SELECT Boeking.reisnummer, (aantal_volwassenen + aantal_kinderen) AS totaal_reizigers
FROM Boeking
WHERE Boeking.reisnummer = Reis.Reisnummer
AND Reis.Reisnummer = Reis.Bestemmingscode;
Table 1 (Boeking) has aantal_volwassen and aantal_kinderen, and Reisnummer.
Table 2 (Reis) has Reisnummer and Bestemmingscode.
I have to show the total of aantal_volwassenen and aantal_kinderen. But i also have to show Reis.bestemmingscode which comes from a different table. Currently i have to enter a parameter, how can i solve this?
You need to specify all the tables in the FROM part of your query. The tables should then be joined (JOIN) to get the data you need.
SELECT Boeking.reisnummer
,(aantal_volwassenen + aantal_kinderen) AS totaal_reizigers
,Reis.Bestemmingscode
FROM Boeking INNER JOIN Reis
ON Boeking.reisnummer = Reis.Reisnummer
Related
I have two tables, temp_am and amphibian. The relationship between the two tables comes from the lake_id and the survey_date column in both tables. Both tables have 24,109 entries.
temp_am
id
lake_id
survey_date
1
10,001
7/25/2001
5
10,005
7/27/2001
6
10,006
7/29/2001
etc...
amphibain
id
lake_id
survey_date
amhibian_survey_id
1
10,002
7/25/2001
2
10,005
7/27/2001
etc...
I want to input the temp_am.id into the amphibian.amphibian_survey_id when both lake_ids and survey dates equal each other.
I have tried this sql query but it never worked. I canceled the query after 600 seconds as I figured a 29,000 observation table should not take that long. Please let me know if you see any issues in my query statement.
update amphibian
set amphibian_survey_id = tm.id
from amphibian a
inner join temp_am tm
on a.lake_id = tm.lake_id
and a.survey_date = tm.survey_date
This query worked in microsoft access but not on DBeaver
UPDATE amphibian
inner JOIN amphibian_survey_meta_data md ON
(amphibian.survey_date = md.survey_date) AND (amphibian.lake_id = md.lake_id) SET amphibian.amphibian_survey_id = [md.id];
Postgres does not require repeating the table name for an update join. In this case even the join is not necessary just set <column> = ( select ... ) is sufficient. See demo here.
update amphibain a
set amhibian_survey_id =
( select tm.id
from temp_am tm
where (tm.lake_id, tm.survey_date) =
(a.lake_id, a.survey_date)
) ;
I created a query which selects sum of columns from a table grouped by a field in Crystal reports, now I want the result to be filtered by a date range from another table which I am unable to do. Please Help...
Here is the query
SELECT
BDETAIL.HSN,
SUM(BDETAIL.TAXABLE),
SUM(BDETAIL.SGST_V),
SUM(BDETAIL.CGST_V),
SUM(BDETAIL.TOTAL),
BDETAIL.SGST_P
FROM
BDETAIL
JOIN
BILL ON BDETAIL.BILL_ID = BILL.BILL_ID
WHERE
BILL.BDATE BETWEEN {?FROM_DATE} AND {?TO_DATE} )
GROUP BY
BDETAIL.HSN, BDETAIL.SGST_P
I finally figured it out ..here is the working query
SELECT BDETAIL.HSN,
sum(BDETAIL.TAXABLE),
Sum(BDETAIL.SGST_V),
Sum(BDETAIL.CGST_V),
Sum(BDETAIL.TOTAL),
BDETAIL.SGST_P
FROM BDETAIL INNER JOIN BILL ON
( BILL.BILL_ID = BDETAIL.BILL_ID AND
BILL.BDATE BETWEEN {?FROM_DATE} AND {?TO_DATE} )
GROUP BY BDETAIL.HSN, BDETAIL.SGST_P;
thank you all for showing interest in my issue.
My title is probably not very clear, so I made a little schema to explain what I'm trying to achieve. The xxxx_uid labels are foreign keys linking two tables.
Goal: Retrieve a column from the grids table by giving a proj_uid value.
I'm not very good with SQL joins and I don't know how to build a single query that will achieve that.
Actually, I'm doing 3 queries to perform the operation:
1) This gives me a res_uid to work with:
select res_uid from results where results.proj_uid = VALUE order by res_uid asc limit 1"
2) This gives me a rec_uid to work with:
select rec_uid from receptor_results
inner join results on results.res_uid = receptor_results.res_uid
where receptor_results.res_uid = res_uid_VALUE order by rec_uid asc limit 1
3) Get the grid column I want from the grids table:
select grid_name from grids
inner join receptors on receptors.grid_uid = grids.grid_uid
where receptors.rec_uid = rec_uid_VALUE;
Is it possible to perform a single SQL that will give me the same results the 3 I'm actually doing ?
You're not limited to one JOIN in a query:
select grids.grid_name
from grids
inner join receptors
on receptors.grid_uid = grids.grid_uid
inner join receptor_results
on receptor_results.rec_uid = receptors.rec_uid
inner join results
on results.res_uid = receptor_results.res_uid
where results.proj_uid = VALUE;
select g.grid_name
from results r
join resceptor_results rr on r.res_uid = rr.res_uid
join receptors rec on rec.rec_uid = rr.rec_uid
join grids g on g.grid_uid = rec.grid_uid
where r.proj_uid = VALUE
a small note about names, typically in sql the table is named for a single item not the group. thus "result" not "results" and "receptor" not "receptors" etc. As you work with sql this will make sense and names like you have will seem strange. Also, one less character to type!
I am having a bit of trouble, probably from my understanding of SQL. Here is the SQL I am currently using:
CREATE TEMPORARY TABLE Temp
(
sPropertyCode VARCHAR(9),
sDataDate DATE,
PRIMARY KEY (sPropertyCode)
);
INSERT IGNORE Temp (sPropertyCode, sDataDate)
SELECT sPropertyCode, sDataDate
FROM tasks as t, task_data AS d
WHERE t.iTaskId = d.iTaskId
AND iRemoved = 1
AND sDataType = 'sAgencyAgreementDate'
AND iBusinessStreamId = 9;
SELECT t.sPropertyCode, sDataDate, SFirstSeen, sTaskType
FROM tasks AS t, temp AS a
WHERE iRemoved = 1
AND iBusinessStreamId = 9
AND sTaskType IN ('RF', 'IF', 'CM')
AND t.sPropertyCode = a.sPropertyCode
ORDER BY sPropertyCode, sFirstSeen;
DROP TABLE Temp;
So the references 'RF', 'IF' and 'CM' are tasks that we receive. Each propertycode can touch each of these tasks once, and only once. I would like to show the date that each one of these was touched by the propertycode. It is working at the moment but it is showing it in three columns with the tasks types in one column. I would like each task to show in a seperate column with the date it was first seen in its own corresponding column.
So from the picture below is how it is currently laid out with the code above.
And here is how I would like it to look, instead of the tasks showing down the side, I would like them to show accross in columns with their own specific dates
Thank you in advance :)
SELECT t.sPropertyCode, sDataDate, SFirstSeen, a1.sTaskType, a2.sTaskType, a3.sTaskType
FROM tasks AS t
INNER JOIN temp AS a1 on t.sPropertyCode = a1.sPropertyCode and a1.sTaskType = 'RF'
INNER JOIN temp as a2 on t.sPropertyCode = a2.sPropertyCode and a2.sTaskType = 'IF'
INNER JOIN temp as a3 on t.sPropertyCode = a3.sPropertyCode and a3.sTaskType = 'CM'
WHERE iRemoved = 1 AND iBusinessStreamId = 9
ORDER BY sPropertyCode, sFirstSeen;
You can also user outer join if not always have all 3 tast type.
What is the difference in meaning between the CM,IF and RF columns for any row in your 5-col table ? They're always the very same value in the example you listed.
I'm working on a DB2 stored procedure and am having a little trouble getting the results I want. The problem with the following query is that it does not return rows from table A that don't pass the final where clause. I would like to receive all rows from table A that meet the first WHERE clause (WHERE A.GENRC_CD_TYPE = 'MDAA'). Then, add an email column from table B for each of those rows(WHERE (A.DESC) = B.MATL_PLNR_ID).
SELECT A.GENRC_CD,
A.DESC_30,
A.DOL,
A.DLU,
A.LU_LID,
B.EMAIL_ID_50
FROM GENRCCD A,
MPPLNR B
WHERE A.GENRC_CD_TYPE = 'MDAA'
AND (A.DESC_30) = B.MATL_PLNR_ID;
Any help is much appreciated, thanks!
Then what you need is a LEFT JOIN:
SELECT A.GENRC_CD,
A.DESC_30,
A.DOL,
A.DLU,
A.LU_LID,
B.EMAIL_ID_50
FROM GENRCCD A LEFT JOIN
MPPLNR B on A.DESC_30=B.MATL_PLNR_ID
WHERE A.GENRC_CD_TYPE = 'MDAA'