I am writing a query in which I have to get the data for only the last year. What is the best way to do this?
SELECT ... FROM ... WHERE date > '8/27/2007 12:00:00 AM'
The following adds -1 years to the current date:
SELECT ... From ... WHERE date > DATEADD(year,-1,GETDATE())
I found this page while looking for a solution that would help me select results from a prior calendar year. Most of the results shown above seems return items from the past 365 days, which didn't work for me.
At the same time, it did give me enough direction to solve my needs in the following code - which I'm posting here for any others who have the same need as mine and who may come across this page in searching for a solution.
SELECT .... FROM .... WHERE year(*your date column*) = year(DATEADD(year,-1,getdate()))
Thanks to those above whose solutions helped me arrive at what I needed.
Well, I think something is missing here. User wants to get data from the last year and not from the last 365 days. There is a huge diference. In my opinion, data from the last year is every data from 2007 (if I am in 2008 now). So the right answer would be:
SELECT ... FROM ... WHERE YEAR(DATE) = YEAR(GETDATE()) - 1
Then if you want to restrict this query, you can add some other filter, but always searching in the last year.
SELECT ... FROM ... WHERE YEAR(DATE) = YEAR(GETDATE()) - 1 AND DATE > '05/05/2007'
The most readable, IMO:
SELECT * FROM TABLE WHERE Date >
DATEADD(yy, -1, CONVERT(datetime, CONVERT(varchar, GETDATE(), 101)))
Which:
Gets now's datetime GETDATE() = #8/27/2008 10:23am#
Converts to a string with format 101 CONVERT(varchar, #8/27/2008 10:23am#, 101) = '8/27/2007'
Converts to a datetime CONVERT(datetime, '8/27/2007') = #8/27/2008 12:00AM#
Subtracts 1 year DATEADD(yy, -1, #8/27/2008 12:00AM#) = #8/27/2007 12:00AM#
There's variants with DATEDIFF and DATEADD to get you midnight of today, but they tend to be rather obtuse (though slightly better on performance - not that you'd notice compared to the reads required to fetch the data).
Look up dateadd in BOL
dateadd(yy,-1,getdate())
GETDATE() returns current date and time.
If last year starts in midnight of current day last year (like in original example) you should use something like:
DECLARE #start datetime
SET #start = dbo.getdatewithouttime(DATEADD(year, -1, GETDATE())) -- cut time (hours, minutes, ect.) -- getdatewithouttime() function doesn't exist in MS SQL -- you have to write one
SELECT column1, column2, ..., columnN FROM table WHERE date >= #start
I, like #D.E. White, came here for similar but different reasons than the original question. The original question asks for the last 365 days. #samjudson's answer provides that. #D.E. White's answer returns results for the prior calendar year.
My query is a bit different in that it works for the prior year up to and including the current date:
SELECT .... FROM .... WHERE year(date) > year(DATEADD(year, -2, GETDATE()))
For example, on Feb 17, 2017 this query returns results from 1/1/2016 to 2/17/2017
For some reason none of the results above worked for me.
This selects the last 365 days.
SELECT ... From ... WHERE date BETWEEN CURDATE() - INTERVAL 1 YEAR AND CURDATE()
The other suggestions are good if you have "SQL only".
However I suggest, that - if possible - you calculate the date in your program and insert it as string in the SQL query.
At least for for big tables (i.e. several million rows, maybe combined with joins) that will give you a considerable speed improvement as the optimizer can work with that much better.
argument for DATEADD function :
DATEADD (*datepart* , *number* , *date* )
datepart can be: yy, qq, mm, dy, dd, wk, dw, hh, mi, ss, ms
number is an expression that can be resolved to an int that is added to a datepart of date
date is an expression that can be resolved to a time, date, smalldatetime, datetime, datetime2, or datetimeoffset value.
declare #iMonth int
declare #sYear varchar(4)
declare #sMonth varchar(2)
set #iMonth = 0
while #iMonth > -12
begin
set #sYear = year(DATEADD(month,#iMonth,GETDATE()))
set #sMonth = right('0'+cast(month(DATEADD(month,#iMonth,GETDATE())) as varchar(2)),2)
select #sYear + #sMonth
set #iMonth = #iMonth - 1
end
I had a similar problem but the previous coder only provided the date in mm-yyyy format. My solution is simple but might prove helpful to some (I also wanted to be sure beginning and ending spaces were eliminated):
SELECT ... FROM ....WHERE
CONVERT(datetime,REPLACE(LEFT(LTRIM([MoYr]),2),'-
','')+'/01/'+RIGHT(RTRIM([MoYr]),4)) >= DATEADD(year,-1,GETDATE())
Here's my version.
YEAR(NOW())- 1
Example:
YEAR(c.contractDate) = YEAR(NOW())- 1
For me this worked well
SELECT DATE_ADD(Now(),INTERVAL -2 YEAR);
If you are trying to calculate "rolling" days, you can simplify it by using:
Select ... FROM ... WHERE [DATE] > (GETDATE()-[# of Days])
Related
I am working on a query that tries to count from an exact date to an exact date. Today is 2/16/2022. Between 6/30/2020 and 2/16/2022 19 months have gone by. My DateDiff query returns 20? How can I force DateDiff function to return 19?
select datediff(month, '6/30/2020', getdate())
As per documentationSQL Docs, datediff returns
The int difference between the startdate and enddate, expressed in the boundary set by datepart.
which in your example is the number of months from June '20 to February '22 which is indeed 20. User user716255's code is pointing into the right direction in that it uses the first of each month in question. If your intention however is to really know how many months elapsed between two dates, the code should be amended like so:
(sorry, need to correct my original answer, as I misread the code from the other answer)
declare #start date
declare #end date
set #start = '20200630'
set #end = '20220216'
select datediff(month, dateadd(day, -day(#start)+1, #start), dateadd(day, -
day(#end)+1,#end))+CASE WHEN DAY(#end)>DAY(#start) THEN 1 ELSE 0 END
(with dates written in a format more useful for our international readers...)
The original coude would fail if start date would i.e. be 31st of July and the end date in February (as -31+1 would lead to a date in January)
Here is the solution that worked for me.
declare #start date
declare #end date
set #start = '6/30/2020'
set #end = '2/16/2022'
select datediff(month, dateadd(day, -day(#start)+1, #start), dateadd(day, -day(#start)+1,#end))
link to fiddle
I Need help in finding upcoming birthday in a month.
My Data is something like below , Both data types are nvarchar
Could anyone help me with the sql query please? how to set the DOB column into a date format and then find the birthday with month as 11 and date as 24.
Thanks in advance
Assuming SQL Server, you can use month() to extract the month from a date, for example getdate(), which is the current point in time. With left() you can extract the first characters of a string. That leads to something like:
SELECT [Name],
[Dob(mmdd)]
FROM elbat
WHERE month(getdate()) = left([Dob(mmdd)], 2);
In Microsoft SQL Server you can Create a date using the DATEFROMPARTS(int year, int month, int day) function. To get your month and day you would have to get the 2 parts of the string, the first 2 characters for month and the third and fourth characters as the day, you can use the SUBSTRING function for this. Then take each pair of characters for month and day and cast to int and use them in the DATEFROMPARTS function.
Then you want to see if your newly created date is BETWEEN today AND one month from today. So you could do something like this:
SELECT *
FROM SomeTable
WHERE
DATEFROMPARTS(YEAR(GETDATE()), CAST(SUBSTRING([Dob(mmdd)], 1, 2) as INT), CAST(SUBSTRING([Dob(mmdd)], 3, 2) as INT))
BETWEEN
DATEADD(DAY, -1, GETDATE()) AND DATEADD(MONTH, 1, GETDATE())
Note: this assumes [Dob(mmdd)] is always 4 characters.
You don't need the DOB in a date format. I am unclear what "upcoming" month means, but I suspect that it means a calendar month. If the current month, then:
where month(getdate()) = cast(left(dob, 2) as int)
If the next month, then:
where month(dateadd(month, 1, getdate())) = cast(left(dob, 2) as int)
Thanks, Everyone for the help.. I got this working,. both works perfect
select [USER_ID],[EMP_FULL_NM],[Birthday_Date] from [dbo].[COE]
where month(getdate())=left([Birthday_Date],2)
select [USER_ID],[JOINING_DT],[EMP_FULL_NM] from [dbo].[COE]
where SUBSTRING(CONVERT(VARCHAR(10), [JOINING_DT], 101),1,2) = month(getdate())
Actually I have different date in SQL table when I pull those via SQL query, day of datetime field should have fixed day.
Example: (DD-MM-YYYY) day should be "7" > (7-MM-YYYY)
10-08-2007 > 07-08-2007
27-12-2013 > 07-12-2013
01-03-2017 > 07-03-2017
Can someone help me on this. Thanks in Advance.
Find the difference between 7 and the day of the original date and add that to the original date:
SELECT DATEADD(DAY, 7 - DAY(OriginalDate), OriginalDate)
Use DATEPART to take out the month and year parts. Cast those into varchar and concatenate with 07.
Query
select '07-' +
cast(DATEPART(mm, [date_column]) as varchar(2)) + '-' +
cast(DATEPART(yyyy, [date_column]) as varchar(4))
from your_table_name;
Assuming You might have to change the day number example
DECLARE #dayNum char(2)
SELECT #dayNum = '07'
select #dayNum + Right(convert(char(10),getdate(),105),8)
If that is not the case You could do this
select '07'+ Right(convert(char(10),'10-08-2007',105),8)
I'd go this way:
SELECT CONVERT(DATE,CONVERT(VARCHAR(6),GETDATE(),112)+'25',112);
CONVERT with format 112 will return the date as unseparated ISO (today we would get 20170407). Convert this to VARCHAR(6) will implicitly cut away the day's part (201704).
Now we add a day and use again CONVERT with 112, but now with DATE as target type.
One thing to keep in mind: The day you add must be two-digit. You can achieve this with
DECLARE #int INT=7;
SELECT REPLACE(STR(#int,2),' ','0');
Use DATEFROMPARTS: Updated ONLY works from 2012 - OP has tagged SQL-Server 2008
select DATEFROMPARTS ( year('10-08-2007'), month('10-08-2007'), 7 )
Assuming that your field is of datetime datatype and your fixed day is of integer type.
select datetimecolumn+(yourparamfixedday-datepart(dd,datetimecolumn))
I need to get the last day of month with input of month and year. For example, with input 06/2016 it will return 30. I use SQL Server 2005. Thanks for any help.
Suppose your input is VARCHAR in the form of MM/YYYY.
Use RIGHT and LEFT to get the year and month respectively. Then use DATEFROMPARTS to generate the starting date. Next, use EOMONTH to get the last day of the month. Finally use DAY to extract the day part.
DECLARE #input VARCHAR(7) = '06/2016'
SELECT
DAY(
EOMONTH(
DATEFROMPARTS(CAST(RIGHT(#input,4) AS INT),CAST(LEFT(#input, 2) AS INT),1)
)
)
The above only works for SQL Server 2012+.
For SQL Server 2005, you can use DATEADD to generate the dates:
SELECT
DAY( -- Day part
DATEADD(DAY, -1, -- Last day of the month
DATEADD(MONTH, CAST(LEFT(#input, 2) AS INT), -- Start of next month
DATEADD(YEAR, CAST(RIGHT(#input, 4) AS INT) - 1900, 0) -- Start of the year
)
)
)
Reference:
Some Common Date Routines
You would do something like this:
select eomonth(getdate(), 0);
If you want it formatted as MM/YYYY then you'd do this:
select format(eomonth(getdate(), 0), 'MM/yyyy');
Pardon me for tossing-in a response that is not specific to "SQL Server," nor thence to "2005," but the generalized way to compute the answer that you seek is as follows:
Break down the input that you have, e.g. 06/2016, into two parts. Call 'em #MONTH and #YEAR. Define a third value, #DAY, equal to 1.
Typecast this into a date-value ... "June 1, 2016."
Now, using the date-handling functions that you're sure to have, "first add one month, then subtract one day."
One thing that you must be very careful of, when designing code like this, is to be certain(!) that your code for decoding 06/2016 works for every(!) value that actually occurs in that database, or that it can be relied upon to fail.
try this,
declare #input varchar(20)='06/2016'
set #input=#input+'/01'
declare #dtinput datetime=#input
select dateadd(day,-1,dateadd(month,datediff(month,0,#dtinput)+1,0))
--OR in sql server 2012
select eomonth(#dtinput)
SELECT Date_Received, DateAdd(Year, DateDiff(year, Cast('3/01/2010 12:00:00AM' as DateTime) ,
GetDate())-1, Cast('3/01/2010 12:00:00AM' as DateTime)) as minimum_date
FROM [Volunteers].[dbo].[Applications]
WHERE Date_received >= DateAdd(Year, DateDiff(year, Cast('3/01/2010 12:00:00AM' as DateTime),
GetDate())-1, Cast('3/01/2010 12:00:00AM' as DateTime))
In several subqueries where I need to check that a date is within an acceptable range. I need to avoid using a simple constant as I really don't want to update it or a config file each new school year.
My current solution is to enter the date into the query and use some complicated DATEADD tricks to get the current year(or previous year) into the date I am using in the comparison. The exact code is above. Is there a cleaner way for me to do this?
Thanks
Edit
The business requirement is to find applications submitted between 3/01 and 7/31.
We are running background checks and it costs us money for each check we do. Identifying applications submitted during this time period helps us determine if we should do a full, partial or no background check. I will also need to check if dates concerning the previous year.
We will be doing this every year and we need to know if they were in the current year. Maintaining the queries each year to update the dates is not something I want to do.
So I am looking for a good technique to keep the year parts of the dates relevant without having to update the query or a config file.
Old TSQL trick: cast the date to a string in a format that starts with the four-digit year, using substring to take the first four characters of that, cast it back to a date.
Actually, the reason that it's an old TSQL trick is that, if I recall correctly, there wasn't a year() function back then. Given that there's one now, using year( getdate() ) , as others' have answered, is probably the better answer.
SELECT YEAR(GETDATE())
will give you the current year.
If you need to query by month and year a lot, you should also consider making those properties into persisted, computed fields:
ALTER TABLE dbo.Applications
ADD DateReceivedMonth AS MONTH(Date_Received) PERSISTED
ALTER TABLE dbo.Applications
ADD DateReceivedYear AS YEAR(Date_Received) PERSISTED
SQL Server will now extract the MONTH and YEAR part of your Date_Received and place them into two new columns. Those are persisted, e.g. stored along side with your table data. SQL Server will make sure to keep them up to date automatically, e.g. if you change Date_Received, those two new columns will be recomputed (but not on every SELECT).
Now, your queries might be a lot easier:
SELECT (list of fields)
FROM dbo.Applications
WHERE DateReceivedYear = 2010 AND DateReceivedMonth BETWEEN 3 AND 7
Since these are persisted fields, you can even put an index on them to speed up queries against them!
Is there any reason you cannot simply use the Year function?
Select Date_Received
, Year(GetDate())
- Year('3/01/2010 12:00:00AM') - 1
+ Year('3/01/2010 12:00:00AM')
From [Volunteers].[dbo].[Applications]
Where Date_received >= ( Year(GetDate())
- Year('3/01/2010 12:00:00AM') - 1
+ Year('3/01/2080 12:00:00AM') )
Another way would be to use a common-table expression
With Years As
(
Select Year(GetDate()) As CurrentYear
, Year('3/01/2010 12:00:00AM') As ParamYear
, Year('3/01/2080 12:00:00AM') As BoundaryYear
)
Select Date_Received
, CurrentYear - Years.ParamYear - 1 + Years.ParamYear
From [Volunteers].[dbo].[Applications]
Cross Join Years
Where Date_received >= ( Years.CurrentYear
- Years.ParamYear - 1 + Years.BoundaryYear )
TSQL Function returns four digit year dependent on year. This behaves much like the standard SQL YEAR functions [Thomas - nod] which 'CAN' be tweaked using sp_configure on the advanced options, however, the code below is provided as a framework for CUSTOM requirements and can be modified as required. e.g. return as int, use with standard DATETIME functions in SQL to achieve what is needed. e.g. When working with "dirty" data I had to migrate, I used it with the PATINDEX() function to strip non-numeric values etc.
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
-- =============================================
-- Author: Andrew McLintock
-- Create date: 13 July 2016
-- Description: Return 4-digit YEAR
-- =============================================
/*
SELECT Staging.fn_4year('06')
SELECT Staging.fn_4year('56')
SELECT Staging.fn_4year('99')
SELECT Staging.fn_4year('1906')
SELECT Staging.fn_4year('2025')
*/
CREATE FUNCTION Staging.fn_4year
(
#year_in varchar (4)
)
RETURNS varchar(4)
AS
BEGIN
DECLARE #yeartmp int, #Retval varchar(4)
SET #yeartmp = CAST(REPLACE(#year_in,' ','') AS INT)
IF LEN(CAST(#yeartmp AS Varchar)) = 4
BEGIN
Return cast(#yeartmp as varchar(4))
END
IF LEN(#year_in) = 2
BEGIN
SET #Retval = CAST(iif(#yeartmp > 49, #yeartmp + 1900, #yeartmp + 2000) AS varchar(4))
END
RETURN #Retval
END
GO
Consider keeping a set of datetime variables help readability and maintainability. I'm not sure I've captured all your requirements, especially with reference to 'previous year'. If it's as simple as finding applications submitted between 3/01 and 7/31, then this should work. If you need to determine those that were submitted Aug 1 (last year) through Feb 28 (current year), this solution could be modified to suit.
DECLARE #Start smalldatetime, #End smalldatetime, #CurrYear char(4)
SELECT #CurrYear = YEAR(getdate())
SELECT #Start = CAST( 'mar 1 ' + #CurrYear as smalldatetime),
#End = CAST( 'jul 31 ' + #CurrYear as smalldatetime)
SELECT *
FROM Applications
WHERE Date_Received
BETWEEN #Start AND #End