Can somebody help me figure out if there is a way for the query below:
I have an internal table with one column with 69 records.
I want all these 69 records to be populated into a variant and get saved so that with this variant and the values saved in it I can run a particular program
How can I populate these values ?
Your question is a bit unclear for me.
Do you speak about two programs or one program?
What's the parameter you want to fill in the variant?
I'll just give you some hints - depending on your situation you must pick the correct parts.
I have an internal table with one column with 69 records.
How is the internal table filled?
I want all these 69 records to be populated into a variant and get saved so that with this variant and the values saved in it I can run a particular program
You have a program and you want to save a selection in a variant. So you need some parameters for the selection screen.
You want a table, so you need a SELECT-OPTION.
To define a SELECT-OPTION you need a DDIC-reference (you must say, what kind of field you want.). In the following example I use a material number (MARA-MATNR).
So you program contains something like:
TABLES mara.
SELECT-OPTIONS: s_matnr FOR mara-matnr.
With this you would get:
You can define ranges (from-to) and list of values. As you want only single values, you need something like:
SELECT-OPTIONS: s_matnr FOR mara-matnr NO INTERVALS.
Now you get:
When you push (1) you can enter values.
With (2) you can load from an external file,
with (3) you can load values from clipboard.
So you can fill your values and store the selection in a variant.
When you execute your program, the data is stored in a ranges table:
Now you can loop on this table and copy the S_MATNR-LOW value into your internal table for further processing.
If I misunderstood you question and you want to create a variant dynamically, then take a look on function module RS_VARIANT_ADD (or RS_VARIANT_COPY,RS_VARIANT_CHANGE...)
You could always put the values in TVARVC, either manually or via code. Then specify the TVARVC variable in the variant definition.
Related
I’m new to Pentaho and I’m currently having an issue with mapping specific row values to an ID.
I have a data file with around 30 columns, one of which is for currencies (USD, GBP, AUD, etc).
The main objective is to have the user select up to 8 (minimum of 1) currencies and map them to a corresponding ID 1-8. All other currencies not in the specified 8 will be mapped with an ID of 9.
The final step is to then output the original data set, along with the IDs.
I’m pretty sure I’m making this way harder than it should, but here is what I have at the moment.
I have created a job where the first step is to set the variables for my 8 currencies, selectionOne -> AUD, selectionTwo -> GBP, …, selectionEight -> JPY.
I then have a transformation to read the data from the file and use the copy rows to result step.
Following that I have a second job called for-each which is my loop for checking the current currency in the row.
Within this job I have two transformations, one called set-current, one called map-currencies.
set-current simply uses the get rows from result step (to grab the data from the first transformation). I then use the set variable step to set the current currency to the value in currency field. This works fine, as each pass through in the loop changes the current variable to the correct value.
Map-currencies is where I’m having the most issues.
The goal is to use the filter row step to compare the current currency against the original 8 selected currencies, and then using the value mapper step to map it to an ID, before outputting the csv file.
The main issue here, is that I can’t use my original variables in the filter or value mapper.
So, what I’ve done here is use the get variables step to retrieve the variables and named them: one, two, three, …, eight. This allows me to bypass the filtering issue, but they don’t seem to work for the value mapper, which is the all important step.
The second issue is that when the file is output it only outputs one value (because of the loop), selecting the append option works, but this could be a problem if the job is run more than once.
However, the priority here is the mapping issue.
I understand that this is rather long, and perhaps a tad confusing, but I will greatly appreciate any help on this, even if it’s an entirely new approach 😊.
Like I said, I’m probably making it harder than it should be.
Thanks for your time.
Edit for AlainD
Input example
Output example
This should be doable in a single transformation using the Stream Lookup step.
Text File Input is your main file, Property input reads your property file into Key and Value columns. You could use a normal text file with two columns instead of the property input.
Below are the settings of the Stream lookup. Note the default value "9" for records that are not found in the lookup stream.
I am new on VBA, I am creating a script to generate a report from a DB, I have been able to assemble a general draft of my report but I need to insert a table into an existing cell inside a word document, I have been surfing around but I am unable either to do a websearch with the correct terms in order to find some guidance on how to achieve this, If I am able to do it with my mouse I am sure I am able to do it through scripting, any resources that would help me in the right direction will be deeply appreciated.
Ok I found a way, The secret is in the Range, to specify where do you want your nested table to be placed.
so, I am using Powershell so the syntax might vary a little
For creating the Table in the Document (assuming you already have a created document, if not you are missing that part which I am not going through since they already are several question/answer pairs on that subject).
$TableX = $oDoc.Tables.Add($oDoc.Bookmarks("TableX").Range, 4, 3)
So TableX is our actual table, then we are telling word to use the helper method on the oDoc (Which is the name of our document object) to add a table, with a Bookmark named TableX (I will again not do a large explanation on this one, just for practical purposes, we name the Bookmark so we can reference to the table by Bookmark name later if we need to add data to it or manipulate it in any way we need) and at the same time we are calling to the method Range which is going to tell the Document Object where do we want the table to be placed, since we have not defined the range explicitly it will insert it in the next available line on the document,
Finally we specify how many rows and columns we would like in the table.
That is what we need for creating a table, now the tricky part, how do we insert a nested table, and moreover how do we specify where do we want this second table to be nested.
Well, with this:
$oNestedTable = $oDoc.Tables.Add($TableX.Cell(4, 2).Range,7,3)
We name our nested table oNestedTable, then we are calling the same helper method we called before to add a new table to the document, but wait, look carefully at the differences, the range part of the command is pointing to a specific cell on in our first table, that is in the fourth row within the second cell, it is there where we are explicitly telling the document to insert a new table with 7 rows and 3 columns.
I hope this gives you some bare minimum guidance.
Regards
en
I have a very large array of data with many columns that display different outputs for the values presented. I would like to add a row above the data that will display the most common occurring value or word below.
Generally I would like to have each top of the column (right under the column label in row 1) have the most common value below. I will then use this value for various data analysis functions!
Is this possible, and if so, how? Preferably this will not require VBA, but simply a short code in the cell.
One caveat: The exact values may vary, so there is no set list where I can say "it will be one of these."
Any ideas appreciated!
Try a series of =COUNTIF(A:A,"VALUE TO SEARCH") functions if you want to stay away from VBA.
Otherwise, the best method would be to iterate through each column via VBA. With this method, you can even count the "varying" values and return the count and/or the value itself.
http://www.excel-easy.com/examples/most-frequently-occurring-word.html
This is a single formula you would write at the top of each column. Does not require VBA. You can replace the set range to an entire column, such as (A:A) instead of (A1:A7).
If you mean an array as in a data type, it could work differently but it depends what you're trying to do.
With data from A3 through A16, in A2 enter:
=INDEX($A$3:$A$16,MODE(MATCH($A$3:$A$16,$A$3:$A$16,0)))
This will work for text as well as numbers. Adjust this to match the column size.
I am exporting a file from a system as .csv. My aim is to link to this file as a table (which matches the output field for field) and then run the queries and export.
The problem I am having is that, upon import, all the fields are 255 bytes wide rather than what they need to be.
Here's what I've tried so far:
I've looked at ALTER TABLE but I cannot run multiple ALTER TABLE statements in one macro.
I've also tried appending the table into another table with the correct structure but it seems to overwrite the structure.
I've also tried using the Left function with the appropriate field length, but when I try to export, I pretty much just see 5 bytes per column.
What I would like is a suggestion as to what is the best path to take given my situation. I am not able to amend the initial .csv export, and I would like to avoid VBA if possible, as I am not at all familiar with it.
You don't really need to worry about the size of Text fields in an Access linked table that is connected to a CSV file. Access simply assigns each Text field the largest possible maximum size: 255. It does not mean that every value is actually 255 characters long, it just means that any values in those fields can be at most 255 characters long.
Even if you could change the structure of the linked table (which you can't), it wouldn't make any real difference except to possibly truncate longer Text values, and you could easily do that with a String function. For example, if a particular field had to be restricted to 15 characters then you could simply use Left([fieldName], 15) as a query column or as the control source in a report.
In the end, as the data set is not that large, I have set this up to append from my source data into a table with the correct structure. I can now run my processes against this table as per normal.
This is probably one of those that is so simple I can't see it. I have a string variable called Market. The variable is user chosen and is the exact same name as one of many tables in my dataset. Basically I am having the user choose which table they want in a combobox, then I want to use that variable to access the table. So if the user picks "Market1" then I want to open the table named Market1.
I am simplifying here, but need to know how to open:
For ds.<variable here>.rows.count - 1
'perform steps
Next
How do I inject the variable correctly? Thanks ahead of time!
Dataset has Tables property, which accepts table name as a parameter. So in your case if string variable Market holds table name, you can access the table by referring to ds.Tables(Market)