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I am trying to write a report whereby the report will have the contract updated records for the past week using ms sql script. Every Monday the report will be sent for the last Mon-sun. I tried the below query. it doesnt seems to work. Any idea how to achieve this?
SET DATEFIRST 1
select distinct [...]
where CONTRACT_UPDATE_DATE>= dateadd(day, 1-datepart(dw, getdate()), CONVERT(date,getdate()))
AND CONTRACT_UPDATE_DATE< dateadd(day, 8-datepart(dw, getdate()), CONVERT(date,getdate()))
Thanks.
select * from table_abc WHERE
CAST(CONTRACT_UPDATE_DATE as date) between
CAST(DATEADD(dd, -7, GETDATE()) as date) and
CAST(GETDATE() AS DATE)
use dateadd to get 1 week before current date.
You can remove the cast as date if you need to validate by timestamp also.
You can try this,
SELECT Created_Date
FROM sample1
WHERE Created_Date >= DATEADD(day,-11117, GETDATE())
I suggest this solution:
select * from DB where Datediff(day, CONVERT(DATE, Sysdatetime()),
CONVERT(DATE, CONTRACT_UPDATE_DATE))<=7 and Datediff(day, CONVERT(DATE, Sysdatetime()),
CONVERT(DATE, CONTRACT_UPDATE_DATE))>0
You could try to achieve this by using the calender week.
Try the following:
-- Get last calendar week in format JJJJWW
DECLARE #jjjjkw varchar(6)
SELECT #jjjjkw =
CONVERT(varchar, DATEPART(YYYY,GETDATE()-7)) +
CASE WHEN LEN(CONVERT(varchar,DATEPART(ISO_WEEK,GETDATE()-7))) = 1 THEN '0'
+ CONVERT(varchar,DATEPART(ISO_WEEK,GETDATE()-7))
ELSE CONVERT(varchar,DATEPART(ISO_WEEK,GETDATE()-7)) END
-- Compare with the calendar week of your data-set
SELECT DISTINCT [...]
WHERE
CONVERT(varchar, DATEPART(YYYY,CONTRACT_UPDATE_DATE)) +
CASE WHEN LEN(CONVERT(varchar,DATEPART(ISO_WEEK,CONTRACT_UPDATE_DATE))) = 1
THEN '0' + CONVERT(varchar,DATEPART(ISO_WEEK,CONTRACT_UPDATE_DATE))
ELSE CONVERT(varchar,DATEPART(ISO_WEEK,CONTRACT_UPDATE_DATE)) END = #jjjjkw
Maybe not the most elegant way but it should work.
I have searched far and wide, but I can't seem find a way to convert julian to yyyy-mm-dd.
Here is the format of my julian:
The Julian format consists of the year, the first two digits, and the day within the year, the last three digits.
For example, 95076 is March 17, 1995. The 95 indicates the year and the
076 indicates it is the 76th day of the year.
15260
I have tried this but it isn't working:
dateadd(d,(convert(int,LAST_CHANGED_DATE) % 1000)-1, convert(date,(convert(varchar,convert(int,LAST_CHANGED_DATE) /1000 + 1900) + '/1/1'))) as GrgDate
You can select each part of the date using datepart()
SELECT DATEPART(yy, 95076), DATEPART(dy, 95076)
+++EDIT: I misunderstood something. Here's my correction: +++++
SELECT DATEADD(day, CAST(RIGHT('95076',3) AS int) – 1, CONVERT(datetime,LEFT('95076',2) + '0101', 112))
Edit: leaving this answer for Oracle and MySQL users
This will not work in T-SQL.
Use this:
MAKEDATE(1900 + d / 1000, d % 1000)
For example:
SELECT MAKEDATE(1900 + 95076 / 1000, 95076 % 1000)
This returns March, 17 1995 00:00:00.
SQLFiddle
I concatenated 20 to my JD and then ran
DATEADD(YEAR, LAST_CHANGE_DATE / 1000 - 1900, LAST_CHANGE_DATE % 1000 - 1)
this got me the result. Thank you!!!
FOR SQL Users
DECLARE #jdate VARCHAR(10)
SET #jdate = 117338
SELECT dateadd(dd, (#jdate - ((#jdate/1000) * 1000)) - 1, dateadd(yy, #jdate/1000, 0))
This will definitely work in all case.
DECLARE #date int
SET #date = 21319
SELECT DATEADD(dd, RIGHT(#date,LEN(#date)-3)-1, DATEADD(yy,LEFT(#date,1)*100 +RIGHT(LEFT(#date,3),2),'1 Jan 1900'))
You need to specify 1 or 0 for century in first character. For example, SET #date = 21319 should be prefixed with 1 or 0. Below is an example that will work with all y2k use cases.
DECLARE #jdate INT
SET #jdate = 119150
SELECT DATEADD(dd, (#jdate - ((#jdate/1000) * 1000)) - 1, DATEADD(yy, #jdate/1000, 0))
Declare #Julian varchar(7)
Declare #date date
Set #Julian = 2020277
Set #Date = Dateadd(day,+ Cast(right(#Julian,3) as int)-1, Cast(left(#Julian,4) + '0101' as Date))
Select #Date
Standard SQL is simple (you can do similar for 2 digit year YYMMDD)
Declare #julDate int = 2020275
Select
DateAdd
(
day
, Right(#julDate,3)-1
, Cast((Left(#julDate,4)+'-01-01') as smalldatetime)
)
Try this out:
DECLARE #jdate int
SET #jdate = 21243
select dateadd(dd, (#jdate - ((#jdate/1000) * 1000)) - 1, dateadd(yy, #jdate/1000+100, 0))
I have a query to fetch date diff between 2 datetime as :
SELECT DATEDIFF(DAY, #CreatedDate , GETDATE())
Ex :
SELECT DATEDIFF(DAY, '2013-03-13 00:00:00.000' , GETDATE())
I need to have a query work like this which will subtract a day from created day:
SELECT DATEDIFF(DAY, **#CreatedDate- 1** , GETDATE())
Try this
SELECT DATEDIFF(DAY, DATEADD(day, -1, '2013-03-13 00:00:00.000'), GETDATE())
OR
SELECT DATEDIFF(DAY, DATEADD(day, -1, #CreatedDate), GETDATE())
I am not certain about what precisely you are trying to do, but I think this SQL function will help you:
SELECT DATEADD(day,-1,'2013-04-01 16:25:00.250')
The above will give you 2013-03-31 16:25:00.250.
It takes you back exactly one day and works on any standard date-time or date format.
Try running this command and see if it gives you what you are looking for:
SELECT DATEADD(day,-1,#CreatedDate)
To simply subtract one day from todays date:
Select DATEADD(day,-1,GETDATE())
(original post used -7 and was incorrect)
Apparently you can subtract the number of days you want from a datetime.
SELECT GETDATE() - 1
2016-12-25 15:24:50.403
This should work.
select DATEADD(day, -1, convert(date, GETDATE()))
SELECT DATEDIFF (
DAY,
DATEDIFF(DAY, #CreatedDate, -1),
GETDATE())
Try this, may this will help you
SELECT DATEDIFF(DAY, DATEADD(DAY,-1,'2013-03-13 00:00:00.000') , GETDATE())
To be honest I just use:
select convert(nvarchar(max), GETDATE(), 112)
which gives YYYYMMDD and minus one from it.
Or more correctly
select convert(nvarchar(max), GETDATE(), 112) - 1
for yesterdays date.
Replace Getdate() with your value OrderDate
select convert(nvarchar (max),OrderDate,112)-1 AS SubtractDate FROM Orders
should do it.
You can try this.
Timestamp=2008-11-11 13:23:44.657;
SELECT DATE_SUB(OrderDate,INTERVAL 1 DAY) AS SubtractDate FROM Orders
output :2008-11-10 13:23:44.657
I hope, it will help to solve your problem.
I'm trying to select records that were added to the database between the start of the current month and the current day - I more or less know how to get records from the current day, and within a specific time period - but how do I get it so it starts from the beginning of the current calendar month?
DECLARE #sm DATETIME;
SET #sm = DATEADD(DAY, 1-DAY(GETDATE()), DATEDIFF(DAY, 0, GETDATE()));
SELECT columns
FROM dbo.foo
WHERE datetime_column >= #sm;
WHERE YEAR([Date])=YEAR(GETDATE())
AND MONTH([Date])=MONTH(GETDATE())
AND DAY([Date])<=DAY(GETDATE())
select *
from YourTable
where DateCol >= dateadd(month, datediff(month, 0, getdate()), 0)
Basically what you're doing here is Getting the Month, appending '/01' and then appending the year. Casting it as a string to handle the appending, then casting it as a DateTime.
So it's a little bit more involved than doing any sort of date math, but it's readable I think.
DECLARE #firstOfMonth DATETIME
SET #firstOfMonth = CAST(CAST(DATEPART(mm, GetDate()) as varchar) + '/01/' + cast(DATEPART(yyyy, Getdate()) as varchar) as datetime)
WHERE DateToCheck BETWEEN #firstOfMonth and GetDate()
WHERE DateToCheck > LAST_DAY(CURDATE()-INTERVAL 1 MONTH))
http://www.sqlfiddle.com/#!2/3d673/2/0
I need the month+year from the datetime in SQL Server like 'Jan 2008'. I'm grouping the query by month, year. I've searched and found functions like datepart, convert, etc., but none of them seem useful for this. Am I missing something here? Is there a function for this?
select
datepart(month,getdate()) -- integer (1,2,3...)
,datepart(year,getdate()) -- integer
,datename(month,getdate()) -- string ('September',...)
If you mean you want them back as a string, in that format;
SELECT
CONVERT(CHAR(4), date_of_birth, 100) + CONVERT(CHAR(4), date_of_birth, 120)
FROM customers
Here are the other format options
Beginning with SQL Server 2012, you can use:
SELECT FORMAT(#date, 'yyyyMM')
Use:
select datepart(mm,getdate()) --to get month value
select datename(mm,getdate()) --to get name of month
In SQL server 2012, below can be used
select FORMAT(getdate(), 'MMM yyyy')
This gives exact "Jun 2016"
Funny, I was just playing around writing this same query out in SQL Server and then LINQ.
SELECT
DATENAME(mm, article.Created) AS Month,
DATENAME(yyyy, article.Created) AS Year,
COUNT(*) AS Total
FROM Articles AS article
GROUP BY
DATENAME(mm, article.Created),
DATENAME(yyyy, article.Created)
ORDER BY Month, Year DESC
It produces the following ouput (example).
Month | Year | Total
January | 2009 | 2
How about this?
Select DateName( Month, getDate() ) + ' ' + DateName( Year, getDate() )
That format doesn't exist. You need to do a combination of two things,
select convert(varchar(4),getdate(),100) + convert(varchar(4),year(getdate()))
( Month(Created) + ',' + Year(Created) ) AS Date
the best way to do that is with :
dateadd(month,datediff(month,0,*your_date*),0)
it will keep your datetime type
cast(cast(sq.QuotaDate as date) as varchar(7))
gives "2006-04" format
The question is about SQL Server 2005, many of the answers here are for later version SQL Server.
select convert (varchar(7), getdate(),20)
--Typical output 2015-04
SQL Server 2005 does not have date function which was introduced in SQL Server 2008
returns the full month name, -, full year e.g. March-2017
CONCAT(DATENAME(mm, GetDate()), '-', DATEPART(yy, GetDate()))
I had the same problem and after looking around I found this:
SELECT DATENAME(yyyy, date) AS year
FROM Income
GROUP BY DATENAME(yyyy, date)
It's working great!
Converting the date to the first of the month allows you to Group By and Order By a single attribute, and it's faster in my experience.
declare #mytable table(mydate datetime)
declare #date datetime
set #date = '19000101'
while #date < getdate() begin
insert into #mytable values(#date)
set #date = dateadd(day,1,#date)
end
select count(*) total_records from #mytable
select dateadd(month,datediff(month,0,mydate),0) first_of_the_month, count(*) cnt
from #mytable
group by dateadd(month,datediff(month,0,mydate),0)
---Lalmuni Demos---
create table Users
(
userid int,date_of_birth date
)
---insert values---
insert into Users values(4,'9/10/1991')
select DATEDIFF(year,date_of_birth, getdate()) - (CASE WHEN (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()),date_of_birth)) > getdate() THEN 1 ELSE 0 END) as Years,
MONTH(getdate() - (DATEADD(year, DATEDIFF(year, date_of_birth, getdate()), date_of_birth))) - 1 as Months,
DAY(getdate() - (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()), date_of_birth))) - 1 as Days,
from users
Yes, you can use datename(month,intime) to get the month in text.
,datename(month,(od.SHIP_DATE)) as MONTH_
Answer:
MONTH_
January
January
September
October
December
October
September
It's work great.
DECLARE #pYear VARCHAR(4)
DECLARE #pMonth VARCHAR(2)
DECLARE #pDay VARCHAR(2)
SET #pYear = RIGHT(CONVERT(CHAR(10), GETDATE(), 101), 4)
SET #pMonth = LEFT(CONVERT(CHAR(10), GETDATE(), 101), 2)
SET #pDay = SUBSTRING(CONVERT(CHAR(10), GETDATE(), 101), 4,2)
SELECT #pYear,#pMonth,#pDay
The following works perfectly! I just used it, try it out.
date_format(date,'%Y-%c')