I have the ff. table:
as you can see i have duplicate rows for column inseciid. This data is correct btw, they differ on other columns, it just not shown in the screenshot.
I want to be able to select all columns but for those rows with the same inseciID, i want the sum(insebrbillresidentamt). so the output will be 24.00 for inseciid=4037. How do i do that using group by?
I tried doing it like this
select
sum(A.insebrBillResidentAmt) as insebrBillResidentAmt
from InspectionsBillResidentServiceAction A
group by A.inseciid
when i add other columns in the select statement, it requires me to add the columns in the group by clause. but in doing that, the rows get duplicated again. can you shed some light on how do i use group by in cases like this? thanks in advance
Just use max on all other columns:
select max(insebrid) as insebrid,
max(inceciid) as inceciid,
sum(insebrBillResidentAmt) as insebrBillResidentAmt,
max(said) as said,
max(wgid) as wgid,
max(setID) as setID
from InspectionsBillResidentServiceAction
group by inseciid
Related
I am attempting to combine a rows based on the customer id and a T/F column. I am new to coding and SQL and I've tried 'GROUP BY' in my query that has 50 plus columns but i am unable to do so.
Data Set:
Desired Result
Thank you in advance.
There are probably more elegant solutions, but try the following...
select recordID, city, max(ispaid)
from dat
group by recordID, city
Here's a link to SQL Fiddle where you can play with it.
You can use distinct
select
distinct recordId,
city,
isPaid
from yourTable
I need to know where the mistake is in this oracle query?
SELECT(KEY1),COUNT(*) FROM TABLE1 GROUP BY AGE
SELECT KEY1,COUNT(*) FROM TABLE1 GROUP BY KEY1
There are two problems. First one: You cannot close the parenthesis after the first keyword. Second: You have to group by all keys that are in the query that are not all row dependend. In that case "KEY1". If you want to order by age you have to query age as parameter.
SELECT AGE,COUNT(*) FROM TABLE1 GROUP BY AGE
Your table naming is not very good. I assume you should have a look at group by tutorials like https://www.w3schools.com/sql/sql_groupby.asp or the sql tutorial https://www.w3schools.com/sql/
Your query had an issue. You have to modify your query as below
SELECT KEY1,COUNT(*) FROM TABLE1 GROUP BY KEY1.
Observation:
All the columns that are added in the select statement alongside the aggregate functions, should be included the group by columns.
Your first column does have the bracket in it which should be removed.
I have a scenario for a type2 table where I have to remove duplicates on total row level.
Lets consider below example as the data in table.
A|B|C|D|E
100|12-01-2016|2|3|4
100|13-01-2016|3|4|5
100|14-01-2016|2|3|4
100|15-01-2016|5|6|7
100|16-01-2016|5|6|7
If you consider A as key column, you know that last 2 rows are duplicates.
Generally to find duplicates, we use group by function.
select A,C,D,E,count(1)
from table
group by A,C,D,E
having count(*)>1
for this output would be 100|2|3|4 as duplicate and also 100|5|6|7.
However, only 100|5|6|7 is only duplicate as per type 2 and not 100|2|3|4 because this value has come back in 3rd run and not soon after 1st load.
If I add date field into group by 100|5|6|7 will not be considered as duplicate, but in reality it is.
Trying to figure out duplicates as explained above.
Duplicates should only be 100|5|6|7 and not 100|2|3|4.
can someone please help out with SQL for the same.
Regards
Raghav
Use row_number analytical function to get rid of duplicates.
delete from
(
select a,b,c,d,e,row_number() over (partition by a,b,c,d,e) as rownumb
from table
) as a
where rownumb > 1
if you want to see all duplicated rows, you need join table with your group by query or filter table using group query as subquery.
wITH CTE AS (select a, B, C,D,E, count(*)
from TABLE
group by 1,2,3,4,5
having count(*)>1)
sELECT * FROM cte
WHERE B <> B + 1
Try this query and see if it works. In case you are getting any errors then let me know.
I am assuming that your column B is in the Date format if not then cast it to date
If you can see the duplicate then just replace select * to delete
I need help on creating a select statement in sql to get the unique rows.
I need the unique Reference ID but since Call Time is also unique, I only need to get the first row out of the similar rows.
I have this table[Calls]:
The result should be:
When I used:
Select Distinct * FROM Calls
It will return the same table and not the result I want.
It may helps you...
min(date) is the first datetime for each individual
Select referenceid,min(date),number from calls
group by referenceid,number
Perhaps a simple GROUP BY:
SELECT ReferenceID,
MIN(CallTime) AS CallTime,
MIN(Number) AS Number
FROM dbo.TableName t
GROUP BY ReferenceID
I realize my title probably doesnt explain my situation very well, but I honestly have no idea how to word this.
I am using SQL to access a DB2 database.
Using my screenshot image 1 below as a reference:
column 1 has three instances of "U11124", with three different descriptions (column 2)
I would like this query to return the first instance of "U11124" and its description, but then also unique records for the other rows. image 2 shows my desired result.
image 1
image 2
----- EDIT ----
to answer some of the questions / posts:
technically, it does not need to be the first , just any single one of those records. the problem is that we have three descriptions, and only one needs to be shown, i am now told it does not matter which one.
SELECT STVNST, MAX(STDESC) FROM MY_TABLE GROUP BY STVNST;
In SQL Server:
select stvnst, stdesc
from (
select
stvnst, stdesc
row_number() over (order by stdesc partition by stvnst) row
from table
) a
where row = 1
This method has an advantage over a simple group by, in that it will also work when there's more than two columns in the table.
SELECT STVNST,FIRST(STDESC) from table group by STVNST ORDER BY what_you_want_first
All you need to do is use GROUP BY.
You say you want the first instance of the STDESC column? Well you can't guarntee the order of the rows without another column, however if you want to order by the highest ordered value the following will suffice:
SELECT STVNST, MAX(STDESC) FROM MY_TABLE GROUP BY STVNST;