My table has records like below:
ID EmpID EffectiveDate PayElement Amount ComputeType AddDeduction
42 ISIPL001 2010-04-16 00:00:00.000 Basic 8000.00 On Attendance Addition
43 ISIPL001 2010-04-01 00:00:00.000 Con 2000.00 On Attendance Addition
44 ISIPL001 2010-04-01 00:00:00.000 HRA 2000.00 On Attendance Addition
54 ISIPL001 2011-01-01 00:00:00.000 Basic 15000.00 On Attendance Addition
55 ISIPL001 2011-01-01 00:00:00.000 Con 6000.00 On Attendance Addition
57 ISIPL001 2011-01-01 00:00:00.000 HRA 6000.00 On Attendance Addition
61 ISIPL001 2010-07-10 00:00:00.000 Basic 12000.00 On Attendance Addition
66 ISIPL001 2010-07-10 00:00:00.000 HRA 4200.00 On Attendance Addition
68 ISIPL001 2010-07-10 00:00:00.000 Con 5600.00 On Attendance Addition
I want the result display below:
i.e for each pay element available in my database, I need to record which is having maximum date for each pay element.
So my output should be like given below:
54 Basic 15000
55 Con 6000
57 HRA 6000
Try this:
SELECT ID,
PayElement,
Amount
FROM (
SELECT a.*,
RANK() OVER(PARTITION BY PayElement ORDER BY EffectiveDate DESC) AS rn
FROM <YOUR_TABLE> a
) a
WHERE rn = 1
;with cte as
(
select *,
row_number() over(partition by PayElement order by EffectiveDate desc) as rn
from YourTable
)
select
ID,
PayElement,
Amount
from cte
where rn = 1
Try this.
select
T.ID,
T.PayElement,
T.Amount
from
Test T inner join (select MAX(T_DATE.EffectiveDate) as MAX_DATE, T_DATE.PayElement from Test T_DATE group by T_DATE.PayElement) T_DATE on (T.PayElement = T_DATE.PayElement) and (T.EffectiveDate = T_DATE.MAX_DATE)
order by
T.ID
Select a.Id,
a.PayElement,
a.Amount
From dbo.YourTable a
Join
(
Select PayElement,
Max(EffectiveDate) as[MaxDate]
From dbo.YourTable
Group By PayElement
)b on a.PayElement = b.PayElement
And a.EffectiveDate = b.MaxDate
try something like
Select
a.ID, a.PayElement, a.Amount
From MyTable a
Inner Join (
Select PayElement, max(EffectiveDate) as MaxDate From MyTable Group By PayElement
) sub on a.EffectiveDate = sub.MaxDate and a.PayElement = sub.PayElement
select
Id, PayElement, Amount
from
YourTable a
inner join
(select
Id, PayElement, max(EffectiveDate) as EffectiveDate
from
YourTable
group by
PayElement, Id) b
on
a.Id = b.Id
Related
I have a table as follows
Date
Id
Group
Name
ScoreCount
2022-06-20
1
Athlete
Adam
52
2022-06-23
1
Athlete
Adam
77
2022-06-25
1
Athlete
Adam
79
2022-06-19
1
Employee
Adam
65
2022-06-22
1
Employee
Adam
28
I'd like this for the dates to be added for each individual id and type of group. So it should look something like:
Date
Id
Group
Name
ScoreCount
2022-06-20
1
Athlete
Adam
52
2022-06-21
1
Athlete
Adam
52
2022-06-22
1
Athlete
Adam
52
2022-06-23
1
Athlete
Adam
77
2022-06-24
1
Athlete
Adam
77
2022-06-25
1
Athlete
Adam
79
2022-06-19
1
Employee
Adam
65
2022-06-20
1
Employee
Adam
65
2022-06-21
1
Employee
Adam
65
2022-06-22
1
Employee
Adam
28
My code is as follows:
WITH t as (SELECT
Id,
Group,
Name,
min(Date) as MinDate
max(Date) as MaxDate
FROM recordTable
GROUP BY Id,Group,Name
SELECT t.Id,
t.Group,
t.Name,
c.Days,
(SELECT LAST_VALUE(ScoreCount) FROM recordTable WHERE t.Id = recordTable.Id AND t.Group = recordTable.Group)
FROM t
LEFT JOIN calendar c ON c.Days BETWEEN t.MinDate AND t.MaxDate
calendar is the table that contains individual dates for the year 2022, so they can be joined. Everything works, except for the ScoreCount, which Last_Value isn't actually doing what I want it to do. How can I fix this?
You can simply try reversing the order of your joined tables -
WITH t as (SELECT Id,
Group,
Name,
min(Date) as MinDate,
max(Date) as MaxDate
FROM recordTable
GROUP BY Id,Group,Name
)
SELECT t.Id,
t.Group,
t.Name,
c.Days,
(SELECT LAST_VALUE(ScoreCount) OVER(<your over clause is missing>)
FROM recordTable
WHERE t.Id = recordTable.Id
AND t.Group = recordTable.Group)
FROM calendar c
LEFT JOIN t ON c.Days BETWEEN t.MinDate AND t.MaxDate
Although I have not tested the query yet this will give you an idea to proceed further.
You don't need the last_value, you can get the first value
WITH t as (
SELECT
[Id],
[Group],
[Name],
min([Date]) as MinDate,
max([Date]) as MaxDate
FROM recordTable
GROUP BY [Id],[Group],[Name]
)
SELECT
t.Id,
t.[Group],
t.[Name],
c.[Date],
(SELECT top 1 ScoreCount
from recordTable x
where x.[Date] <= c.[Days]
and x.[Group] = t.[Group]
and x.[Name] = t.[Name]
order by x.[Date] desc
) ScoreCount
FROM t
LEFT JOIN calendar c ON c.[Days] BETWEEN t.MinDate AND t.MaxDate
I have a table that specifies exactly what date and time each employee was in a particular office.
EmployeeTable looks like this:
id
EmployeeID
DateP
TimeP
1
11111
1397/01/02
01:30
2
11111
1398/05/09
05:30
3
11111
1398/06/07
05:10
4
22222
1398/08/09
06:12
5
22222
1399/02/01
07:15
6
11111
1399/07/02
08:51
7
11111
1399/08/06
12:20
8
33333
1399/09/04
20:01
9
33333
1399/12/08
22:05
10
33333
1400/01/01
23:11
11
33333
1400/02/05
14:10
12
22222
1400/04/05
16:25
I want exactly select Min and Max date and time for each Employee when present in a office:
id
EmployeeID
MinDateP
TimeMinDateP
MaxDateP
TimeMaxDateP
1
11111
1397/01/02
01:30
1398/06/07
05:10
2
22222
1398/08/09
06:12
1399/02/01
07:15
3
11111
1399/07/02
08:51
1399/08/06
12:20
4
33333
1399/09/04
20:01
1400/02/05
14:10
5
22222
1400/04/05
16:25
1400/04/05
16:25
My SQL code is:
with tab1 as
(
select *
from EmployeeTable
), tab2 as
(
select
t1.*,
case when lag(t1.EmployeeID) over(order by t1.id) is null then 1
when lag(t1.EmployeeID) over(order by t1.id) = t1.EmployeeID then 0
else 1
end lg
from tab1 t1
)
, tab3 as (
select t1.*,
sum(t1.lg) over(order by t1.id) grp
from tab2 t1
)
select t1.EmployeeID,
min(t1.DateP) as min,
TimeP,
max(t1.DateP)as max,
TimeP
from tab3 t1
group by t1.EmployeeID, t1.grp
But above codes has error.
Can every body help me?
This is a gaps and islands problem. One approach to solve this uses the difference in row numbers method:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (ORDER BY DateP, TimeP) rn1,
ROW_NUMBER() OVER (PARTITION BY EmployeeID ORDER BY DateP, TimeP) rn2
FROM EmployeeTable
),
cte2 AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY EmployeeID, rn1 - rn2
ORDER BY DateP, TimeP) rn_first,
ROW_NUMBER() OVER (PARTITION BY EmployeeID, rn1 - rn2
ORDER BY DateP DESC, TimeP DESC) rn_last
FROM cte
)
SELECT
EmployeeID,
MAX(CASE WHEN rn_first = 1 THEN DateP END) AS MinDateP,
MAX(CASE WHEN rn_first = 1 THEN TimeP END) AS TimeMinDateP,
MAX(CASE WHEN rn_last = 1 THEN DateP END) AS MaxDateP,
MAX(CASE WHEN rn_last = 1 THEN TimeP END ) AS TimeMaxDateP
FROM cte2
GROUP BY
EmployeeID,
rn1 - rn2
ORDER BY
MIN(DateP),
MIN(TimeP);
Note that the logic in the second CTE would be totally unnecessary if you were using a single datetime column to represent the date and time. It is usually not beneficial to separate date and time as you are currently doing.
I have 2 tables:
NDEvent:
EventId EndTime
33 2020-10-23 15:00:00.000
33 2020-10-23 15:00:00.000
35 2020-10-21 03:30:00.000
35 2020-10-24 15:00:00.000
35 2020-10-25 15:00:00.000
34 2020-10-23 15:00:00.000
EventAppointment:
Id DocId EventId Amount
1 7647 34 10.00
2 7647 34 10.00
3 28531 33 20.00
4 7647 35 20.00
5 7647 35 100.00
6 7647 35 200.00
And I want result to be like this:
DocId EventId Amount Id
7647 34 20.00 1,2
28531 33 20.00 3
7647 35 320.00 4,5,6
What I have tried is:
select e.Amount,e.DoctorId,e.EventId,
Id= STUFF(
(SELECT DISTINCT ',' + CAST(e.Id as nvarchar(max))
from NDEvent nd
inner join EventAppointment e on nd.Id = e.EventId
where
GETDATE() > nd.EndTime
GROUP BY
e.Amount,e.DoctorId,e.EventId,e.Id
FOR XML PATH(''))
, 1, 1, ''
)
from NDEvent nd
inner join EventAppointment e on nd.Id = e.EventId
where
GETDATE() > nd.EndTime
GROUP BY
e.Amount,e.DoctorId,e.EventId
But it is not giving expected result.
Could anyone help with this query? Or point me to a right direction? Thank you.
It doesn't look like yo need to NDEvent table here at all (though I include it in the sample data). Just SUM and STRING_AGG against EventAppointment:
USE Sandbox
GO
WITH NDEvent AS(
SELECT *
FROM (VALUES(33,CONVERT(datetime,'2020-10-23T15:00:00.000')),
(33,CONVERT(datetime,'2020-10-23T15:00:00.000')),
(35,CONVERT(datetime,'2020-10-21T03:30:00.000')),
(35,CONVERT(datetime,'2020-10-24T15:00:00.000')),
(35,CONVERT(datetime,'2020-10-25T15:00:00.000')),
(34,CONVERT(datetime,'2020-10-23T15:00:00.000')))V(EventID,EndTime)),
EventAppointment AS(
SELECT *
FROM (VALUES(1,7647 ,34,10.00),
(2,7647 ,34,10.00),
(3,28531,33,20.00),
(4,7647 ,35,20.00),
(5,7647 ,35,100.00),
(6,7647 ,35,200.00))V(Id,DocId, EventID, Amount))
SELECT DocID,
EventID,
SUM(Amount) AS Amount,
STRING_AGG(Id,',') WITHIN GROUP (ORDER BY Id) AS IDs
FROM EventAppointment EA
GROUP BY DocId,
EventID;
Can be used in other data.
WITH Table1 AS(
SELECT EventId FROM NDEvent
GROUP BY EventId
),
Table2 AS(
SELECT e.DocId,e.EventId,e.Amount,
STUFF((
SELECT ',' + CAST(ee.Id as nvarchar)
FROM EventAppointment ee
where ee.EventId = e.EventId
GROUP BY ee.EventId,ee.Id
FOR XML PATH('')), 1, 1, '') AS Id
FROM Table1 t
LEFT OUTER JOIN EventAppointment e ON t.EventId = e.EventId
)
SELECT DocId,EventId,SUM(Amount) AS Amount,Id FROM Table2
GROUP BY DocId,EventId,Id
I need to get member personal data for all our members whose subscriptions have lapsed i.e. have a subscription end date before 31/03/2020, however I want to show one member record only (distinct by membership number) ideally the most recent one
I've tried a ROW_NUMBER() solution SQL - Distinct One Col, Select Multiple other? and a cross apply solution sql distinct, getting 2 columns but I can't get it to work.
SELECT membershipnumber AS Id,
subscription.enddate
FROM [dbo].[userprofile]
INNER JOIN dbo.subscription
ON userprofile.id = subscription.userprofileid
INNER JOIN dbo.subscriptiontype
ON subscriptiontype.id = subscription.subscriptiontypeid
Output is
Id Enddate
1 2006-04-01 00:00:00.000
1 2001-04-01 00:00:00.000
1 1999-04-01 00:00:00.000
1 1998-04-01 00:00:00.000
1 2008-04-01 00:00:00.000
1 2007-04-01 00:00:00.000
1 2011-04-01 00:00:00.000
1 2005-04-01 00:00:00.000
1 2000-04-01 00:00:00.000
1 1997-04-01 00:00:00.000
2 1999-04-01 00:00:00.000
2 2012-04-01 00:00:00.000
2 2004-04-01 00:00:00.000
2 2001-04-01 00:00:00.000
2 2018-04-01 00:00:00.000
2 2009-04-01 00:00:00.000
2 2005-04-01 00:00:00.000
2 1997-04-01 00:00:00.000
Desired output
Id Enddate
1 2011-04-01 00:00:00.000
2 2018-04-01 00:00:00.000
Solved sql answer
;WITH cte
AS (SELECT membershipnumber AS Id,
subscription.enddate,
Row_number()
OVER (
partition BY membershipnumber
ORDER BY subscription.enddate DESC) AS rownumber
FROM [dbo].[userprofile]
INNER JOIN dbo.subscription
ON userprofile.id = subscription.userprofileid
INNER JOIN dbo.subscriptiontype
ON subscriptiontype.id = subscription.subscriptiontypeid
)
SELECT *
FROM cte
WHERE rownumber = 1
https://stackoverflow.com/a/6841644/5859743
Not sure if I got your question right.
but you can use DISTINCT in the SELECT, that would show only one record for each member.
SELECT DISTINCT Membershipnumber as Id
,'P' as PartyType
,'A' as Status
,case
when Name = 'Standard Membership paid annually.' and EndDate > '2020-03-31' then 'Member'
when Name = 'Lapsed subscription renewal' and EndDate > '2020-03-31' then 'Member'
when Name = '3 Year Subscription (members outside of UK and Ireland, Jersey, Guernsey and the Channel Islands)' and EndDate > '2020-03-31' then 'Overseas member'
when Name = '1 Year Subscription (members outside of UK and Ireland, Jersey, Guernsey and the Channel Islands).' and EndDate > '2020-03-31' then 'Overseas member'
when Name = 'Lapsed subscription renewal' and EndDate > '2020-03-31' then 'Member'
when Name = 'Lifetime membership' then 'Lifetime member'
when Name = 'Retired membership paid annually' and EndDate > '2020-03-31' then 'Retired member'
else 'Non member'
end As MemberType
,Title as NamePrefix
,FirstName as FirstName
,Surname as LastName
,DateOfBirth as BirthDate
,'Home' as AddressPurpose
,'Default' as CommunicationReasons
,AddressLine1
,AddressLine2
,AddressLine3
,Addressline4 as CityName
,'' as CountrySubEntityName
,Country as CountryCode
,'' as CountryName
,Postcode as PostalCode
,EmailAddress as Email
FROM [dbo].[UserProfile]
inner join dbo.Subscription on
UserProfile.Id = Subscription.UserProfileId
inner join dbo.SubscriptionType on
SubscriptionType.id = Subscription.SubscriptionTypeId```
If you are getting as above mentioned output. Then from that, your desired output will easily get using distinct.
; with cte as (
----- query which gives you above mentioned output
)
select distinct id, max(Enddate) as Enddate from cte
I suspect you want something like this:
select *
from (select . . ., -- all the columns you want
row_number() over (partition by Membershipnumber as Id order by s.Enddate) as seqnum
from [dbo].[UserProfile] up inner join
dbo.Subscription s
on up.Id = s.UserProfileId inner join
dbo.SubscriptionType st
on st.id = s.SubscriptionTypeId
) x
where seqnum = 1;
I've got script that gives me all transactions for day for all accounts and sub accounts. His return you can see on the image. What I want, is return result as two last transactions for each accountId and subaccountId. Ideal return would be:
AccountId| SubAccountId| AmountInDay | Date
---------------------------------------------
210 | 1 | 0.00 |2017-06-20 00:00:00.000
210 | 1 | 0.00 |2017-06-05 00:00:00.000
1234 | 1 | 0.00 |2017-06-20 00:00:00.000
1234 | 1 | 0.00 |2017-06-05 00:00:00.000
This is the code of my script:
with CTE1 as
(
select top 2 AccountId, SubAccountId, [Date], sum(Amount_Amount) as Amount
from dbo.PayoutInstallment
group by accountId, SubAccountId, [Date]
)
, CTE2 as
(
select AccountId,SubAccountId, Amount_Amount, [Date],
dense_rank() over (partition by AccountId order by [Date] desc) as rn
from dbo.PayoutInstallment
)
select a1.AccountId,a1.SubAccountId, Sum(a1.Amount_Amount) as AmountInDay, a1.[Date]
from CTE2 a1
left join CTE2 a2
on a1.AccountId = a2.AccountId and a1.[Date] > a2.[Date]
and a2.rn = a1.rn+1
group by a1.[Date], a1.AccountId, a1.SubAccountId
order by a1.[Date] desc
EDIT
Sample Data
AccountId| SubAccountId| AmountInDay | Date
---------------------------------------------
210 | 1 | 0.00 |2017-03-15 00:00:00.000
210 | 1 | 0.00 |2017-04-20 00:00:00.000
210 | 1 | 100.00 |2017-05-17 00:00:00.000
210 | 1 | 1.00 |2017-06-05 00:00:00.000
210 | 1 | 1.00 |2017-06-05 00:00:00.000
1234 | 1 | 0.00 |2017-06-05 00:00:00.000
1234 | 1 | 0.00 |2017-06-05 00:00:00.000
1234 | 1 | 1.00 |2017-06-10 00:00:00.000
1234 | 1 | 1.00 |2017-04-10 00:00:00.000
I think you can use row_number and get 2 records as below:
Select * from (
Select AccountId, SubAccountId, [Date], sum(Amount_Amount) over (partition by accountid, SubAccountId, [Date])
,RowN = Row_number() over (partition by accountid, SubAccountId, [Date] order by [date] desc)
from dbo.PayoutInstallment
) a where a.RowN <= 2
Assume one day one transaction,
;WITH cte AS(SELECT *
, ROW_NUMBER() OVER (PARTITION BY AccountId, SubAccountId ORDER BY [Date] DESC) AS Rownum
FROM PayoutInstallment
)
SELECT *
, SUM(AmountInDay) OVER (PARTITION BY AccountId, SubAccountId) AS SumLast2days
FROM cte
WHERE Rownum<=2
If you want the SUM for the last two day you need to assign a number to each day. Then bring all the data related to those days by JOIN both dataset and then perform a GROUP BY
WITH cte as (
SELECT AccountId, SubAccountId, [Date],
ROW_NUMBER() OVER (PARTITION BY AccountId, SubAccountId
ORDER BY [Date] DESC) AS rn
FROM dbo.PayoutInstallment
)
SELECT P.AccountId,
P.SubAccountId,
P.[Date],
SUM(ammount)
FROM dbo.PayoutInstallment P
JOIN cte C
ON P.[Date] = C.[Date]
AND P.AccountId = C.AccountId
AND P.SubAccountId = C.SubAccountId
WHERE rn <= 2 -- Just the last day of each account, subacount
GROUP BY P.AccountId,
P.SubAccountId,
P.[Date]
I see you are using GROUP BY, so if you want the results to be sorted after the grouping, you should use HAVING if you want otherwise you should use WHERE. Here is an example of a WHERE clause you can use in your query to get only results between the last two days.
WHERE (a1.[Date] BETWEEN GETDATE()AND GETDATE()-2)