SQL Pivot table CTE and Order producing Null values - sql

I'm trying to get the following to work, I'm new to Pivot tables, I thought I had it but I get a lot of null values. What am I missing? Also where can I insert the ORDER BY clause to sort on NUM.
with cte_Inst as
(
SELECT Inst.Num, Branch.BranchNum,
inst.Name as 'InstName', Center.ProfitCenter,
Center.plant, Branch.Idx, Inst.Enable,Inst.BranchBilling, mainframe.Name as 'Host', center.Name as 'Center'
FROM Center RIGHT OUTER JOIN
mainframe ON Center.Idx = mainframe.CenterIdx RIGHT OUTER JOIN
DB ON mainframe.Idx = DB.MainframeIdx RIGHT OUTER JOIN
Inst ON DB.DBIdx = Inst.DBIdx RIGHT OUTER JOIN
Branch ON Inst.Idx = Branch.InstIdx
where BranchNum = 999999
--order by Num, BranchNum
)
select num, PRB575 as 'PRB575', PRB576 as 'PRB576', PRB577 as 'PRB577', PRB578 as 'PRB578', PRB579 as'PRB579',PRB580 as'PRB580', PRB572 as 'PRB572', PRB573 as 'PRB573',PRB851 as'PRB851', PRB581 as 'PRB581', PRB582 as 'PRB582',PRB583 as'PRB583'
From
(
SELECT InputCounts.Count as 'Total', InputCounts.DateTime, cte_Inst.num, --cte_Inst.InstName,
InputDesc.ShortName,
Material.FoundationMaterialNumber, cte_inst.host, cte_Inst.Center
FROM cte_Inst
left OUTER JOIN InputCounts on InputCounts.BranchIdx = cte_Inst.Idx
left outer join PhysicalSource on InputCounts.PhysicalSourceIdx = PhysicalSource.Idx
left outer join InputDesc ON InputDesc.Idx = inputcounts.inputdescidx
left OUTER JOIN Material ON InputDesc.MaterialIdx = Material.Idx
WHERE ( (cte_Inst.Enable ='true')
and (InputCounts.DateTime > '2017-03-28')
and FoundationMaterialNumber in ('PRB575','PRB576','PRB577','PRB578','PRB579','PRB580','PRB572','PRB573','PRB851','PRB581','PRB582','PRB583')
))
As SourceDataTable
Pivot
(
Max(Total) for FoundationMaterialNumber in (PRB575, PRB576, PRB577,PRB578,PRB579,PRB580,PRB572,PRB573,PRB851,PRB581,PRB582,PRB583))
as pivottable
The Original Data Set Before the Pivot
After Pivot

Related

LEFT JOIN & SUM GROUP BY

EDIT:
The result supposed to be like this:
desired result
I have this query:
SELECT DISTINCT mitarbeiter.mitarbnr, mitarbeiter.login, mitarbeiter.name1, mitarbeiter.name2
FROM vertragspos
left join vertrag_ek_vk_zuord ON vertragspos.id = vertrag_ek_vk_zuord.ek_vertragspos_id
left join mitarbeiter ON vertrag_ek_vk_zuord.anlage_mitarbnr = mitarbeiter.mitarbnr
left join vertragskopf ON vertragskopf.id = vertragspos.vertrag_id
left join
(
SELECT wkurse.*, fremdwaehrung.wsymbol
FROM wkurse
INNER join
(
SELECT lfdnr, Max(tag) AS maxTag
FROM wkurse
WHERE tag < SYSDATE
GROUP BY lfdnr
) t1
ON wkurse.lfdnr = t1.lfdnr AND wkurse.Tag = t1.maxTag
INNER JOIN fremdwaehrung ON wkurse.lfdnr = fremdwaehrung.lfdnr
) wkurse ON vertragskopf.blfdwaehrung = wkurse.lfdnr
left join
(
SELECT vertrag_ID, Sum (preis) preis, Sum (menge) menge, Sum (preis * menge / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
GROUP BY vertrag_ID
) s ON vertragskopf.id = s.vertrag_id
But I always get an error on line 21 Pos 145:
ORA-00904 WKURSE.KURS invalid identifier
The WKURSE table is supposed be joined already above, but why do I still get error?
How can I do join with all these tables?
I need to join all these tables:
Mitarbeiter, Vertragspos, vertrag_ek_vk_zuord, wkurse, fremdwaehrung, vertragskopf.
What is the right syntax? I'm using SQL Tool 1,8 b38
Thank you.
Because LEFT JOIN is executed on entire dataset, and not in row-by-row manner. So there's no wkurse.kurs available in the execution context of subquery. Since you join that tables, you can place the calculation in the top-most select statement.
EDIT:
After you edited the statement, it became clear where does vertragskopf.zahlintervall came from. But I don't know where are you going to use calculated vertragswert (now it is absent in the query), so I've put it in the result. As I'm not a SQL parser and have no idea of your tables, so I cannot check the code, but calculation now can be resolved (all the values are available in calculation context).
SELECT DISTINCT mitarbeiter.mitarbnr, mitarbeiter.login, mitarbeiter.name1, mitarbeiter.name2, s.amount / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
left join vertrag_ek_vk_zuord ON vertragspos.id = vertrag_ek_vk_zuord.ek_vertragspos_id
left join mitarbeiter ON vertrag_ek_vk_zuord.anlage_mitarbnr = mitarbeiter.mitarbnr
left join vertragskopf ON vertragskopf.id = vertragspos.vertrag_id
left join (
SELECT wkurse.*, fremdwaehrung.wsymbol
FROM wkurse
INNER join (
SELECT lfdnr, Max(tag) AS maxTag
FROM wkurse
WHERE tag < SYSDATE
GROUP BY lfdnr
) t1
ON wkurse.lfdnr = t1.lfdnr AND wkurse.Tag = t1.maxTag
INNER JOIN fremdwaehrung ON wkurse.lfdnr = fremdwaehrung.lfdnr
) wkurse ON vertragskopf.blfdwaehrung = wkurse.lfdnr
left join (
SELECT vertrag_ID, Sum (preis) preis, Sum (menge) menge, Sum (preis * menge) as amount
FROM vertragspos
GROUP BY vertrag_ID
) s ON vertragskopf.id = s.vertrag_id
Rewriting the code using WITH clause makes it much clearer than select from select.
Also get the rate on last day before today in oracle is as simple as
select wkurse.lfdnr
, max(wkurse.kurs) keep (dense_rank first order by wkurse.tag desc) as rate
from wkurse
where tag < sysdate
group by wkurse.lfdnr
One option is a lateral join:
left join lateral
(SELECT vertrag_ID, Sum(preis) as preis, Sum(menge) as menge,
Sum (preis * menge / Decode (vertragskopf.zahlintervall, 1,1,2,2,3,3,4,6,5,12,1) / wkurse.kurs) vertragswert
FROM vertragspos
GROUP BY vertrag_ID
) s
ON vertragskopf.id = s.vertrag_id

Combine SQL statements as columns, not as rows

First Query:
SELECT OPENING.COMP_CODE, COMPANY.COMP_NAME, OPENING.QUAL_CODE, QUALIFICATION.QUAL_DESCRIPTION
FROM OPENING
LEFT JOIN COMPANY ON OPENING.COMP_CODE = COMPANY.COMP_CODE
LEFT JOIN QUALIFICATION ON OPENING.QUAL_CODE = QUALIFICATION.QUAL_CODE
Second Query:
SELECT EDUCATION.CAND_NUM, CANDIDATE.CAND_LNAME, EDUCATION.QUAL_CODE, QUALIFICATION.QUAL_DESCRIPTION
FROM EDUCATION
LEFT JOIN CANDIDATE ON EDUCATION.CAND_NUM = CANDIDATE.CAND_NUM
LEFT JOIN QUALIFICATION ON EDUCATION.QUAL_CODE = QUALIFICATION.QUAL_CODE
I tried using <Query1> UNION ALL <Query2> but it combines the results as rows. I want to combine the results as columns (side by side)
If you need to bring all the result in one row, UNION ALL / UNION wont work. Use cross apply instead. Such as,
SELECT A.* ,B.*
FROM
(
SELECT
OPENING.COMP_CODE, COMPANY.COMP_NAME, OPENING.QUAL_CODE, QUALIFICATION.QUAL_DESCRIPTION
FROM OPENING
LEFT JOIN COMPANY ON OPENING.COMP_CODE = COMPANY.COMP_CODE
LEFT JOIN QUALIFICATION ON OPENING.QUAL_CODE = QUALIFICATION.QUAL_CODE
) AS A
CROSS APPLY
(
SELECT EDUCATION.CAND_NUM, CANDIDATE.CAND_LNAME, EDUCATION.QUAL_CODE, QUALIFICATION.QUAL_DESCRIPTION
FROM EDUCATION
LEFT JOIN CANDIDATE ON EDUCATION.CAND_NUM = CANDIDATE.CAND_NUM
LEFT JOIN QUALIFICATION ON EDUCATION.QUAL_CODE = QUALIFICATION.QUAL_CODE
) AS B

SQL Selecting rows with not the same condition for all

I have to create SQL query that select persons datas. Every person has several grades and I have to select first by time for everyone. I don't know how do it because conditional is different for every person. Below is my current code which doesn't works.
SELECT s.sol_last_name,
g.grade_name,
MIN(sg.sol_grade_date_from)
FROM [dbo].[dim_s####] AS s
LEFT JOIN [dbo].[fact_s####_grade] AS sg ON s.sol_key = sg.sol_grade_sollers_key
LEFT JOIN [dbo].[dim_grade] AS g ON g.grade_key = sg.sol_grade_grade_key
GROUP BY s.sol_last_name,
g.grade_name
HAVING MIN(sg.sol_grade_date_from) = sg.sol_grade_date_from
You can put the earliest date in a subquery, and then inner join there:
SELECT s.sol_last_name,
g.grade_name,
sg.sol_grade_date_from
FROM [dbo].[dim_s####] AS s
INNER JOIN (
select sol_grade_grade_key
,min(sol_grade_date_from) as sol_grade_date_
from from [dbo].[dim_grade]
GROUP BY sol_grade_grade_key) AS g
ON g.grade_key = sg.sol_grade_grade_key
LEFT JOIN [dbo].[fact_s####_grade] AS sg
ON s.sol_key = sg.sol_grade_sollers_key
Use a Common Table Expression (cte) to save some typing. Then do a NOT EXISTS to return a row only if same sol_last_name has no older grade.
WITH CTE (sol_last_name, grade_name, grade_date_from) AS
(
SELECT s.sol_last_name,
g.grade_name,
sg.sol_grade_date_from
FROM [dbo].[dim_s####] AS s
LEFT JOIN [dbo].[fact_s####_grade] AS sg ON s.sol_key = sg.sol_grade_sollers_key
LEFT JOIN [dbo].[dim_grade] AS g ON g.grade_key = sg.sol_grade_grade_key
)
select sol_last_name, grade_name, grade_date_from
from cte as t1
where not exists (select 1 from cte t2
where t2.sol_last_name = t1.sol_last_name
and t2.grade_date_from < t2.grade_date_from)

Nested SQL - Distinct Load Left Join in one statement

I wanted to left join two queries:
First:
SELECT TIG_TOL.sName AS Maschine,
TIG_TOL.lTolRef,
Max(TIG_JOB.tActBegin) AS MaxvontActBegin
FROM TIG_JOB LEFT JOIN TIG_TOL ON TIG_JOB.lMacRef = TIG_TOL.lTolRef
WHERE (((TIG_JOB.sState)="Run" Or (TIG_JOB.sState)="Ready"))
GROUP BY TIG_TOL.sName, TIG_TOL.lTolRef;
Second:
SELECT TIG_JOB.sName AS Auftrag,
TIG_JOB.lJobRef,
TIG_TOL.sName AS Artikel,
TIG_TOL.sDescript AS Artikel_Bezeichnung
FROM (TIG_JOB LEFT JOIN TIG_TOL_BOK ON TIG_JOB.lJobRef = TIG_TOL_BOK.lJobRef)
LEFT JOIN TIG_TOL ON (TIG_TOL_BOK.lTolRef = TIG_TOL.lTolRef)
AND (TIG_TOL_BOK.lTolTypRef = TIG_TOL.lTolTypRef)
WHERE (((TIG_TOL.lTolTypRef)=10));
Over a left join
on First.MaxvontActBegin = Second.TIG_JOB.tActBegin
AND First.TIG_TOL.lTolRef = Second.TIG_JOB.lMacRef
Is that possible? In Access Im doing it over two queries, where the second is using the first..
I (blindly) added TIG_JOB.tActBegin and TIG_JOB.lMacRef to the 2nd SELECT (hoping they exist) in order to JOIN the two results.
I used SELECT * only because you did not specify the column selection.
SELECT *
FROM
(
SELECT TIG_TOL.sName AS Maschine,
TIG_TOL.lTolRef,
Max(TIG_JOB.tActBegin) AS MaxvontActBegin
FROM TIG_JOB LEFT JOIN TIG_TOL ON TIG_JOB.lMacRef = TIG_TOL.lTolRef
WHERE (((TIG_JOB.sState)="Run" Or (TIG_JOB.sState)="Ready"))
GROUP BY TIG_TOL.sName, TIG_TOL.lTolRef
) AS FirstTable
LEFT JOIN
(
SELECT TIG_JOB.sName AS Auftrag,
TIG_JOB.lJobRef,
TIG_TOL.sName AS Artikel,
TIG_TOL.sDescript AS Artikel_Bezeichnung,
TIG_JOB.tActBegin,
TIG_JOB.lMacRef
FROM (TIG_JOB LEFT JOIN TIG_TOL_BOK ON TIG_JOB.lJobRef = TIG_TOL_BOK.lJobRef)
LEFT JOIN TIG_TOL ON (TIG_TOL_BOK.lTolRef = TIG_TOL.lTolRef)
AND (TIG_TOL_BOK.lTolTypRef = TIG_TOL.lTolTypRef)
WHERE (((TIG_TOL.lTolTypRef)=10))
) AS SecondTable
ON FirstTable.MaxvontActBegin = SecondTable.tActBegin
AND FirstTable.lTolRef = SecondTable.lMacRef`

How to write subquery inside the OUTER JOIN Statement

I want to join two table CUSTMR and DEPRMNT.
My needed is: LEFT OUTER JOIN OF two or more Tables with subquery inside the LEFT OUTER JOIN as shown below:
Table: CUSTMR , DEPRMNT
Query as:
SELECT
cs.CUSID
,dp.DEPID
FROM
CUSTMR cs
LEFT OUTER JOIN (
SELECT
dp.DEPID
,dp.DEPNAME
FROM
DEPRMNT dp
WHERE
dp.DEPADDRESS = 'TOKYO'
)
ON (
dp.DEPID = cs.CUSID
AND cs.CUSTNAME = dp.DEPNAME
)
WHERE
cs.CUSID != ''
Here the subquery is:
SELECT
dp.DEPID, dp.DEPNAME
FROM
DEPRMNT dp
WHERE
dp.DEPADDRESS = 'TOKYO'
Is it possible to write such subquery inside LEFT OUTER JOIN?
I am getting an error when running this query on my DB2 database.
You need the "correlation id" (the "AS SS" thingy) on the sub-select to reference the fields in the "ON" condition. The id's assigned inside the sub select are not usable in the join.
SELECT
cs.CUSID
,dp.DEPID
FROM
CUSTMR cs
LEFT OUTER JOIN (
SELECT
DEPID
,DEPNAME
FROM
DEPRMNT
WHERE
dp.DEPADDRESS = 'TOKYO'
) ss
ON (
ss.DEPID = cs.CUSID
AND ss.DEPNAME = cs.CUSTNAME
)
WHERE
cs.CUSID != ''
I think you don't have to use sub query in this scenario.You can directly left outer join the DEPRMNT table .
While using Left Outer Join ,don't use columns in the RHS table of the join in the where condition, you ll get wrong output