Adding value to column depending on LIKE - sql

Question

I have SSMS 2008 R2. This is my table
PK | DateOf | Other Columns | Items
01 | 05/30/2017 15:30 | Blah | truck, elephant, apple, . . .
02 | 04/15/2012 07:07 | Bluh | foot, orange, horse, . . .
03 | 11/01/2016 10:30 | Wham | apple, screen, penny, . . .
I am trying to search the Items column for each record and count how many times the fruits occur. Conveniently enough, there will only be a single fruit for each record, but it would be cool if the solution would be able to handle several fruits (maybe even duplicates). The result table would look like this for the above
Count | Fruit
2 | Apple
1 | Orange
I have a complete list of the "fruits". I was trying to figure out how to make it work with LIKE's.
SELECT
count(PK) AS [Count]
??? AS [Fruit]
WHERE DateOf >= '2011-01-01 00:00' AND DateOf < '2012-01-01 00:00'
AND Items LIKE '%Apple%' --??(some kind of code that looks for the fruit values??)

Answer 1

This is the wrong way to store lists. But, sometimes we are stuck with other people's really bad design decisions.
In this case, you want a split() function. SQL Server 2016 offers one. You can also find code for one on the web (Google "SQL Server split string"):
SELECT ss.fruit, count(*) AS [Count]
FROM t CROSS APPLY
string_split(t.items) ss(fruit)
WHERE DateOf >= '2011-01-01' AND DateOf < '2012-01-01'
GROUP BY ss.fruit;

Answer 2

You can use a simple outer apply to identify fruits if you have table with fruits. Like this:
drop table if exists dbo.Details;
drop table if exists dbo.Fruits;
create table dbo.Details (
PK int not null primary key
, DateOf datetime2(3)
, Items varchar(100)
);
create table dbo.Fruits (
Fruit varchar(100) not null primary key
);
insert into dbo.Details (PK, DateOf, Items)
values (1, '20170530 15:30', 'truck, elephant, apple, . . .')
, (2, '20120415 07:07', 'foot, orange, horse, . . .')
, (3, '20161101 10:30', 'apple, screen, penny, orange, . . .')
insert into dbo.Fruits (Fruit)
values ('apple'), ('orange');
select
d.PK, d.DateOf, d.Items, count(*) as CountOfFruit
from dbo.Details d
outer apply (
select
*
from dbo.Fruits f
where d.Items like '%' + f.Fruit + '%'
) tf
group by d.PK, d.DateOf, d.Items

Answer 3

Try this it may helps you
IF OBJECT_ID('Tempdb..#Temp') IS NOT NULL
DROP TABLE #Temp
DECLARE #SearchWords nvarchar(max)='Apple,Orange'
DECLARE #Table TABLE (SearchWords nvarchar(max))
INSERT INTO #Table
SELECT #SearchWords
;With cte_Search
AS
(
SELECT ROW_NUMBER()OVER(ORDER BY (SELECT 1) )AS Seq,
Split.a.value('.', 'VARCHAR(1000)') AS SearchWords
FROM (
SELECT
CAST('<S>' + REPLACE(SearchWords, ',', '</S><S>') + '</S>' AS XML) AS SearchWords
FROM #Table
) AS A
CROSS APPLY SearchWords.nodes('/S') AS Split(a)
)
SELECT * INTO #Temp FROM cte_Search
;With CTE (PK , DateOf , OtherColumns , Items)
AS
(
SELECT 01 , '05/30/2017 15:30' ,'Blah', 'truck, elephant, apple'UNION ALL
SELECT 02 , '04/15/2012 07:07' ,'Bluh', 'foot, orange, horse' UNION ALL
SELECT 03 , '11/01/2016 10:30' ,'Wham', 'apple, screen, penny'
)
SELECT SearchWords AS Fruit,
MAX(Seq) AS CountOFFruits FROM
(
SELECT C.OtherColumns,
t.SearchWords,
C.Items,
COUNT(C.Items) CntItems,
ROW_NUMBER()OVER(Partition by t.SearchWords order by C.OtherColumns ) AS Seq
FROM CTE c ,#Temp t
WHERE CHARINDEX(t.SearchWords,c.Items) >0
Group by C.OtherColumns,t.SearchWords,C.Items
)dt
Group by SearchWords
Result
Fruit CountOFFruits
----------------------
Apple 2
Orange 1