I have a table like this. I'm looking for a clean way in SQL to create a new column with the average between the Column 2 values for the rows where Column 1 equals 1 and 2 for each id.
I have some ideas on gross ways to do this, but I am looking for a straightforward solution since this seems like it should not be too difficult.
ID
Column 1
Column 2
1
1
100
1
2
75
1
3
50
2
1
45
2
2
90
2
3
60
Use window function avg with filtering.
select *,
avg(column2)
filter (where column1 in (1,2))
over (partition by id) as avrg
from the_table;
id
column1
column2
avrg
1
1
100
87.50
1
2
75
87.50
1
3
50
87.50
2
1
45
67.50
2
2
90
67.50
2
3
60
67.50
db-fiddle
Related
My data has the following Structure
ID
Month
Year
Revenue
1
1
20
860
1
2
20
22
1
5
20
339
2
3
20
12098
3
3
20
12
3
4
20
10
3
6
20
9
3
7
20
122
3
8
20
11
There are 1000s of IDs and I want to select a random sample of 100 IDs. So if I randomly select ID 3, I need all rows of data for ID 3. I have to use SQL for this. I welcome any suggestions.
You can use following query.
For MS-Sql
Select top 100 * from table_name where ID=$randomId ORDER BY NEWID(); //like ID=3
For My-Sql
Select * from table_name where ID=$randomId ORDER BY RAND() LIMIT 100; //like ID=3
I have a table as follows:
ID | Value
1 5
1 1000
1 1500
2 1000
2 1800
3 40
3 1000
3 1200
3 2000
3 2500
I want to obtain the average of each ID groupped by a given range r of value. For instance, if in this case r=1000, The expected result would be:
ID | Value
1 5
1 1250
2 1400
3 40
3 1100
3 2250
I have seen that this can be done with time intervals as seen here. My question is, how can I perform this type of group by operation for integer/float types?
You could try this way:
SELECT id, avg(value) as AvgValue
FROM (SELECT id, value, ROUND(value/1000, 0) AS range FROM yourtable) t
GROUP BY id, range
I need to create 2 cumulative sums based on the value type, for example:
I have values of incoming stock units from 2 types: A and B. and I also have records of outgoing stock units.
If we have enough stock of type "A" it should taken out of type A, if not- it should be taken out of type B. so basically I need to crate the columns "A stock" and "B stock" below, representing the current balance of each type.
I tried using cumulative sum but I'm having trouble with the condition... is there a way to write this query without using a loop ? ( Vertica DB)
In table below A_stock and B_stock are the final result I need to create
ID Type In OUT A stock B stock Order_id
1 A 100 0 100 0 1
1 B 50 0 100 50 2
1 A 100 0 200 50 3
1 - 0 -200 0 50 4
1 - 0 -10 0 40 5
1 B 50 0 0 90 6
1 A 40 0 40 90 7
1 - 0 -20 20 90 8
2 A 30 0 30 0 1
2 B 20 0 30 20 2
2 A 10 0 40 20 3
2 - 0 -20 20 20 4
You can use window functions - but you need a column that defines the ordering of the rows, I assumed ordering_id:
select t.*,
sum(case when type = 'A' then in + out else 0 end) over(partition by id order by ordering_id) a_stock,
sum(case when type = 'B' then in + out else 0 end) over(partition by id order by ordering_id) b_stock
from mytable t
This assumes that you want the stock on a per-id basis; if that's not the case, just remove the partition clause from the over() clause.
Hi I have a table below;
ID length
1 1050
1 1000
1 900
1 600
2 545
2 434
3 45
3 7
4 5
I need an SQL code to make the below table
ID IDK length
1 1 1050
1 2 1000
1 3 900
1 4 600
2 1 545
2 2 434
3 1 45
3 2 7
4 1 5
IDK is the new column to reindexing the same ID according to ascending order of length.
Thank you very much
This is a pain in MS Access. Here is one way using a correlated subquery:
select t.*,
(select count(*)
from foo as t2
where t2.id = t.id and t2.length >= t.length
) as idk
from foo as t;
I am trying to change something like this:
Index Record Time
1 10 100
1 10 200
1 10 300
1 10 400
1 3 500
1 10 600
1 10 700
2 10 800
2 10 900
2 10 1000
3 5 1100
3 5 1200
3 5 1300
into this:
Index CountSeq Record LastTime
1 4 10 400
1 1 3 500
1 2 10 700
2 3 10 1000
3 3 5 1300
I am trying to apply this logic per unique index -- I just included three indexes to show the outcome.
So for a given index I want to combine them by streaks of the same Record. So notice that the first four entries for Index 1 have Records 10, but it is more succinct to say that there were 4 entries with record 10, ending at time 400. Then I repeat the process going forward, in sequence.
In short I am trying to perform a count-grouping over sequential chunks of the same Record, within each index. In other words I am NOT looking for this:
select index, count(*) as countseq, record, max(time) as lasttime
from Table1
group by index,record
Which combines everything by the same record whereas I want them to be separated by sequence breaks.
Is there a way to do this in SQL?
It's hard to solve your problem without having a single primary key, so I'll assume you have a primary key column that increases each row (primkey). This request would return the same table with a 'diff' column that has value 1 if the previous primkey row has the same index and record as the current one, 0 otherwise :
SELECT *,
IF((SELECT index, record FROM yourTable p2 WHERE p1.primkey = p2.primkey)
= (SELECT index, record FROM yourTable p2 WHERE p1.primkey-1 = p2.primkey), 1, 0) as diff
FROM yourTable p1
If you use a temporary variable that increases each time the IF expression is false, you would get a result like this :
primkey Index Record Time diff
1 1 10 100 1
2 1 10 200 1
3 1 10 300 1
4 1 10 400 1
5 1 3 500 2
6 1 10 600 3
7 1 10 700 3
8 2 10 800 4
9 2 10 900 4
10 2 10 1000 4
11 3 5 1100 5
12 3 5 1200 5
13 3 5 1300 5
Which would solve your problem, you would just add 'diff' to the group by clause.
Unfortunately I can't test it on sqlite, but you should be able to use variables like this.
It's probably a dirty workaround but I couldn't find any better way, hope it helps.