Actually I have different date in SQL table when I pull those via SQL query, day of datetime field should have fixed day.
Example: (DD-MM-YYYY) day should be "7" > (7-MM-YYYY)
10-08-2007 > 07-08-2007
27-12-2013 > 07-12-2013
01-03-2017 > 07-03-2017
Can someone help me on this. Thanks in Advance.
Find the difference between 7 and the day of the original date and add that to the original date:
SELECT DATEADD(DAY, 7 - DAY(OriginalDate), OriginalDate)
Use DATEPART to take out the month and year parts. Cast those into varchar and concatenate with 07.
Query
select '07-' +
cast(DATEPART(mm, [date_column]) as varchar(2)) + '-' +
cast(DATEPART(yyyy, [date_column]) as varchar(4))
from your_table_name;
Assuming You might have to change the day number example
DECLARE #dayNum char(2)
SELECT #dayNum = '07'
select #dayNum + Right(convert(char(10),getdate(),105),8)
If that is not the case You could do this
select '07'+ Right(convert(char(10),'10-08-2007',105),8)
I'd go this way:
SELECT CONVERT(DATE,CONVERT(VARCHAR(6),GETDATE(),112)+'25',112);
CONVERT with format 112 will return the date as unseparated ISO (today we would get 20170407). Convert this to VARCHAR(6) will implicitly cut away the day's part (201704).
Now we add a day and use again CONVERT with 112, but now with DATE as target type.
One thing to keep in mind: The day you add must be two-digit. You can achieve this with
DECLARE #int INT=7;
SELECT REPLACE(STR(#int,2),' ','0');
Use DATEFROMPARTS: Updated ONLY works from 2012 - OP has tagged SQL-Server 2008
select DATEFROMPARTS ( year('10-08-2007'), month('10-08-2007'), 7 )
Assuming that your field is of datetime datatype and your fixed day is of integer type.
select datetimecolumn+(yourparamfixedday-datepart(dd,datetimecolumn))
Related
In SQL. How to convert a column A from (YYYY-MM-DD) to (YYYYMM)? I want to show the dates in YYYYMM format instead of YYYY-MM-DD.
Data type is TIMESTAMP. Using Teradata Studio 15.10.10.
For Teradata either use
to_char(tscol, 'YYYYMM') -- varchar result
or
extract(year from tscol) * 100 + extract(month from tscol) -- integer result
In Teradata you can format dates pretty much at will. To get YYYYMM, you would use
select <your date> (format 'yyyymm') (char(6))
Your date column needs to be actual date for this, not a string.
There are 3 functions you'll need.
MONTH() function. Returns the MONTH for the date within a range of 1 to 12 ( January to December). It Returns 0 when MONTH part for the date is 0.
YEAR() function. Returns a 4 digit YEAR.
CONCAT() function is used to concatenate two or more strings together.
So here's an example of combining the 3 functions.
SELECT CONCAT(YEAR('1969-02-18'),MONTH('1969-02-18'))
or you can do it in one with
select DATE_FORMAT('1969-02-18','%Y%m')
So to answer your question if it is referring to column A, you can use
SELECT DATE_FORMAT(A,'%Y%m')
SQL Fiddle:
http://www.sqlfiddle.com/#!9/a6c585/48362
You can use DATEPART to get the year and month parts of the date, cast to a varchar, pad and the concaternate.
SELECT DATEPART(YEAR,GETDATE())
SELECT DATEPART(MONTH,GETDATE())
SELECT CAST(DATEPART(YEAR,GETDATE()) AS VARCHAR(4)) + RIGHT('00' + CAST(DATEPART(MONTH,GETDATE()) AS VARCHAR(2)),2)
Is there a elegant way to convert a "date of birth" column with format like "28-Mar-99" to "1999-03-28" in hive?
I used the below query to handel these, it works well for the date after 2000, but for the date before 2000, it gives NULL or 20XX.
select a.d_cancel,
from_unixtime(unix_timestamp(a.d_cancel ,'dd-MMM-yy'), 'yyyy-MM-dd') as new_date
from test_table a;
d_cancel new_date
0 12-Apr-07 2007-04-12
1 31-Dec-99 NULL
2 20-Sep-98 2098-09-20
You can use this query:
-- D/M/Y format (everywhere else)
SELECT CAST(DAY(#date) AS varchar(2)) + '/'
+ CAST(MONTH(#date) AS varchar(2)) + '/'
+ CAST(YEAR(#date) AS varchar(4))
DECLARE #Day VARCHAR(10)='28-Mar-99'
SELECT CONVERT (DATE,#Day,126) AS ConvertedDate
DECLARE #Day VARCHAR(10)='28-Mar-99'
SELECT CAST (#Day AS DATE) AS ConvertedDate
I had a similar problem. I solve it with this:
select
if( to_date(from_unixtime(unix_timestamp( old_date_of_birth, "ddMMMyy"))) < from_unixtime(unix_timestamp()),
to_date(from_unixtime(unix_timestamp( old_date_of_birth, "ddMMMyy"))),
concat(year(to_date(from_unixtime(unix_timestamp( old_date_of_birth, "ddMMMyy"))))-100, SUBSTRING(to_date(from_unixtime(unix_timestamp( old_date_of_birth, "ddMMMyy"))),5,10))
) as new_date_of_birth
from users
In my case the dates were in the format ddMMMyy (24MAR93) and I didnt have the problem of the null you mention. But I did have the issue with the future dates of birth.
Since it is a late answer I assume you solved already the issue, but it may help other users.
I have gone through the suggested date formats here but didn't find any that meets my requirement.
I have the following date format:
05-JUN-99. 05 being dd as in day, JUN and the year 1999.
I have been asked to convert that to mmddyy (two digit month, two digit day and two digit year).
Any ideas how to do this?
Thanks for your assistance
You can use convert here.
select convert(varchar(20),cast('05-JUN-99' as date),10)
--Output: 06-05-99
select replace(convert(varchar(20),cast('05-JUN-99' as date),10),'-','')
--Output: 060599
Date Styles from the documentation
My Vote use FORMAT for SQL-SERVER 2012 +
SELECT FORMAT(CAST('05-JUN-99' AS DATETIME),'MMddyy')
This means no nested replaces, no extraneous cast/converts etc. keeps it tidier IMHO
I usually just convert to string. Get the year, month, day, put them each in a string and concatinate them.
Declare #InputValue Varchar(16) = '05-JUN-99'
set #InputValue = replace(#InputValue,'-','/')
declare #TestDate DateTime
set #TestDate = convert(DateTime,#InputValue)
select #TestDate
select right ('0' + convert(Varchar(2),DATEPART(mm,#TestDate)),2)
+ right ('0' + convert(Varchar(2),DATEPART(dd,#TestDate)),2)
+ right ('0' + convert(Varchar(4),DATEPART(yy,#TestDate)),2)
I have a date in following format in my DB.
10/16 - mm/yy
I need to convert it to:
October/16
Is this possible?
If it's not possible then please tell me why.
This is not a date, it's missing the day, it's a bad way to store year/month. There should be a 4 digit year to avoid confusion and the year should be listed first to enable correct sorting, e.g. '2016/10' or a numeric value 201610.
You can cast it to a DATE first and then use a FORMAT to disply only month/year:
set dateformat myd;
select format(cast(mystupidcolumn + '/1' as date), 'MMMM/yy')
Or SUBSTR the month part and use a CASE.
try this format,
SELECT DATENAME(month, DATEADD(month, #mydate-1, CAST('2008-01-01' AS datetime)))
You can display date by using this code
select datename(month, YourColumnName) + '/' + right(YEAR(YourColumnName),2)
FROM yourTableName
Simply change yourColumnName with name of your table column and yourTableName with name of table.
Yes you can, and it depend in what database you use to call date functions
If you column Datetime format
SQL server DATENAME(Month, GETDATE())
MySQL database MONTHNAME(now())
otherwise
convert it will in your choice at database or you code logic
split the value and lookup at month enum or fake the date to be accepted and complete date format like 01/10/16
so do something like SELECT DATENAME(Month, datecolumn) + '/' + YEAR (datecolumn)
also you can use instead of Year function DATEPART(yy,datecolumn)
the way you do it with format will look like
CONVERT(VARCHAR(11),GETDATE(),106)
but excepted to get first 3 char of month JUN
I am writing a query in which I have to get the data for only the last year. What is the best way to do this?
SELECT ... FROM ... WHERE date > '8/27/2007 12:00:00 AM'
The following adds -1 years to the current date:
SELECT ... From ... WHERE date > DATEADD(year,-1,GETDATE())
I found this page while looking for a solution that would help me select results from a prior calendar year. Most of the results shown above seems return items from the past 365 days, which didn't work for me.
At the same time, it did give me enough direction to solve my needs in the following code - which I'm posting here for any others who have the same need as mine and who may come across this page in searching for a solution.
SELECT .... FROM .... WHERE year(*your date column*) = year(DATEADD(year,-1,getdate()))
Thanks to those above whose solutions helped me arrive at what I needed.
Well, I think something is missing here. User wants to get data from the last year and not from the last 365 days. There is a huge diference. In my opinion, data from the last year is every data from 2007 (if I am in 2008 now). So the right answer would be:
SELECT ... FROM ... WHERE YEAR(DATE) = YEAR(GETDATE()) - 1
Then if you want to restrict this query, you can add some other filter, but always searching in the last year.
SELECT ... FROM ... WHERE YEAR(DATE) = YEAR(GETDATE()) - 1 AND DATE > '05/05/2007'
The most readable, IMO:
SELECT * FROM TABLE WHERE Date >
DATEADD(yy, -1, CONVERT(datetime, CONVERT(varchar, GETDATE(), 101)))
Which:
Gets now's datetime GETDATE() = #8/27/2008 10:23am#
Converts to a string with format 101 CONVERT(varchar, #8/27/2008 10:23am#, 101) = '8/27/2007'
Converts to a datetime CONVERT(datetime, '8/27/2007') = #8/27/2008 12:00AM#
Subtracts 1 year DATEADD(yy, -1, #8/27/2008 12:00AM#) = #8/27/2007 12:00AM#
There's variants with DATEDIFF and DATEADD to get you midnight of today, but they tend to be rather obtuse (though slightly better on performance - not that you'd notice compared to the reads required to fetch the data).
Look up dateadd in BOL
dateadd(yy,-1,getdate())
GETDATE() returns current date and time.
If last year starts in midnight of current day last year (like in original example) you should use something like:
DECLARE #start datetime
SET #start = dbo.getdatewithouttime(DATEADD(year, -1, GETDATE())) -- cut time (hours, minutes, ect.) -- getdatewithouttime() function doesn't exist in MS SQL -- you have to write one
SELECT column1, column2, ..., columnN FROM table WHERE date >= #start
I, like #D.E. White, came here for similar but different reasons than the original question. The original question asks for the last 365 days. #samjudson's answer provides that. #D.E. White's answer returns results for the prior calendar year.
My query is a bit different in that it works for the prior year up to and including the current date:
SELECT .... FROM .... WHERE year(date) > year(DATEADD(year, -2, GETDATE()))
For example, on Feb 17, 2017 this query returns results from 1/1/2016 to 2/17/2017
For some reason none of the results above worked for me.
This selects the last 365 days.
SELECT ... From ... WHERE date BETWEEN CURDATE() - INTERVAL 1 YEAR AND CURDATE()
The other suggestions are good if you have "SQL only".
However I suggest, that - if possible - you calculate the date in your program and insert it as string in the SQL query.
At least for for big tables (i.e. several million rows, maybe combined with joins) that will give you a considerable speed improvement as the optimizer can work with that much better.
argument for DATEADD function :
DATEADD (*datepart* , *number* , *date* )
datepart can be: yy, qq, mm, dy, dd, wk, dw, hh, mi, ss, ms
number is an expression that can be resolved to an int that is added to a datepart of date
date is an expression that can be resolved to a time, date, smalldatetime, datetime, datetime2, or datetimeoffset value.
declare #iMonth int
declare #sYear varchar(4)
declare #sMonth varchar(2)
set #iMonth = 0
while #iMonth > -12
begin
set #sYear = year(DATEADD(month,#iMonth,GETDATE()))
set #sMonth = right('0'+cast(month(DATEADD(month,#iMonth,GETDATE())) as varchar(2)),2)
select #sYear + #sMonth
set #iMonth = #iMonth - 1
end
I had a similar problem but the previous coder only provided the date in mm-yyyy format. My solution is simple but might prove helpful to some (I also wanted to be sure beginning and ending spaces were eliminated):
SELECT ... FROM ....WHERE
CONVERT(datetime,REPLACE(LEFT(LTRIM([MoYr]),2),'-
','')+'/01/'+RIGHT(RTRIM([MoYr]),4)) >= DATEADD(year,-1,GETDATE())
Here's my version.
YEAR(NOW())- 1
Example:
YEAR(c.contractDate) = YEAR(NOW())- 1
For me this worked well
SELECT DATE_ADD(Now(),INTERVAL -2 YEAR);
If you are trying to calculate "rolling" days, you can simplify it by using:
Select ... FROM ... WHERE [DATE] > (GETDATE()-[# of Days])