Get month and year from a datetime in SQL Server 2005 - sql

Question

I need the month+year from the datetime in SQL Server like 'Jan 2008'. I'm grouping the query by month, year. I've searched and found functions like datepart, convert, etc., but none of them seem useful for this. Am I missing something here? Is there a function for this?

Answer 1

select
datepart(month,getdate()) -- integer (1,2,3...)
,datepart(year,getdate()) -- integer
,datename(month,getdate()) -- string ('September',...)

Answer 2

If you mean you want them back as a string, in that format;
SELECT
CONVERT(CHAR(4), date_of_birth, 100) + CONVERT(CHAR(4), date_of_birth, 120)
FROM customers
Here are the other format options

Answer 3

Beginning with SQL Server 2012, you can use:
SELECT FORMAT(#date, 'yyyyMM')

Answer 4

Use:
select datepart(mm,getdate()) --to get month value
select datename(mm,getdate()) --to get name of month

Answer 5

In SQL server 2012, below can be used
select FORMAT(getdate(), 'MMM yyyy')
This gives exact "Jun 2016"

Answer 6

Funny, I was just playing around writing this same query out in SQL Server and then LINQ.
SELECT
DATENAME(mm, article.Created) AS Month,
DATENAME(yyyy, article.Created) AS Year,
COUNT(*) AS Total
FROM Articles AS article
GROUP BY
DATENAME(mm, article.Created),
DATENAME(yyyy, article.Created)
ORDER BY Month, Year DESC
It produces the following ouput (example).
Month | Year | Total
January | 2009 | 2

Answer 7

How about this?
Select DateName( Month, getDate() ) + ' ' + DateName( Year, getDate() )

Answer 8

That format doesn't exist. You need to do a combination of two things,
select convert(varchar(4),getdate(),100) + convert(varchar(4),year(getdate()))

Answer 9

( Month(Created) + ',' + Year(Created) ) AS Date

Answer 10

the best way to do that is with :
dateadd(month,datediff(month,0,*your_date*),0)
it will keep your datetime type

Answer 11

cast(cast(sq.QuotaDate as date) as varchar(7))
gives "2006-04" format

Answer 12

The question is about SQL Server 2005, many of the answers here are for later version SQL Server.
select convert (varchar(7), getdate(),20)
--Typical output 2015-04
SQL Server 2005 does not have date function which was introduced in SQL Server 2008

Answer 13

returns the full month name, -, full year e.g. March-2017
CONCAT(DATENAME(mm, GetDate()), '-', DATEPART(yy, GetDate()))

Answer 14

I had the same problem and after looking around I found this:
SELECT DATENAME(yyyy, date) AS year
FROM Income
GROUP BY DATENAME(yyyy, date)
It's working great!

Answer 15

Converting the date to the first of the month allows you to Group By and Order By a single attribute, and it's faster in my experience.
declare #mytable table(mydate datetime)
declare #date datetime
set #date = '19000101'
while #date < getdate() begin
insert into #mytable values(#date)
set #date = dateadd(day,1,#date)
end
select count(*) total_records from #mytable
select dateadd(month,datediff(month,0,mydate),0) first_of_the_month, count(*) cnt
from #mytable
group by dateadd(month,datediff(month,0,mydate),0)

Answer 16

---Lalmuni Demos---
create table Users
(
userid int,date_of_birth date
)
---insert values---
insert into Users values(4,'9/10/1991')
select DATEDIFF(year,date_of_birth, getdate()) - (CASE WHEN (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()),date_of_birth)) > getdate() THEN 1 ELSE 0 END) as Years,
MONTH(getdate() - (DATEADD(year, DATEDIFF(year, date_of_birth, getdate()), date_of_birth))) - 1 as Months,
DAY(getdate() - (DATEADD(year, DATEDIFF(year,date_of_birth, getdate()), date_of_birth))) - 1 as Days,
from users

Answer 17

Yes, you can use datename(month,intime) to get the month in text.

Answer 18

,datename(month,(od.SHIP_DATE)) as MONTH_
Answer:
MONTH_
January
January
September
October
December
October
September

Answer 19

It's work great.
DECLARE #pYear VARCHAR(4)
DECLARE #pMonth VARCHAR(2)
DECLARE #pDay VARCHAR(2)
SET #pYear = RIGHT(CONVERT(CHAR(10), GETDATE(), 101), 4)
SET #pMonth = LEFT(CONVERT(CHAR(10), GETDATE(), 101), 2)
SET #pDay = SUBSTRING(CONVERT(CHAR(10), GETDATE(), 101), 4,2)
SELECT #pYear,#pMonth,#pDay

Answer 20

The following works perfectly! I just used it, try it out.
date_format(date,'%Y-%c')