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The question is to Produce a list of the latest movies by genres for the current month. How to find the current month from the Date???
You are looking for DATEPART()
Select
*
From YourTable
Where
datepart(month,ReleaseDate) = datepart(month,getdate())
and datepart(year,ReleaseDate) = datepart(year,getdate())
Order by Genre, ReleaseDate desc
You can try this:
SELECT SUBSTRING(TO_CHAR(now(),'YYYYMMDD'),5,2)
In which:
Format to date and you get only the month
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I have two tables with many columns. One contains 50k custIDs, date & Payments received for every id and the other table contains 5k custIDs. I need to find How much payment received per CustId on monthly basis for these 5k CustIDs ?
Assuming your dates are stored as date...
select i.custId, i.custName,
to_char(p.payment_date,'yyyy-mm') as payment_month,
sum(p.amount_paid) as total_amount_paid
from customers i
join payments p
on i.custId = p.custId
group by i.custId, i.custName, to_char(p.payment_date,'yyyy-mm')
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Question was:
average grade for the whole study year of that student.
Select FirstName,LastName,Year,AverageGrade,
Avg AverageGrade Order by YearAverageGrade
from Student
You don't have a PARTITION BY clause. Unless you tell SQL server what the window is, it will use the entire dataset (it can't read your mind, and guess what you're after). I also doubt you need the ORDER BY in the window (as that would default to ORDER BY [Year] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW). I assume you therefore want this:
SELECT FirstName,
LastName,
[Year],
AverageGrade,
AVG(AverageGrade) OVER (PARTITION BY [Year]) AS YearAverageGrade
FROM dbo.Student;
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I Need help to select a number of data per month, there are 4 retailers and I need to select a total of transactions per month and the total amount for that month showing each month separately in sql.
Extract the month from the date and group by it. Then you can use aggregate functions to sum and count
select month(date_column),
sum(amount) as total_amount,
count(*) as transaction_count
from your_table
group by month(date_column)
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I'm trying to display hotel bookings from the 1st of every month.
Hotel (hotelNo,hotelName,hotelAddress)
Room (hotelNo,roomNo,type,price)
Guest (guestNo,guestName,guestAddress)
Booking (hotelNo,guestNo,dateFrom,dateTo,roomNo)
Here's what I have so far. Obviously it isn't working. How do I select the first of any given month?
SELECT hotelNo, dateFrom
FROM booking
WHERE datefrom >= to_date('01', 'dd');
If you want records that are on the first day of any month, then you can EXTRACT the day part of the date and compare it with 1:
SELECT hotelNo, dateFrom
FROM booking
WHERE EXTRACT(DAY FROM datefrom) = 1;
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I have a table
ID______credit________paydate
------------------------------
101_____10____________2012/01/01
101_____13____________2012/02/01
101_____8 ____________2012/03/01
101_____3 ____________2012/03/01
101_____22____________2012/05/01
..._____..____________..........
..._____..____________..........
999_____13____________2012/07/01
999_____38____________2012/08/01
I want to select all records for last 3 months(it is different last paydate for every ID) and where credit < 10
can someone help me with this??
thx and regards
You could use the DATEADD function to get the desired result:
SELECT *
FROM table
WHERE paydate >= DATEADD(month, -3, GETDATE())
AND credit < 10