#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server - sql

Question

I was trying to run following Query on my sql server :
CREATE TABLE `e_store`.`products`(
`id` INT UNSIGNED NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(250) NOT NULL ,
`brand_id` INT UNSIGNED NOT NULL ,
`category_id` INT UNSIGNED NOT NULL ,
`attributes` JSON NOT NULL ,
PRIMARY KEY(`id`) ,
INDEX `CATEGORY_ID`(`category_id` ASC) ,
INDEX `BRAND_ID`(`brand_id` ASC) ,
CONSTRAINT `brand_id` FOREIGN KEY(`brand_id`) REFERENCES `e_store`.`brands`(`id`) ON DELETE RESTRICT ON UPDATE CASCADE ,
CONSTRAINT `category_id` FOREIGN KEY(`category_id`) REFERENCES `e_store`.`categories`(`id`) ON DELETE RESTRICT ON UPDATE CASCADE
);
I have already brands and categories tables on my e_store database.
But I got the following Error :
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'JSON NOT NULL ,
PRIMARY KEY(`id`) ,
INDEX `CATEGORY_ID`('category_id' ' at line 6

Answer 1

For those who are facing this issue similar to me:
MariaDB does not natively implement the JSON data type but it uses it as an alias for LONGTEXT for compatibility reasons. According to the documentation (https://mariadb.com/kb/en/library/json-data-type/):
JSON is an alias for LONGTEXT introduced for compatibility reasons with MySQL's JSON data type. MariaDB implements this as a LONGTEXT rather, as the JSON data type contradicts the SQL standard, and MariaDB's benchmarks indicate that performance is at least equivalent.
In order to ensure that a a valid json document is inserted, the JSON_VALID function can be used as a CHECK constraint.
So if you are having issues with the JSON data type in MariaDB, simply just change to LONGTEXT. ;-)

Answer 2

I think you are getting error for JSON datatype.
For Mysql 5.7 you can get help from below link.
https://dev.mysql.com/doc/refman/5.7/en/json.html
You can check vesrion using below query.
select version() as 'mysql version'

Answer 3

"JSON" is parsed in the server. JSON is one of the points of divergence.
MySQL 5.7 introduced the JSON datatype, which matches your syntax.
MariaDB 10.0.16 introduced a ENGINE=CONNECT table_type=JSON which does not match your attempted syntax.

Answer 4

You have given single quotes in your index definitions instead of backticks
Try this:
CREATE TABLE `e_store`.`products`(
`id` INT UNSIGNED NOT NULL AUTO_INCREMENT ,
`name` VARCHAR(250) NOT NULL ,
`brand_id` INT UNSIGNED NOT NULL ,
`category_id` INT UNSIGNED NOT NULL ,
`attributes` JSON NOT NULL ,
PRIMARY KEY(`id`) ,
INDEX `CATEGORY_ID`(`category_id` ASC) , -- Changed single quotes to backticks
INDEX `BRAND_ID`(`brand_id` ASC) , -- Changed single quotes to backticks
CONSTRAINT `brand_id` FOREIGN KEY(`brand_id`) REFERENCES `e_store`.`brands`(`id`) ON DELETE RESTRICT ON UPDATE CASCADE ,
CONSTRAINT `category_id` FOREIGN KEY(`category_id`) REFERENCES `e_store`.`categories`(`id`) ON DELETE RESTRICT ON UPDATE CASCADE
);