a column like this 'abc%def'. i want to retrieve '%' based columns from that table.
Please help me in this regard.
Is abc%def the column name? or column value? Not sure what you are asking but if you mean your column name contains special character then you can escape them which would be different based on specific RDBMS you are using
SQL Server use []
select [abc%def] from tab
MySQL use backquote
select `abc%def` from tab
EDIT:
Try like below to fetch column value containing % character (Checked, it works in Ingres as well)
select * from tab where col like '%%%'
Others suggest that like '%%%' works in Ingres. So this is something special in Ingres. It does not work in other dbms.
In standard SQL you would have to declare an escape character. I think this should work in Ingres, too.
select * from mytable where str like '%!%%' escape '!';