I want to convert Oracle
to_timestamp(coloum_name,'DD-MM-YYYY') to sql
required output : 24-APR-17 12.00.00.000000000 PM
I know this is old, but it has an very searchable title, and there's no accepted answer.
The TO_TIMESTAMP function converts text representations of dates to a standard date/time format. From your question, it sounds like you have dates stored as characters in the format 'DD-MM-YYYY', but you want SQL Server DATETIME2(7) (based on the number of decimals in the seconds) as your output. It also seems you want the default time to be noon, rather than midnight, since your sample output shows 12:00 PM, not AM.
Using CONVERT with style 103 will change the European styled date to a DATETIME2(7), as shown below. But then you'll need to do a DATEADD to move from midnight (which will be the default value) to noon, which is twelve hours later.
DECLARE #DateSample NVARCHAR(10) = '17-04-2017';
SELECT CONVERT( DATETIME2(7), #DateSample, 103 );
--Results
--2017-04-17 00:00:00.0000000
SELECT DATEADD( HOUR, 12, CONVERT( DATETIME2(7), #DateSample, 103 ));
--Results
--2017-04-17 12:00:00.0000000
The SQL Server default is 24 hour time, so if you absolutely must switch to AM/PM designators, you'll have to convert it back to a string, which seems to be the opposite of what you're trying to do.
This is a way to convert a date/timestamp into varchar2 in Oracle with the format you want
select to_char(yourColumn, 'DD-MON-YY HH.MI.SS.FF9 PM')
from yourTable
SELECT FORMAT(SYSDATETIME(), 'dd-MMM-yyyy h.mm.ss.fffffff tt')
Related
I have the following data in TIMESTAMP column
TIMESTAMP - VARCHAR2
Format - YYYY-MM-DD hh24:mi:ss.0
2018-01-31 23:47:35.0
2018-01-01 00:00:48.0
2018-01-01 06:54:36.0
I'm trying to make a query to get data between two dates (example 4th Jan to 18th Jan) but im not sure how can i convert this into DATE format. Previously i used to get the data everyday and used WHERE TIMESTAMP LIKE '2018-01-04%' in my sql query.
Really appreciate if someone could assist
One method uses to_date():
where to_date(timestamp, 'YYYY-MM-DD HH24:MI:SS.F') >= date '2018-01-04' and
to_date(timestamp, 'YYYY-MM-DD HH24:MI:SS.F') < date '2018-01-09'
However, you are using a good date format, so you can use string comparisons:
where timestamp >= '2018-01-04' and
timestamp < '2018-01-09'
Although this is convenient, you should be storing the value as a date or timestamp. Storing date/time values as strings is generally bad (although your format makes this more reasonable).
I have a column in a table with time stamps from Germany (Utc + 6) in their local time (Utc -1). How do I convert all those datetimes in my local time?
I think the correct way of converting UTC datetime into local datetime is using CLR function. You can find an example below.
https://www.mssqltips.com/sqlservertip/2339/converting-utc-to-local-time-with-sql-server-clr/
There are -7 hour between germany and central time zone in us
CT (-6)
Berlin (+1)
If your column is datetime USE THE FOLLOWING
Select DATEADD(HOUR,-7,[DATECOLUMN])
Update 1
Consider that #bdate and #edate are the begin and end date of the daylight savings so you can use this query
Select case when DATEADD(HOUR,-7,[DATECOLUMN]) between #bdate and #edate Then
DATEADD(HOUR,-8,[DATECOLUMN]) else
DATEADD(HOUR,-7,[DATECOLUMN]) end
If your data is in a string format like "dd.mm.yy," then you would use the code page 104 to tell SQL how to parse your date from string to a DateTime format.
CONVERT(DateTime, DateField, 104)
If your string is in some other format, then look up the correct codepage in the table here (CAST and CONVERT in T-SQL):
I have the following date in our SQL Server 2008 database: 06-24-1881 00:00:00:000 as a DOB and it's stored as datetime.
I need to copy this data into our Oracle 11g database and from my understanding Oracle does not accept milliseconds into a Datetime column. For my data after 1900 I converted the data to smalldatetime and it worked but for this piece of data, it won't convert to smalldatetime since it doesn't allow for dates prior to 1/1/1900.
How do I get many rows of data into my Oracle database?
I tried this:
left(DOB, 19) as DOB
but that rendered the data as "Jun 24 1881 12:00AM", so I tried inserting with:
to_date('Jun 24 1881 12:00AM', 'MON-DD-YYYY HH:MI:SSAM')
and that didn't work either. I am stuck and need help.
Jun 24 1881 12:00AM matches the Oracle format string MON DD YYYY HH12:MIAM. Your format mask has an added seconds :SS mask that Oracle is trying to match but not finding in the input so will throw an ORA-01861: literal does not match format string exception.
So, if the output from SQL Server is in that format then in Oracle you should be able to do:
TO_DATE( 'Jun 24 1881 12:00AM', 'MON DD YYYY HH12:MIAM' )
CONVERT(VARCHAR(20),#Date,101) will give you 06/24/1881 I am looking for code now.
REPLACE(CONVERT(VARCHAR(200),#Date,101),'/','-') + ' 00:00:00:000'
Weird I tried a bunch of the century codes with CONVERT and it worked for 101 and some others but the 113 you want failed but because you don't have minutes, hours, seconds etc. you can just take the the 101 format and manipulate the string to what you want.
DECLARE #Date DATE = '06-24-1881 00:00:00:000'
SELECT #Date
,FORMAT(#Date, 'MM-dd-yyyy HH:mm:ss')
,REPLACE(CONVERT(VARCHAR(200),#Date,101),'/','-') + ' 00:00:00:000'
Note the FORMAT(#Date, 'MM-dd-yyyy HH:mm:ss') is SQL 2012 or newer and works well.
There are many t-sql CONVERT strings to produce quite a variety of date and or time strings. But I cannot find the solution to needing no date and no seconds.
We want to return the time only from a datetime field, and eliminate the seconds. It would not matter if the seconds were truncated or rounded, but we need to show no seconds.
desired results- from any DATETIME field
10:00 AM
11:00 AM
4:59 PM
any and all insights or suggestions appreciated!!
Would this do it?
select CONVERT(varchar(15),CAST(GETDATE() AS TIME),100)
Just change out GETDATE() with your date variable.
Try this:
SELECT LTRIM(RIGHT(CONVERT(VARCHAR(20), GETDATE(), 100), 7))
Put your DATETIME field instead GETDATE()
If you want a space then the AM /PM try this:
SELECT
Left(CONVERT(varchar(15),CAST(GETDATE() AS TIME),100),(len(CONVERT(varchar(15),CAST(GETDATE() AS TIME),100))-2)) +' ' + right((CONVERT(varchar(15),CAST(GETDATE() AS TIME),100)),2) as NiceTimeAMPm
NiceTime
7:35 AM
3:00 PM
How do i assign current date with a specific time?
let's say 8:00:00 AM to Column EXIT_DT of datatype datetime??
I have tried GETDATE() AS EXIT_DT but it gives me current datetime. I am using Sql server 2005. Any help?
Lets say Today is 1/3/2013 and i want my result to return as a datetime datatype with value 1/3/2013 8:00:00 AM. If i run the statement ytd, the result will be 1/2/2013 8:00:00 AM
This formula will always produce 08:00 for the day it is called, and avoids string manipulation:
select DATEADD(day,DATEDIFF(day,'20010101',GETDATE()),'2001-01-01T08:00:00')
Try to avoid solutions that convert to and from strings - treating datetime values as strings is one of the largest sources of bugs.
It works by computing the number of days (as an integer) that have elapsed since 1st January 2001. It then adds that same number of days to 08:00 on 1st January 2001.
You can try this :
DECLARE #dt datetime;
SET #dt=CONVERT(DateTime, CONVERT(VARCHAR,GETDATE(),101)+' 8:00:00')
SELECT CONVERT(VARCHAR, #dt, 101)+' '+ LTRIM(RIGHT(CONVERT(VARCHAR(20),#dt, 100), 7))
Visit http://www.sql-server-helper.com/tips/date-formats.aspx for datetime formats.
Use Convert along with getdate() to get specific formats.
ex:
SELECT CONVERT(VARCHAR(30),GETDATE(),113)
This is a bit stupid, but it works
select cast(cast(getdate() as date) as datetime) + '08:00:00'
it casts the getdate() to date thus losing the hours, than it casts it to datetime and adds 8 hours.
If you want to avoid implicit conversion of varchar to datetime, you could use this version:
select cast(cast(getdate() as date) as datetime)
+ convert(datetime,'08:00:00',114)
This is also working. (1). convert today's date to ISO format (yyyymmdd) (2). add the time, (3). convert back to datetime
Select convert(datetime, convert(varchar, getdate(),112) + ' ' + '8:00:00AM')
--Results
2013-01-03 08:00:00.000
If you need in specific format you need to convert back to varchar again.
-- AM/PM --
SELECT TO_CHAR(sysdate, 'MM/DD/YYYY HH:MI:SS AM') FROM dual
/
-- 24 hrs format --
SELECT TO_CHAR(sysdate, 'MM/DD/YYYY HH24:MI:SS') FROM dual
/