Let's say I have a database with rows like this
ID PNR NAME
1 35 Television
2 35 Television, flat screen
3 35 Television, CRT
4 87 Hat
5 99 Cup
6 99 Cup, small
I want to select each individual type of item (television, hat, cup) - but for the ones that have multiple entries in PNR I only want to select the one with the shortest NAME. So the result set would be
ID PNR NAME
1 35 Television
4 87 Hat
5 99 Cup
How would I construct such a query using SQLite? Is it even possible, or do I need to do this filtering in the application code?
Since SQLite 3.7.11, you can use MIN() or MAX() to select a row in a group:
SELECT ID,
PNR,
Name,
min(length(Name))
FROM MyTable
GROUP BY PNR;
You can use MIN(length(name))-aggregate function to find out the minimum length of several names; the slightly tricky thing is to get corresponding ID and NAME into the result. The following query should work:
select mt1.ID, mt1.PNR, mt1.Name
from MyTable mt1 inner join (
select pnr, min(length(Name)) as minlength
from MyTable group by pnr) mt2
on mt1.pnr = mt2.pnr and length(mt1.Name) = mt2.minlength
Related
I have a dataset that I need to query from and aggregate the selected records based on a string similarity.
For example a simple SELECT, COUNT query can return a set of records like:
NAME
COUNT
CAR
6
CAR 1
12
CAR 22
2
CAR 45
9
Van 2
4
Van 22
5
Van 12
16
UNKNOWN
6
I want the result to be aggregate by a substring as:
NAME
COUNT
CAR
29
VAN
25
UNKOWN
6
A sample of the current query I have is:
SELECT "vehicle_name" AS "NAME", count(*) AS "Count"
FROM "vehicles"
WHERE ("registered" = 'true'GROUP BY "public"."players"."device_name"
ORDER BY "vehicle_name" ASC
You can use the metabase regexextract function to solve your problem, matching the first word by exploiting the start of string symbol.
SELECT REGEXEXTRACT([NAME], "^[A-Za-z]+") AS "NAME",
SUM([COUNT]) AS "COUNT"
FROM vehicles
GROUP BY REGEXEXTRACT([NAME], "^[A-Za-z]+")
Does it solve your problem?
Please try like this
SELECT
SUM(COUNT),
SUBSTRING(vehicle_name,1,ISNULL(NULLIF(PATINDEX('%[^A-Za-z.''0-9]%',LTRIM(RTRIM(vehicle_name))),0)-1,LEN(vehicle_name))) AS Value
FROM
vehicles
GROUP BY SUBSTRING(vehicle_name,1,ISNULL(NULLIF(PATINDEX('%[^A-Za-z.''0-9]%',LTRIM(RTRIM(vehicle_name))),0)-1,LEN(vehicle_name)))
I am hoping someone can advise on the below please?
I have some code (below), it is pulling the data I need with no issues. I have been trying (in vain) to add a COUNT function in here somewhere. The output I am looking for would be a count of how many orders are assigned to each agent. I tried a few diffent things based on other questions but can't seem to get it correct. I think I am placing the COUNT 'Agent' statement and the GROUP BY in the wrong place. Please can someone advise? (I am using Oracle SQL Developer).
select
n.ordernum as "Order",
h.employee as "Name"
from ordermgmt n, orderheader h
where h.ordernum = n.ordernum
and h.employee_group IN ('ORDER.MGMT')
and h.employee is NOT NULL
and n.percentcomplete = '0'
and h.order_status !='CLOSED'
Output I am looking for would be, for example:
Name Orders Assigned
Bob 3
Peter 6
John 2
Thank you in advance
Name
Total
49
49
49
49
49
John
4
John
4
John
4
John
4
Peter
2
Peter
2
Bob
3
Bob
3
Bob
3
for example. so there are 49 blank rows summed up as 49 in the Total column. I did not add the full 49 blank columns to save space
Would be easier with sample data and expected output, but maybe you are looking for something like this
select
n.ordernum as "Order",
h.employee as "Name",
count(*) over (partition by h.employee) as OrdersAssigned
from ordermgmt n, orderheader h
where h.ordernum = n.ordernum
and h.employee_group IN ('ORDER.MGMT')
and h.employee is NOT NULL
and n.percentcomplete = '0'
and h.order_status !='CLOSED'
The use of COUNT (as other aggregate functions) is simple.
If you want to add an aggregate function, please group all scalar fields in the GROUP BY clause.
So, in the SELECT you can manage field1, field2, count(1) and so on but you must add in group by (after where conditions) field1, field2
Try this:
select
h.employee as "Name",
count(1) as "total"
from ordermgmt n, orderheader h
where h.ordernum = n.ordernum
and h.employee_group IN ('ORDER.MGMT')
and h.employee is NOT NULL
and n.percentcomplete = '0'
and h.order_status !='CLOSED'
GROUP BY h.employee
I have a query that collects many different columns, and I want to include a column that sums the price of every component in an order. Right now, I already have a column that simply shows the price of every component of an order, but I am not sure how to create this new column.
I would think that the code would go something like this, but I am not really clear on what an aggregate function is or why I get an error regarding the aggregate function when I try to run this code.
SELECT ID, Location, Price, (SUM(PriceDescription) FROM table GROUP BY ID WHERE PriceDescription LIKE 'Cost.%' AS Summary)
FROM table
When I say each component, I mean that every ID I have has many different items that make up the general price. I only want to find out how much money I spend on my supplies that I need for my pressure washers which is why I said `Where PriceDescription LIKE 'Cost.%'
To further explain, I have receipts of every customer I've worked with and in these receipts I write down my cost for the soap that I use and the tools for the pressure washer that I rent. I label all of these with 'Cost.' so it looks like (Cost.Water), (Cost.Soap), (Cost.Gas), (Cost.Tools) and I would like it so for Order 1 it there's a column that sums all the Cost._ prices for the order and for Order 2 it sums all the Cost._ prices for that order. I should also mention that each Order does not have the same number of Costs (sometimes when I use my power washer I might not have to buy gas and occasionally soap).
I hope this makes sense, if not please let me know how I can explain further.
`ID Location Price PriceDescription
1 Park 10 Cost.Water
1 Park 8 Cost.Gas
1 Park 11 Cost.Soap
2 Tom 20 Cost.Water
2 Tom 6 Cost.Soap
3 Matt 15 Cost.Tools
3 Matt 15 Cost.Gas
3 Matt 21 Cost.Tools
4 College 32 Cost.Gas
4 College 22 Cost.Water
4 College 11 Cost.Tools`
I would like for my query to create a column like such
`ID Location Price Summary
1 Park 10 29
1 Park 8
1 Park 11
2 Tom 20 26
2 Tom 6
3 Matt 15 51
3 Matt 15
3 Matt 21
4 College 32 65
4 College 22
4 College 11 `
But if the 'Summary' was printed on every line instead of just at the top one, that would be okay too.
You just require sum(Price) over(Partition by Location) will give total sum as below:
SELECT ID, Location, Price, SUM(Price) over(Partition by Location) AS Summed_Price
FROM yourtable
WHERE PriceDescription LIKE 'Cost.%'
First, if your Price column really contains values that match 'Cost.%', then you can not apply SUM() over it. SUM() expects a number (e.g. INT, FLOAT, REAL or DECIMAL). If it is text then you need to explicitly convert it to a number by adding a CAST or CONVERT clause inside the SUM() call.
Second, your query syntax is wrong: you need GROUP BY, and the SELECT fields are not specified correctly. And you want to SUM() the Price field, not the PriceDescription field (which you can't even sum as I explained)
Assuming that Price is numeric (see my first remark), then this is how it can be done:
SELECT ID
, Location
, Price
, (SELECT SUM(Price)
FROM table
WHERE ID = T1.ID AND Location = T1.Location
) AS Summed_Price
FROM table AS T1
to get exact result like posted in question
Select
T.ID,
T.Location,
T.Price,
CASE WHEN (R) = 1 then RN ELSE NULL END Summary
from (
select
ID,
Location,
Price ,
SUM(Price)OVER(PARTITION BY Location)RN,
ROW_number()OVER(PARTITION BY Location ORDER BY ID )R
from Table
)T
order by T.ID
This is how my query results look like currently. How can I get the MAX() value for each unique id ?
IE,
for 5267139 is 8.
for 5267145 is 4
5267136 5
5267137 8
5267137 2
5267139 8
5267139 5
5267139 3
5267141 4
5267141 3
5267145 4
5267145 3
5267146 1
5267147 2
5267152 3
5267153 3
5267155 8
SELECT DISTINCT st.ScoreID, st.ScoreTrackingTypeID
FROM ScoreTrackingType stt
LEFT JOIN ScoreTracking st
ON stt.ScoreTrackingTypeID = st.ScoreTrackingTypeID
ORDER BY st.ScoreID, st.ScoreTrackingTypeID DESC
GROUP BY will partition your table into separate blocks based on the column(s) you specify. You can then apply an aggregate function (MAX in this case) against each of the blocks -- this behavior applies by default with the below syntax:
SELECT First_column, MAX(Second_column) AS Max_second_column
FROM Table
GROUP BY First_column
EDIT: Based on the query above, it looks like you don't really need the ScoreTrackingType table at all, but leaving it in place, you could use:
SELECT st.ScoreID, MAX(st.ScoreTrackingTypeID) AS ScoreTrackingTypeID
FROM ScoreTrackingType stt
LEFT JOIN ScoreTracking st ON stt.ScoreTrackingTypeID = st.ScoreTrackingTypeID
GROUP BY st.ScoreID
ORDER BY st.ScoreID
The GROUP BY will obviate the need for DISTINCT, MAX will give you the value you are looking for, and the ORDER BY will still apply, but since there will only be a single ScoreTrackingTypeID value for each ScoreID you can pull it out of the ordering.
Lets say I have the following data in the Employee table: (nothing more)
ID FirstName LastName x
-------------------------------------------------------------------
20 John Mackenzie <A>te</A><b>wq</b><a>342</a><d>rt21</d>
21 Ted Green <A>re</A><b>es</b><1>t34w</1><4>65z</4>
22 Marcy Nate <A>ds</A><b>tf</b><3>fv 34</3><6>65aa</6>
I need to search in the X column and get highest number in <> these brackets
What sort of SELECT statement can get me, for example, the number 6 like in <6>, in the x column?
This type of query generally works on finding patterns, I consider that the <6> is at the 9th position from left.
Please note if the pattern changes the below query will not work.
SELECT A.* FROM YOURTABLE A INNER JOIN
(SELECT TOP 1 ID,Firstname,Lastname,SUBSTRING(X,LEN(X)-9,1) AS [ORDER]
FROM YOURTABLE
WHERE ISNUMERIC(SUBSTRING(X,LEN(X)-9,1))=1
ORDER BY SUBSTRING(X,LEN(X)-9,1))B
ON
A.ID=B.ID AND
A.FIRSTNAME=B.FIRSTNAME AND
A.LASTNAME=B.LASTNAME