Not Getting Latest date's using date parameter - sql

This is my query.
AND PTP.END_DATE = (Select MAX(END_DATE) FROM PAY_TIME_PERIODS WHERE END_DATE <=:to_date)-- Parameter
I'm trying to get latest end date from table but not getting all persons latest dates getting only few persons only.
If you have any Idea please help me

This is probably not the best way to write the query, but you don't provide much information.
Your subquery would seem to need a correlation clause:
PTP.END_DATE = (SELECT MAX(END_DATE)
FROM PAY_TIME_PERIODS PTP2
WHERE PTP2.?? = PTP.?? AND END_DATE <=:to_date
)-- Parameter
The ?? is for whatever column identifies a person in your table.

Related

get the latest records

I am currently still on my SQL educational journey and need some help!
The query I have is as below;
SELECT
Audit_Non_Conformance_Records.kf_ID_Client_Reference_Number,
Audit_Non_Conformance_Records.TimeStamp_Creation,
Audit_Non_Conformance_Records.Clause,
Audit_Non_Conformance_Records.NC_type,
Audit_Non_Conformance_Records.NC_Rect_Received,
Audit_Non_Conformance_Records.Audit_Num
FROM Audit_Non_Conformance_Records
I am trying to tweak this to show only the most recent results based on Audit_Non_Conformance_Records.TimeStamp_Creation
I have tried using MAX() but all this does is shows the latest date for all records.
basically the results of the above give me this;
But I only need the result with the date 02/10/2019 as this is the latest result. There may be multiple results however. So for example if 02/10/2019 had never happened I would need all of the idividual recirds from the 14/10/2019 ones.
Does that make any sense at all?
You can filter with a subquery:
SELECT
kf_ID_Client_Reference_Number,
TimeStamp_Creation,
Clause,
NC_type,
NC_Rect_Received,
Audit_Num
FROM Audit_Non_Conformance_Records a
where TimeStamp_Creation = (
select max(TimeStamp_Creation)
from Audit_Non_Conformance_Records
)
This will give you all whose TimeStamp_Creation is equal to the greater value available in the table.
If you want all records that have the greatest day (exluding time), then you can do:
SELECT
kf_ID_Client_Reference_Number,
TimeStamp_Creation,
Clause,
NC_type,
NC_Rect_Received,
Audit_Num
FROM Audit_Non_Conformance_Records a
where cast(TimeStamp_Creation as date) = (
select cast(max(TimeStamp_Creation) as date)
from Audit_Non_Conformance_Records
)
Edit
If you want the latest record per refNumber, then you can correlate the subquery, like so:
SELECT
kf_ID_Client_Reference_Number,
TimeStamp_Creation,
Clause,
NC_type,
NC_Rect_Received,
Audit_Num
FROM Audit_Non_Conformance_Records a
where TimeStamp_Creation = (
select max(TimeStamp_Creation)
from Audit_Non_Conformance_Records a1
where a1.refNumber = a.refNumber
)
For performance, you want an index on (refNumber, TimeStamp_Creation).
If you want the latest date in SQL Server, you can express this as:
SELECT TOP (1) WITH TIES ancr.kf_ID_Client_Reference_Number,
ancr.TimeStamp_Creation,
ancr.Clause,
ancr.NC_type,
ancr.NC_Rect_Received,
ancr.Audit_Num
FROM Audit_Non_Conformance_Records ancr
ORDER BY CONVERT(date, ancr.TimeStamp_Creation) DESC;
SQL Server is pretty good about handling dates with conversions, so I would not be surprised if this used an index on TimeStamp_Creation.

Get Max(date) or latest date with 2 conditions or group by or subquery

I only have basic SQL skills. I'm working in SQL in Navicat. I've looked through the threads of people who were also trying to get latest date, but not yet been able to apply it to my situation.
I am trying to get the latest date for each name, for each chemical. I think of it this way: "Within each chemical, look at data for each name, choose the most recent one."
I have tried using max(date(date)) but it needs to be nested or subqueried within chemical.
I also tried ranking by date(date) DESC, then using LIMIT 1. But I was not able to nest this within chemical either.
When I try to write it as a subquery, I keep getting an error on the ( . I've switched it up so that I am beginning the subquery a number of different ways, but the error returns near that area always.
Here is what the data looks like:
1
Here is one of my failed queries:
SELECT
WELL_NAME,
CHEMICAL,
RESULT,
APPROX_LAT,
APPROX_LONG,
DATE
FROM
data_all
ORDER BY
CHEMICAL ASC,
date( date ) DESC (
SELECT
WELL_NAME,
CHEMICAL,
APPROX_LAT,
APPROX_LONG,
DATE
FROM
data_all
WHERE
WELL_NAME = WELL_NAME
AND CHEMICAL = CHEMICAL
AND APPROX_LAT = APPROX_LAT
AND APPROX_LONG = APPROX_LONG,
LIMIT 2
)
If someone does have a response, it would be great if it is in as lay language as possible. I've only had one coding class. Thanks very much.
Maybe something like this?
SELECT WELL_NAME, CHEMICAL, MAX(DATE)
FROM data_all
GROUP BY WELL_NAME, CHEMICAL
If you want all information, then use the ANSI-standard ROW_NUMBER():
SELECT da.*
FROM (SELECT da.*
ROW_NUMBER() OVER (PARTITION BY chemical, name ORDER BY date DESC) as senum
FROM data_all da
) da
WHERE seqnum = 1;

How to select within the closest thing to Y in SAS as a starting point

So I have a dataset where I want to select the closest records to point X for my output,
What I have is
PROC SQL ;
create table Check_vs_Excel2 as
SELECT PROPERTY, START_DATE, END_DATE, DAY_OF_WEEK, MARKET_CODE_PREFIX, RATE_PGM, ROOM_POOL, QUOTE_SERIES_NO, QUOTE_POSITION
FROM Sbtddraf.Vssmauditdraftfull
group by Property, RATE_PGM
having START_DATE = MAX(START_DATE);
quit;
I want to take the START_DATE = Max(Start_DATE); and change it to something which is (effectively)
having START_DATE = close to(TODAY())
Advice would be much appreciated
In SQL your query would be using a Correlated Subquery:
SELECT PROPERTY, START_DATE, END_DATE, DAY_OF_WEEK, MARKET_CODE_PREFIX, RATE_PGM, ROOM_POOL, QUOTE_SERIES_NO, QUOTE_POSITION
FROM Sbtddraf.Vssmauditdraftfull AS t
-- group by Property, RATE_PGM
WHERE START_DATE =
( select MAX(START_DATE)
FROM Sbtddraf.Vssmauditdraftfull AS t2
where t1.Property = t2.Property
and t1.RATE_PGM = t2.RATE_PGM
)
how close is 'close to'? This might be what you are looking for
where START_DATE between TODAY() and DATE_ADD(TODAY(),INTERVAL 30 DAY)
Assuming I understand that you want the row that has the minimum absolute difference between start_date and today() (so, MIN(ABS(START_DATE-TODAY()))), you can do a somewhat messy query using the having clause this way:
data have;
do id = 2 to 9;
do start_date = '02MAR2016'd to '31MAR2016'd by id;
output;
end;
end;
run;
proc sql;
select id, start_date format=date9.
from have
group by id
having abs(start_date-today()) = min(abs(start_date-today()));
quit;
I don't like this in part because it's non-standard SQL and gives a note about re-merging data (it's non-standard and gives you that note because you're using a value that's not really available in a group by), and in part because it gives you multiple rows if two are tied (see id=4 if you run this on 3/16/2016).
A correlated subquery version, which at least avoids the remerging note (but actually does effectively the same thing):
proc sql;
select id, start_date format=date9.
from have H
where abs(start_date-today()) = (
select min(abs(start_date-today()))
from have V
where H.id=V.id
);
quit;
Still gives two for id=4 though (on 3/16/2016). You'd have to make a way to pick if there are possibly two answers (or perhaps you want strictly less than?). This does a subquery to determine what the smallest difference is then returns it.

SQL: Getting the latest date using Max() while using group by

I'm struggling to get the correct result with this query:
select max(kts.my_date), kts.name
join ktt on ktt.someId = kts.someOtherId
where ktt.someId = 'example'
group by kts.name;
I have two (possibly stupid) questions:
Will this max() take time into account? I know that order by does if the dates are the same. Does max do the same?
This is connected to my previous question, but when I run the query above, if the dates are same, it orders it by the name. I want the latest date at the top. Do I need to put an order by clause for the date in? If so, using Max is pointless, right?
Thanks for the help.
Yes,
--2
select max(kts.my_date) over (partition by kts.name) as maxdate, kts.name
from -- chose your table
join ktt on ktt.someId = kts.someOtherId
where ktt.someId = 'example'
order by --chose here your column
give this a try

SQL merging result sets on a unique column value

I have 2 similar queries which both work on the same table, and I essentially want to combine their results such that the second query supplies default values for what the first query doesn't return. I've simplified the problem as much as possible here. I'm using Oracle btw.
The table has account information in it for a number of accounts, and there are multiple entries for each account with a commit_date to tell when the account information was inserted. I need get the account info which was current for a certain date.
The queries take a list of account ids and a date.
Here is the query:
-- Select the row which was current for the accounts for the given date. (won't return anything for an account which didn't exist for the given date)
SELECT actr.*
FROM Account_Information actr
WHERE actr.account_id in (30000316, 30000350, 30000351)
AND actr.commit_date <= to_date( '2010-DEC-30','YYYY-MON-DD ')
AND actr.commit_date =
(
SELECT MAX(actrInner.commit_date)
FROM Account_Information actrInner
WHERE actrInner.account_id = actr.account_id
AND actrInner.commit_date <= to_date( '2010-DEC-30','YYYY-MON-DD ')
)
This looks a little ugly, but it returns a single row for each account which was current for the given date. The problem is that it doesn't return anything if the account didn't exist until after the given date.
Selecting the earliest account info for each account is trival - I don't need to supply a date for this one:
-- Select the earliest row for the accounts.
SELECT actr.*
FROM Account_Information actr
WHERE actr.account_id in (30000316, 30000350, 30000351)
AND actr.commit_date =
(
SELECT MAX(actrInner .commit_date)
FROM Account_Information actrInner
WHERE actrInner .account_id = actr.account_id
)
But I want to merge the result sets in such a way that:
For each account, if there is account info for it in the first result set - use that.
Otherwise, use the account info from the second result set.
I've researched all of the joins I can use without success. Unions almost do it but they will only merge for unique rows. I want to merge based on the account id in each row.
Sql Merging two result sets - my case is obviously more complicated than that
SQL to return a merged set of results - I might be able to adapt that technique? I'm a programmer being forced to write SQL and I can't quite follow that example well enough to see how I could modify it for what I need.
The standard way to do this is with a left outer join and coalesce. That is, your overall query will look like this:
SELECT ...
FROM defaultQuery
LEFT OUTER JOIN currentQuery ON ...
If you did a SELECT *, each row would correspond to the current account data plus your defaults. With me so far?
Now, instead of SELECT *, for each column you want to return, you do a COALESCE() on matched pairs of columns:
SELECT COALESCE(currentQuery.columnA, defaultQuery.columnA) ...
This will choose the current account data if present, otherwise it will choose the default data.
You can do this more directly using analytic functions:
select *
from (SELECT actr.*, max(commit_date) over (partition by account_id) as maxCommitDate,
max(case when commit_date <= to_date( '2010-DEC-30','YYYY-MON-DD ') then commit_date end) over
(partition by account_id) as MaxCommitDate2
FROM Account_Information actr
WHERE actr.account_id in (30000316, 30000350, 30000351)
) t
where (MaxCommitDate2 is not null and Commit_date = MaxCommitDate2) or
(MaxCommitDate2 is null and Commit_Date = MaxCommitDate)
The subquery calculates two values, the two possibilities of commit dates. The where clause then chooses the appropriate row, using the logic that you want.
I've combined the other answers. Tried it out at apex.oracle.com. Here's some explanation.
MAX(CASE WHEN commit_date <= to_date('2010-DEC-30', 'YYYY-MON-DD')) will give us the latest date not before Dec 30th, or NULL if there isn't one. Combining that with a COALESCE, we get
COALESCE(MAX(CASE WHEN commit_date <= to_date('2010-DEC-30', 'YYYY-MON-DD') THEN commit_date END), MAX(commit_date)).
Now we take the account id and commit date we have and join them with the original table to get all the other fields. Here's the whole query that I came up with:
SELECT *
FROM Account_Information
JOIN (SELECT account_id,
COALESCE(MAX(CASE WHEN commit_date <=
to_date('2010-DEC-30', 'YYYY-MON-DD')
THEN commit_date END),
MAX(commit_date)) AS commit_date
FROM Account_Information
WHERE account_id in (30000316, 30000350, 30000351)
GROUP BY account_id)
USING (account_id, commit_date);
Note that if you do use USING, you have to use * instead of acrt.*.