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I Need help to select a number of data per month, there are 4 retailers and I need to select a total of transactions per month and the total amount for that month showing each month separately in sql.
Extract the month from the date and group by it. Then you can use aggregate functions to sum and count
select month(date_column),
sum(amount) as total_amount,
count(*) as transaction_count
from your_table
group by month(date_column)
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I have below database table,In here i need group some data and get sum and avg of some data.
In here i need to calculate Item marketers monthly sales(Each Month)
As a Example :
I need to get a Patric Newton's Sales in Each months.
And also i need to calculate AvarageFactor of each month Each employee.
AvgFactor = SUM(Daily Sales)/ SUM(Value Factor) * 100( Each Month )
Database Table
I have tried it like below,
SELECT ItemMarketerName,DailySales,ValueFactor,[Month],[Year]
FROM [SR_Hotel].[dbo].[Table_1]
WHERE ItemMarketerName IS NOT NULL
Group by ItemMarketerName,DailySales,ValueFactor,[Month],[Year]
Order by ItemMarketerName
You should not include your aggregated columns in your GROUP BY.
Try:
SELECT ItemMarketerName, [Month], [Year], SUM(DailySales), SUM(DailySales) / SUM(ValueFactor) * 100
FROM [SR_Hotel].[dbo].[Table_1]
WHERE ItemMarketerName IS NOT NULL
GROUP BY ItemMarketerName, [Month], [Year]
ORDER BY ItemMarketerName
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The question is to Produce a list of the latest movies by genres for the current month. How to find the current month from the Date???
You are looking for DATEPART()
Select
*
From YourTable
Where
datepart(month,ReleaseDate) = datepart(month,getdate())
and datepart(year,ReleaseDate) = datepart(year,getdate())
Order by Genre, ReleaseDate desc
You can try this:
SELECT SUBSTRING(TO_CHAR(now(),'YYYYMMDD'),5,2)
In which:
Format to date and you get only the month
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I'm trying to display hotel bookings from the 1st of every month.
Hotel (hotelNo,hotelName,hotelAddress)
Room (hotelNo,roomNo,type,price)
Guest (guestNo,guestName,guestAddress)
Booking (hotelNo,guestNo,dateFrom,dateTo,roomNo)
Here's what I have so far. Obviously it isn't working. How do I select the first of any given month?
SELECT hotelNo, dateFrom
FROM booking
WHERE datefrom >= to_date('01', 'dd');
If you want records that are on the first day of any month, then you can EXTRACT the day part of the date and compare it with 1:
SELECT hotelNo, dateFrom
FROM booking
WHERE EXTRACT(DAY FROM datefrom) = 1;
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I have a table
ID______credit________paydate
------------------------------
101_____10____________2012/01/01
101_____13____________2012/02/01
101_____8 ____________2012/03/01
101_____3 ____________2012/03/01
101_____22____________2012/05/01
..._____..____________..........
..._____..____________..........
999_____13____________2012/07/01
999_____38____________2012/08/01
I want to select all records for last 3 months(it is different last paydate for every ID) and where credit < 10
can someone help me with this??
thx and regards
You could use the DATEADD function to get the desired result:
SELECT *
FROM table
WHERE paydate >= DATEADD(month, -3, GETDATE())
AND credit < 10
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How do I select records in Postgres that have hour values greater than 00:00:00? The field type is Timestamp with time zone.
Example record:
"2012-07-30 07:00:00-07"
I need everything that is greater than 00:00:00
Use extract(hour from ...). See the PostgreSQL date/time functions in the user manual.
CREATE TABLE test AS SELECT TIMESTAMP WITH TIME ZONE '2012-07-30 07:00:00-07' AS tstamp;
SELECT tstamp FROM test WHERE extract(hour from tstamp) > 0;