Hi I have a table below;
ID length
1 1050
1 1000
1 900
1 600
2 545
2 434
3 45
3 7
4 5
I need an SQL code to make the below table
ID IDK length
1 1 1050
1 2 1000
1 3 900
1 4 600
2 1 545
2 2 434
3 1 45
3 2 7
4 1 5
IDK is the new column to reindexing the same ID according to ascending order of length.
Thank you very much
This is a pain in MS Access. Here is one way using a correlated subquery:
select t.*,
(select count(*)
from foo as t2
where t2.id = t.id and t2.length >= t.length
) as idk
from foo as t;
Related
I have a table like this. I'm looking for a clean way in SQL to create a new column with the average between the Column 2 values for the rows where Column 1 equals 1 and 2 for each id.
I have some ideas on gross ways to do this, but I am looking for a straightforward solution since this seems like it should not be too difficult.
ID
Column 1
Column 2
1
1
100
1
2
75
1
3
50
2
1
45
2
2
90
2
3
60
Use window function avg with filtering.
select *,
avg(column2)
filter (where column1 in (1,2))
over (partition by id) as avrg
from the_table;
id
column1
column2
avrg
1
1
100
87.50
1
2
75
87.50
1
3
50
87.50
2
1
45
67.50
2
2
90
67.50
2
3
60
67.50
db-fiddle
My data has the following Structure
ID
Month
Year
Revenue
1
1
20
860
1
2
20
22
1
5
20
339
2
3
20
12098
3
3
20
12
3
4
20
10
3
6
20
9
3
7
20
122
3
8
20
11
There are 1000s of IDs and I want to select a random sample of 100 IDs. So if I randomly select ID 3, I need all rows of data for ID 3. I have to use SQL for this. I welcome any suggestions.
You can use following query.
For MS-Sql
Select top 100 * from table_name where ID=$randomId ORDER BY NEWID(); //like ID=3
For My-Sql
Select * from table_name where ID=$randomId ORDER BY RAND() LIMIT 100; //like ID=3
I am trying to change something like this:
Index Record Time
1 10 100
1 10 200
1 10 300
1 10 400
1 3 500
1 10 600
1 10 700
2 10 800
2 10 900
2 10 1000
3 5 1100
3 5 1200
3 5 1300
into this:
Index CountSeq Record LastTime
1 4 10 400
1 1 3 500
1 2 10 700
2 3 10 1000
3 3 5 1300
I am trying to apply this logic per unique index -- I just included three indexes to show the outcome.
So for a given index I want to combine them by streaks of the same Record. So notice that the first four entries for Index 1 have Records 10, but it is more succinct to say that there were 4 entries with record 10, ending at time 400. Then I repeat the process going forward, in sequence.
In short I am trying to perform a count-grouping over sequential chunks of the same Record, within each index. In other words I am NOT looking for this:
select index, count(*) as countseq, record, max(time) as lasttime
from Table1
group by index,record
Which combines everything by the same record whereas I want them to be separated by sequence breaks.
Is there a way to do this in SQL?
It's hard to solve your problem without having a single primary key, so I'll assume you have a primary key column that increases each row (primkey). This request would return the same table with a 'diff' column that has value 1 if the previous primkey row has the same index and record as the current one, 0 otherwise :
SELECT *,
IF((SELECT index, record FROM yourTable p2 WHERE p1.primkey = p2.primkey)
= (SELECT index, record FROM yourTable p2 WHERE p1.primkey-1 = p2.primkey), 1, 0) as diff
FROM yourTable p1
If you use a temporary variable that increases each time the IF expression is false, you would get a result like this :
primkey Index Record Time diff
1 1 10 100 1
2 1 10 200 1
3 1 10 300 1
4 1 10 400 1
5 1 3 500 2
6 1 10 600 3
7 1 10 700 3
8 2 10 800 4
9 2 10 900 4
10 2 10 1000 4
11 3 5 1100 5
12 3 5 1200 5
13 3 5 1300 5
Which would solve your problem, you would just add 'diff' to the group by clause.
Unfortunately I can't test it on sqlite, but you should be able to use variables like this.
It's probably a dirty workaround but I couldn't find any better way, hope it helps.
I have the following data in SQL Server
St 1 2 3 4 5 6 7 8
===========================================
603 2 5 1.5 3 0 0 0 0
603 0 0 0 0 2 1 3 5
As I insert the data by batches, each batch only has 4 columns each and I want to collate the data to the following
St 1 2 3 4 5 6 7 8
===========================================
603 2 5 1.5 3 2 1 3 5
but most of the threads I see here are about concatenating strings of a single column.
Anyone has any idea on how to collate or even merge different rows into a single row.
You can use the group by and Sum key word of the t-SQL
SELECT SUM(COL1) , SUM(COL2)..... FROM tbl GROUP BY ST
You can use the GROUP BY clause and aggregate with SUM fields 1-8 :
SELECT St, SUM(1), SUM(2),.. FROM tbl GROUP BY St
I've got a bit of a complicated query that I'm struggling with. You will notice that the schema isn't the easiest thing to work with but it's what I've been given and there isn't time to re-design (common story!).
I have rows like the ones below. Note: The 3 digit value numbers are just random numbers I made up.
id field_id value
1 5 999
1 6 888
1 7 777
1 8 foo <--- foo so we want the 3 values above
1 9 don't care
2 5 123
2 6 456
2 7 789
2 8 bar <--- bar so we DON'T want the 3 values above
2 9 don't care
3 5 623
3 6 971
3 7 481
3 8 foo <--- foo so we want the 3 values above
3 9 don't care
...
...
n 5 987
n 6 654
n 7 321
n 8 foo <--- foo so we want the 3 values above
n 9 don't care
I want this result:
id result
1 999*888*777
3 623*971*481
...
n 987*654*321
Is this clear? So we have a table with n*5 rows. For each of the sets of 5 rows: 3 of them have values we might want to multiply together, 1 of them tells us if we want to multiply and 1 of them we don't care about so we don't want the row in the query result.
Can we do this in Oracle? Preferably one query.. I guess you need to use a multiplication operator (somehow), and a grouping.
Any help would be great. Thank you.
something like this:
select m.id, exp(sum(ln(m.value)))
from mytab m
where m.field_id in (5, 6, 7)
and m.id in (select m2.id
from mytab m2
where m2.field_id = 8
and m2.value = 'foo')
group by m.id;
eg:
SQL> select * from mytab;
ID FIELD_ID VAL
---------- ---------- ---
1 5 999
1 6 888
1 7 777
1 8 foo
1 9 x
2 5 123
2 6 456
2 7 789
2 8 bar
2 9 x
3 5 623
3 6 971
3 7 481
3 8 foo
3 9 x
15 rows selected.
SQL> select m.id, exp(sum(ln(m.value))) result
2 from mytab m
3 where m.field_id in (5, 6, 7)
4 and m.id in (select m2.id
5 from mytab m2
6 where m2.field_id = 8
7 and m2.value = 'foo')
8 group by m.id;
ID RESULT
---------- ----------
1 689286024
3 290972773
Same logic; just removed the hard-coded values. posting this answer thinking might be helpful to some others.
SELECT a.id,
exp(sum(ln(a.val)))
FROM mytab a,
(SELECT DISTINCT id,
field_id
FROM mytab
WHERE val = 'foo') b
WHERE a.id = b.id
AND a.field_id < b.field_id
GROUP BY a.id;