SPARQL list literals of selected OWL Datatype - sparql

How to list all literals of only selected OWL datatype (here :VisibilityKind) in SPARQL? The OWL datatype definition of VisibilityKind is:
DatatypeDefinition( :VisibilityKind
DataOneOf( "public"^^xsd:string "private"^^xsd:string "package"^^xsd:string )
)

With SPARQL, you can get all the literals that have a certain datatype IRI. For instance, assuming you have data with literals such as "public"^^:VisibilityKind, you can write:
SELECT ?literal WHERE {
?s ?p ?literal .
FILTER (datatype(?literal) = :VisibilityKind)
}
But this is certainly not what you want because you probably do not have literals with this datatype IRI. What you would probably like is something that could roughly be formulated as:
SELECT ?literal WHERE {
?s ?p ?literal .
FILTER (isInDatatype(?literal,:VisibilityKind))
}
where isInDatatype checks if the value associated with ?o belongs to the value space of :VisibilityKind. However, such function does not exist in standard SPARQL 1.1. Moreover, even if it existed, it would require the query engine to understand the semantics of OWL 2 and do reasoning. So you would need a SPARQL engine that implements the OWL 2 DL entailment regime and you'd have to hack a bit the query to get what you want:
SELECT ?literal WHERE {
?s ?p ?literal .
[] a :VisibilityKind;
:owl:sameAs ?literal;
FILTER (isLiteral(?literal))
}
If you want to find implementations of SPARQL 1.1 Entailment regimes, you could take a look at the implementation reports collected by the SPARQL working group.

To answer directly, you need to search for all values in the owl:oneOf list:
SELECT ?resource ?value
WHERE {
:VisibilityKind owl:equivalentClass / owl:oneOf / ( rdf:rest*/rdf:first ) ?value .
?resource ?prop ?value .
}
However, there is a caveat - other properties could have the value "public" "private" or "package". To ensure that you're getting only the values of :VisibilityKind, define that datatype as a range of properties that use the datatype:
{ :someProp rdfs:domain :VisibilityKind }
Then use the following query to get all properties that define :VisibilityKind in the range:
SELECT ?resource ?value
WHERE {
?prop rdfs:range :VisibilityKind .
?resource ?prop ?value
}

Related

Type of returned value in SPARQL Query

Is it possible to know the type of the return values in a SPARQL query?
For example, is there a function to define the type of ?x ?price ?p
in the following query?
SELECT DISTINCT ?x ?price ?p
WHERE {
?x a :Product .
?x :price ?price .
?x ?p ?o .
}
I want to know that
typeOf(x) = resource
typeOf(?p) = property
typeOf(?price) = property target etc.
datatype(?x)
The datatype function will tell you whether a result is a resource or a literal and in the latter case tell you which datatype it has exactly.
For example, the following query on https://dbpedia.org/sparql...
SELECT DISTINCT ?x ?code ?p datatype(?x) datatype(?code) datatype(?p)
WHERE {
?x a dbo:City.
?x dbo:areaCode ?code .
?x ?p ?o .
} limit 1
...will return:
x
code
p
callret-3
callret-4
callret-5
http://dbpedia.org/resource/Aconchi
"+52 623"
http://www.w3.org/1999/02/22-rdf-syntax-ns#type
http://www.w3.org/2001/XMLSchema#anyURI
http://www.w3.org/2001/XMLSchema#string
http://www.w3.org/2001/XMLSchema#anyURI
However this will not differentiate between "resource" and "property" because a resource may be a property. What you probably mean is "individual" and "property" but even a property can be treated as an individual, for example in the triple rdfs:label rdfs:label "label".
However you can always query the rdf:type of a resource, which may give you rdf:Property, owl:DatatypeProperty or owl:ObjectProperty.

How to get all property from an item based on its Q number?

I want to gather all properties of a item from wikidata.
All queries I see so far assume you know properties you are looking for, but in my case, I'm not.
For example, when querying for Q1798740, I would like a returned value that looks like
[{"item": "Q1798740",
"P31": ["Q1146"],
"P17": ["Q70972"],
...
"P2043":"70 metres"}
]
and that contains all statements from the wikidata page
What query should I perform?
You need only to ask for {wd:Q1798740 ?p ?value} but it would be useful also to get the labels of the properties, which is a bit trickier:
SELECT DISTINCT ?p ?property_label ?value
WHERE
{
wd:Q1798740 ?p ?value .
?property wikibase:directClaim ?p ;
rdfs:label ?property_label .
FILTER(LANG(?property_label)="en")
}

i want to get the names of similar types using sparql queries from dbpedia

I need to find the names of similar types from DBpedia so I'm trying to figure out a query which can return me the names of entities which have same subject type in its dct:subject (example I want to find similar types of white house so i want to write a query for same . I'm considering the dct:subject to find them ). If there is any other approach please mention it
Previously I tried it for rdf:type but the result are not so good and some time it shows time out
I have done my problem by the query mentioned below and now i want to consider dct:subject instead of rdf:type
select distinct ?label ?resource count(distinct ?type) as ?score where {
values ?type { dbo:Thing dbo:Organization yago:WikicatIslam-relatedControversies yago:WikicatIslamistGroups yago:WikicatRussianFederalSecurityServiceDesignatedTerroristOrganizations yago:Abstraction100002137 yago:Act100030358 yago:Cabal108241798 yago:Group100031264 yago:Movement108464601 yago:PoliticalMovement108472335
}
?resource rdfs:label ?label ;
foaf:name ?name ;
a ?type .
FILTER (lang(?label) = 'en').
}
ORDER BY DESC(?score)

How to return all S->P->O triples from a starting resource to a specified path depth?

My goal is to graphically represent the S->P->O relations within a depth two edges from the specified resource, p:Person_1. I want all relations within that path length to be returned from my query as ?s, ?p, ?o for further processing in my graphical application.
I tried the first query below which gives me my first set of ?s ?p ?o with repeats, then ?p2, ?o2, ?p3, ?o3 as additional columns in the result. I want to bind ?p2 and ?p3 to ?p, ?o2 and ?o3 to ?o.
SELECT *
WHERE {
p:Person_1 ?p ?o .
BIND("p:Person_1" as ?s)
OPTIONAL{
?o ?p2 ?o2 .
}
OPTIONAL{
?o2 ?p3 ?o3 .
}
}
Then, based on How do I construct get the whole sub graph from a given resource in RDF Graph?, I tried using CONSTRUCT to return the graph.
PREFIX p: <http://www.example.org/person/>
PREFIX x: <example.org/foo/>
construct { ?s ?p ?o }
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:|!x:)* ?s .
?s ?p ?o .
}
I am using Virtuoso and I get the error:
Virtuoso 37000 Error SP031: SPARQL compiler: Variable ?_::trans_subj_9_3 in T_IN list is not a value from some triple
I could post-process the result from my first query but I want to learn how to do this correctly with SPARQL, preferably on Virtuoso.
Update after testing the advice from #AKSW :
Both CONSTRUCT and SELECT statements work with the pattern suggested.
CONSTRUCT { ?s ?p ?o }
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:foo|!x:bar)* ?s .
?s ?p ?o .
} LIMIT 100
and:
SELECT s ?p ?o
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:foo|!x:bar)* ?s .
?s ?p ?o .
} LIMIT 100
The SELECT results in several duplicates that cannot be removed using DISTINCT, which results in an error that I assume is due to the 'datatype' of some of the returned values.
Virtuoso 22023 Error SR066: Unsupported case in CONVERT (DATETIME -> IRI_ID)
It appears some post-SPARQL processing is in order.
This gets me most of the way there. Still hoping I can find a solution for SPARQL that is like Cypher's "number of hops away" :
OPTIONAL MATCH path=s-[*1..3]-(o)
Here is a SPARQL query that works in Virtuoso. Note the SPARQL W3C standard does not support this syntax and it will fail in other triplestores.
PREFIX p: <http://www.example.org/person/>
PREFIX x: <example.org/foo/>
# CONSTRUCT {?s ?p ?o} # If you wish to return the graph
SELECT ?s ?p ?o # To return the triples
FROM <http://localhost:8890/MYGRAPH>
where { p:Person_1 (x:foo|!x:bar){1,3} ?s .
?s ?p ?o .
}LIMIT 100
See also K. Idehen's wiki entry here: http://linkedwiki.com/exampleView.php?ex_id=141
And thanks to #Joshua Taylor for advice in the same area.
Working Drafts of SPARQL 1.1 Property Paths included the {n,m} operator for handling this issue, which was implemented (and will remain supported) in Virtuoso. Here's a tweak to #tim's response.
Live SPARQL Query Results Page using the DBpedia endpoint (which is a Virtuoso instance).
Live SPARQL Query Definition Page that opens up query source code in the default DBpedia query editor.
Actual Query Example:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
SELECT DISTINCT ?s AS ?Entity
?o AS ?Category
WHERE {
?s rdf:type <http://dbpedia.org/ontology/AcademicJournal> ;
rdf:type{1,3} ?o
}
LIMIT 100
Should you be looking for LinkedIn-like presentation of Contact Networks and Degrees of Separation between individuals, here is an example using Virtuoso-specific SPARQL Extensions that solve this particular issue:
SELECT ?o AS ?WebID
((SELECT COUNT (*) WHERE {?o foaf:knows ?xx})) AS ?contact_network_size
?dist AS ?DegreeOfSeparation
<http://www.w3.org/People/Berners-Lee/card#i> AS ?knowee
WHERE
{
{
SELECT ?s ?o
WHERE
{
?s foaf:knows ?o
}
} OPTION (TRANSITIVE, t_distinct, t_in(?s), t_out(?o), t_min (1), t_max (4), t_step ('step_no') AS ?dist) .
FILTER (?s= <http://www.w3.org/People/Berners-Lee/card#i>)
FILTER (isIRI(?s) and isIRI(?o))
}
ORDER BY ?dist DESC (?contact_network_size)
LIMIT 500
Note: this approach is the only way (at the current time) to expose actual relational hops between entities in an Entity Relationship Graph that includes Transitive relations.
Live Link to Query Results
Live Link to Query Source Code
Bearing in mind that the r{n,m} operator was deprecated in the final SPARQL 1.1 (but will remain supported in Virtuoso), you can use r/r?/r? instead of r{1,3}, if you want to work strictly off the current spec:
PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
SELECT DISTINCT ?s AS ?Entity
?o AS ?Category
WHERE {
?s rdf:type <http://dbpedia.org/ontology/AcademicJournal> ;
rdf:type / rdf:type? / rdf:type? ?o
}
LIMIT 100
Here's a live example, against the DBpedia instance hosted in Virtuoso.

sparql to retrieve the value of a min constraint

How can I retrieve a min constraint on a class' attribute using sparql? I have value min 1000 decimal, and I would like to get 1000
In a hypothetical world that you have such a statement:
Class: X subClassOf: hasObjectProperty min 1 Y
If you write a SPARQL query as:
SELECT *
WHERE {
?s rdfs:subClassOf ?o.
}
You must extract all the refs:subClassOf axioms. However, if you need to precise and know which ones have cardinality restrictions, you need to go further:
PREFIX rdfs: <http://www.w3.org/2000/01/rdf-schema#>
prefix : <http://example.com#>
SELECT *
WHERE {
?s rdfs:subClassOf ?o.
?o ?x ?y.
filter(?s = :X)
}
Among others, you can see the following result:
As you can see, there are 2 relevant items, one is Y and one is the number presented as a non-negative integer. Therefore, one way to get each item is to put a filter for ?x in the SPARQL query and get each one one by one out. For example, filter owl:onClass will give you ?y:
prefix : <http://example.com#>
SELECT *
WHERE {
?s rdfs:subClassOf ?o.
?o owl:onClass ?y.
filter(?s = :X)
Here is the sparql query I used following Artemis' answer
SELECT ?min
WHERE {?s rdfs:subClassOf ?o.
?o owl:minQualifiedCardinality ?min.
FILTER(?s = :value) }
And with jena, I use getLiteral("min").getFloat();