Get last two entries of each account in table - sql

Question

I've got script that gives me all transactions for day for all accounts and sub accounts. His return you can see on the image. What I want, is return result as two last transactions for each accountId and subaccountId. Ideal return would be:
AccountId| SubAccountId| AmountInDay | Date
---------------------------------------------
210 | 1 | 0.00 |2017-06-20 00:00:00.000
210 | 1 | 0.00 |2017-06-05 00:00:00.000
1234 | 1 | 0.00 |2017-06-20 00:00:00.000
1234 | 1 | 0.00 |2017-06-05 00:00:00.000
This is the code of my script:
with CTE1 as
(
select top 2 AccountId, SubAccountId, [Date], sum(Amount_Amount) as Amount
from dbo.PayoutInstallment
group by accountId, SubAccountId, [Date]
)
, CTE2 as
(
select AccountId,SubAccountId, Amount_Amount, [Date],
dense_rank() over (partition by AccountId order by [Date] desc) as rn
from dbo.PayoutInstallment
)
select a1.AccountId,a1.SubAccountId, Sum(a1.Amount_Amount) as AmountInDay, a1.[Date]
from CTE2 a1
left join CTE2 a2
on a1.AccountId = a2.AccountId and a1.[Date] > a2.[Date]
and a2.rn = a1.rn+1
group by a1.[Date], a1.AccountId, a1.SubAccountId
order by a1.[Date] desc
EDIT
Sample Data
AccountId| SubAccountId| AmountInDay | Date
---------------------------------------------
210 | 1 | 0.00 |2017-03-15 00:00:00.000
210 | 1 | 0.00 |2017-04-20 00:00:00.000
210 | 1 | 100.00 |2017-05-17 00:00:00.000
210 | 1 | 1.00 |2017-06-05 00:00:00.000
210 | 1 | 1.00 |2017-06-05 00:00:00.000
1234 | 1 | 0.00 |2017-06-05 00:00:00.000
1234 | 1 | 0.00 |2017-06-05 00:00:00.000
1234 | 1 | 1.00 |2017-06-10 00:00:00.000
1234 | 1 | 1.00 |2017-04-10 00:00:00.000

Answer 1

I think you can use row_number and get 2 records as below:
Select * from (
Select AccountId, SubAccountId, [Date], sum(Amount_Amount) over (partition by accountid, SubAccountId, [Date])
,RowN = Row_number() over (partition by accountid, SubAccountId, [Date] order by [date] desc)
from dbo.PayoutInstallment
) a where a.RowN <= 2

Answer 2

Assume one day one transaction,
;WITH cte AS(SELECT *
, ROW_NUMBER() OVER (PARTITION BY AccountId, SubAccountId ORDER BY [Date] DESC) AS Rownum
FROM PayoutInstallment
)
SELECT *
, SUM(AmountInDay) OVER (PARTITION BY AccountId, SubAccountId) AS SumLast2days
FROM cte
WHERE Rownum<=2

Answer 3

If you want the SUM for the last two day you need to assign a number to each day. Then bring all the data related to those days by JOIN both dataset and then perform a GROUP BY
WITH cte as (
SELECT AccountId, SubAccountId, [Date],
ROW_NUMBER() OVER (PARTITION BY AccountId, SubAccountId
ORDER BY [Date] DESC) AS rn
FROM dbo.PayoutInstallment
)
SELECT P.AccountId,
P.SubAccountId,
P.[Date],
SUM(ammount)
FROM dbo.PayoutInstallment P
JOIN cte C
ON P.[Date] = C.[Date]
AND P.AccountId = C.AccountId
AND P.SubAccountId = C.SubAccountId
WHERE rn <= 2 -- Just the last day of each account, subacount
GROUP BY P.AccountId,
P.SubAccountId,
P.[Date]

Answer 4

I see you are using GROUP BY, so if you want the results to be sorted after the grouping, you should use HAVING if you want otherwise you should use WHERE. Here is an example of a WHERE clause you can use in your query to get only results between the last two days.
WHERE (a1.[Date] BETWEEN GETDATE()AND GETDATE()-2)