multidimensional array linq query - vb.net

i have 5 dimensional array, when using linq to query, the results are sorted in dimensional way:
array(a)(b)(c)(d)(e) , dimension = 1
using for next:
For e = 0 To dimension - 1
For d = 0 To dimension - 1
For c = 0 To dimension - 1
For b = 0 To dimension - 1
For a = 0 To dimension - 1
listbox.Items.Add(array(a, b, c, d, e).disc)
Next
Next
Next
Next
Next
this would result in:
abcde
00000
10000
01000
...
if i use linq:
listbox.Items.AddRange((From item In array Select item.disc).ToArray)
this would result in:
abcde
00000
00001
00010
...
how can i achieve the first result with linq?

Public Class ArrayExt
Public Shared Function GetFirstFastestEnumerator(Of T)(source As Array) As IEnumerable(Of T)
Dim srcRank = source.Rank
Dim indices = New Integer((srcRank) - 1) {}
Dim len = source.Length
For i = 0 To srcRank - 1
indices(i) = source.GetLowerBound(i)
Next
Dim curRank As Integer = 0
For i = 0 To len - 1
Return CType(source.GetValue(indices), T)
While (curRank < srcRank)
If (indices(curRank) < source.GetUpperBound(curRank)) Then
indices(curRank) = indices(curRank) + 1
curRank = 0
Exit While
Else
indices(curRank) = source.GetLowerBound(curRank)
curRank = curRank + 1
End If
End While
Next
End Function
End Class

You need a custom Iterator to go through the array in the rank order you want, which is opposite the built-in order.
public static class ArrayExt {
public static IEnumerable<T> GetFirstFastestEnumerator<T>(this Array src) {
var srcRank = src.Rank;
var indices = new int[srcRank];
var len = src.Length;
for (var j1 = 0; j1 < srcRank; ++j1)
indices[j1] = src.GetLowerBound(j1);
int curRank = 0;
for (var j1 = 0; j1 < len; ++j1) {
yield return (T)src.GetValue(indices);
while (curRank < srcRank) {
if (indices[curRank] < src.GetUpperBound(curRank)) {
++indices[curRank];
curRank = 0;
break;
}
else {
indices[curRank] = src.GetLowerBound(curRank);
++curRank;
}
}
}
}
}
Which you can use either with LINQ or foreach. Replace arrayType with the class stored in array.
listbox.Items.AddRange((From item In array.GetFirstFastestEnumerator<arrayType>() Select item.disc).ToArray)
Or Visual Basic version:
Public Module Ext
<Extension()> _
Public Iterator Function GetFirstFastestIterator(Of T)(source As Array) As IEnumerable(Of T)
Dim srcRank = source.Rank
Dim indices = New Integer((srcRank) - 1) {}
Dim len = source.Length
For i = 0 To srcRank - 1
indices(i) = source.GetLowerBound(i)
Next
Dim curRank As Integer = 0
For i = 0 To len - 1
Yield CType(source.GetValue(indices), T)
While (curRank < srcRank)
If (indices(curRank) < source.GetUpperBound(curRank)) Then
indices(curRank) = indices(curRank) + 1
curRank = 0
Exit While
Else
indices(curRank) = source.GetLowerBound(curRank)
curRank = curRank + 1
End If
End While
Next
End Function
End Module

Related

I have problem that says System.Security.Cryptography.CryptographicException: 'Bad Data. ' in vb.net when trying to import RSA parameters

Here's the code I am not sure if there's any hidden error but on runtime when trying to import the rsa parameters it pops up that error
Imports System.Security.Cryptography
Imports System.Security
Imports System.Text
Imports System.IO
Public Class RSA_Test_Form
Public FactorList As New List(Of Integer)
Public FindFactor As Long
Public PString, QString, ModulusString, ExponentString, DString, DPString,
DQString, InverseQString As String
Function ModInverse(ByVal a As Long, ByVal b As Long) As Long
Dim b0 As Long = b
Dim t As Long
Dim q As Long
Dim x0 As Long = 0
Dim x1 As Long = 1
If b = 1 Then Return 1
While a > 1
q = a \ b
t = b
b = a Mod b
a = t
t = x0
x0 = x1 - q * x0
x1 = t
End While
If x1 < 0 Then x1 += b0
Return x1
End Function
Function gcd(ByVal n1 As Long, ByVal n2 As Long) As Long
Dim i As Integer
Dim minimum As Integer
If n1 < n2 Then
minimum = n1
Else
minimum = n2
End If
For i = minimum To 1 Step -1
If n1 Mod i = 0 And n2 Mod i = 0 Then
Return i
End If
Next
Return gcd
End Function
Sub FindFactorFunction()
Dim x As Long
For x = 2 To FindFactor - 1
If FindFactor Mod x = 0 Then
FactorList.Add(x)
End If
Next
End Sub
Private Sub GenerateBTN_Click(sender As Object, e As EventArgs) Handles GenerateBTN.Click
Dim Result As Long = 0
Dim Result2 As Long = 0
Dim Result3 As Long = 0
Dim Random1, Random2 As New Random()
Dim P, Q, Modulus As Long
Dim Exponent, D, DP, DQ As New Nullable(Of Long)
Dim InverseQ As New Nullable(Of ULong)
Dim Modulus1 As Long = 0
Dim LoopCount As Integer = 0
Dim ls, ls2 As New List(Of Long)
Dim PrimeString As String
PrimeString = ""
Using MyNewStreamReader As StreamReader = New StreamReader("AllPrimes.txt")
PrimeString = MyNewStreamReader.ReadLine().ToString
MessageBox.Show(PrimeString)
While PrimeString <> "" And LoopCount <= 1249
ls.Add(Long.Parse(PrimeString))
LoopCount += 1
PrimeString = ""
PrimeString = MyNewStreamReader.ReadLine
End While
End Using
Using MyNewStreamReader2 As StreamReader = New StreamReader("AllPrimes.txt")
PrimeString = ""
PrimeString = MyNewStreamReader2.ReadLine().ToString
LoopCount = 0
MessageBox.Show(PrimeString)
While PrimeString <> ""
If LoopCount >= 1250 And LoopCount <= 2499 Then
ls2.Add(Long.Parse(PrimeString))
End If
LoopCount += 1
PrimeString = ""
PrimeString = MyNewStreamReader2.ReadLine
End While
End Using
Dim rand = Random1.Next(0, ls.Count)
Dim rand2 = Random2.Next(0, ls2.Count)
P = ls(rand)
Q = ls2(rand2)
Result3 = gcd(P, Q)
While Result3 <> 1
rand = Random1.Next(0, ls.Count)
rand2 = Random2.Next(0, ls2.Count)
P = ls(rand)
Q = ls2(rand2)
Result3 = gcd(P, Q)
End While
MessageBox.Show("P= " & P & "Q= " & Q)
Modulus = (P - 1) * (Q - 1)
Modulus1 = Modulus + 1
FindFactor = Modulus1
FindFactorFunction()
Dim Count As Integer = 0
Dim Count2 As Integer = 0
For A As Integer = 0 To FactorList.Count - 1
Result = gcd(FactorList.ElementAt(A), Modulus)
If Result = 1 Then
Count += 1
End If
Next
Dim PositionArray(Count) As Integer
Count = 0
For A As Integer = 0 To FactorList.Count - 1
Result = gcd(FactorList.ElementAt(A), Modulus)
If Result = 1 Then
PositionArray(Count) = FactorList.ElementAt(A)
Count += 1
End If
Next
Dim Number1, Number2 As Long
Dim GetResult As Boolean = False
Count = 0
If PositionArray.Count = 2 Then
Exponent = PositionArray(0)
D = PositionArray(1)
Else
While GetResult = False And Count <> PositionArray.Count
For Count = 0 To PositionArray.Count - 1
For Count2 = Count + 1 To PositionArray.Count - 1
Number1 = PositionArray(Count)
Number2 = PositionArray(Count2)
Result2 = Number1 * Number2 Mod Modulus
If Result2 = 1 Then
GetResult = True
End If
If GetResult = True Then
Exit While
End If
Next
Next
End While
End If
Dim Selection As Integer = MessageBox.Show(Number1 & "=E And D= " & Number2, "Information", MessageBoxButtons.OKCancel, MessageBoxIcon.Information)
If Selection = DialogResult.OK Then
Exponent = Number1
D = Number2
DP = D * P
DQ = D * Q
InverseQ = ModInverse(Q, P)
MessageBox.Show("DP= " & DP)
MessageBox.Show("DQ= " & DQ)
MessageBox.Show("InverseQ= " & InverseQ)
In here when generating RSA numbers, I can not always get the correct numbers so i am using this website to check that i have get the correct RSA numbers and the D and Exponent was not = 0
Exponent=e
Everytime I get Exponent and D, I will always use this website to check P,Q,Exponent and D to make sure it's correct
https://www.cs.drexel.edu/~jpopyack/IntroCS/HW/RSAWorksheet.html
End If
If Exponent.HasValue And D.HasValue Then
PString = P.ToString
QString = Q.ToString
ModulusString = Modulus.ToString
ExponentString = Exponent.ToString
DString = D.ToString
DPString = DP.ToString
DQString = DQ.ToString
InverseQString = InverseQ.ToString
In here all D,P,Q,DP,DQ,Exponent,Modulus,InverseQ value has been calculated and checked
End If
End Sub
Private Sub Number2ByteConverterBTN_Click(sender As Object, e As EventArgs) Handles Number2ByteConverterBTN.Click
If it's possible try check the coding here, perhaps this place was the place that i do it wrongly
I initially thought of using BitCoverter.GetBytes() to convert the long and Ulong datatype value
But in the end, the bitconverter.getbytes() doesn't work for me so i have to first convert all those long and ulong data type values into string then use BYTE.PARSE() to convert the string into byte value
That's how i do it
If let's any experts here confirmed that the coding above worked and all the values are correct then try to check is there any potential error here
Dim PByte, QByte, ModulusByte, ExponentByte, DByte, DPByte, DQByte, InverseQByte As Byte()
ReDim PByte(PString.Count)
ReDim QByte(QString.Count)
ReDim ModulusByte(ModulusString.Count)
ReDim ExponentByte(ExponentString.Count)
ReDim DByte(DString.Count)
ReDim DPByte(DPString.Count)
ReDim DQByte(DQString.Count)
ReDim InverseQByte(InverseQString.Count)
Dim TempPByte, TempQByte, TempModulusByte, TempExponentByte, TempDByte As New Byte
Dim StringBuilder As New StringBuilder
Dim StringBuilder2 As New StringBuilder
Dim StringBuilder3 As New StringBuilder
Dim StringBuilder4 As New StringBuilder
Dim StringBuilder5 As New StringBuilder
Dim StringBuilder6 As New StringBuilder
Dim StringBuilder7 As New StringBuilder
Dim StringBuilder8 As New StringBuilder
For i As Integer = 0 To PString.Length - 1
PByte(i) = Byte.Parse(PString.ElementAt(i))
StringBuilder.Append(PByte(i).ToString)
Next
For i As Integer = 0 To QString.Length - 1
QByte(i) = Byte.Parse(QString.ElementAt(i))
StringBuilder2.Append(QByte(i).ToString)
Next
For i As Integer = 0 To ModulusString.Length - 1
ModulusByte(i) = Byte.Parse(ModulusString.ElementAt(i))
StringBuilder3.Append(ModulusByte(i).ToString)
Next
For i As Integer = 0 To ExponentString.Length - 1
ExponentByte(i) = Byte.Parse(ExponentString.ElementAt(i))
StringBuilder4.Append(ExponentByte(i).ToString)
Next
For i As Integer = 0 To DString.Length - 1
DByte(i) = Byte.Parse(DString.ElementAt(i))
StringBuilder5.Append(DByte(i).ToString)
Next
For i As Integer = 0 To DPString.Length - 1
DPByte(i) = Byte.Parse(DPString.ElementAt(i))
StringBuilder6.Append(DPByte(i).ToString)
Next
For i As Integer = 0 To DQString.Length - 1
DQByte(i) = Byte.Parse(DQString.ElementAt(i))
StringBuilder7.Append(DQByte(i).ToString)
Next
For i As Integer = 0 To InverseQString.Length - 1
InverseQByte(i) = Byte.Parse(InverseQString.ElementAt(i))
StringBuilder8.Append(InverseQByte(i).ToString)
Next
Dim MyRSAParams As New RSAParameters
MyRSAParams.P = PByte
MyRSAParams.Q = QByte
MyRSAParams.Exponent = ExponentByte
MyRSAParams.Modulus = ModulusByte
MyRSAParams.D = DByte
MyRSAParams.DP = DPByte
MyRSAParams.DQ = DQByte
MyRSAParams.InverseQ = InverseQByte
Dim MyRSA As RSA
MyRSA = RSA.Create()
MyRSA.ImportParameters(MyRSAParams)
End Sub
Private Sub RSA_Test_Form_Load(sender As Object, e As EventArgs) Handles MyBase.Load
Dim temp, temp2 As Integer
temp = gcd(1, 2)
temp2 = gcd(2, 3)
FindFactor = 0
End Sub
End Class
What I am trying to do in the generate button was to create the suitable parameters for RSA.
The parameters I was actually able to generate them but in either ULong or Long data type.
When i first convert them into array of Bytes I have considered to use BitConverter but it doesn't work at least in my case.
The only way i am only able to make them into array of Bytes was by making the ULong or Long data type variable into string.
Then convert those string into Byte then put them into ByteArray
I hope it was correct but it is out of my reach for now.
Any ideas on how can i make the parameter data to be accepted as rsa parameter?

Converting arabic numerals to roman numerals in a visual basic console application [duplicate]

Is it possible to use Format function to display integers in roman numerals?
For Counter As Integer = 1 To 10
Literal1.Text &= Format(Counter, "???")
Next
This is what I found on http://www.source-code.biz/snippets/vbasic/7.htm
(originally written by Mr Christian d'Heureuse in VB)
I converted it to VB.net:
Private Function FormatRoman(ByVal n As Integer) As String
If n = 0 Then FormatRoman = "0" : Exit Function
' there is no Roman symbol for 0, but we don't want to return an empty string
Const r = "IVXLCDM" ' Roman symbols
Dim i As Integer = Math.Abs(n)
Dim s As String = ""
For p As Integer = 1 To 5 Step 2
Dim d As Integer = i Mod 10
i = i \ 10
Select Case d ' format a decimal digit
Case 0 To 3 : s = s.PadLeft(d + Len(s), Mid(r, p, 1))
Case 4 : s = Mid(r, p, 2) & s
Case 5 To 8 : s = Mid(r, p + 1, 1) & s.PadLeft(d - 5 + Len(s), Mid(r, p, 1))
Case 9 : s = Mid(r, p, 1) & Mid(r, p + 2, 1) & s
End Select
Next
s = s.PadLeft(i + Len(s), "M") ' format thousands
If n < 0 Then s = "-" & s ' insert sign if negative (non-standard)
FormatRoman = s
End Function
I hope this will help others.
Cheers - Dave.
No, there is no standard formatter for that.
If you read the Wikipedia on Roman numerals you'll find that there are multiple ways of formatting Roman Numerals. So you will have to write your own method our use the code of someone else.
I wrote this code that works perfectly up to a million.
You can use it but, please, do not make it your own.
Public NotInheritable Class BRoman
'Written by Bernardo Ravazzoni
Public Shared Function hexRoman(ByVal input As Integer) As String
Return mainROMAN(input)
End Function
Private Shared Function mainROMAN(ByVal input As Integer) As String
Dim under As Boolean = udctr(input)
Dim cifretotali As Integer = input.ToString.Length
Dim output As String = ""
Dim remaning As String = input
Dim cifracor As Integer = cifretotali
While Not cifracor = 0
output = output & coreROMAN(division(remaning, remaning), cifracor)
cifracor = cifracor - 1
End While
If under Then
output = "-" & output
End If
Return output
End Function
Private Shared Function coreROMAN(ByVal num As Integer, ByVal pos As Integer) As String
Dim output As String = ""
Debug.WriteLine(num)
Select Case num
Case 1 To 3
output = say(num, getStringFor(True, pos))
Case 4
output = getStringFor(True, pos) & getStringFor(False, pos)
Case 5 To 8
output = getStringFor(False, pos) & say(num - 5, getStringFor(True, pos))
Case 9, 10
output = say(10 - num, getStringFor(True, pos)) & getStringFor(True, pos + 1)
End Select
Return output
End Function
Private Shared Function getStringFor(ByVal first As Boolean, ByVal index As Integer) As String
Dim output As String = ""
index = index * 2
If first Then
index = index - 1
End If
output = rGetStringFor(index)
Return output
End Function
Private Shared Function rGetStringFor(ByVal index As Integer) As String
Dim output As String = ""
Dim sy As Integer
If index < 8 Then
output = rrGetStringFor(index)
Else
sy = index \ 6
output = say(sy, rrGetStringFor(8)) & rrGetStringFor(((index - 2) Mod 6) + 2) & say(sy, rrGetStringFor(9))
End If
Return output
End Function
Private Shared Function rrGetStringFor(ByVal index As Integer) As String
Dim output As String = ""
Select Case index
Case 1
output = "I"
Case 2 '8
output = "V"
Case 3 '9
output = "X"
Case 4 '10
output = "L"
Case 5 '11
output = "C"
Case 6 '12
output = "D"
Case 7 '13
output = "M"
Case 8
output = "["
Case 9
output = "]"
End Select
Return output
End Function
Private Shared Function division(ByVal inputs As String, ByRef resto As String) As Integer
resto = ""
If inputs.Length > 1 Then
resto = inputs.Substring(1)
End If
Dim output As Integer = Integer.Parse(StrReverse(inputs).Substring(inputs.Length - 1))
Return output
End Function
Public Shared Function say(ByVal index As Integer, ByVal letter As String) As String
Dim output As String = ""
While Not index = 0
output = output & letter
index = index - 1
End While
Return output
End Function
Public Shared Function udctr(ByRef num As Integer) As Boolean
Dim und As Boolean = (num < 0)
If und Then
num = 0 - num
End If
Return und
End Function
End Class
Use the function hexRoman, like this example:
msgbox(Broman.hexRoman(50))
Public Class RomanNumber
Public Shared Function FromNumber(val As Byte) As String
Return GetNumberToRoman(val)
End Function
Public Shared Function FromNumber(val As SByte) As String
Return GetNumberToRoman(val)
End Function
Public Shared Function FromNumber(val As Int16) As String
Return GetNumberToRoman(val)
End Function
Public Shared Function FromNumber(val As Int32) As String
Return GetNumberToRoman(val)
End Function
Public Shared Function FromNumber(val As UInt16) As String
Return GetNumberToRoman(val)
End Function
Public Shared Function FromNumber(val As UInt32) As String
Return GetNumberToRoman(val)
End Function
Public Shared Function ToByte(val As String) As Byte
Return GetNumberFromRoman(val)
End Function
Public Shared Function ToSByte(val As String) As SByte
Return GetNumberFromRoman(val)
End Function
Public Shared Function ToInt16(val As String) As Int16
Return GetNumberFromRoman(val)
End Function
Public Shared Function ToInt32(val As String) As Int32
Return GetNumberFromRoman(val)
End Function
Public Shared Function ToUInt16(val As String) As UInt16
Return GetNumberFromRoman(val)
End Function
Public Shared Function ToUInt32(val As String) As UInt32
Return GetNumberFromRoman(val)
End Function
Private Shared Function GetNumberToRoman(val As Integer) As String
Dim v As String = ""
Do While val > 0
If val >= 1000 Then
v &= "M" : val -= 1000
ElseIf val >= 900 Then
v &= "CM" : val -= 900
ElseIf val >= 500 Then
v &= "D" : val -= 500
ElseIf val >= 400 Then
v &= "CD" : val -= 400
ElseIf val >= 100 Then
v &= "C" : val -= 100
ElseIf val >= 90 Then
v &= "XC" : val -= 90
ElseIf val >= 50 Then
v &= "L" : val -= 50
ElseIf val >= 40 Then
v &= "XL" : val -= 40
ElseIf val >= 10 Then
v &= "X" : val -= 10
ElseIf val >= 9 Then
v &= "IX" : val -= 9
ElseIf val >= 5 Then
v &= "V" : val -= 5
ElseIf val >= 4 Then
v &= "IV" : val -= 4
Else
v &= "I" : val -= 1
End If
Loop
Return v
End Function
Private Shared Function GetNumberFromRoman(val As String) As Object
Dim v As Integer = 0
If val.Contains("IV") Then v += 4 : val = val.Replace("IV", "")
If val.Contains("IX") Then v += 9 : val = val.Replace("IX", "")
If val.Contains("XL") Then v += 40 : val = val.Replace("XL", "")
If val.Contains("XC") Then v += 90 : val = val.Replace("XC", "")
If val.Contains("CD") Then v += 400 : val = val.Replace("CD", "")
If val.Contains("CM") Then v += 900 : val = val.Replace("CM", "")
For Each c As Char In val
If c = "I" Then v += 1
If c = "V" Then v += 5
If c = "X" Then v += 10
If c = "L" Then v += 50
If c = "C" Then v += 100
If c = "D" Then v += 500
If c = "M" Then v += 1000
Next
Return v
End Function
End Class

Initialize structure

Public Enum eSourceMode
AUS = 0
EIN = 1
End Enum
Public Structure tSourceChannel
Dim OnOff() As eSourceMode
Dim chan_nr As Short
End Structure
I'm trying to set value to
For i = gSources.GetLowerBound(0) To gSources.GetUpperBound(0) Step 1
gSources(i).chan_nr = i
'gSources is 0 based ?
If gSources.GetLowerBound(0) = 0 Then
k = i + 1
Else
k = i
End If
Dim hehe As Integer = gSources.Count
For j = gNoiseBands.GetLowerBound(0) To gNoiseBands.GetUpperBound(0) Step 1
'ab 17.1.2012: gNrSources sets nr of available outputs
If k <= gNrSources Then
gSources(i).OnOff(j) = eSourceMode.EIN
Else
gSources(i).OnOff(j) = eSourceMode.AUS
End If
Next j
Next i
result is exception
System.NullReferenceException occurred
Object reference not set to an instance of an object.
I need this, because I have .ini file and these values :
"gSources0",1,0,1,1,1,1,1
"gSources1",1,1,1,1,1,1,1
"gSources2",1,1,1,1,1,1,1
"gSources3",1,1,1,1,1,1,1
Result of should be for an example :
gSources(0).OnOff(0) = 1 , gSources(0).OnOff(1) = 0
Here you declare that OnOff is an array
Dim OnOff() As eSourceMode
but you never define how large the array should be or assign memory to the array.
'...
Dim hehe As Integer = gSources.Count
'Specify array size
Redim gSources(i).OnOff(gNoiseBands.GetUpperBound(0) - gNoiseBands.GetLowerBound(0))
For j = gNoiseBands.GetLowerBound(0) To gNoiseBands.GetUpperBound(0) Step 1
'...
Next j

Splitting a String into Pairs

How would I go on splitting a string into pairs of letter in VB?
for example: abcdefgh
split into: ab cd ef gh
I'll throw my hat in the ring:
Dim test As String = "abcdefgh"
Dim results As New List(Of String)
For i As Integer = 0 To test.Length - 1 Step 2
If i + 1 < test.Length Then
results.Add(test.Substring(i, 2))
Else
results.Add(test.Substring(i))
End If
Next
MessageBox.Show(String.Join(" ", results.ToArray))
The following allows for odd length strings. If the string is zero-length, I'm not sure what you'd want to do, you'll want to address that case.
Dim src As String = "abcdef"
Dim size As Integer
If src.Length > 0 Then
If src.Length Mod 2 = 0 Then
size = (src.Length / 2) - 1
Else
size = ((src.Length + 1) / 2) - 1
End If
Dim result(size) As String
For i = 0 To src.Length - 1 Step 2
If i = src.Length - 1 Then
result(i / 2) = src.Substring(i, 1)
Else
result(i / 2) = src.Substring(i, 2)
End If
Next
End If
In C# you would do like this:
Dictionary<String, String> Split(String input)
{
if (input.Count % 2 == 0)
{
Dictionary<string, string> Pairs = new Dictionary( );
for (int L = 0, R = 1; L < input.Count && R <= input.Count; ++L, ++R)
{
Char
Left = input[L],
Right = input[R];
Pairs.Add(
Left.ToString(),
Right.ToString());
}
}
else
{
throw new NotEvenException( );
}
return Pairs( );
}
void Main()
{
var Pairs = Split("ABCDEFGH");
foreach(string Key in Split("ABCDEFGH"))
{
Console.Write("{0}{1}\n", Key, Pairs[Key]);
}
}
/*
Output:
AB
CD
EF
GH
*/
Now, I know what you think: This isn't what I want! But I say: It is actually, at least partly.
Since I presume you're working in VB.net, the basic structure of what you want performed is outlined in the short snippet above.
For example: The method Count (of the object String) exists in both C# and in VB.
Hope it helps a bit at least!

Developing Fibonacci Series in VB

I am trying to write a code for Fibonacci series in VB, but some of the values in my series are incorrect. Can somebody help me with the code?
Below is what I have so far.
Private Function FibNumber(number As Integer) As Integer
If (number > 2) Then
FibNumber = (FibNumber(number - 2) + FibNumber(number - 1))
Else
FibNumber = 1
End If
End Function
Private Sub command1_click()
Dim x As Integer
x = Text1.Text
Call FibNumber(number)
End Sub
Well, I did a quick search and I came up with the following in the first couple of results:
Private Function FibNumber(number As Integer) As Integer
If (number > 2) Then
FibNumber = (FibNumber(number - 2) + FibNumber(number - 1))
Else
FibNumber = 1
End If
End Function
I know this is way old, but I think the issue could be with how compgeek is calling the function.
Instead of:
Call FibNumber(number)
It should be:
Call FibNumber(x)
My solution:
Private Function FibNumber(number As Integer) As Integer
If (number > 2) Then
FibNumber = (FibNumber(number - 2) + FibNumber(number - 1))
Else
FibNumber = 1
End If
End Function
Private Sub command1_click()
Dim x As Integer
x = Text1.Text
Call FibNumber(number)
End Sub
It's a Java function, and believe me; Fibonacci wont get much more faster or complex than
this particular version. It is optimized to operate at about 100 times faster than the original recursive one.
Tip: You might need to change maxN to extend parameter length!
For example if you want to input numbers between 0 and 199, you must increase the maxN to 200
static final int maxN = 72;
static long knownF[] = new long[maxN];
static long F(int i) {
if (knownF[i] != 0) {
return knownF[i];
}
long t = i;
if (i < 0) {
return 0;
}
if (i > 1) {
t = F(i - 1) + F(i - 2);
}
return knownF[i] = t;
}
Module Module1
Sub Main()
Console.WriteLine("The Fibonacci Series")
Console.WriteLine("Enter how many elements-")
Dim n As Integer = Console.ReadLine
If (n = 1) Then
Dim a As Integer = 1
Console.WriteLine("{0}", a)
Else
Dim a As Integer = 1
Dim b As Integer = 2
Console.WriteLine("{0}", a)
Console.WriteLine("{0}", b)
Dim i As Integer = 1
While (i < n - 1)
Dim c As Integer = a + b
Console.WriteLine(" {0}", c)
a = b
b = c
i = i + 1
End While
End If
Console.ReadKey()
End Sub
End Module