Select only characters in SQL - sql

Question

I have strings in a database like this:
firstname.lastname#email.com
And I only need the characters that appear after the # symbol and before (.) symbol i.e. (email) from the above example
I am trying to find a simple way to do this in SQL.

Answer 1

Do this:
use [your_db_name];
go
create table dbo.test
(
string varchar(max) null
)
insert into dbo.test values ('firstname.lastname#email.com')
select
string,
substring(
string,
charindex('#', string, 0) + 1,
charindex('.', string, charindex('#', string, 0)) - charindex('#', string, 0) - 1
) as you_need
from dbo.test

Answer 2

String manipulations are such a pain in SQL Server. Here is one method:
select t.*,
left(en.emailname, charindex('.', en.emailname + '.') - 1)
from t outer apply
(select stuff(email, 1, charindex('#', email + '#'), '') as emailname) en;
That that in the charindex() calls, the character being searched for is placed at the end of the string. This allows the code to work even for malformed emails -- it returns an empty string when the email is not of the form '%#%.%'.

Answer 3

DECLARE #col char(200)
set #col = 'firstname.lastname#email.com'
SELECT SUBSTRING(#col, LEN(LEFT(#col, CHARINDEX ('#', #col))) + 1, LEN(#col) - LEN(LEFT(#col, CHARINDEX ('#', #col))) - LEN(RIGHT(#col, LEN(#col) - CHARINDEX ('.', #col))) - 4);

Answer 4

DECLARE #str varchar(50) = 'firstname.lastname#email.com';
SELECT LEFT(
RIGHT(#str, LEN(#str) - CHARINDEX('#', #str))
,CHARINDEX('.', RIGHT(#str, LEN(#str) - CHARINDEX('#', #str))
) - 1) AS OUTPUT
Above query gives only domain-name from Email. The query can be applied for column in a table

Answer 5

Try This:-
DECLARE #Text varchar(100)
SET #Text = 'firstname.lastname#email.com'
SELECT SUBSTRING(STUFF(#Text, 1, CHARINDEX('#',#Text), ''), 0,
CHARINDEX('.', STUFF(#Text, 1, CHARINDEX('#',#Text), '')))
Result:-
email

Answer 6

DECLARE #myStr varchar(100) = 'firstname.lastname#email.com'
SELECT
SUBSTRING(SUBSTRING(#myStr,CHARINDEX('#',#myStr)+1,LEN(#myStr)-CHARINDEX('#',#myStr)+1),0,CHARINDEX('.',SUBSTRING(#myStr,CHARINDEX('#',#myStr)+1,LEN(#myStr)-CHARINDEX('#',#myStr)+1)))
That can be useful but I really recommend you to build user defined function in C#/Visaul basic they could be much more faster that this.

Answer 7

Using charindex, len and reverse to search for the positions of the # and the last dot.
And substring to get the name based on those positions:
create table test (id int identity(1,1), email varchar(60));
insert into test (email) values
('jane.doe#email.com'),
('not an email'),
('#invalid.email.xxx'),
('john.doe#longer.domainname.net');
select *,
(case
when email like '[a-z]%#%.%'
then substring(email,
charindex('#',email)+1,
len(email) - charindex('#',email) - charindex('.',reverse(email))
)
end) as email_domain_without_extension
from test;
The CASE WHEN is used to return NULL when it's not an email (instead of an empty string).