I have a table with Ids and a subId column. And I have a user defined data type with a list of SubIds. I want all those ids which have all the sub-ids present in my user-defined data type. for example:
The table is:
ID SubID
1 2
1 3
1 4
2 3
2 4
2 2
3 3
3 2
and the data type is
CREATE TYPE SubIds AS TABLE
( SubId INT );
GO
With Value
SubID
3
4
I want the output to be
ID
1
2
Because only the ID 1 and 2 contain both the subIds 3 & 4
Note: the combination of Id and Sub ID will always be unique if its of any use
Let's assume that #s is your table of ids:
select t.ID
from t
Where t.SubId in (select SubId from #s)
group by t.Id
having count(*) = (select count(*) from #s);
This assumes that the two tables do not have duplicates. If duplicates are present, you can use:
select t.ID
from t
Where t.SubId in (select SubId from #s)
group by t.Id
having count(distinct t.SubId) = (select count(distinct s.SubId) from #s s);
Try this way
select ID
from yourtable
Where SubID in (3,4)
Group by ID
having Count(distinct SubID)=2
Another more flexible approach
select ID
from yourtable
Group by ID
having sum(case when SubID = 3 then 1 else 0 end) >= 1
and sum(case when SubID = 4 then 1 else 0 end) >= 1
If you want to pull SubId's from SubIds table type then,
SELECT ID
FROM yourtable T
JOIN (SELECT SubID,
Count(1) OVER() AS cnt
FROM SubIds) S
ON T.SubID = S.SubID
GROUP BY ID,Cnt
HAVING Count(DISTINCT T.SubID) = s.cnt
Related
I want to select only those ID‘s which are in specific groups.
For example:
ID GroupID
1 11
1 12
2 11
2 12
2 13
Here I want to select the ID's which are in the groups 11 and 12 but in no other groups.
So the result should show just the ID 1 and not 2.
Can someone provide a SQL for that?
I tried it with
SELECT ID FROM table
WHERE GroupID = 11 AND GroupID = 12 AND GroupID != 13;
But that didn't work.
You can use aggregation:
select id
from mytable
group by id
having min(groupID) = 11 and max(groupID) = 12
This having condition ensures that the given id belongs to groupIDs 11 and 12, and to no other group. This works because 11 and 12 are sequential numbers.
Other options: if you want ids that belong to group 11 or 12 (not necessarily both), and to no other group, then:
having sum(case when groupId in (11, 12) then 1 end) = count(*)
If numbers are not sequential, and you want ids in both groups (necessarily) and in no other group:
having
max(case when groupID = 11 then 1 end) = 1
and max(case when groupID = 12 then 1 end) = 1
and max(case when groupID in (11, 12) then 0 else 1 end) = 0
SELECT t.id FROM table t
where exists(
SELECT * FROM table
where group = 11
and t.id = id
)
and exists(
SELECT * FROM table
where group = 12
and t.id = id
)
and not exists(
SELECT * FROM table
where group = 13
and t.id = id
)
group by t.id
One method is conditional aggregation:
select id
from t
group by id
having sum(case when groupid = 1 then 1 else 0 end) > 0 and
sum(case when groupid = 2 then 1 else 0 end) > 0 and
sum(case when groupid in (1, 2) then 1 else 0 end) = 0 ;
You can use GROUP BY with HAVING and a conditional COUNT:
SELECT id
FROM table_name
GROUP BY ID
HAVING COUNT( CASE Group_ID WHEN 11 THEN 1 END ) > 0
AND COUNT( CASE Group_ID WHEN 12 THEN 1 END ) > 0
AND COUNT( CASE WHEN Group_ID NOT IN ( 11, 12 ) THEN 1 END ) = 0
Or you can use collections:
CREATE TYPE int_list IS TABLE OF NUMBER(8,0);
and:
SELECT id
FROM table_name
GROUP BY id
HAVING int_list( 11, 12 ) SUBMULTISET OF CAST( COLLECT( group_id ) AS int_list )
AND CARDINALITY( CAST( COLLECT( group_id ) AS int_list )
MULTISET EXCEPT int_list( 11, 12 ) ) = 0
(Using collections has the advantage that you can pass the collection of required values as a single bind parameter whereas using conditional aggregation is probably going to require dynamic SQL if you want to pass a variable number of items to the query.)
Both output:
| ID |
| -: |
| 1 |
db<>fiddle here
Use joins:
SELECT DISTINCT c11.ID
FROM (SELECT ID FROM WORK_TABLE WHERE GROUPID = 11) c11
INNER JOIN (SELECT ID FROM WORK_TABLE WHERE GROUPID = 12) c12
ON c12.ID = c11.ID
LEFT OUTER JOIN (SELECT ID FROM WORK_TABLE WHERE GROUPID NOT IN (11, 12)) co
ON co.ID = c11.ID
WHERE co.ID IS NULL;
The INNER JOIN between the first two subqueries ensures that rows exist for both GROUPID 11 and 12, and the LEFT OUTER JOIN and WHERE verify that there are no rows for any other GROUPIDs.
dbfiddle here
I need to select data base upon three conditions
Find the latest date (StorageDate Column) from the table for each record
See if there is more then one entry for date (StorageDate Column) found in first step for same ID (ID Column)
and then see if DuplicateID is = 2
So if table has following data:
ID |StorageDate | DuplicateTypeID
1 |2014-10-22 | 1
1 |2014-10-22 | 2
1 |2014-10-18 | 1
2 |2014-10-12 | 1
3 |2014-10-11 | 1
4 |2014-09-02 | 1
4 |2014-09-02 | 2
Then I should get following results
ID
1
4
I have written following query but it is really slow, I was wondering if anyone has better way to write it.
SELECT DISTINCT(TD.RecordID)
FROM dbo.MyTable TD
JOIN (
SELECT T1.RecordID, T2.MaxDate,COUNT(*) AS RecordCount
FROM MyTable T1 WITH (nolock)
JOIN (
SELECT RecordID, MAX(StorageDate) AS MaxDate
FROM MyTable WITH (nolock)
GROUP BY RecordID)T2
ON T1.RecordID = T2.RecordID AND T1.StorageDate = T2.MaxDate
GROUP BY T1.RecordID, T2.MaxDate
HAVING COUNT(*) > 1
)PT ON TD.RecordID = PT.RecordID AND TD.StorageDate = PT.MaxDate
WHERE TD.DuplicateTypeID = 2
Try this and see how the performance goes:
;WITH
tmp AS
(
SELECT *,
RANK() OVER (PARTITION BY ID ORDER BY StorageDate DESC) AS StorageDateRank,
COUNT(ID) OVER (PARTITION BY ID, StorageDate) AS StorageDateCount
FROM MyTable
)
SELECT DISTINCT ID
FROM tmp
WHERE StorageDateRank = 1 -- latest date for each ID
AND StorageDateCount > 1 -- more than 1 entry for date
AND DuplicateTypeID = 2 -- DuplicateTypeID = 2
You can use analytic function rank , can you try this query ?
Select recordId from
(
select *, rank() over ( partition by recordId order by [StorageDate] desc) as rn
from mytable
) T
where rn =1
group by recordId
having count(*) >1
and sum( case when duplicatetypeid =2 then 1 else 0 end) >=1
I'm trying get to find out if a row has the max value in a group. Here's really simple example:
Data
VoteCount LocationId UserId
3 1 1
4 1 2
3 2 2
4 2 1
Pseudo-query
select
LocationId,
sum(case
when UserId = 1 /* and has max vote count*/
then 1 else 0
end) as IsUser1Winner,
sum(case
when UserId = 2 /* and has max vote count*/
then 1 else 0
end) as IsUser2Winner
from LocationVote
group by LocationID
It should return:
LocationId IsUser1Winner IsUser2Winner
1 0 1
2 1 1
I also couldn't find a way to generate dynamic column names here. What would be the simplest way to write this query?
You could also do this using a Case statement
WITH CTE as
(SELECT
MAX(VoteCount) max_votes
, LocationId
FROM LocationResult
group by LocationId
)
SELECT
A.LocationId
, Case When UserId=1
THEN 1
ELSE 0
END IsUser1Winner
, Case when UserId=2
THEn 1
ELSE 0
END IsUser2Winner
from LocationResult A
inner join
CTE B
on A.VoteCount = B.max_votes
and A.LocationId = B.LocationId
Try this:
select *
from table t
cross apply (
select max(votes) max_value
from table ref
where ref.group = t.group
)votes
where votes.max_value = t.votes
but if your table is huge and has no propriate indexes performance may be poor
Another way is to get max values by groups into table variable or temp table and then join it to original table.
In the example table below, I'm trying to figure out a way to sum amount over id for all marks where mark 'C' doesn't exist within an id. When mark 'C' does exist in an id, I want the sum of amounts over that id, excluding the amount against mark 'A'. As illustration, my desired output is at the bottom. I've considered using partitions and the EXISTS command, but I'm having trouble conceptualizing the solution. If any of you could take a look and point me in the right direction, it would be greatly appreciated :)
sample table:
id mark amount
------------------
1 A 1
2 A 3
2 B 2
3 A 2
4 A 1
4 B 3
5 A 1
5 C 3
6 A 2
6 C 2
desired output:
id sum(amount)
-----------------
1 1
2 5
3 2
4 4
5 3
6 2
select
id,
case
when count(case mark when 'C' then 1 else null end) = 0
then
sum(amount)
else
sum(case when mark <> 'A' then amount else 0 end)
end
from sampletable
group by id
Here is my effort:
select id, sum(amount) from table t where not t.id = 'A' group by id
having id in (select id from table t where mark = 'C')
union
select id, sum(amount) from table t where t.id group by id
having id not in (select id from table t where mark = 'C')
SELECT
id,
sum(amount) AS sum_amount
FROM atable t
WHERE mark <> 'A'
OR NOT EXISTS (
SELECT *
FROM atable
WHERE id = t.id
AND mark = 'C'
)
GROUP BY
id
;
I need to GROUP BY item_id and check if user_id in any of those matches a variable. If so, I want it to = 1, if not 0.
for example, imagine table like this:
item_id, user_id
1 1
1 3
2 4
2 1
2 7
2 3
3 4
3 6
4 8
4 1
5 3
IF (user_id = 3,1,0) AS match,
Want my Query to come back as
item_id, match
1 1
2 1
3 0
4 0
5 1
Where "1" all occurrences of user_id 3 in an item_id group.
You need the right aggregation function:
select item_id,
max(case when user_id = 3 then 1 else 0 end) as hasmatch
from t
group by item_id
order by item_id
In MySQL, true is 1 and false is 0, so you can just do:
SELECT item_id, MAX(user_id = 3) AS has_match
FROM table
GROUP BY 1
You can even count the number of matches:
SELECT item_id, SUM(user_id = 3) AS matches
FROM table
GROUP BY 1
GROUP BY 1 is short for GROUP BY item_id, as item_id is the first select expression.
I would do it as follows:
SELECT
A.item_id, ISNULL(B.count, 0)
FROM
(SELECT DISTINCT item_id 'item_id' FROM myTable) AS A
LEFT JOIN
(
SELECT item_id, count(*) 'count'
FROM myTable WHERE user_id IN (3, 1, 0)
GROUP BY item_id
) AS B
ON A.item_id = B.item_id