compare images using systemC - systemc

I wrote in this forum asking for help to solve this problem that took ame a lot of my time,i write my first program using systemC, I will expain my aim as much as I can , I stored 2 matrix of pixel value of image in two different text files, I write a systemC code that load two matrix and apply somme of absolute difference, if number of different superior of a Threshold the code displays message (motion).
My code composed of two modules, the first module check if there a number stored in a text file, if yes this Module will automates the other module to load the two matrix and compare them, I really need this code for my project graduation any help or suggestion.
#include "systemC.h"
#include "string.h"
#include "stdio.h"
#include"stdlib.h"
#include <time.h>
#include <math.h> /* fabs */
#include <fstream>
#include <iostream>
#include <fstream>
using namespace std;
#define _CRT_SECURE_NO_WARNINGS
_CRT_SECURE_NO_WARNINGS
double elapsed;
int H = 0;
int D = 0;
int a, b;
int in = false;
int L = 0;
char *mode1 = "r";
char *mode2 = "w";
int i, j, k;
int rows1, cols1, rows2, cols2;
bool fileFound = false;
FILE *SwitchContext;
FILE *image1;
FILE *image2;
FILE *image3;
int sum = 0;
clock_t start = clock();
SC_MODULE(synchronization)
{
sc_in<bool>sig ;
SC_CTOR(synchronization)
{
SC_METHOD(synchroprocess)
}
void synchroprocess()
{
cout << "\n Running Automation";
SwitchContext = fopen("F:/SWITCH CONTEXT.txt", mode2);
fscanf(SwitchContext, "%d", &L);
while (L != 0)
{
cout << "waiting...";
}
sig == true;
}
};
SC_MODULE(imageProcess)
{
sc_in<bool>sig;
SC_CTOR(imageProcess)
{
SC_METHOD(MotionDetector)
sensitive(sig);
}
void MotionDetector()
{
image3 = fopen("F:/image3.txt", mode2);
do
{
char *mode1 = "r";
char *mode2 = "w";
image1 = fopen("F:/image1.txt", mode1);
if (!image1)
{
printf("File Not Found!!\n");
fileFound = true;
}
else
fileFound = false;
}
while (fileFound);
do
{
image2 = fopen("F:/image2.txt", mode1);
if (!image2)
{
printf("File Not Found!!\n");
fileFound = true;
}
else
fileFound = false;
}
while (fileFound);
rows1 = rows2 = 384;
cols1 = cols2 = 512;
int **mat1 = (int **)malloc(rows1 * sizeof(int*));
for (i = 0; i < rows1; i++)
mat1[i] = (int *)malloc(cols1 * sizeof(int));
i = 0;
int **mat2 = (int **)malloc(rows2 * sizeof(int*));
for (i = 0; i < rows2; i++)
mat2[i] = (int *)malloc(cols2 * sizeof(int));
i = 0;
while (!feof(image1))
{
for (i = 0; i < rows1; i++)
{
for (j = 0; j < cols1; j++)
fscanf(image1, "%d%", &mat1[i][j]);
}
}
i = 0;
j = 0;
while (!feof(image2))
{
for (i = 0; i < rows2; i++)
{
for (j = 0; j < cols2; j++)
fscanf(image2, "%d%", &mat2[i][j]);
}
}
i = 0;
j = 0;
printf("\n\n");
for (i = 0; i < rows1; i++)
{
for (j = 0; j < cols1; j++) {
a = abs(mat1[i][j] = mat2[i][j]);
b = b + a;
}
}
i = j = 0;
D = b / 196608;
if (D > 0.9)
{
printf("%d,&K");
printf("MOTION...DETECTED");
getchar();
sc_pause;
for (i = 0; i < rows1; i++) {
for (j = 0; j < cols1; j++)
{
fprintf(image3, "%d ", mat2[i][j]);
}
fprintf(image3, "\n");
}
printf("\n Image Saved....");
std::ofstream mon_fichier("F:\toto.txt");
mon_fichier << elapsed << '\n';
}
fclose(image1);
fclose(image2);
fclose(image3);
clock_t end = clock();
elapsed = ((double)end - start) / CLOCKS_PER_SEC;
printf("time is %f", elapsed);
}
};
int sc_main(int argc, char* argv[])
{
imageProcess master("EE2");
master.MotionDetector();
sc_start();
return(0);
}

What you did is basically wrong.
You copy pasted code to SC_MODULE, this code is simple C code
(Do not mix C and C++ files)
This is not how you use clock
What you should do:
You need to check if your algorithm works, for this you do not need SystemC at all
Then you can replace data types with HW one and check if it still works
Then you have to find which data interface is used in HW and how to use this interface
Then you have to tweak your alg. to work with this interface (There you can use SC_MODULE, sc ports etc...)
Also take look at SC_CTHREAD, you will need it.
Without any informations about target platform I can not provide any other help.

Related

Access .csv file from a dll

I am trying to access a file inside my DLL, but fopen always returns NULL. I am not very familiar with DLL's and I do not know how to debug this problem. I tried to run my program with executable and it runs without an error. I am posting my .c and .h files below, any help appreciated.
ReadFile1.c:
#include "ReadFile1.h"
#define MAX_STR_LEN 257
#define MAX_Color_Maps 17
int __declspec(dllexport) __stdcall ReadF(char* ColorMap)
{
FILE* bookFile;
/* allocation of the buffer for every line in the File */
char* buf = malloc(MAX_STR_LEN);
char* tmp;
/* if the space could not be allocated, return an error */
if (buf == NULL)
{
printf("No memory\n");
return 1;
}
if ((bookFile = fopen("Colormaps2.csv", "r")) == NULL) //Reading a file
{
printf("File could not be opened.\n");
printf("%s",strerror(errno));
return 1;
}
struct Color_decider Colors[MAX_Color_Maps];
int i = 1;
fgets(buf, 256, bookFile);
tmp = strtok(buf, ";");
char* temp1;
temp1= strdup(tmp);
strncpy(Colors[0].Color_maps, temp1, strlen(temp1));
while (i<17)
{
tmp = strtok(NULL, ";");
temp1 = strdup(tmp);
strncpy(Colors[i].Color_maps, temp1, strlen(temp1));
i++;
}
for (int k = 1; k < 17; k++)
{
if (!strcmp(Colors[k].Color_maps, ColorMap)) // Find the input column.
{
for (int j = 0; j < 256; j++)
{
fgets(buf, 256, bookFile);
tmp = strtok(buf, ";");
for (int l = 1; l < k * 3; l++)
tmp = strtok(NULL, ";");
tmp = strtok(NULL, ";");
temp1 = strdup(tmp);
Colors->C[j][0] = atoi(temp1);
tmp = strtok(NULL, ";");
temp1 = strdup(tmp);
Colors->C[j][1] = atoi(temp1);
tmp = strtok(NULL, ";");
temp1 = strdup(tmp);
Colors->C[j][2] = atoi(temp1);
printf("%d\t", Colors->C[j][0]);
printf("%d\t", Colors->C[j][1]);
printf("%d\n", Colors->C[j][2]);
}
break;
}
}
free(buf);
fclose(bookFile);
return 0;
}
ReadFile1.h
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <errno.h>
struct Color_decider {
char Color_maps[10];
int C[256][3];
};
char *strdup(char *org)
{
int org_size;
static char *dup;
char *dup_offset;
/* Allocate memory for duplicate */
org_size = strlen(org);
dup = (char *)malloc(sizeof(char)*org_size+1);
if( dup == NULL)
return( (char *)NULL);
/* Copy string */
dup_offset = dup;
while(*org)
{
*dup_offset = *org;
dup_offset++;
org++;
}
*dup_offset = '\0';
return(dup);
}
int __declspec(dllexport) __stdcall ReadF(char* ColorMap);

Comparing Execution time with Time Complexity in Merge & Quick Sort

I have implemented Merge & Quick Sort in the textbook what I've learned, and it says Time Complexities of each sorts are like this:
Merge Sort: O(n.log(n)) / Quick Sort: average O(n.log(n)) and O(n2) in the worst case (if key array is sorted).
So I executed the programs with Two types of Arrays: sorted and random, with different sizes.
Since I wanted to get the Average time, I have tried 10 times per each case.
Here is the code of Merge & Quick Sort:
#include <iostream>
#include <ctime>
#include <vector>
#include <algorithm>
using namespace std;
void Merge(vector<int>& s, int low, int mid, int high) {
int i = low;
int j = mid + 1;
int k = low;
vector<int> u(s);
while (i <= mid && j <= high) {
if (s.at(i) < s.at(j)) {
u.at(k) = s.at(i);
i++;
} else {
u.at(k) = s.at(j);
j++;
}
k++;
}
if (i > mid) {
for (int a = j; a < high + 1; a++) {
u.at(k) = s.at(a);
k++;
}
} else {
for (int a = i; a < mid + 1; a++) {
u.at(k) = s.at(a);
k++;
}
}
for (int a = low; a < high + 1; a++)
s.at(a) = u.at(a);
}
void MergeSort(vector<int>& s, int low, int high) {
int mid;
if (low < high) {
mid = (low + high) / 2;
MergeSort(s, low, mid);
MergeSort(s, mid + 1, high);
Merge(s, low, mid, high);
}
}
void swap(int& a, int& b) {
int tmp = a;
a = b;
b = tmp;
}
void Partition(vector<int>& s, int low, int high, int& pvpoint) {
int j;
int pvitem;
pvitem = s.at(low);
j = low;
for (int i = low + 1; i <= high; i++) {
if (s.at(i) < pvitem) {
j++;
swap(s.at(i), s.at(j));
}
pvpoint = j;
swap(s.at(low), s.at(pvpoint));
}
}
void QuickSort(vector<int>& s, int low, int high) {
int pvpoint;
if (high > low) {
Partition(s, low, high, pvpoint);
QuickSort(s, low, pvpoint - 1);
QuickSort(s, pvpoint + 1, high);
}
}
And each of these main() functions are printing the execution times in SORTED, and RANDOM key arrays.
you can see the result with adding one of these main functions in Visual Studio(C++):
//Sorted key array
int main() {
int s;
for (int i = 1; i < 21; i++) { //Size is from 300 to 6000
s = i * 300;
vector<int> Arr(s);
cout << "N : " << s << "\n";
//Assign Random numbers to each elements
Arr.front() = rand() % Arr.size();
for (int j = 1; j < Arr.size(); j++) { Arr.at(j) = ((737 * Arr.at(j - 1) + 149) % (Arr.size() * 5)); }
sort(Arr.begin(), Arr.end());
//QuickSort(Arr, 0, Arr.size() - 1); <- you can switch using this instead of MergeSort(...) below
for (int i = 0; i < 10; i++) { //print 10 times of execution time
clock_t start, end;
start = clock();
MergeSort(Arr, 0, Arr.size() - 1);
end = clock() - start;
printf("%12.3f ", (double)end * 1000.0 / CLOCKS_PER_SEC);
}
cout << endl;
}
return 0;
}
//Random key array
int main() {
int s;
for (int i = 1; i < 21; i++) {
s = i * 3000;
vector<int> Arr(s);
cout << "N : " << s << "\n";
for (int i = 0; i < 10; i++) {
//Assign Random numbers to each elements
Arr.front() = rand() % Arr.size();
for (int j = 1; j < Arr.size(); j++) { Arr.at(j) = ((737 * Arr.at(j - 1) + 149) % (Arr.size() * 5)); }
//QuickSort(Arr, 0, Arr.size() - 1); <- you can switch using this instead of MergeSort(...) below
clock_t start, end;
start = clock();
MergeSort(Arr, 0, Arr.size() - 1);
end = clock() - start;
printf("%12.3f ", (double)end * 1000.0 / CLOCKS_PER_SEC);
}
cout << endl;
}
return 0;
}
And the THING is, the result is not matching with their time complexity. for example, Merge sort in(RANDOM Array)
size N=3000 prints 20 ms, but size N=60000 prints 1400~1600 ms !! it supposed to print almost 400 ms because Time complexity (Not in worse case) in Quick Sort is O(n.log(n)), isn't it? I want to know what affects to this time and how could I see the printed time that I expected.
You posted the same code in this question: Calculate Execution Times in Sort algorithm and you did not take my answer into account.
Your MergeSort function has a flaw: you duplicate the whole array in merge causing a lot of overhead and quadratic time complexity. This innocent looking definition: vector<int> u(s); defines u as a vector initialized as a copy of s, the full array.
C++ is a very powerful language, often too powerful, littered with traps and pitfalls such as this. It is a very good thing you tried to verify that your program meets the expected performance from the known time complexity of the algorithm. Such a concern is alas too rare.
Here are some guidelines:
For getting execution time:
#include <time.h>
int main()
{
struct timeval stop, start;
int arr[10000];
gettimeofday(&start, NULL);
mergeSort(arr, 0, 9999);
gettimeofday(&stop, NULL);
printf("Time taken for Quick sort is: %ld microseconds\n",
(stop.tv_sec-start.tv_sec)*1000000+stop.tv_usec-start.tv_usec);
}

TLE in Foe Pairs (Educational Codeforces Round 10)

On implementing O(N+M) complexity code for Foe Pairs problem
http://codeforces.com/contest/652/problem/C, I am getting TLE in Test Case 12.
Constraint : (1 ≤ N, M ≤ 3·105)
I am not getting, why for this constraint O(N+M) is getting TLE.
Here, is the code
#include<iostream>
#include<vector>
using namespace std;
int main()
{
int n,m;
cin>>n>>m;
std::vector<int> v(n+1);
for (int i = 0; i < n; ++i)
{
int x;
cin>>x;
v[x] = i;
}
std::vector<int> dp(n,0);
for (int i = 0; i < m; ++i)
{
int a,b;
cin>>a>>b;
if(v[a]>v[b])
swap(a,b);
dp[v[b]] = max(dp[v[b]], v[a]+1);
}
for (int i = 1; i < n; ++i)
{
dp[i] = max(dp[i], dp[i-1]);
}
long long s = 0;
for (int i = 0; i < n; ++i)
{
s+=(i+1-dp[i]);
}
cout<<s;
}
Is there anything, I am missing?
I changed all cin to scanf, it passed all test cases : http://codeforces.com/contest/652/submission/17014495
#include<cstdio>
#include<iostream>
#include<vector>
using namespace std;
int main()
{
int n,m;
scanf("%d%d", &n, &m);
//cin>>n>>m;
std::vector<int> v(n+1);
for (int i = 0; i < n; ++i)
{
int x;
//cin>>x;
scanf("%d", &x);
v[x] = i;
}
std::vector<int> dp(n,0);
for (int i = 0; i < m; ++i)
{
int a,b;
//cin>>a>>b;
scanf("%d%d", &a, &b);
if(v[a]>v[b])
swap(a,b);
dp[v[b]] = max(dp[v[b]], v[a]+1);
}
for (int i = 1; i < n; ++i)
{
dp[i] = max(dp[i], dp[i-1]);
}
long long s = 0;
for (int i = 0; i < n; ++i)
{
s+=(i+1-dp[i]);
}
cout<<s;
return 0;
}
You should always try to use scanf when the amount of input is large as it is faster.
You can read more about scanf being faster here : Using scanf() in C++ programs is faster than using cin?

mupdf render jpeg2000 lose color?

I am working on an android project, which use vudroid, which in turn use mupdf version 0.5.
Vudroid remove the original openjpeg support of mupdf, I have ported the mupdf version 1.5's openjpeg support.
But I encounter a new problem, color information in jpx image gone, the desired effect:
my effect:
the ported load-jpx code:
#include "fitz.h"
#include "mupdf.h"
/* Without the definition of OPJ_STATIC, compilation fails on windows
* due to the use of __stdcall. We believe it is required on some
* linux toolchains too. */
#define OPJ_STATIC
#ifndef _MSC_VER
#define OPJ_HAVE_STDINT_H
#endif
#include <openjpeg.h>
static void fz_opj_error_callback(const char *msg, void *client_data)
{
//fz_context *ctx = (fz_context *)client_data;
//fz_warn(ctx, "openjpeg error: %s", msg);
}
static void fz_opj_warning_callback(const char *msg, void *client_data)
{
//fz_context *ctx = (fz_context *)client_data;
//fz_warn(ctx, "openjpeg warning: %s", msg);
}
static void fz_opj_info_callback(const char *msg, void *client_data)
{
/* fz_warn("openjpeg info: %s", msg); */
}
typedef struct stream_block_s
{
unsigned char *data;
int size;
int pos;
} stream_block;
static OPJ_SIZE_T fz_opj_stream_read(void * p_buffer, OPJ_SIZE_T p_nb_bytes, void * p_user_data)
{
stream_block *sb = (stream_block *)p_user_data;
int len;
len = sb->size - sb->pos;
if (len < 0)
len = 0;
if (len == 0)
return (OPJ_SIZE_T)-1; /* End of file! */
if ((OPJ_SIZE_T)len > p_nb_bytes)
len = p_nb_bytes;
memcpy(p_buffer, sb->data + sb->pos, len);
sb->pos += len;
return len;
}
static OPJ_OFF_T fz_opj_stream_skip(OPJ_OFF_T skip, void * p_user_data)
{
stream_block *sb = (stream_block *)p_user_data;
if (skip > sb->size - sb->pos)
skip = sb->size - sb->pos;
sb->pos += skip;
return sb->pos;
}
static OPJ_BOOL fz_opj_stream_seek(OPJ_OFF_T seek_pos, void * p_user_data)
{
stream_block *sb = (stream_block *)p_user_data;
if (seek_pos > sb->size)
return OPJ_FALSE;
sb->pos = seek_pos;
return OPJ_TRUE;
}
fz_error
fz_load_jpx(pdf_image* img, unsigned char *data, int size, fz_colorspace *defcs, int indexed)
{
//fz_pixmap *img;
opj_dparameters_t params;
opj_codec_t *codec;
opj_image_t *jpx;
opj_stream_t *stream;
fz_colorspace *colorspace;
unsigned char *p;
OPJ_CODEC_FORMAT format;
int a, n, w, h, depth, sgnd;
int x, y, k, v;
stream_block sb;
if (size < 2)
fz_throw("not enough data to determine image format");
/* Check for SOC marker -- if found we have a bare J2K stream */
if (data[0] == 0xFF && data[1] == 0x4F)
format = OPJ_CODEC_J2K;
else
format = OPJ_CODEC_JP2;
opj_set_default_decoder_parameters(&params);
if (indexed)
params.flags |= OPJ_DPARAMETERS_IGNORE_PCLR_CMAP_CDEF_FLAG;
codec = opj_create_decompress(format);
opj_set_info_handler(codec, fz_opj_info_callback, 0);
opj_set_warning_handler(codec, fz_opj_warning_callback, 0);
opj_set_error_handler(codec, fz_opj_error_callback, 0);
if (!opj_setup_decoder(codec, &params))
{
fz_throw("j2k decode failed");
}
stream = opj_stream_default_create(OPJ_TRUE);
sb.data = data;
sb.pos = 0;
sb.size = size;
opj_stream_set_read_function(stream, fz_opj_stream_read);
opj_stream_set_skip_function(stream, fz_opj_stream_skip);
opj_stream_set_seek_function(stream, fz_opj_stream_seek);
opj_stream_set_user_data(stream, &sb);
/* Set the length to avoid an assert */
opj_stream_set_user_data_length(stream, size);
if (!opj_read_header(stream, codec, &jpx))
{
opj_stream_destroy(stream);
opj_destroy_codec(codec);
fz_throw("Failed to read JPX header");
}
if (!opj_decode(codec, stream, jpx))
{
opj_stream_destroy(stream);
opj_destroy_codec(codec);
opj_image_destroy(jpx);
fz_throw("Failed to decode JPX image");
}
opj_stream_destroy(stream);
opj_destroy_codec(codec);
/* jpx should never be NULL here, but check anyway */
if (!jpx)
fz_throw("opj_decode failed");
pdf_logimage("opj_decode succeeded");
for (k = 1; k < (int)jpx->numcomps; k++)
{
if (!jpx->comps[k].data)
{
opj_image_destroy(jpx);
fz_throw("image components are missing data");
}
if (jpx->comps[k].w != jpx->comps[0].w)
{
opj_image_destroy(jpx);
fz_throw("image components have different width");
}
if (jpx->comps[k].h != jpx->comps[0].h)
{
opj_image_destroy(jpx);
fz_throw("image components have different height");
}
if (jpx->comps[k].prec != jpx->comps[0].prec)
{
opj_image_destroy(jpx);
fz_throw("image components have different precision");
}
}
n = jpx->numcomps;
w = jpx->comps[0].w;
h = jpx->comps[0].h;
depth = jpx->comps[0].prec;
sgnd = jpx->comps[0].sgnd;
if (jpx->color_space == OPJ_CLRSPC_SRGB && n == 4) { n = 3; a = 1; }
else if (jpx->color_space == OPJ_CLRSPC_SYCC && n == 4) { n = 3; a = 1; }
else if (n == 2) { n = 1; a = 1; }
else if (n > 4) { n = 4; a = 1; }
else { a = 0; }
if (defcs)
{
if (defcs->n == n)
{
colorspace = defcs;
}
else
{
fz_warn("jpx file and dict colorspaces do not match");
defcs = NULL;
}
}
if (!defcs)
{
switch (n)
{
case 1: colorspace = pdf_devicegray; break;
case 3: colorspace = pdf_devicergb; break;
case 4: colorspace = pdf_devicecmyk; break;
}
}
//error = fz_new_pixmap(&img, colorspace, w, h);
//if (error)
// return error;
pdf_logimage("colorspace handled\n");
int bpc = 1;
if (colorspace) {
bpc = 1 + colorspace->n;
};
pdf_logimage("w = %d, bpc = %d, h = %d\n", w, bpc, h);
img->samples = fz_newbuffer(w * bpc * h);
//opj_image_destroy(jpx);
//fz_throw("out of memory loading jpx");
p = (char*)img->samples->bp;
pdf_logimage("start to deal with samples");
for (y = 0; y < h; y++)
{
for (x = 0; x < w; x++)
{
for (k = 0; k < n + a; k++)
{
v = jpx->comps[k].data[y * w + x];
if (sgnd)
v = v + (1 << (depth - 1));
if (depth > 8)
v = v >> (depth - 8);
*p++ = v;
}
if (!a)
*p++ = 255;
}
}
img->samples->wp = p;
pdf_logimage("start to deal with samples succeeded");
opj_image_destroy(jpx);
// if (a)
// {
// if (n == 4)
// {
// fz_pixmap *tmp = fz_new_pixmap(ctx, fz_device_rgb(ctx), w, h);
// fz_convert_pixmap(ctx, tmp, img);
// fz_drop_pixmap(ctx, img);
// img = tmp;
// }
// fz_premultiply_pixmap(ctx, img);
// }
return fz_okay;
}
The render code:
JNIEXPORT jbyteArray JNICALL Java_org_vudroid_pdfdroid_codec_PdfPage_drawPage
(JNIEnv *env, jclass clazz, jlong dochandle, jlong pagehandle)
{
renderdocument_t *doc = (renderdocument_t*) dochandle;
renderpage_t *page = (renderpage_t*) pagehandle;
//DEBUG("PdfView(%p).drawpage(%p, %p)", this, doc, page);
fz_error error;
fz_matrix ctm;
fz_irect viewbox;
fz_pixmap *pixmap;
jfloat *matrix;
jint *viewboxarr;
jint *dimen;
jint *buffer;
int length, val;
pixmap = nil;
/* initialize parameter arrays for MuPDF */
ctm.a = 1;
ctm.b = 0;
ctm.c = 0;
ctm.d = 1;
ctm.e = 0;
ctm.f = 0;
// matrix = (*env)->GetPrimitiveArrayCritical(env, matrixarray, 0);
// ctm.a = matrix[0];
// ctm.b = matrix[1];
// ctm.c = matrix[2];
// ctm.d = matrix[3];
// ctm.e = matrix[4];
// ctm.f = matrix[5];
// (*env)->ReleasePrimitiveArrayCritical(env, matrixarray, matrix, 0);
// DEBUG("Matrix: %f %f %f %f %f %f",
// ctm.a, ctm.b, ctm.c, ctm.d, ctm.e, ctm.f);
// viewboxarr = (*env)->GetPrimitiveArrayCritical(env, viewboxarray, 0);
// viewbox.x0 = viewboxarr[0];
// viewbox.y0 = viewboxarr[1];
// viewbox.x1 = viewboxarr[2];
// viewbox.y1 = viewboxarr[3];
// (*env)->ReleasePrimitiveArrayCritical(env, viewboxarray, viewboxarr, 0);
// DEBUG("Viewbox: %d %d %d %d",
// viewbox.x0, viewbox.y0, viewbox.x1, viewbox.y1);
viewbox.x0 = 0;
viewbox.y0 = 0;
viewbox.x1 = 595;
viewbox.y1 = 841;
/* do the rendering */
DEBUG("doing the rendering...");
//buffer = (*env)->GetPrimitiveArrayCritical(env, bufferarray, 0);
// do the actual rendering:
error = fz_rendertree(&pixmap, doc->rast, page->page->tree,
ctm, viewbox, 1);
/* evil magic: we transform the rendered image's byte order
*/
int x, y;
if (bmpdata)
fz_free(bmpdata);
bmpstride = ((pixmap->w * 3 + 3) / 4) * 4;
bmpdata = fz_malloc(pixmap->h * bmpstride);
DEBUG("inside drawpage, bmpstride = %d, pixmap->w = %d, pixmap->h = %d\n", bmpstride, pixmap->w, pixmap->h);
if (!bmpdata)
return;
for (y = 0; y < pixmap->h; y++)
{
unsigned char *p = bmpdata + y * bmpstride;
unsigned char *s = pixmap->samples + y * pixmap->w * 4;
for (x = 0; x < pixmap->w; x++)
{
p[x * 3 + 0] = s[x * 4 + 3];
p[x * 3 + 1] = s[x * 4 + 2];
p[x * 3 + 2] = s[x * 4 + 1];
}
}
FILE* fp = fopen("/sdcard/drawpage", "wb");
fwrite(bmpdata, pixmap->h * bmpstride, 1, fp);
fclose(fp);
jbyteArray array = (*env)->NewByteArray(env, pixmap->h * bmpstride);
(*env)->SetByteArrayRegion(env, array, 0, pixmap->h * bmpstride, bmpdata);
// if(!error) {
// DEBUG("Converting image buffer pixel order");
// length = pixmap->w * pixmap->h;
// unsigned int *col = pixmap->samples;
// int c = 0;
// for(val = 0; val < length; val++) {
// col[val] = ((col[val] & 0xFF000000) >> 24) |
// ((col[val] & 0x00FF0000) >> 8) |
// ((col[val] & 0x0000FF00) << 8);
// }
// winconvert(pixmap);
// }
// (*env)->ReleasePrimitiveArrayCritical(env, bufferarray, buffer, 0);
fz_free(pixmap);
if (error) {
DEBUG("error!");
throw_exception(env, "error rendering page");
}
DEBUG("PdfView.drawPage() done");
return array;
}
I have compare the jpx output samples to the mupdf-1.5 windows, it is the same, but the colorspace of original jpx have gone.
Could help me to get the colorspace back?
It seems you are trying to use an old version of MuPDF with some bits pulled in from a more recent version. TO be honest that's hardly likely to work. I would also guess that its not the OpenJPEG library causing your problem, since the image appears, but converted to grayscale.
Have you tried opening the file in the current version of MuPDF ? Does it work ?
If so then it seems to me your correct approach should be to use the current code, not try and bolt pieces onto an older version.

Retrieving and manipulating data from file

The following code is supposed to retrieve the data related to the players info, sort it out and then rewrite the file now organized. Going to give an example of the files.
Original layout:
3
2 2
John 33 M 5
Anna 20 F 2
Rody 23 M 1
What it has to look like after the code:
3
2 2
Rody 23 M 1
Anna 20 F 2
John 33 M 5
I made the following code:
vector<string> playerScoresFromFile(const string filename) //Gets each one of those lines with the name, ..., and score of the person
{
int dim = filename[7] - '0'; // char to integer
vector<string> vec;
string line;
ifstream fin (filename.c_str());
for (int i = 0; i < dim + 1; i++)
{
getline(fin, line);
}
while(! fin.eof())
{
getline(fin, line);
vec.push_back(line);
}
return vec;
}
vector< vector<int> > readBoardFromFile(const string filename) //gets the board from the file (first 3 numbers)
{
int dim = filename[7] - '0'; // char to integer
string line;
vector< vector<int> >vec(dim, vector<int>(dim));
ifstream fin (filename.c_str());
int i = 0;
int j, k;
while(i < dim)
{
getline(fin, line);
int sizeOfLine = line.length();
if (line[0] == '\0')
{
break;
}
else
{
for (j = 0, k = 0; j < (sizeOfLine / 3); j++, k += 3)
{
string elementOfVectorStr = (line.substr(k,3));
int elementOfVectorInt = stringToInt(elementOfVectorStr);
if (abs(elementOfVectorInt) > 100) // when the element is a " ", the corresponding integer is always
{ // a very large number, positive or negative
elementOfVectorInt = 0;
}
vec[i][j] = elementOfVectorInt;
}
}
i++;
}
return vec;
}
vector<string> sortPlayersByTime (vector<string> &vec) // Creates a substring of the string extracted by "playerScoresFromFile" and analyses the times (Which are the last numbers to the right)
{
vector<int> timesInt(vec.size());
for (size_t i = 0; i < vec.size(); i++)
{
string str = vec[i];
timesInt[i] = stringToInt(str.substr(26));
}
for (size_t i = 0; i < vec.size() - 1; i++)
{
if(timesInt[i] > timesInt[i+1])
{
swap(vec[i], vec[i+1]);
}
}
return vec;
}
bool isOrdered (const vector<string> vec) //Checks if the vector is ordered
{
vector<int> timesInt(vec.size());
for (size_t i = 0; i < vec.size(); i++)
{
string str = vec[i];
timesInt[i] = stringToInt(str.substr(26));
}
for (size_t i = 0; i < vec.size() - 1; i++)
{
if(timesInt[i] > timesInt[i+1])
{
return false;
}
}
return true;
}
void writeBoardToFile(vector< vector<int> >&vec, string filename) //Rewrites the board to the file (Those first 3 numbers of the file)
{
ofstream fout(filename.c_str());
for (size_t i = 0; i < vec.size(); i++)
{
for (size_t j = 0; j < vec.size(); j++)
{
if(vec[i][j] != 0)
{
fout << setw(3) << vec[i][j];
}
else
{
fout << setw(3) << " ";
}
}
fout << endl;
}
fout << endl;
}
void vec_to_file(vector<string> vec, string filename) //Rewrites the vector to the file
{
ofstream fout(filename, ios::app);
for (int i = 0; i < vec.size(); i++)
{
fout << vec[i] <<endl;
}
}
void displayFile (string filename) //Displays the final board to check if it worked
{
vector<string> vec;
string line;
ifstream myfile (filename);
while ( ! myfile.eof() )
{
getline (myfile, line);
vec.push_back(line);
}
for (size_t i = 0; i < vec.size(); i++)
{
cout << vec[i] <<endl;
}
}
int main()
{
vector< vector<int> > vec = readBoardFromFile("puzzle_2x2_001.txt");
vector<string> vecxz = playerScoresFromFile("puzzle_2x2_001.txt");
writeBoardToFile(vec, "puzzle_2x2_001.txt"); //Writes the board to the file
while (! isOrdered(vecxz)) //This loop should run while they haven't been sorted out, but the program crashes here and I have no idea why.
{
sortPlayersByTime(vecxz);
}
//vec_to_file(vecxy, "puzzle_2x2_001.txt"); //Should write the vector to the file upon sorting them out successfully.
cin.get();
}
My problem is the program crashes everytime it gets to the while(! isOrdered(vecxz)) loop but I have no idea why. Can anyone give me a hand? I'd be thankful :)