I would like to extract information from 2 tables (joined).
SELECT B.INVOICE_NUMBER,
B.BILL_TO_NAME,
B.SHIP_TO_NAME //Need this some how joined, see comment on code below
FROM ADJUSTMENTS A,
INVOICE B,
CUSTOMER_LOCATION C,
CUSTOMER_NAME D
WHERE A.INVOICE_ID = B.INVOICE_ID
AND C.CUSTOMER_ID = D.CUSTOMER_ID
AND B.BILL_ID = C.ACCOUNT_NUMBER
//I want to add B.SHIP_ID = C.ACCOUNT_NUMBER as well,
//but I am unsure if it will work. Not sure how to extract information from
//two columns from the same table that is joined to one table.
I researched into sub-query, but that was returning to many rows so it errored out. I am a beginner to Oracle SQL, I've tried researching but not getting the solution. Any help is appreciated.
I can't tell 100% what you are wanting, but if b.bill_id and b.ship_id have 2 different account_number's and there is only one customer_location for each account_number, then you can probably add customer_location a second time with a different alias. If you need the customer_name record for the second customer_location then you will have to join that a second time as well. Perhaps:
SELECT b.invoice_number, b.bill_to_name, b.ship_to_name
FROM adjustments a, invoice b, customer_location c,
customer_location c2, customer_name d, customer_name d2
WHERE a.invoice_id = b.invoice_id
AND c.customer_id = d.customer_id
AND c2.customer_id = d2.customer_id
AND b.bill_id = c.account_number
AND b.ship_id = c2.account_number
Now your question is vague so it is hard to tell if this is what you are looking for. Watch for multiple rows per invoice invoice number if there is more than one customer_location record per account_number, and problem solve from there if needed. I hope this gets you closer to what you are looking for.
Related
My query here has a sub-query in it but it returns no output, but in reality it has to give some output because I manually checked and output exists.I have posted the query below.
select mac.mac_id,mac.mac1,mac.mac_type,record.soc_id
from mso_charter.mac
join record on mac.record_id = record.record_id
where mac.mac_type='ethB' and record.soc_id IN (select soc from d);
Sample data is below
mac_id mac1 mac_type record_id--- for table mac
1 6142 ethA 1
2 6412 ethB 1
3 2313 ethC 1
record_id soc_id ---- for table record
1 Qu132
1 as432
1 342aq
soc --- for table d
a12w2
23we
qw12
mso_charter is the schema name mac,d and record is the table name.
Note that your subquery is actually still a join and can be written that way:
select mac.mac_id,mac.mac1,mac.mac_type,record.soc_id
from mso_charter.mac
join record using(record_id)
join d on record.soc_id = d.soc
where mac.mac_type='ethB';
As per the comment we still need a data set to reproduce and help.
Should be select soc_id from d instead of select select soc from d
According to your sample data, d has a column soc_id. That should be used for the comparison:
select m.mac_id, m.mac1, m.mac_type, r.soc_id
from mso_charter.mac m join
record r
on m.record_id = r.record_id
where m.mac_type = 'ethB' and
r.soc_id in (select d.soc_id from d);
It is possible that ids look the same but are not, because of international characters, hidden characters, spaces in the wrong place, and so on.
If this doesn't work then try the following:
Remove the soc_id condition and see if any rows match the first condition and join.
If that still returns nothing, remove the entire where clause to see if anything matches the join.
None of your record.soc_id match any of your d.soc_id. So you get no row.
Also, you write select soc from d. soc, not soc_id. Typo or error?
So, thanks to all who tried helping me in this situation. I actually had did a very silly mistake.The reason I am posting the right answer is probably because if someone else in future get stuck in such a issue or something similar it would be helpful to them.
select m.mac_id,m.mac,m.mac_type,r.soc_id
from mso_charter.mac m
join mso_charter.record r on m.record_id = r.record_id
where m.mac_type = 'ethB' and r.soc_id IN (select d.soc_id from d);
Mistake was I had not mentioned the schema name while performing join and there were multiple tables named record in other schema's, it was just out of frustration we tend to forget small things which costed me few hours to work over.
Tables
ARMASTER = Customer Information
ORDERHEAD = Sales order information (Ship to, bill to)
Hey everyone! I'm still quite new to SQL and I do belive I'm picking it up fairly quick. I have been racking my brain on this for a few hours now and have asked around the office and nobody seems to have a solution.
I'm trying to identify how many times a customer account has been used as a SHIP TO location & a BILL TO location.
SELECT ARMASTER.CUSTOMER,
ARMASTER.DIVISION,
ARMASTER.STATUS,
ARMASTER.CUHEAD AS "MASTER",
COUNT (ORDERHEAD.BILLTO) AS "COUNT_BILL",
COUNT (ORDERHEAD.SHIPTO) AS "COUNT_SHIP"
FROM ARMASTER
LEFT OUTER JOIN ORDERHEAD
ON ARMASTER.CUSTOMER = ORDERHEAD.BILLTO
LEFT OUTER JOIN ORDERHEAD
ON ARMASTER.CUSTOMER = ORDERHEAD.SHIPTO
GROUP BY ARMASTER.CUSTOMER,
ARMASTER.DIVISION,
ARMASTER.STATUS,
ARMASTER.CUHEAD
And I'm not even remotley getting what I should be getting. However, when I remove one of my joins the count is exactly what it should be for either 1 or the other of them.
Any guidance would be muchly appreciated! Thank you!
I think it can also work
SELECT CUSTOMER,
DIVISION,
STATUS,
CUHEAD AS "MASTER",
(SELECT COUNT(1) FROM ORDERHEAD WHERE SHIPTO = ARMASTER.CUSTOMER ) AS "COUNT_BILL",
(SELECT COUNT(1) FROM ORDERHEAD WHERE BILLTO = ARMASTER.CUSTOMER ) AS "COUNT_SHIP"
FROM ARMASTER
I am trying to make a summary table of all the items I have. I have a raw data table with 10 users who respectively have different items. There are maximum 3 different items and I want to do a count to see how many items each individual has. The following is my code.
Select b.Country,b.UserID,Num_including_fruits, Apple,Orange
from
(((SELECT o.Country,o.UserID, IIF(ISNULL(Count(o.UserID)),0,Count(o.UserID))
AS Num_including_fruits
FROM [SEA2_View] as o
GROUP BY o.UserID, o.Country
ORDER BY Country)as b
LEFT JOIN
(SELECT o.Country,o.UserID,IIF(ISNULL(Count(o.UserID)),0,Count(o.UserID)
AS Apple
FROM [APAC2_View] as o
WHERE o.fruit_status <>"fresh" AND o.HWType = "Apple"
GROUP BY o.Country,o.UserID)as d
ON (b.UserID = d.UserID))
LEFT JOIN
(SELECT o.Country,o.UserID,IIF(ISNULL(Count(o.UserID)),0,Count(o.UserID))
AS Orange
FROM [SEA2_View] as o
WHERE o.fruit_status <>"fresh" AND o.HWType = "Orange"
GROUP BY o.Country,o.UserID)as e
ON (d.UserID = e.UserID))
;
The first join returns the correct result but the second join somehow returns all 0, which is incorrect. Therefore please help! and I would appreciate any advice for best practice when it comes to joins in SQL. Thanks lot!
Are you sure you don't have a table naming error?
You're first joining [SEA2_View] with [APAC2_View]. The second join is joining with [SEA2_View] with itself.
I know there are a lot of other SO entries that seem like this one, but I haven't found one that actually answers my question so hopefully one of you can either answer it or point me to another SO question that is related.
Basically, I have the following query that returns Venues that have any CheckIns that contain the searched Keyword ("foobar" in this example).
SELECT DISTINCT v.*
FROM "venues" v
INNER JOIN "check_ins" c ON c."venue_id" = v."id"
INNER JOIN "keywordings" ks ON ks."check_in_id" = c."id"
INNER JOIN "keywords" k ON ks."keyword_id" = k."id"
WHERE (k."name" = 'foobar')
I want to SELECT and ORDER BY the count of the matched Keyword for each given Venue. E.g. if there have been 5 CheckIns that have been created, associated with that Keyword, then there should be a returned column (called something like keyword_count) with the value 5 which is sorted.
Ideally this should be done without any queries in the SELECT clause, or preferably none at all.
I've been struggling with this for a while and my mind is just going blank (perhaps it's been too long a day) so some help would be greatly appreciated here.
Thanks in advance!
Sounds like you need something like:
SELECT v.x, v.y, count(*) AS keyword_count
FROM "venues" v
INNER JOIN "check_ins" c ON c."venue_id" = v."id"
INNER JOIN "keywordings" ks ON ks."check_in_id" = c."id"
INNER JOIN "keywords" k ON ks."keyword_id" = k."id"
WHERE (k."name" = 'foobar')
GROUP BY v.x, v.y
ORDER BY 3
Need help on a query using sql server 2005
I am having two tables
code
chargecode
chargeid
orgid
entry
chargeid
itemNo
rate
I need to list all the chargeids in entry table if it contains multiple entries having different chargeids
which got listed in code table having the same charge code.
data :
code
100,1,100
100,2,100
100,3,100
101,11,100
101,12,100
entry
1,x1,1
1,x2,2
2,x3,2
11,x4,1
11,x5,1
using the above data , it query should list chargeids 1 and 2 and not 11.
I got the way to know how many rows in entry satisfies the criteria, but m failing to get the chargeids
select count (distinct chargeId)
from entry where chargeid in (select chargeid from code where chargecode = (SELECT A.chargecode
from code as A join code as B
ON A.chargecode = B.chargeCode and A.chargetype = B.chargetype and A.orgId = B.orgId AND A.CHARGEID = b.CHARGEid
group by A.chargecode,A.orgid
having count(A.chargecode) > 1)
)
First off: I apologise for my completely inaccurate original answer.
The solution to your problem is a self-join. Self-joins are used when you want to select more than one row from the same table. In our case we want to select two charge IDs that have the same charge code:
SELECT DISTINCT c1.chargeid, c2.chargeid FROM code c1
JOIN code c2 ON c1.chargeid != c2.chargeid AND c1.chargecode = c2.chargecode
JOIN entry e1 ON e1.chargeid = c1.chargeid
JOIN entry e2 ON e2.chargeid = c2.chargeid
WHERE c1.chargeid < c2.chargeid
Explanation of this:
First we pick any two charge IDs from 'code'. The DISTINCT avoids duplicates. We make sure they're two different IDs and that they map to the same chargecode.
Then we join on 'entry' (twice) to make sure they both appear in the entry table.
This approach gives (for your example) the pairs (1,2) and (2,1). So we also insist on an ordering; this cuts to result set down to just (1,2), as you described.