How do i assign current date with a specific time?
let's say 8:00:00 AM to Column EXIT_DT of datatype datetime??
I have tried GETDATE() AS EXIT_DT but it gives me current datetime. I am using Sql server 2005. Any help?
Lets say Today is 1/3/2013 and i want my result to return as a datetime datatype with value 1/3/2013 8:00:00 AM. If i run the statement ytd, the result will be 1/2/2013 8:00:00 AM
This formula will always produce 08:00 for the day it is called, and avoids string manipulation:
select DATEADD(day,DATEDIFF(day,'20010101',GETDATE()),'2001-01-01T08:00:00')
Try to avoid solutions that convert to and from strings - treating datetime values as strings is one of the largest sources of bugs.
It works by computing the number of days (as an integer) that have elapsed since 1st January 2001. It then adds that same number of days to 08:00 on 1st January 2001.
You can try this :
DECLARE #dt datetime;
SET #dt=CONVERT(DateTime, CONVERT(VARCHAR,GETDATE(),101)+' 8:00:00')
SELECT CONVERT(VARCHAR, #dt, 101)+' '+ LTRIM(RIGHT(CONVERT(VARCHAR(20),#dt, 100), 7))
Visit http://www.sql-server-helper.com/tips/date-formats.aspx for datetime formats.
Use Convert along with getdate() to get specific formats.
ex:
SELECT CONVERT(VARCHAR(30),GETDATE(),113)
This is a bit stupid, but it works
select cast(cast(getdate() as date) as datetime) + '08:00:00'
it casts the getdate() to date thus losing the hours, than it casts it to datetime and adds 8 hours.
If you want to avoid implicit conversion of varchar to datetime, you could use this version:
select cast(cast(getdate() as date) as datetime)
+ convert(datetime,'08:00:00',114)
This is also working. (1). convert today's date to ISO format (yyyymmdd) (2). add the time, (3). convert back to datetime
Select convert(datetime, convert(varchar, getdate(),112) + ' ' + '8:00:00AM')
--Results
2013-01-03 08:00:00.000
If you need in specific format you need to convert back to varchar again.
-- AM/PM --
SELECT TO_CHAR(sysdate, 'MM/DD/YYYY HH:MI:SS AM') FROM dual
/
-- 24 hrs format --
SELECT TO_CHAR(sysdate, 'MM/DD/YYYY HH24:MI:SS') FROM dual
/
Related
I want to convert Oracle
to_timestamp(coloum_name,'DD-MM-YYYY') to sql
required output : 24-APR-17 12.00.00.000000000 PM
I know this is old, but it has an very searchable title, and there's no accepted answer.
The TO_TIMESTAMP function converts text representations of dates to a standard date/time format. From your question, it sounds like you have dates stored as characters in the format 'DD-MM-YYYY', but you want SQL Server DATETIME2(7) (based on the number of decimals in the seconds) as your output. It also seems you want the default time to be noon, rather than midnight, since your sample output shows 12:00 PM, not AM.
Using CONVERT with style 103 will change the European styled date to a DATETIME2(7), as shown below. But then you'll need to do a DATEADD to move from midnight (which will be the default value) to noon, which is twelve hours later.
DECLARE #DateSample NVARCHAR(10) = '17-04-2017';
SELECT CONVERT( DATETIME2(7), #DateSample, 103 );
--Results
--2017-04-17 00:00:00.0000000
SELECT DATEADD( HOUR, 12, CONVERT( DATETIME2(7), #DateSample, 103 ));
--Results
--2017-04-17 12:00:00.0000000
The SQL Server default is 24 hour time, so if you absolutely must switch to AM/PM designators, you'll have to convert it back to a string, which seems to be the opposite of what you're trying to do.
This is a way to convert a date/timestamp into varchar2 in Oracle with the format you want
select to_char(yourColumn, 'DD-MON-YY HH.MI.SS.FF9 PM')
from yourTable
SELECT FORMAT(SYSDATETIME(), 'dd-MMM-yyyy h.mm.ss.fffffff tt')
I have a column in a table with time stamps from Germany (Utc + 6) in their local time (Utc -1). How do I convert all those datetimes in my local time?
I think the correct way of converting UTC datetime into local datetime is using CLR function. You can find an example below.
https://www.mssqltips.com/sqlservertip/2339/converting-utc-to-local-time-with-sql-server-clr/
There are -7 hour between germany and central time zone in us
CT (-6)
Berlin (+1)
If your column is datetime USE THE FOLLOWING
Select DATEADD(HOUR,-7,[DATECOLUMN])
Update 1
Consider that #bdate and #edate are the begin and end date of the daylight savings so you can use this query
Select case when DATEADD(HOUR,-7,[DATECOLUMN]) between #bdate and #edate Then
DATEADD(HOUR,-8,[DATECOLUMN]) else
DATEADD(HOUR,-7,[DATECOLUMN]) end
If your data is in a string format like "dd.mm.yy," then you would use the code page 104 to tell SQL how to parse your date from string to a DateTime format.
CONVERT(DateTime, DateField, 104)
If your string is in some other format, then look up the correct codepage in the table here (CAST and CONVERT in T-SQL):
There are many t-sql CONVERT strings to produce quite a variety of date and or time strings. But I cannot find the solution to needing no date and no seconds.
We want to return the time only from a datetime field, and eliminate the seconds. It would not matter if the seconds were truncated or rounded, but we need to show no seconds.
desired results- from any DATETIME field
10:00 AM
11:00 AM
4:59 PM
any and all insights or suggestions appreciated!!
Would this do it?
select CONVERT(varchar(15),CAST(GETDATE() AS TIME),100)
Just change out GETDATE() with your date variable.
Try this:
SELECT LTRIM(RIGHT(CONVERT(VARCHAR(20), GETDATE(), 100), 7))
Put your DATETIME field instead GETDATE()
If you want a space then the AM /PM try this:
SELECT
Left(CONVERT(varchar(15),CAST(GETDATE() AS TIME),100),(len(CONVERT(varchar(15),CAST(GETDATE() AS TIME),100))-2)) +' ' + right((CONVERT(varchar(15),CAST(GETDATE() AS TIME),100)),2) as NiceTimeAMPm
NiceTime
7:35 AM
3:00 PM
How to get the date and hour information for a given datetime object in Transact-SQL?
E.g. 2014-12-18 21:00:00 for 2014-12-18 21:24:05.
I need to truncate off all parts after the hour - i.e. minutes, seconds, and partial seconds.
For SQL Server:
Select DATEPART(HOUR, [date]) + ":" + DATEPART(MINUTE, [date]);
Oracle:
Select TO_CHAR([date], 'HH:MI') From...
SELECT
CONVERT(TIME,GETDATE()) AS TimeOnly,
CONVERT(DATE,GETDATE(),101) AS DateOnly
GO
Replace the GETDATE() function with whatever you need.
i have a column with dates, but it is a varchar:
8/31/2010 9:48
8/31/2010 9:49
8/31/2010 9:51
8/31/2010 9:52
8/31/2010 9:55
8/31/2010 9:59
8/31/2010 10:11
8/31/2010 10:13
8/31/2010 10:16
8/31/2010 10:37
8/31/2010 10:42
i made sure that none of these will be a BAD date:
SELECT *
FROM qcvalues.dbo.batchinfo
WHERE ISDATE(reporttime) <> 1
this returned 0 results
question:
i need to return dates between a certain range:
select rowid from qcvalues.dbo.batchinfo where CONVERT(DATE, Substring( reporttime, 1, LEN(reporttime)), 103)
between cast('2010-08-01' as datetime) and CAST('2010-08-31' as datetime)
and i am getting this error;
Msg 241, Level 16, State 1, Line 2
Conversion failed when converting date and/or time from character string.
what is wrong with my conversion?
If you need to store dates then use a datetime column in the future
does this work?
WHERE CONVERT(DATE,RTRIM(reporttime))
BETWEEN '2010-08-01' and '2010-08-31'
If not use SET DATEFORMAT MDY before running it
And if you have to store it in a varchar column then use YYYYMMDD format...that way you can do
WHERE reporttime like '201008%' if you want August 2010
This will solve your problem:
select rowid
from qcvalues.dbo.batchinfo
where
CONVERT(DATE, reporttime, 101) >= '20100801'
-- style 101, not 103
-- also notice date conversion invariant format YYYYMMDD with no separators
AND CONVERT(DATE, reporttime, 101) < '20100901'
-- using BETWEEN with an end date of '8/31/2010' will skip
-- times between '8/31/2010 00:00:00.003' and '8/31/2010 23:59:59.997'
Try this to see what the problem is:
select convert(datetime, '8/31/2010 9:48', 103)
select convert(datetime, '8/31/2010 9:48', 101)
put SET DATEFORMAT MDY before your query.
This will strip out the time portion too
select rowid
from qcvalues.dbo.batchinfo
Where cast(floor(cast(cast(reportTime as datetime)as float))as datetime)
between cast('2010-08-01' as datetime)
and cast('2010-08-31' as datetime)
Remember, this CAST('2010-08-31' as datetime) will have its time portion as 00:00.
Consider casting your varchar data as smalldatetime, and being specific about the boundaries of times in your between. No need to be converting, substring, etc. Just one CAST will do.
Consider this as a potential solution:
SELECT rowid from qcvalues.dbo.batchinfo
WHERE CAST(reporttime as smalldatetime)
BETWEEN '2010-08-01' AND '2010-08-31 23:59'