I have this query:
SELECT * FROM TABLE1 WHERE KEY_COLUMN='NJCRF' AND TYPE_COLUMN IN ('SCORE1', 'SCORE2', 'SCORE3') AND DATE_EFFECTIVE_COLUMN<='2016-09-17'
I get about 12 record(rows) as result.
How to get result closest to DATE_EFFECTIVE_COLUMN for each TYPE_COLUMN? In this case, how to get three records, for each type, that are closest to effective date?
UPDATE: I could use TOP if I had to go over only single type, but I have three at this moment and for each of them I need to get closest time result.
Hope I made it clear, let me know if you need more info.
If I understand correctly, you can use ROW_NUMBER():
SELECT t.*
FROM (SELECT t.*,
ROW_NUMBER() OVER (PARTITION BY TYPE_COLUMN ORDER BY DATE_EFFECTIVE_COLUMN DESC) as seqnum
FROM TABLE1 t
WHERE KEY_COLUMN = 'NJCRF' AND
TYPE_COLUMN IN ('SCORE1', 'SCORE2', 'SCORE3') AND
DATE_EFFECTIVE_COLUMN <= '2016-09-17'
) t
WHERE seqnum = 1;
If you want three records per type, just use seqnum <= 3.
I like ROW_NUMBER() for this. You want to partition by TYPE, which will start the row count over for each type, then order by DATE_EFFECTIVE desc, and take only the highest date (the first row):
SELECT *
FROM (
SELECT *,
ROW_NUMBER() over (PARTITION BY TYPE_COLUMN ORDER BY DATE_EFFECTIVE_COLUMN desc) RN
FROM TABLE1
WHERE KEY_COLUMN = 'NJCRF'
AND TYPE_COLUMN IN ('SCORE1', 'SCORE2', 'SCORE3')
AND DATE_EFFECTIVE_COLUMN <= '2016-09-17'
) A
WHERE RN = 1
Related
Hopefully, someone can help me...
I'm trying to get the last two values from a row_number() window function. Let's say my results contain row numbers up to 6, for example. How would it be possible to get the rows where the row number is 5 and 6?
Let me know if it can be done with another window function or in another way.
Kind regards,
Using QUALIFY:
SELECT *
FROM tab
QUALIFY ROW_NUMBER() OVER(ORDER BY ... DESC) <= 2;
This approach could be further extended to get two rows per each partition:
SELECT *
FROM tab
QUALIFY ROW_NUMBER() OVER(PARTITION BY ... ORDER BY ... DESC) <= 2;
You can use top with order by desc like:
select top 2 row_number() over([partition by] [order by]) as rn
from table
order by rn desc
I'd say #Shmiel is the formal and elegant way, just in case, would be the same as :
WITH CTE AS
(SELECT product,
user_id,
ROW_NUMBER() OVER (PARTITION BY user_id order by product desc)
as RN
FROM Mytable)
SELECT product, user_id
FROM CTE
WHERE RN < 3;
You will use order by [order_condition] with "desc". And then you will use RN(row number) to select as many rows as you want
I need to select the data of all my customers with the records displayed in the image. But I need to get the most recent record only, for example I need to get the order # E987 for John and E888 for Adam. As you can see from the example, when I do the select statement, I get all the order records.
You don't mention the specific database, so I'll answer with a generic solution.
You can do:
select *
from (
select t.*,
row_number() over(partition by name order by order_date desc) as rn
from t
) x
where rn = 1
You can use analytical function row_number.
Select * from
(Select t.*,
Row_number() over (partition by customer_id order by order_date desc) as rn
From your_table t) t
Where rn = 1
Or you can use not exists as follows:
Select *
From yoir_table t
Where not exists
(Select 1 from your_table tt
Where t.customer_id = tt.custome_id
And tt.order_date > t.order_date)
You can do it with a subquery that finds the last order date.
SELECT t.*
FROM yoir_table t
JOIN (SELECT tt.custome_id,
MAX(tt.order_date) MaxOrderDate
FROM yoir_table tt
GROUP BY tt.custome_id) AS tt
ON t.custome_id = tt.custome_id
AND t.order_date = tt.MaxOrderDate
I am currently getting the output of the image below. I want to be able to retrieve the latest Turn Time. Essentially the MAX beginning date and MAX end date. How Should I structure my query ?
I think you just want order by:
select top (1) t.*
from t
order by enddate desc, beginning_date desc;
If you want this per id, then you can use window functions or top (1) with ties:
select top (1) t.*
from (select t.*,
row_number() over (partition by id order by enddate desc, beginning_date desc) as seqnum
from t
) t
where seqnum = 1;
You can use row_number()
select * from
(
select *,row_number() over(parition by id order by beginningdate desc) as rn
from tablename
)A where rn=1
For the larger turn time -
select * from
(
select *,row_number() over(parition by id order by turntime desc) as rn
from tablename
)A where rn=1
I have a table where first I need to select data by max(event_date) then need to
filter the data by max(event_sequence) then filter again by max(event_number)
I wrote following query which works but takes time.
Here the the query
SELECT DISTINCT a.stuid,
a.prog,
a.stu_prog_id,
a.event_number,
a.event_date,
a.event_sequence,
a.prog_status
FROM table1 a
WHERE a.event_date=
(SELECT max(b.event_date)
FROM table1 b
WHERE a.stuid=b.stuid
AND a.prog=b.prog
AND a.stu_prog_id=b.stu_prog_id)
AND a.event_seq=
(SELECT max(b.event_sequence)
FROM table1 b
WHERE a.stuid=b.stuid
AND a.prog=b.prog
AND a.stu_prog_id=b.stu_prog_id
AND a.event_date=b.event_date)
AND a.event_number=
(SELECT max(b.event_number)
FROM table1 b
WHERE a.stuid=b.stuid
AND a.prog=b.prog
AND a.stu_prog_id=b.stu_prog_id
AND a.event_date=b.event_date
AND a.event_sequence=b.event_sequence
I was wondering is there there a faster way to get the data?
I am using Oracle 12c.
You could try rephrasing your query using analytic functions:
SELECT
stuid,
prog,
stu_prog_id,
event_number,
event_date,
event_sequence,
prog_status
FROM
(
SELECT t.*,
RANK() OVER (PARTITION BY studio, prog, stu_prog_id
ORDER BY event_date DESC) rnk1,
RANK() OVER (PARTITION BY studio, prog, stu_prog_id, event_date
ORDER BY event_sequence DESC) rnk2,
RANK() OVER (PARTITION BY studio, prog, stu_prog_id, event_date, event_sequence
ORDER BY event_number DESC) rnk3
FROM table1 t
) t
WHERE rnk1 = 1 AND rnk2 = 1 AND rnk3 = 1;
Note: I don't actually know if you really need all three subqueries there. Adding sample data to your question might help someone else improve upon the solution I have given above.
I think you want a simple row_number() or rank():
select t1.*
from (select t1.*,
rank() over (partition by stuid, prog, stu_prog_id
order by event_date desc, event_sequence desc, event_number desc
) as seqnum
from table1 t1
) t1
where seqnum = 1;
If you have multiple records with EVENT_DATE, EVENT_SEQUENCE, EVENT_NUMBER as max respectively then in Tim's solution, Use DENSE_RANK or use the following to fetch the exact max and compare with original column data.
SELECT DISTINCT
A.STUID,
A.PROG,
A.STU_PROG_ID,
A.EVENT_NUMBER,
A.EVENT_DATE,
A.EVENT_SEQUENCE,
A.PROG_STATUS
FROM
(
SELECT
A.STUID,
A.PROG,
A.STU_PROG_ID,
A.EVENT_NUMBER,
A.EVENT_DATE,
A.EVENT_SEQUENCE,
A.PROG_STATUS,
MAX(A.EVENT_DATE) OVER(
PARTITION BY A.STUID, A.PROG, A.STU_PROG_ID
) AS MAX_EVENT_DATE,
MAX(A.EVENT_SEQUENCE) OVER(
PARTITION BY A.STUID, A.PROG, A.STU_PROG_ID, A.EVENT_DATE
) AS MAX_EVENT_SEQUENCE,
MAX(A.EVENT_NUMBER) OVER(
PARTITION BY A.STUID, A.PROG, A.STU_PROG_ID, A.EVENT_DATE, A.EVENT_SEQUENCE
) AS MAX_EVENT_NUMBER
FROM
TABLE1 A
) A
WHERE
A.MAX_EVENT_DATE = A.EVENT_DATE
AND A.MAX_EVENT_SEQUENCE = A.EVENT_SEQUENCE
AND A.MAX_EVENT_NUMBER = A.EVENT_NUMBER;
Cheers!!
As being an Oracle 12c user, you can use
[ OFFSET offset { ROW | ROWS } ]
[ FETCH { FIRST | NEXT } [ { rowcount | percent PERCENT } ]
{ ROW | ROWS } { ONLY | WITH TIES } ]
syntax as :
SELECT DISTINCT a.stuid,
a.prog,
a.stu_prog_id,
a.event_number,
a.event_date,
a.event_sequence,
a.prog_status
FROM table1 a
ORDER BY event_date DESC, event_sequence DESC, event_number DESC
FETCH FIRST 1 ROW ONLY;
where WITH TIES clause is not needed for your case, since you're looking for DISTINCT rows, and OFFSET is not needed either, since starting point is just the beginning of a descendingly ordered columns. Even, using the keyword ROW as ROWS is optional, even for the case of plural rows such as FETCH FIRST 5 ROW ONLY;
^^ --> ROWS without S
Demo
So I have a table that looks something like this:
Now, I want the max totalcst for both days, something like this:
I tried using different variations of max and the Row_number funtion but still can't seem to get the result I want. My query:
select date,pid,max(quan*cst), totalcst
from dbo.test1
group by date, pid
But this returns all the records. So if somebody can point me towards the right direction, that would be very helpful.
Thanks in advance!
ROW_NUMBER should work just fine:
WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER(PARTITION BY [date] ORDER BY totalcst)
FROM dbo.YourTable
)
SELECT [date],
pid,
totalcst
FROM CTE
WHERE RN = 1
;
Here is one simple way:
select t.*
from test1 t
where t.totalcst = (select max(t2.totalcst) from test1 t2 where t2.date = t.date);
This often has the best performance if you have an index on (date, totalcst). Of course, row_number()/rank() is also a very acceptable solution:
select t.*
from (select t.*, row_number() over (partition by date order by totalcst desc) as seqnum
from test1
) t
where seqnum = 1;