Merge Two Rows When DATEDIFF>3 - sql

Question

I have a temp table which has the results of a main query where all records have been pivoted out. However, there are two date fields, that when they do not match, cannot pivot into a single row.
I am checking if they have greater than a 3 day difference between them, and if there is, then I need to delete the oldest date and merge the rest of the columns together.
I am using SQL Server 2014
Example Table
+--------------+-------------+-------------------------------+
| Lname | Date1 | idCode1 | idCode2 |
+--------------+-------------+-------------------------------+
| Higgins | 11/30/16 | 9008 2172 | NULL |
| Higgins | 12/31/16 | NULL | 4007 3589 |
| Shaffer | 11/15/16 | 9000 1541 | NULL |
| Shaffer | 11/21/16 | NULL | 7889 9412 |
+--------------+-------------+-------------------------------+
Needs to look like this.
+--------------+-------------+-------------------------------+
| Lname | Date1 | idCode1 | idCode2 |
+--------------+-------------+-------------------------------+
| Higgins | 12/31/16 | 9008 2172 | 4007 3589 |
| Shaffer | 11/21/16 | 9000 1541 | 7889 9412 |
+--------------+-------------+-------------------------------+

Answer 1

Unless I'm missing something here, a simple group by should do it (Assuming you are only going to get max 2 rows for each Lname):
Create and populate sample table (Please save us this step in your future questions)
DECLARE #T AS TABLE
(
Lname varchar(10),
Date1 date,
idCode1 varchar(20),
idCode2 varchar(20)
)
INSERT INTO #T VALUES
('Higgins', '11/30/16', '9008 2172', NULL ),
('Higgins', '12/31/16', NULL , '4007 3589'),
('Shaffer', '11/15/16', '9000 1541', NULL ),
('Shaffer', '11/21/16', NULL , '7889 9412')
The query:
SELECT LName,
MAX(Date1) As Date1,
MAX(IdCode1) As IdCode1,
Max(IdCode2) As IdCode2
FROM #T
GROUP BY LName
HAVING DATEDIFF(DAY, MIN(Date1), MAX(Date1)) > 3
Results:
LName Date1 IdCode1 IdCode2
Higgins 31.12.2016 00:00:00 9008 2172 4007 3589
Shaffer 21.11.2016 00:00:00 9000 1541 7889 9412