When I update a column using phpmyadmin in database with following query
UPDATE members
SET `refered` = (SELECT COUNT (*)
FROM `user_details`
WHERE `user_details.sponser`=`members.username`
)
It show a error message like this
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '*) FROM `user_details` WHERE `user_details.sponser`=`members.username`)' at line 1
What may be reason?
Error is in
COUNT (*)
-----^
Remove the space between COUNT and (*).
Try the below query
UPDATE members SET refered = (SELECT COUNT(*) FROM user_details
WHERE user_details.sponser=members.username)
Does the Select query returns any result. If so what is the result. Looks like all your query is inside '' single quotes that you are using it should be removed. Single quotes need to be removed for example .
UPDATE members
SET refered = (SELECT COUNT (*)
FROM user_details
WHERE user_details.sponser=members.username
)
-- there is not single quotes in the query above. please remove it from yours.
Part of your problem, or maybe the whole problem, is the WHERE clause. You've used backticks for the table name, which is correct (or, at least, it's optional in this case; it's needed if your database name or table name has a MySQL reserved name or is otherwise ambiguous). The problem, though, is that the dot separating the database from the table needs to be outside the backticks. So your WHERE clause should look like this instead:
WHERE `user_details`.`sponser`=`members`.`username`
Related
I have the following query in a stored procedure in SQL server:
SELECT TLI.LESNumber
,COUNT(TLT.PL)
INTO #PWCM
FROM #tmpLESImport TLI
INNER JOIN tbl_LES L
on TLI.LESNumber=L.NUMB
WHERE ISNULL(L.DELT_FLAG,0)=0
AND L.SCHL_PK=#SCHL_PK
AND TLI.PL IS NOT NULL
AND LEN(TLI.PL)>0
GROUP BY LESNumber
HAVING COUNT(PL)>1
When the query is run I get the following error:
An object or column name is missing or empty. For SELECT INTO statements, verify each column has a name. For other statements, look for empty alias names. Aliases defined as "" or [] are not allowed. Change the alias to a valid name.
Can anyone tell me why? #PWCM does not appear anywhere until this query.
When you SELECT INTO a table, it creates the table (in this case, a temp table). In order to create a table, each column needs a name, which your count column does not. You just need to give it a name:
SELECT TLI.LESNumber,COUNT(TLT.PL) [NumRecords]
INTO #PWCM
FROM #tmpLESImport TLI
...
I had this error for this query
SELECT
CASE WHEN COALESCE([dbo].[my-table].[field],"") = '...' THEN 'A'
WHEN COALESCE([dbo].[my-table].[field],"") = '...' THEN 'B'
...
END AS aaa INTO ##TEMPTABLE
FROM [dbo].[my-table]
Turns out I had to change the "" inside the COALSCE into ''.
Solved it for me
I just came across this, and the core reason was actually related to an errant set of brackets in the code which made the engine think there was a missing alias. Something along the lines of:
select *
from SOME_TABLE
where x = 1
[]
A stringified version of the query included a parameter list for logging, but that was being issued as the query instead of the actual query object. Deleting [] at the end resolved it.
I want to Select a column and set it equal to 0. In SQL I just do this: SELECT Dealer_Fee = 0.
Do I have to use an update? When I try the same thing in Oracle I get "FROM keyword not found where expected."
I am not sure what do you want to do and in which SQL dialect the construction you mentioned works. If you just want to retrieve some value and place it in a named column in Oracle you have to use DUAL table. Try this:
SELECT 0 AS dealer_fee FROM dual;
On the other hand, if you ment T-SQL and placing a value into variable you need to use PL/SQL SELECT INTO clause, like that:
SELECT 0 INTO dealer_fee from dual;
If not try to explain in more detail what are you trying to achieve.
1) In Oracle you must specify FROM clause within SELECT, is not like MS sqlserver where you can omit a FROM clause.
2) If you want to update one specific value, you must use UPDATE clause instead SELECT.
hth
You should use the Update statement. Please visit this oracle reference which explains the Update statement in detail: Update Statement
Take a look at the reference for UPDATE in Oracle:
UPDATE <table_name>
SET <column_name> = <value>
I made a mistake and entered:
SELECT * FROM table LIMIT1
instead of
SELECT * FROM table LIMIT 1 (note the space between LIMIT and 1)
in the CLI of MySQL. I expected to receive some kind of parse error, but I was surprised, because the query returned all of the records in the table. My first thought was "stupid MySQL, I bet that this will return error in PostgreSQL", but PostgreSQL also returned all records. Then tested it with SQLite - with the same result.
After some digging, I realized that it doesn't matter what I enter after the table. As long as there are no WHERE/ORDER/GROUP clauses:
SELECT * FROM table SOMETHING -- works and returns all records in table
SELECT * FROM table WHERE true SOMETHING -- doesn't work - returns parse error
I guess that this is a standardized behavior, but I couldn't find any explanation why's that. Any ideas?
Your first query is equivalent to this query using a table alias:
SELECT * FROM yourtable AS LIMIT1
The AS keyword is optional. The table alias allows you to refer to columns of that table using the alias LIMIT1.foo rather than the original table name. It can be useful to use aliases if you wish to give tables a shorter or a more descriptive alias within a query. It is necessary to use aliases if you join a table to itself.
From the SQL lite documentation:
This is why I want DB engine to force the usage of keyword AS for alias names
http://beyondrelational.com/modules/2/blogs/70/posts/10814/should-alias-names-be-preceded-by-as.aspx
SELECT * FROM table LIMIT1;
LIMIT1 This has taken as alias by SQL, cause LIMIT1 is not a reserved literal of SQL.
Something after table name and that is not a reserved keyword always taken as an table alias by SQL.
SELECT * FROM table LIMIT 1;
When you used LIMIT just after the table name, SQL found that as a reserved keyword and worked for it as per the behavior. IF you want to use reserved key words in query It can be done by putting reserved literals in quotes. like..
SELECT * FROM table `LIMIT`;
OR
SELECT * FROM table `LIMIT 1`;
Now all words covered under `` quotes will treated as user defined.
Commonly we did mistake with date, timestamp, limit etc.. keywords by using them as column names.
I am trying to update a value in my database but am recieving the following error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''users' ('new_user') VALUES ('1') WHERE 'id'= 5' at line 1
I am trying to UPDATE the table 'users' in the column 'new_user' where the id is equal to $userid. But it don't work. Please help.
$newuservalue = '1';
$notnewuser ="UPDATE 'users' ('new_user') VALUES ('$newuservalue') WHERE 'id'= $userid ";
$query2 = mysql_query($notnewuser) or die(mysql_error());
Well, your syntax is wrong.
It should be:
UPDATE table_name SET field1=new-value1, field2=new-value2 [WHERE Clause]
So, remove the "values" part of your query and put in the "set" part.
Here's a link to the official documentation.
i have that problems some times, that's the code to insert a new row :d
It should be:
UPDATE users SET new_user='$newuservalue' WHERE id=$userid
you also don't need to put quotes around your column names, that might give some problems as well.
I have a table and one of the columns holds web addresses like: 'http://...' or 'https://...'.
The problem is that there are some invalid entries, like 'shttp://...' or '#http//...' (the first character is invalid) and I want to correct all of them.
I use the following SQL statement:
'SELECT [...] FROM MyTable WHERE WebAddress LIKE '_http%'
and I successfuly get the problematic rows.
But how am I going to change/correct all of them using an UPDATE statement?
If you have some other solution please share it!
Simply change the SELECT to an UPDATE (of course, with some syntax changes) with a "fix" expression
UPDATE
MyTable
SET
WebAddress = SUBSTRING(WebAddress, 2, 8000)
WHERE
WebAddress LIKE '_http%'
You Can use Sub string property as you can trim odd letters .Also like '_word start' suitable for your question