Ordering Data using sql - sql

Question

I have a requirement where from a View need to get result in a specific sorting order. Here is sample table:
Now the data has to arrange in Descending order based on the last day BASE_PERCENTAGE. So Last day is 04-Feb-2017 and the highest to lowest order is Jessie, Ricky, Jammie and Jasmine. The final output should arrange data based on BASE_PERCENTAGE, CURR_DATE and Name. Like This-
Could someone please help to how to get the same result using sql. How sql can be written to that it gives the same result.
Please let me know if you need more explanation.
Attached Table_View_sql.sql is having table create, Sample Data Insert and View creation. View will give the data with BASE_Percentage.
Table View Script

Answer 1

You need to be able to tell on every row what the most recent date base_percentage is, if you want to be able to sort by it. One way to do that is something like this. You don't need to keep the LD.LastDayBase in the select output, I added it so you can easily see what the value is while testing.
If you know what the #LastDay is, you could pass it through to the query and skip the first line.
DECLARE #LastDay date = (select MAX(Curr_Date) from v_DailyDetails);
SELECT VD.*, LD.LastDayBase
FROM v_DailyDetails VD
LEFT OUTER JOIN
(
Select Name, BASE_PERCENTAGE LastDayBase
From v_DailyDetails VD
Where CURR_DATE = #LastDay
) LD on LD.Name = VD.Name
ORDER BY LD.LastDayBase DESC, VD.CURR_DATE DESC, LD.NAME
Note that the order you requested means that if ALICE and BOB both had the same LastDayBase value, then you would get the following order ALICE Feb4, Bob Feb4, Alice Feb3, Bob Feb3 etc. If you want days for a given name to be always together, you should use
ORDER BY LD.LastDayBase DESC, LD.NAME, VD.CURR_DATE DESC