I have a table in oracle 10g and I want to get the last value of specified column of a table based on some conditions. How to write the query for this in NetBeans for exp. Suppose I want to get the last value of balance column where student id = 101, class = nursery and academic year = 2014
You can use ROWNUM to limit the number of results.
And to get the last records, you have to sort the records based on your condition.
An example of your query can be.
select * from (
select * from student
where class='nursery' and academic_year=2014
order by id desc
) where ROWNUM=1;
This will sort the records in DESCENDING order by id and returns the first record from the results.
Updated
As mentioned by MT0 in comments, ROWNUM value will be assigned before ORDER BY clause. Thus, may result in incorrect result.
I have corrected the above query, and now
subquery will sort the records in descending order of id.
selection will be done on the results. (WHERE ROWNUM=1)
Starting with oracle 10g you can use the LAST_VALUE function. Assuming if "balance" per student can be ordered by some time variable, and if student_id is unique within academic_year, class:
SELECT student_id, academic_year,class, LAST_VALUE(balance) OVER
(PARTITION BY student_id, academic_year,class ORDER BY time_variable desc) AS
last_balance from student where student_id ...;
The first row of this query contains the most recent value of "balance" (last_balance)
I am using a little bit different query. Don't know why, but always put rownum in subquery as a new column
select m.* from (
select rownum as rn, t.* from student t
where t.class='nursery' and t.academic_year=2014
order by t.di desc) m
where m.rn=1;
Related
I am trying to pull some specific information from an access control database.
I have a query providing results spanning several days. For a specific day, I need to get the first record of each person for that specific day. I have totally muddled the entire bit, hence my questions
This is the code used to pull the initial query
Select
Message.TimeStamp_SPM,
Message.FirstName,
Message.LastName,
Message.CardNumber,
Message.MessageDescription,
Message.Description,
Department.Description As Description1
From
Message Inner Join
CardHolder On CardHolder.CardHolderID = Message.CardHolderID Inner Join
Department On CardHolder.DepartmentID = Department.DepartmentID
Where
Message.TimeStamp_SPM > Convert(datetime,'2021-03-02',120) And
Message.TimeStamp_SPM < Convert(datetime,'2021-03-03',120) And
Message.Description Not Like '%Truck%'
From this query I need to display the obtain the first record of each person for that specific date. Any advice on the most efficient way to obtain the desired result?
From this query I need to display the obtain the first record of each person for that specific date.
Assuming "person" is CardHolderId, then include that in your query. You can then use window functions to get the most recent record for each CardHolderId:
with cte as (
<your query here with CardHolderId>
)
select cte.*
from (select cte.*,
row_number() over (partition by CardHolderID order by TimeStamp_SPM desc) as seqnum
from cte
) cte
where seqnum = 1;
Let's say I have an Oracle table with measurements in different categories:
CREATE TABLE measurements (
category CHAR(8),
value NUMBER,
error NUMBER,
created DATE
)
Now I want to find the "best" row in each category, where "best" is defined like this:
It has the lowest errror.
If there are multiple measurements with the same error, the one that was created most recently is the considered to be the best.
This is a variation of the greatest N per group problem, but including two columns instead of one. How can I express this in SQL?
Use ROW_NUMBER:
WITH cte AS (
SELECT m.*, ROW_NUMBER() OVER (PARTITION BY category ORDER BY error, created DESC) rn
FROM measurements m
)
SELECT category, value, error, created
FROM cte
WHERE rn = 1;
For a brief explanation, the PARTITION BY clause instructs the DB to generate a separate row number for each group of records in the same category. The ORDER BY clause places those records with the smallest error first. Should two or more records in the same category be tied with the lowest error, then the next sorting level would place the record with the most recent creation date first.
I have table in Access Database with the following columns
ProductID|ProductName|StoreID|StoreName|AuditRating|AuditVisit|NextAuditDue
100100 |Calculator |SC12345|CrawlyRoad| B |11/12/2013|21/02/2014
100100 |Calculator |SC12345|CrawlyRoad| A |11/12/2014|30/04/2015
100100 |Calculator |SC12345|CrawlyRoad| C |16/12/2015|24/01/2017
I need to make a query which will only give me the distinct record where the AuditVisit date is maximum like in this case I only want the third row
100100 |Calculator |SC12345|CrawlyRoad| C |16/12/2015|24/01/2017
I have used group by but as I need to bring all the columns I am getting all the records as the AuditRating column is different in all three rows.
You can use TOP 1:
Select Top 1 * From YourTable Order By AuditVisit Desc
You don't want to have groups, so why use group by?
SELECT
*
FROM your_table
WHERE AuditVisit = (SELECT MAX(AuditVisit) FROM your_table)
Pretty self-explaining, I think.
If you want one record in MS Access, then you need to be very careful with SELECT TOP. It is really SELECT TOP WITH TIES.
Hence, the obvious answer of:
Select Top 1 *
From t
Order By AuditVisit Desc;
would return multiple rows if multiple rows have the same date. If you really want one, then you want to add a unique column as the last key in the order by:
Select Top 1 *
From t
Order By AuditVisit Desc, id;
I don't see such a key in your data, although you might have a combination of columns that are unique in each row (multiple columns can be added to the ORDER BY).
In MS Access -- even more so than in other databases -- primary keys are important on tables for this reason.
I have a table Orders(id_trip, id_order), table Trip(id_hotel, id_bus, id_type_of_trip) and table Hotel(id_hotel, name).
I would like to get name of the most frequent hotel in table Orders.
SELECT hotel.name from Orders
JOIN Trip
on Orders.id_trip = Trip.id_hotel
JOIN hotel
on trip.id_hotel = hotel.id_hotel
FROM (SELECT hotel.name, rank() over (order by cnt desc) rnk
FROM (SELECT hotel.name, count(*) cnt
FROM Orders
GROUP BY hotel.name))
WHERE rnk = 1;
The "most frequently occurring value" in a distribution is a distinct concept in statistics, with a technical name. It's called the MODE of the distribution. And Oracle has the STATS_MODE() function for it. https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions154.htm
For example, using the EMP table in the standard SCOTT schema, select stats_mode(deptno) from scott.emp will return 30 - the number of the department with the most employees. (30 is the department "name" or number, it is NOT the number of employees in that department!)
In your case:
select stats_mode(h.name) from (the rest of your query)
Note: if two or more hotels are tied for "most frequent", then STATS_MODE() will return one of them (non-deterministic). If you need all the tied values, you will need a different solution - a good example is in the documentation (linked above). This is a documented flaw in Oracle's understanding and implementation of the statistical concept.
Use FIRST for a single result:
SELECT MAX(hotel.name) KEEP (DENSE_RANK FIRST ORDER BY cnt DESC)
FROM (
SELECT hotel.name, COUNT(*) cnt
FROM orders
JOIN trip USING (id_trip)
JOIN hotel USING (id_hotel)
GROUP BY hotel.name
) t
Here is one method:
select name
from (select h.name,
row_number() over (order by count(*) desc) as seqnum -- use `rank()` if you want duplicates
from orders o join
trip t
on o.id_trip = t.id_trip join -- this seems like the right join condition
hotels h
on t.id_hotel = h.id_hotel
) oth
where seqnum = 1;
** Getting the most recent statistical mode out of a data sample **
I know it's more than a year, but here's my answer. I came across this question hoping to find a simpler solution than what I know, but alas, nope.
I had a similar situation where I needed to get the mode from a data sample, with the requirement to get the mode of the most recently inserted value if there were multiple modes.
In such a case neither the STATS_MODE nor the LAST aggregate functions would do (as they would tend to return the first mode found, not necessarily the mode with the most recent entries.)
In my case it was easy to use the ROWNUM pseudo-column because the tables in question were performance metric tables that only experienced inserts (not updates)
In this oversimplified example, I'm using ROWNUM - it could easily be changed to a timestamp or sequence field if you have one.
SELECT VALUE
FROM
(SELECT VALUE ,
COUNT( * ) CNT,
MAX( R ) R
FROM
( SELECT ID, ROWNUM R FROM FOO
)
GROUP BY ID
ORDER BY CNT DESC,
R DESC
)
WHERE
(
ROWNUM < 2
);
That is, get the total count and max ROWNUM for each value (I'm assuming the values are discrete. If they aren't, this ain't gonna work.)
Then sort so that the ones with largest counts come first, and for those with the same count, the one with the largest ROWNUM (indicating most recent insertion in my case).
Then skim off the top row.
Your specific data model should have a way to discern the most recent (or the oldest or whatever) rows inserted in your table, and if there are collisions, then there's not much of a way other than using ROWNUM or getting a random sample of size 1.
If this doesn't work for your specific case, you'll have to create your own custom aggregator.
Now, if you don't care which mode Oracle is going to pick (your bizness case just requires a mode and that's it, then STATS_MODE will do fine.
Say that I have some SELECT statement:
SELECT id, name FROM people
ORDER BY name ASC;
I have a few million rows in the people table and the ORDER BY clause can be much more complex than what I have shown here (possibly operating on a dozen columns).
I retrieve only a small subset of the rows (say rows 1..11) in order to display them in the UI. Now, I would like to solve following problems:
Find the number of a row with a given id.
Display the 5 items before and the 5 items after a row with a given id.
Problem 2 is easy to solve once I have solved problem 1, as I can then use something like this if I know that the item I was looking for has row number 1000 in the sorted result set (this is the Firebird SQL dialect):
SELECT id, name FROM people
ORDER BY name ASC
ROWS 995 TO 1005;
I also know that I can find the rank of a row by counting all of the rows which come before the one I am looking for, but this can lead to very long WHERE clauses with tons of OR and AND in the condition. And I have to do this repeatedly. With my test data, this takes hundreds of milliseconds, even when using properly indexed columns, which is way too slow.
Is there some means of achieving this by using some SQL:2003 features (such as row_number supported in Firebird 3.0)? I am by no way an SQL guru and I need some pointers here. Could I create a cached view where the result would include a rank/dense rank/row index?
Firebird appears to support window functions (called analytic functions in Oracle). So you can do the following:
To find the "row" number of a a row with a given id:
select id, row_number() over (partition by NULL order by name, id)
from t
where id = <id>
This assumes the id's are unique.
To solve the second problem:
select t.*
from (select id, row_number() over (partition by NULL order by name, id) as rownum
from t
) t join
(select id, row_number() over (partition by NULL order by name, id) as rownum
from t
where id = <id>
) tid
on t.rownum between tid.rownum - 5 and tid.rownum + 5
I might suggest something else, though, if you can modify the table structure. Most databases offer the ability to add an auto-increment column when a row is inserted. If your records are never deleted, this can server as your counter, simplifying your queries.