How to get elm time subscriptions x times per seconds - elm

In the elm-guide there is a section in Effects/Time which gives an example to return a subscription Time.every second.
In the documentation there seems to be only the granularity units millisecond, second, minute, etc...
Is there a way to get a subscription like 20 per second or another subgranularity?
What is the best way to achieve something like that.

Time is just an alias for Float, so you can do numeric operations on it. If you want a subscription to fire 20 times a second, just make sure it fires every 1/20 of a second.
In other words: Time.every (second / 20.0)

Related

Using Optaplanner for long trip planning of a fleet of vehicles in a Vehicle Routing Problem (VRP)

I am applying the VRP example of optaplanner with time windows and I get feasible solutions whenever I define time windows in a range of 24 hours (00:00 to 23:59). But I am needing:
Manage long trips, where I know that the duration between leaving the depot to the first visit, or durations between visits, will be more than 24 hours. So currently it does not give me workable solutions, because the TW format is in 24 hour format. It happens that when applying the scoring rule "arrivalAfterDueTime", always the "arrivalTime" is higher than the "dueTime", because the "dueTime" is in a range of (00:00 to 23:59) and the "arrivalTime" is the next day.
I have thought that I should take each TW of each Customer and add more TW to it, one for each day that is planned.
Example, if I am planning a trip for 3 days, then I would have 3 time windows in each Customer. Something like this: if Customer 1 is available from [08:00-10:00], then say it will also be available from [32:00-34:00] and [56:00-58:00] which are the equivalent of the same TW for the following days.
Likewise I handle the times with long, converted to milliseconds.
I don't know if this is the right way, my consultation would be more about some ideas to approach this constraint, maybe you have a similar problematic and any idea for me would be very appreciated.
Sorry for the wording, I am a Spanish speaker. Thank you.
Without having checked the example, handing multiple days shouldn't be complicated. It all depends on how you model your time variable.
For example, you could:
model the time stamps as a long value denoted as seconds since epoch. This is how most of the examples are model if I remember correctly. Note that this is not very human-readable, but is the fastest to compute with
you could use a time data type, e.g. LocalTime, this is a human-readable time format but will work in the 24-hour range and will be slower than using a primitive data type
you could use a date time data tpe, e.g LocalDateTime, this is also human-readable and will work in any time range and will also be slower than using a primitive data type.
I would strongly encourage to not simply map the current day or current hour to a zero value and start counting from there. So, in your example you denote the times as [32:00-34:00]. This makes it appear as you are using the current day midnight as the 0th hour and start counting from there. While you can do this it will affect debugging and maintainability of your code. That is just my general advice, you don't have to follow it.
What I would advise is to have your own domain models and map them to Optaplanner models where you use a long value for any time stamp that is denoted as seconds since epoch.

How can I measure instantaneuous bandwidth using ns-3?

I have looked into FlowMon which counts packets over the entire simulation interval. Can I specify shorter intervals and many such intervals? Are there other options to measure instantaneous bandwidth (or at least, bandwidth averaged over short intervals like 1ms) in ns-3?
You could still use FlowMon for this. FlowMon accumulates the number of packets as you progress through the simulation so at different time intervals you can get values such as txBytes and do some calculations with that.
Take a look at NS3 scheduling, and try using that
Simulator::Schedule(Seconds(1), &StatsCalculationCallback);
Where the StatsCalculationsCallback is the function where you would calculate the difference between the value now and value before to get for that short interval. Then in the StatsCalculationsCallback function you would then also need to reschedule again for the next interval.

How to make a query that computes the difference of two timefield objects/attributes in Django?

Suppose I have a model that has four attributes:
name,
time in,
time out,
date.
time in and time out are timefield objects. Now, I want to write a django query that tells me who was available in the office for most time duration in a given range.
I am not sure how do I calculate the time difference (time out - time in) on the fly. Do I need to put another attribute like time duration? I was hoping to avoid that.
I don't think it's possible using vanilla Django ORM.
Two solutions come to my mind:
Fetch the results in RAM and do the computation.
Add a new field to take care of the duration into your model. You can first do an update query to calculate the duration for all rows in your db.
Class.objects.update(duration=F('time_out')-F('time_in'))
And then you can order_by duration and get the first entry as your max duration.

SSAS. Long time processing in second time with ProcessFull

I use ProcessFull parameter for processing one of my dimension. First time processing took 45 min. But second time it takes an hour or even more.
Why second processing takes more time than first one?
This doesnt sound like normal SSAS behaviour. I would suspect some external factor.

Triggering some code on every nth iteration of an NSTimer tick

I'm relatively new to coding, and wondering if there's a conventional way to have some code execute on every nth iteration of a loop (in this case, an NSTimer ticking).
I'm using a CADisplayLink and it updates however many times per second, 40, 50, whatever. If I want to execute some code on every, say, 500 of those loops, is there a standard way to do so? I assume I could put something together with the modulo operator and an integer, but is there a better / more normalized way that a new coder should know?
Extra clarity (though I'm sure this is a fairly common thing to do..): I have a timer that ticks 60 times per second, but I only want to do something with every 10th iteration. I already know that I can use a modulo and an integer to do this, but I want to know if there's any other convention for handling a situation like this.
Thanks in advance!
Establish a dedicated timer for the right interval.
Regardless of whether you're using NSTimer or CADisplayLink, timer calls can be coalesced and offset if they take too long. If you have a display link that takes 20 frames to run, it only gets called thrice every second (given the refresh interval is 60 frames per second). And if you have a timer set to run every second that at one instance takes a bit more than two and a half seconds to run, it will have "ate" its next iteration and will run the next iteration half a second too late.
Because of this, your timer can get out of sync if you only count timer calls. To do something repeatedly on an interval, having a timer set to that interval is the absolute best approximation.
Having a second timer like this is not a performance problem unless you do very many timers, in which case you should standardize on one tick timer and have events scheduled for specific points in time (which still isn't the same as counting previous iterations).