On implementing O(N+M) complexity code for Foe Pairs problem
http://codeforces.com/contest/652/problem/C, I am getting TLE in Test Case 12.
Constraint : (1 ≤ N, M ≤ 3·105)
I am not getting, why for this constraint O(N+M) is getting TLE.
Here, is the code
#include<iostream>
#include<vector>
using namespace std;
int main()
{
int n,m;
cin>>n>>m;
std::vector<int> v(n+1);
for (int i = 0; i < n; ++i)
{
int x;
cin>>x;
v[x] = i;
}
std::vector<int> dp(n,0);
for (int i = 0; i < m; ++i)
{
int a,b;
cin>>a>>b;
if(v[a]>v[b])
swap(a,b);
dp[v[b]] = max(dp[v[b]], v[a]+1);
}
for (int i = 1; i < n; ++i)
{
dp[i] = max(dp[i], dp[i-1]);
}
long long s = 0;
for (int i = 0; i < n; ++i)
{
s+=(i+1-dp[i]);
}
cout<<s;
}
Is there anything, I am missing?
I changed all cin to scanf, it passed all test cases : http://codeforces.com/contest/652/submission/17014495
#include<cstdio>
#include<iostream>
#include<vector>
using namespace std;
int main()
{
int n,m;
scanf("%d%d", &n, &m);
//cin>>n>>m;
std::vector<int> v(n+1);
for (int i = 0; i < n; ++i)
{
int x;
//cin>>x;
scanf("%d", &x);
v[x] = i;
}
std::vector<int> dp(n,0);
for (int i = 0; i < m; ++i)
{
int a,b;
//cin>>a>>b;
scanf("%d%d", &a, &b);
if(v[a]>v[b])
swap(a,b);
dp[v[b]] = max(dp[v[b]], v[a]+1);
}
for (int i = 1; i < n; ++i)
{
dp[i] = max(dp[i], dp[i-1]);
}
long long s = 0;
for (int i = 0; i < n; ++i)
{
s+=(i+1-dp[i]);
}
cout<<s;
return 0;
}
You should always try to use scanf when the amount of input is large as it is faster.
You can read more about scanf being faster here : Using scanf() in C++ programs is faster than using cin?
Related
I wrote in this forum asking for help to solve this problem that took ame a lot of my time,i write my first program using systemC, I will expain my aim as much as I can , I stored 2 matrix of pixel value of image in two different text files, I write a systemC code that load two matrix and apply somme of absolute difference, if number of different superior of a Threshold the code displays message (motion).
My code composed of two modules, the first module check if there a number stored in a text file, if yes this Module will automates the other module to load the two matrix and compare them, I really need this code for my project graduation any help or suggestion.
#include "systemC.h"
#include "string.h"
#include "stdio.h"
#include"stdlib.h"
#include <time.h>
#include <math.h> /* fabs */
#include <fstream>
#include <iostream>
#include <fstream>
using namespace std;
#define _CRT_SECURE_NO_WARNINGS
_CRT_SECURE_NO_WARNINGS
double elapsed;
int H = 0;
int D = 0;
int a, b;
int in = false;
int L = 0;
char *mode1 = "r";
char *mode2 = "w";
int i, j, k;
int rows1, cols1, rows2, cols2;
bool fileFound = false;
FILE *SwitchContext;
FILE *image1;
FILE *image2;
FILE *image3;
int sum = 0;
clock_t start = clock();
SC_MODULE(synchronization)
{
sc_in<bool>sig ;
SC_CTOR(synchronization)
{
SC_METHOD(synchroprocess)
}
void synchroprocess()
{
cout << "\n Running Automation";
SwitchContext = fopen("F:/SWITCH CONTEXT.txt", mode2);
fscanf(SwitchContext, "%d", &L);
while (L != 0)
{
cout << "waiting...";
}
sig == true;
}
};
SC_MODULE(imageProcess)
{
sc_in<bool>sig;
SC_CTOR(imageProcess)
{
SC_METHOD(MotionDetector)
sensitive(sig);
}
void MotionDetector()
{
image3 = fopen("F:/image3.txt", mode2);
do
{
char *mode1 = "r";
char *mode2 = "w";
image1 = fopen("F:/image1.txt", mode1);
if (!image1)
{
printf("File Not Found!!\n");
fileFound = true;
}
else
fileFound = false;
}
while (fileFound);
do
{
image2 = fopen("F:/image2.txt", mode1);
if (!image2)
{
printf("File Not Found!!\n");
fileFound = true;
}
else
fileFound = false;
}
while (fileFound);
rows1 = rows2 = 384;
cols1 = cols2 = 512;
int **mat1 = (int **)malloc(rows1 * sizeof(int*));
for (i = 0; i < rows1; i++)
mat1[i] = (int *)malloc(cols1 * sizeof(int));
i = 0;
int **mat2 = (int **)malloc(rows2 * sizeof(int*));
for (i = 0; i < rows2; i++)
mat2[i] = (int *)malloc(cols2 * sizeof(int));
i = 0;
while (!feof(image1))
{
for (i = 0; i < rows1; i++)
{
for (j = 0; j < cols1; j++)
fscanf(image1, "%d%", &mat1[i][j]);
}
}
i = 0;
j = 0;
while (!feof(image2))
{
for (i = 0; i < rows2; i++)
{
for (j = 0; j < cols2; j++)
fscanf(image2, "%d%", &mat2[i][j]);
}
}
i = 0;
j = 0;
printf("\n\n");
for (i = 0; i < rows1; i++)
{
for (j = 0; j < cols1; j++) {
a = abs(mat1[i][j] = mat2[i][j]);
b = b + a;
}
}
i = j = 0;
D = b / 196608;
if (D > 0.9)
{
printf("%d,&K");
printf("MOTION...DETECTED");
getchar();
sc_pause;
for (i = 0; i < rows1; i++) {
for (j = 0; j < cols1; j++)
{
fprintf(image3, "%d ", mat2[i][j]);
}
fprintf(image3, "\n");
}
printf("\n Image Saved....");
std::ofstream mon_fichier("F:\toto.txt");
mon_fichier << elapsed << '\n';
}
fclose(image1);
fclose(image2);
fclose(image3);
clock_t end = clock();
elapsed = ((double)end - start) / CLOCKS_PER_SEC;
printf("time is %f", elapsed);
}
};
int sc_main(int argc, char* argv[])
{
imageProcess master("EE2");
master.MotionDetector();
sc_start();
return(0);
}
What you did is basically wrong.
You copy pasted code to SC_MODULE, this code is simple C code
(Do not mix C and C++ files)
This is not how you use clock
What you should do:
You need to check if your algorithm works, for this you do not need SystemC at all
Then you can replace data types with HW one and check if it still works
Then you have to find which data interface is used in HW and how to use this interface
Then you have to tweak your alg. to work with this interface (There you can use SC_MODULE, sc ports etc...)
Also take look at SC_CTHREAD, you will need it.
Without any informations about target platform I can not provide any other help.
I am a beginner in working with the MCBSTR9 arm board.
I am trying to use the ESP8266 wifi module in TCP mode with the pushingbox API.
After connecting to the API, pushingbox is unable to send a request GET /pushingbox?devid=deviceid HTTP/1.0\r\nHost: api.pushingbox.com\r\n\r\n.
My Question is how to include the new line key in keil c. I have used \r\n for it but it's not working. It works with ESP 8266 user application, though.
This is the code I tried:
/*ESP8266-01*/
char data[] = "GET /pushingbox?devid=*************&tag=but HTTP/1.0";
char data1[] = "Host: api.pushingbox.com";
char data2[] = "";
void at(void) {
sendchar1('A');
sendchar1('T');
sendchar1('\r');
sendchar1('\n');
for (i = 0; i < 12; i++)
lcd_putchar(getkey1());
}
void atcwmode(void) {
char ch[] = "AT+CWMODE=3\r\n"
for (i = 0; i < 13; i++)
sendchar1(ch[i]);
for (i = 0; i < 21; i++) {
lcd_putchar(getkey1());
if (i == 14)
set_cursor(0, 1);
}
}
void atcipmux(void) {
char ch[] = "AT+CIPMUX=0\r\n";
for (i = 0; i < 13; i++)
sendchar1(ch[i]);
for (i = 0; i < 21; i++) {
lcd_putchar(getkey1());
if (i == 14)
set_cursor(0, 1);
}
}
void atcwjap(void) {
char ch[] = "AT+CWJAP?\r\n";
for (i = 0; i < 11; i++)
sendchar1(ch[i]);
for (i = 0; i < 29; i++) {
lcd_putchar(getkey1());
if (i == 16)
set_cursor(0, 1);
}
}
void atsend() {
char ch[] = "AT+CIPSEND=";
for (i = 0; i < strlen(ch); i++)
sendchar1(ch[i]);
sendchar1('8');
sendchar1('5');
sendchar1('\r');
sendchar1('\n');
for (i = 0; i < 16; i++)
lcd_putchar(getkey1());
set_cursor(0, 1);
lcd_putchar(getkey1());
lcd_putchar(getkey1());
lcd_putchar(getkey1());
lcd_putchar(getkey1());
lcd_putchar(getkey1());
lcd_putchar(getkey1());
lcd_putchar(getkey1());
wait();
wait();
for (i = 0; i < strlen(data) - 1; i++)
sendchar1(data[i]);
GPIO7 - > DR[0x3FC] = 0xFF;
set_cursor(0, 0);
GPIO7 - > DR[0x3FC] = 0x00;
for (i = 0; i < 16; i++)
lcd_putchar(getkey1());
set_cursor(0, 1);
for (i = 0; i < 16; i++)
lcd_putchar(getkey1());
set_cursor(0, 0);
for (i = 0; i < 16; i++)
lcd_putchar(getkey1());
set_cursor(0, 1);
for (i = 0; i < 16; i++)
lcd_putchar(getkey1());
}
I have tried using the esp user application by sending
POST /pushingbox?devid=vD12658A9BB09A13&tag=but HTTP/1.0\r\n
Host: api.pushingbox.com:80
It works and my pushing box scenario gets updated.
But it doesn't work with the board.
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Closed 6 years ago.
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I want to
1) Read a 3 channel image
2) Using K-Means method, create k different classes
3) I will tag pixels accordingly to show which class they belong to and store them in a matrix.
4) And after that I'm thinking using Connected Component Labeling to determine if they are in the same segment or not.
I'm new in opencv so I wanted to ask you for the implementation , some code snippet to to get me started.
Any help will be appreciated. Thank you
typedef struct {
int red;
int green;
int blue;
int b64;
int groupNo;
} IMAGE;
typedef struct _MEANS
{
int r, g, b;
int groupNo;
} point_t, *point;
Mat img = imread("C:\\253027.jpg",CV_LOAD_IMAGE_COLOR);
int clusterCount=5;
IMAGE **strct= {0};
strct = allocate_matrix(img.rows, img.cols);
int i,j,k;
if(! img.data )
{
cout << "Could not open or find the image" << std::endl ;
return -1;
}
for ( i = 0; i < img.rows; i++) {
for ( j = 0; j < img.cols; j++) {
strct[i][j].red = img.at<Vec3b>(i,j)[2];
strct[i][j].green = img.at<Vec3b>(i,j)[1];
strct[i][j].blue = img.at<Vec3b>(i,j)[0];
/* printf("%u",strct[i][j].red);
printf("%u",strct[i][j].green);
printf("%u",strct[i][j].blue);
*/
}
}
double *tempuz= (double *)malloc(sizeof(double) * clusterCount);
point_t* p = (point_t *)malloc(sizeof(point_t) * clusterCount);
for( k = 0; k < clusterCount; k++ )
{
p[k].r= rand()%255;
p[k].g=rand()%255;
p[k].b=rand()%255;
p[k].groupNo=k;
}
int max=0;
for (i = 0; i < img.rows; i++) {
for ( j = 0; j < img.cols; j++) {
for(k = 0; k < clusterCount; k++ ){
tempuz[k]= abs(strct[i][j].red - p[k].r)+abs(strct[i][j].green -p[k].g)+abs(strct[i][j].blue - p[k].b);
// cout<<"tempuz"<<tempuz[k]<<endl;
} strct[i][j].groupNo=min_element(tempuz,clusterCount);
// cout<<"grup no"<<strct[i][j].groupNo<<endl;
}
}
i=0;
int r=0,b=0,g=0,counter=0;
while(i<200){
r=0,b=0,g=0,counter=0;
for(k=0;k<clusterCount;k++){
for (i = 0; i < img.rows; i++) {
for ( j = 0; j < img.cols; j++) {
if(strct[i][j].groupNo==k){
r+=strct[i][j].red;
b+=strct[i][j].blue;
g+=strct[i][j].green;
counter++;
}
}
}
if(counter!=0){
p[k].r=r/counter;
p[k].b=b/counter;
p[k].g=g/=counter;
}
}
i++;
max=0;
for (i = 0; i < img.rows; i++) {
for ( j = 0; j < img.cols; j++) {
for(k = 0; k < clusterCount; k++ ){
tempuz[k]= abs(strct[i][j].red - p[k].r)+abs(strct[i][j].green -p[k].g)+abs(strct[i][j].blue - p[k].b);
} strct[i][j].groupNo=min_element(tempuz,clusterCount);
}
}
}//end of while
for(int k=0;k<clusterCount;k++){
for (int i = 0; i < img.rows; i++) {
for (int j = 0; j < img.cols; j++) {
if(strct[i][j].groupNo==k){
strct[i][j].red=p[k].r;
strct[i][j].blue=p[k].b;
strct[i][j].green=p[k].r;
}
}
}
}
for (int i = 0; i < img.rows; i++) {
for (int j = 0; j < img.cols; j++) {
img.at<Vec3b>(i,j)[2] = strct[i][j].red;
img.at<Vec3b>(i,j)[1] = strct[i][j].green;
img.at<Vec3b>(i,j)[0] = strct[i][j].blue;
}
}
I have a Codility test to take soon.
I was trying to find a modification in the code to avoid EXTREME LARGE NUMBERS ERROR by using LONG instead of INT... but this did not work.
Has anybody tried using CODILITY demo test and get a 100?
I went through previous posts but no solution to this particular problem.
MY CODE: COMPLEXITY O(N)... Still I got 94.
// you can also use includes for example:
// #include <algorithm>
#include<iostream>
#include<vector>
#include<math.h>
int equi ( const vector<int> &A ) {
if((int)A.size()==0)
return -1;
long int sum_l = A[0];
long int total_sum =0;
for(int i =0; i<(int)A.size();i++){
total_sum = total_sum + A[i];
}
int flag =0;
total_sum = total_sum -A[0];
if(total_sum == 0)
return 0;
for(int i=1; i<(int)A.size()-1;i++){
total_sum = total_sum - A[i];
if(sum_l ==total_sum){
flag=1;
return i;
}
sum_l= sum_l + A[i];
}
if(sum_l ==0)
return (int)A.size()-1;
if(flag ==0)
return -1;
}
I used long long, and I had not problem.
Try this one.
int left = A[0];
int right = 0;
for(int i: A){
right += i;
}
right -= left;
int diff = Math.abs(left - right);
for (int i = 1; i < A.length-1; i++) {
left += A[i];
right -= A[i];
int a = Math.abs(left - right);
if(diff > a){
diff = a;
}
}
return diff;
Here's a simple program:
void multiply(const int* v_in, const int* w_in, int n_v, int n_w, int* w_out)
{
for(int i=0; i<n_w; i++)
{
int sum=0;
for(int j=0; j<n_v; j++)
sum += (w_in[i]*v_in[j])>>1;
w_out[i]=sum;
}
}
Presume n_v, n_w ~10^6. Clearly, there's at least a dozen equivalent ways to do this in CUDA, with different ways to subdivide (n_v*n_w) operations into threads, with and without shared memory... Which way should, theoretically speaking, be the fastest?
simplest:
void multiply(const int* v_in, const int* w_in, int n_v, int n_w, int* w_out)
{
int *v = shared; // dynamic
for(int i = block.rank; i < n_w; i += block.size)
{
int w = w_in[i]; // coalesced
int sum=0;
for(int j=0; j<n_v; j += block.size) { // assumption
v[block.rank] = v_in[j+block.rank];
__synch();
for(int k = 0; k < block.size; ++k)
sum += (w*v[k])>>1; //
__synch(); // ouch
}
w_out[i] = sum; // ditto
}
}